Space separated argument to script











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0
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I'm trying to use a wrapper bash script to execute some command with one parameter separated by space 'A B'.



foo-wrapper.sh content:



#/!bin/bash

foo $1


When running foo-wrapper.sh:



$bash -x foo-wrapper.sh "'A B'"

+ Error: foo ''''A' 'B''''


The expected call would be: foo 'A B'



Any ideas how to make that work?






bash







share|improve this question




























    up vote
    0
    down vote

    favorite












    I'm trying to use a wrapper bash script to execute some command with one parameter separated by space 'A B'.



    foo-wrapper.sh content:



    #/!bin/bash
    
foo $1


    When running foo-wrapper.sh:



    $bash -x foo-wrapper.sh "'A B'"
    
+ Error: foo ''''A' 'B''''


    The expected call would be: foo 'A B'



    Any ideas how to make that work?






    bash







    share|improve this question


























      up vote
      0
      down vote

      favorite









      up vote
      0
      down vote

      favorite











      I'm trying to use a wrapper bash script to execute some command with one parameter separated by space 'A B'.



      foo-wrapper.sh content:



      #/!bin/bash
      
foo $1


      When running foo-wrapper.sh:



      $bash -x foo-wrapper.sh "'A B'"
      
+ Error: foo ''''A' 'B''''


      The expected call would be: foo 'A B'



      Any ideas how to make that work?






      bash







      share|improve this question















      I'm trying to use a wrapper bash script to execute some command with one parameter separated by space 'A B'.



      foo-wrapper.sh content:



      #/!bin/bash
      
foo $1


      When running foo-wrapper.sh:



      $bash -x foo-wrapper.sh "'A B'"
      
+ Error: foo ''''A' 'B''''


      The expected call would be: foo 'A B'



      Any ideas how to make that work?






      bash




      bash






      share|improve this question















      share|improve this question













      share|improve this question




      share|improve this question








      edited 2 days ago









      Micha Wiedenmann

      9,6891164102




      9,6891164102










      asked 2 days ago









      ntrax111

      406




      406
























          1 Answer
          1






          active

          oldest

          votes

















          up vote
          1
          down vote



          accepted











          • In the wrapper replace $1 by "$1".

            If your arguments/variables contain space characters, you need to quote them to prevent them from being split.


          • In the call instead of "'A B'" use one of "A B", 'A B' or A B.

            These are the most usual ways of specifying strings in BASH. (Note that the whitespace only makes a difference in the 3rd case. You would have to use quotes in the first two cases no matter whether you have a space or not.)



          If you want to play around a little to get a feeling, you can start with:



          $ foo() { echo "count: $#"; echo "arg 1: $1"; echo "arg 2: $2"; }
          
$ foo A B C
          
count: 2
          
arg 1: A B
          
arg 2: C





          share|improve this answer























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            1 Answer
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            1 Answer
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            active

            oldest

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            active

            oldest

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            active

            oldest

            votes








            up vote
            1
            down vote



            accepted











            • In the wrapper replace $1 by "$1".

              If your arguments/variables contain space characters, you need to quote them to prevent them from being split.


            • In the call instead of "'A B'" use one of "A B", 'A B' or A B.

              These are the most usual ways of specifying strings in BASH. (Note that the whitespace only makes a difference in the 3rd case. You would have to use quotes in the first two cases no matter whether you have a space or not.)



            If you want to play around a little to get a feeling, you can start with:



            $ foo() { echo "count: $#"; echo "arg 1: $1"; echo "arg 2: $2"; }
            
$ foo A B C
            
count: 2
            
arg 1: A B
            
arg 2: C





            share|improve this answer



























              up vote
              1
              down vote



              accepted











              • In the wrapper replace $1 by "$1".

                If your arguments/variables contain space characters, you need to quote them to prevent them from being split.


              • In the call instead of "'A B'" use one of "A B", 'A B' or A B.

                These are the most usual ways of specifying strings in BASH. (Note that the whitespace only makes a difference in the 3rd case. You would have to use quotes in the first two cases no matter whether you have a space or not.)



              If you want to play around a little to get a feeling, you can start with:



              $ foo() { echo "count: $#"; echo "arg 1: $1"; echo "arg 2: $2"; }
              
$ foo A B C
              
count: 2
              
arg 1: A B
              
arg 2: C





              share|improve this answer

























                up vote
                1
                down vote



                accepted







                up vote
                1
                down vote



                accepted







                • In the wrapper replace $1 by "$1".

                  If your arguments/variables contain space characters, you need to quote them to prevent them from being split.


                • In the call instead of "'A B'" use one of "A B", 'A B' or A B.

                  These are the most usual ways of specifying strings in BASH. (Note that the whitespace only makes a difference in the 3rd case. You would have to use quotes in the first two cases no matter whether you have a space or not.)



                If you want to play around a little to get a feeling, you can start with:



                $ foo() { echo "count: $#"; echo "arg 1: $1"; echo "arg 2: $2"; }
                
$ foo A B C
                
count: 2
                
arg 1: A B
                
arg 2: C





                share|improve this answer















                • In the wrapper replace $1 by "$1".

                  If your arguments/variables contain space characters, you need to quote them to prevent them from being split.


                • In the call instead of "'A B'" use one of "A B", 'A B' or A B.

                  These are the most usual ways of specifying strings in BASH. (Note that the whitespace only makes a difference in the 3rd case. You would have to use quotes in the first two cases no matter whether you have a space or not.)



                If you want to play around a little to get a feeling, you can start with:



                $ foo() { echo "count: $#"; echo "arg 1: $1"; echo "arg 2: $2"; }
                
$ foo A B C
                
count: 2
                
arg 1: A B
                
arg 2: C






                share|improve this answer














                share|improve this answer



                share|improve this answer








                edited 2 days ago

























                answered 2 days ago









                Micha Wiedenmann

                9,6891164102




                9,6891164102






























                     

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