quadrature rule has the highest possible order
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Find the weights $w_0, w_1$ and the abscissa $x_0$ such that the following quadrature rule has the highest possible order: $$int_0^1 f(x) dx approx w_0f(x_0) + w_1 f(1)$$
Do I need to use the formula,
$$w_j = frac{2}{(1-x_j^2)
(P'_n(x_j))^2}$$
If so how do I use it? what is $x_j$ and $P'_n$?
numerical-methods
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down vote
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Find the weights $w_0, w_1$ and the abscissa $x_0$ such that the following quadrature rule has the highest possible order: $$int_0^1 f(x) dx approx w_0f(x_0) + w_1 f(1)$$
Do I need to use the formula,
$$w_j = frac{2}{(1-x_j^2)
(P'_n(x_j))^2}$$
If so how do I use it? what is $x_j$ and $P'_n$?
numerical-methods
add a comment |
up vote
0
down vote
favorite
up vote
0
down vote
favorite
Find the weights $w_0, w_1$ and the abscissa $x_0$ such that the following quadrature rule has the highest possible order: $$int_0^1 f(x) dx approx w_0f(x_0) + w_1 f(1)$$
Do I need to use the formula,
$$w_j = frac{2}{(1-x_j^2)
(P'_n(x_j))^2}$$
If so how do I use it? what is $x_j$ and $P'_n$?
numerical-methods
Find the weights $w_0, w_1$ and the abscissa $x_0$ such that the following quadrature rule has the highest possible order: $$int_0^1 f(x) dx approx w_0f(x_0) + w_1 f(1)$$
Do I need to use the formula,
$$w_j = frac{2}{(1-x_j^2)
(P'_n(x_j))^2}$$
If so how do I use it? what is $x_j$ and $P'_n$?
numerical-methods
numerical-methods
asked yesterday
user123
46319
46319
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The abscissas $(x_j)$ are the zeros of the $n$th orthogonal polynomial; here $n=2$ and $P_2$ is the second Legendre polynomial (only the domain of definition has been altered from $[-1,1]$ to $[0,1]$ so you need to change variable. Read about Gaussian quadratures.
I havemade another post about this question with more detail, could you help?
– user123
11 hours ago
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1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
up vote
0
down vote
The abscissas $(x_j)$ are the zeros of the $n$th orthogonal polynomial; here $n=2$ and $P_2$ is the second Legendre polynomial (only the domain of definition has been altered from $[-1,1]$ to $[0,1]$ so you need to change variable. Read about Gaussian quadratures.
I havemade another post about this question with more detail, could you help?
– user123
11 hours ago
add a comment |
up vote
0
down vote
The abscissas $(x_j)$ are the zeros of the $n$th orthogonal polynomial; here $n=2$ and $P_2$ is the second Legendre polynomial (only the domain of definition has been altered from $[-1,1]$ to $[0,1]$ so you need to change variable. Read about Gaussian quadratures.
I havemade another post about this question with more detail, could you help?
– user123
11 hours ago
add a comment |
up vote
0
down vote
up vote
0
down vote
The abscissas $(x_j)$ are the zeros of the $n$th orthogonal polynomial; here $n=2$ and $P_2$ is the second Legendre polynomial (only the domain of definition has been altered from $[-1,1]$ to $[0,1]$ so you need to change variable. Read about Gaussian quadratures.
The abscissas $(x_j)$ are the zeros of the $n$th orthogonal polynomial; here $n=2$ and $P_2$ is the second Legendre polynomial (only the domain of definition has been altered from $[-1,1]$ to $[0,1]$ so you need to change variable. Read about Gaussian quadratures.
edited yesterday
answered yesterday
Richard Martin
1,3588
1,3588
I havemade another post about this question with more detail, could you help?
– user123
11 hours ago
add a comment |
I havemade another post about this question with more detail, could you help?
– user123
11 hours ago
I havemade another post about this question with more detail, could you help?
– user123
11 hours ago
I havemade another post about this question with more detail, could you help?
– user123
11 hours ago
add a comment |
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