Confused about the possibility of different differentiable structures.











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In Loring Tu's "An Introduction to Manifolds" an atlas on a manifold is a collection of coordinate charts that are pairwise compatible and cover the manifold. A smooth manifold is defined to be a topological manifold together with a maximal atlas or differentiable structure. The maximal atlas is constructed by taking an atlas and appending all coordinate charts that are compatible with the atlas and using this he shows that any atlas on a locally Euclidean space is contained in a unique maximal atlas.



He also later shows that for any chart on a manifold, the coordinate map is a diffeomorphism onto it's image.



My question arises when Tu mentions in an aside that every compact topological manifold in dimension four or higher has a finite number of differentiable structures. What I don't understand is how it is possible for a smooth manifold to have more than one differentiable structure. Doesn't the fact that for any chart the coordinate map being a diffeomorphism coupled with the fact that composition of smooth functions is smooth mean that any two coordinate charts on a manifold are compatible and thus they must all belong to one maximal atlas? How is it possible to have another? Am I not understanding the word "maximal" or atlas or some other concept?






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  • 2




    "Maximal" usually means "cannot be further extended", but does not imply uniqueness. For instance a maximal ideal is one any extension of which is either itself or the whole ring. A ring may have many distinct maximal ideals.
    – Eric Towers
    Jun 30 '14 at 16:04










  • Thank you. I think I understand this concept then. But my question still remains in this case. Are all coordinate maps compatible with each other as a result of being diffeomorphisms? Would this not imply that there could only be one maximal atlas on a manifold by our construction regardless of dimension?
    – Memeozuki
    Jun 30 '14 at 16:12










  • All coordinate maps within the same atlas are certainly compatible with each other. As my answer shows, there will always exist coordinate maps which are incompatible with a given atlas. Such coordinate maps may form the foundation of an entirely different maximal atlas for an entirely different differentiable structure.
    – Lee Mosher
    Jun 30 '14 at 18:31

















up vote
3
down vote

favorite












In Loring Tu's "An Introduction to Manifolds" an atlas on a manifold is a collection of coordinate charts that are pairwise compatible and cover the manifold. A smooth manifold is defined to be a topological manifold together with a maximal atlas or differentiable structure. The maximal atlas is constructed by taking an atlas and appending all coordinate charts that are compatible with the atlas and using this he shows that any atlas on a locally Euclidean space is contained in a unique maximal atlas.



He also later shows that for any chart on a manifold, the coordinate map is a diffeomorphism onto it's image.



My question arises when Tu mentions in an aside that every compact topological manifold in dimension four or higher has a finite number of differentiable structures. What I don't understand is how it is possible for a smooth manifold to have more than one differentiable structure. Doesn't the fact that for any chart the coordinate map being a diffeomorphism coupled with the fact that composition of smooth functions is smooth mean that any two coordinate charts on a manifold are compatible and thus they must all belong to one maximal atlas? How is it possible to have another? Am I not understanding the word "maximal" or atlas or some other concept?






differential-geometry manifolds







share|cite|improve this question


















  • 2




    "Maximal" usually means "cannot be further extended", but does not imply uniqueness. For instance a maximal ideal is one any extension of which is either itself or the whole ring. A ring may have many distinct maximal ideals.
    – Eric Towers
    Jun 30 '14 at 16:04










  • Thank you. I think I understand this concept then. But my question still remains in this case. Are all coordinate maps compatible with each other as a result of being diffeomorphisms? Would this not imply that there could only be one maximal atlas on a manifold by our construction regardless of dimension?
    – Memeozuki
    Jun 30 '14 at 16:12










  • All coordinate maps within the same atlas are certainly compatible with each other. As my answer shows, there will always exist coordinate maps which are incompatible with a given atlas. Such coordinate maps may form the foundation of an entirely different maximal atlas for an entirely different differentiable structure.
    – Lee Mosher
    Jun 30 '14 at 18:31















up vote
3
down vote

favorite









up vote
3
down vote

favorite











In Loring Tu's "An Introduction to Manifolds" an atlas on a manifold is a collection of coordinate charts that are pairwise compatible and cover the manifold. A smooth manifold is defined to be a topological manifold together with a maximal atlas or differentiable structure. The maximal atlas is constructed by taking an atlas and appending all coordinate charts that are compatible with the atlas and using this he shows that any atlas on a locally Euclidean space is contained in a unique maximal atlas.



He also later shows that for any chart on a manifold, the coordinate map is a diffeomorphism onto it's image.



My question arises when Tu mentions in an aside that every compact topological manifold in dimension four or higher has a finite number of differentiable structures. What I don't understand is how it is possible for a smooth manifold to have more than one differentiable structure. Doesn't the fact that for any chart the coordinate map being a diffeomorphism coupled with the fact that composition of smooth functions is smooth mean that any two coordinate charts on a manifold are compatible and thus they must all belong to one maximal atlas? How is it possible to have another? Am I not understanding the word "maximal" or atlas or some other concept?






differential-geometry manifolds







share|cite|improve this question













In Loring Tu's "An Introduction to Manifolds" an atlas on a manifold is a collection of coordinate charts that are pairwise compatible and cover the manifold. A smooth manifold is defined to be a topological manifold together with a maximal atlas or differentiable structure. The maximal atlas is constructed by taking an atlas and appending all coordinate charts that are compatible with the atlas and using this he shows that any atlas on a locally Euclidean space is contained in a unique maximal atlas.



He also later shows that for any chart on a manifold, the coordinate map is a diffeomorphism onto it's image.



My question arises when Tu mentions in an aside that every compact topological manifold in dimension four or higher has a finite number of differentiable structures. What I don't understand is how it is possible for a smooth manifold to have more than one differentiable structure. Doesn't the fact that for any chart the coordinate map being a diffeomorphism coupled with the fact that composition of smooth functions is smooth mean that any two coordinate charts on a manifold are compatible and thus they must all belong to one maximal atlas? How is it possible to have another? Am I not understanding the word "maximal" or atlas or some other concept?






differential-geometry manifolds




differential-geometry manifolds






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asked Jun 30 '14 at 15:59









Memeozuki

428312




428312








  • 2




    "Maximal" usually means "cannot be further extended", but does not imply uniqueness. For instance a maximal ideal is one any extension of which is either itself or the whole ring. A ring may have many distinct maximal ideals.
    – Eric Towers
    Jun 30 '14 at 16:04










  • Thank you. I think I understand this concept then. But my question still remains in this case. Are all coordinate maps compatible with each other as a result of being diffeomorphisms? Would this not imply that there could only be one maximal atlas on a manifold by our construction regardless of dimension?
    – Memeozuki
    Jun 30 '14 at 16:12










  • All coordinate maps within the same atlas are certainly compatible with each other. As my answer shows, there will always exist coordinate maps which are incompatible with a given atlas. Such coordinate maps may form the foundation of an entirely different maximal atlas for an entirely different differentiable structure.
    – Lee Mosher
    Jun 30 '14 at 18:31
















  • 2




    "Maximal" usually means "cannot be further extended", but does not imply uniqueness. For instance a maximal ideal is one any extension of which is either itself or the whole ring. A ring may have many distinct maximal ideals.
    – Eric Towers
    Jun 30 '14 at 16:04










  • Thank you. I think I understand this concept then. But my question still remains in this case. Are all coordinate maps compatible with each other as a result of being diffeomorphisms? Would this not imply that there could only be one maximal atlas on a manifold by our construction regardless of dimension?
    – Memeozuki
    Jun 30 '14 at 16:12










  • All coordinate maps within the same atlas are certainly compatible with each other. As my answer shows, there will always exist coordinate maps which are incompatible with a given atlas. Such coordinate maps may form the foundation of an entirely different maximal atlas for an entirely different differentiable structure.
    – Lee Mosher
    Jun 30 '14 at 18:31










2




2




"Maximal" usually means "cannot be further extended", but does not imply uniqueness. For instance a maximal ideal is one any extension of which is either itself or the whole ring. A ring may have many distinct maximal ideals.
– Eric Towers
Jun 30 '14 at 16:04




"Maximal" usually means "cannot be further extended", but does not imply uniqueness. For instance a maximal ideal is one any extension of which is either itself or the whole ring. A ring may have many distinct maximal ideals.
– Eric Towers
Jun 30 '14 at 16:04












Thank you. I think I understand this concept then. But my question still remains in this case. Are all coordinate maps compatible with each other as a result of being diffeomorphisms? Would this not imply that there could only be one maximal atlas on a manifold by our construction regardless of dimension?
– Memeozuki
Jun 30 '14 at 16:12




Thank you. I think I understand this concept then. But my question still remains in this case. Are all coordinate maps compatible with each other as a result of being diffeomorphisms? Would this not imply that there could only be one maximal atlas on a manifold by our construction regardless of dimension?
– Memeozuki
Jun 30 '14 at 16:12












All coordinate maps within the same atlas are certainly compatible with each other. As my answer shows, there will always exist coordinate maps which are incompatible with a given atlas. Such coordinate maps may form the foundation of an entirely different maximal atlas for an entirely different differentiable structure.
– Lee Mosher
Jun 30 '14 at 18:31






All coordinate maps within the same atlas are certainly compatible with each other. As my answer shows, there will always exist coordinate maps which are incompatible with a given atlas. Such coordinate maps may form the foundation of an entirely different maximal atlas for an entirely different differentiable structure.
– Lee Mosher
Jun 30 '14 at 18:31












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You cite from Tu's book a statement that "for any chart on a manifold, the coordinate map is a diffeomorphism onto its image", but if you check that statement carefully I'm sure that it applies only to charts within the given maximal atlas. It is certainly possible to have incompatible coordinate charts that are not in a given maximal atlas, e.g. here are two incompatible coordinate charts on $mathbb{R}$: $f(x)=x$; and $f(x) = sqrt[3]{x}$.






share|cite|improve this answer





















  • Just to be sure I understand you example. Then each of those charts must belong to different maximal atlas for the same manifold ($mathbb{R}$), right?.
    – An old man in the sea.
    14 hours ago












  • That's correct.
    – Lee Mosher
    10 hours ago











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up vote
3
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You cite from Tu's book a statement that "for any chart on a manifold, the coordinate map is a diffeomorphism onto its image", but if you check that statement carefully I'm sure that it applies only to charts within the given maximal atlas. It is certainly possible to have incompatible coordinate charts that are not in a given maximal atlas, e.g. here are two incompatible coordinate charts on $mathbb{R}$: $f(x)=x$; and $f(x) = sqrt[3]{x}$.






share|cite|improve this answer





















  • Just to be sure I understand you example. Then each of those charts must belong to different maximal atlas for the same manifold ($mathbb{R}$), right?.
    – An old man in the sea.
    14 hours ago












  • That's correct.
    – Lee Mosher
    10 hours ago















up vote
3
down vote













You cite from Tu's book a statement that "for any chart on a manifold, the coordinate map is a diffeomorphism onto its image", but if you check that statement carefully I'm sure that it applies only to charts within the given maximal atlas. It is certainly possible to have incompatible coordinate charts that are not in a given maximal atlas, e.g. here are two incompatible coordinate charts on $mathbb{R}$: $f(x)=x$; and $f(x) = sqrt[3]{x}$.






share|cite|improve this answer





















  • Just to be sure I understand you example. Then each of those charts must belong to different maximal atlas for the same manifold ($mathbb{R}$), right?.
    – An old man in the sea.
    14 hours ago












  • That's correct.
    – Lee Mosher
    10 hours ago













up vote
3
down vote










up vote
3
down vote









You cite from Tu's book a statement that "for any chart on a manifold, the coordinate map is a diffeomorphism onto its image", but if you check that statement carefully I'm sure that it applies only to charts within the given maximal atlas. It is certainly possible to have incompatible coordinate charts that are not in a given maximal atlas, e.g. here are two incompatible coordinate charts on $mathbb{R}$: $f(x)=x$; and $f(x) = sqrt[3]{x}$.






share|cite|improve this answer












You cite from Tu's book a statement that "for any chart on a manifold, the coordinate map is a diffeomorphism onto its image", but if you check that statement carefully I'm sure that it applies only to charts within the given maximal atlas. It is certainly possible to have incompatible coordinate charts that are not in a given maximal atlas, e.g. here are two incompatible coordinate charts on $mathbb{R}$: $f(x)=x$; and $f(x) = sqrt[3]{x}$.







share|cite|improve this answer












share|cite|improve this answer



share|cite|improve this answer










answered Jun 30 '14 at 16:09









Lee Mosher

47.2k33681




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  • Just to be sure I understand you example. Then each of those charts must belong to different maximal atlas for the same manifold ($mathbb{R}$), right?.
    – An old man in the sea.
    14 hours ago












  • That's correct.
    – Lee Mosher
    10 hours ago


















  • Just to be sure I understand you example. Then each of those charts must belong to different maximal atlas for the same manifold ($mathbb{R}$), right?.
    – An old man in the sea.
    14 hours ago












  • That's correct.
    – Lee Mosher
    10 hours ago
















Just to be sure I understand you example. Then each of those charts must belong to different maximal atlas for the same manifold ($mathbb{R}$), right?.
– An old man in the sea.
14 hours ago






Just to be sure I understand you example. Then each of those charts must belong to different maximal atlas for the same manifold ($mathbb{R}$), right?.
– An old man in the sea.
14 hours ago














That's correct.
– Lee Mosher
10 hours ago




That's correct.
– Lee Mosher
10 hours ago


















 

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