Radius of a wheel that is in contact with a brick [on hold]











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A brick $4$cm thick is placed so as to block a carriage wheel. If the distance of the brick from the point of contact of the wheel and thre ground is $10$cm, find the radius of the wheel.



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put on hold as off-topic by Rushabh Mehta, John Douma, amWhy, user21820, José Carlos Santos yesterday


This question appears to be off-topic. The users who voted to close gave this specific reason:


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    A brick $4$cm thick is placed so as to block a carriage wheel. If the distance of the brick from the point of contact of the wheel and thre ground is $10$cm, find the radius of the wheel.



    enter image description here










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    put on hold as off-topic by Rushabh Mehta, John Douma, amWhy, user21820, José Carlos Santos yesterday


    This question appears to be off-topic. The users who voted to close gave this specific reason:


    • "This question is missing context or other details: Please improve the question by providing additional context, which ideally includes your thoughts on the problem and any attempts you have made to solve it. This information helps others identify where you have difficulties and helps them write answers appropriate to your experience level." – Rushabh Mehta, John Douma, amWhy, user21820, José Carlos Santos

    If this question can be reworded to fit the rules in the help center, please edit the question.















      up vote
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      down vote

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      up vote
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      down vote

      favorite











      A brick $4$cm thick is placed so as to block a carriage wheel. If the distance of the brick from the point of contact of the wheel and thre ground is $10$cm, find the radius of the wheel.



      enter image description here










      share|cite|improve this question









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      Julian Aung is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
      Check out our Code of Conduct.











      A brick $4$cm thick is placed so as to block a carriage wheel. If the distance of the brick from the point of contact of the wheel and thre ground is $10$cm, find the radius of the wheel.



      enter image description here







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      edited yesterday









      mrtaurho

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      2,3691726






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      asked yesterday









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      put on hold as off-topic by Rushabh Mehta, John Douma, amWhy, user21820, José Carlos Santos yesterday


      This question appears to be off-topic. The users who voted to close gave this specific reason:


      • "This question is missing context or other details: Please improve the question by providing additional context, which ideally includes your thoughts on the problem and any attempts you have made to solve it. This information helps others identify where you have difficulties and helps them write answers appropriate to your experience level." – Rushabh Mehta, John Douma, amWhy, user21820, José Carlos Santos

      If this question can be reworded to fit the rules in the help center, please edit the question.




      put on hold as off-topic by Rushabh Mehta, John Douma, amWhy, user21820, José Carlos Santos yesterday


      This question appears to be off-topic. The users who voted to close gave this specific reason:


      • "This question is missing context or other details: Please improve the question by providing additional context, which ideally includes your thoughts on the problem and any attempts you have made to solve it. This information helps others identify where you have difficulties and helps them write answers appropriate to your experience level." – Rushabh Mehta, John Douma, amWhy, user21820, José Carlos Santos

      If this question can be reworded to fit the rules in the help center, please edit the question.






















          2 Answers
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          Sketch the wheel, the ground and the brick. Draw a right angled triangle with vertices at (a) the centre of the wheel; (b) the point where the wheel contacts the brick, and (c) the point 4 cm above the point where the wheel meets the ground. Point (c) is at the same horizontal level as the point where the wheel contacts the brick, because the brick is 4cm thick.



          If the radius of the wheel is $r$, what are the lengths of the sides of this triangle ? Use Pythagoras's theorem to find an equation involving $r$. Now solve this equation to find the value of $r$.






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            14.5



            If we draw a right triangle with the radius going from the brick to the center of the wheel being the hypotenuse, one side going from the brick parallel to the ground until it meets with the vertical radius, then we get a triangle with hypotenuse R, one side 10 and the other side R-4. $R^2=(R-4)^2+10^2$ solving for R gives 116/8 which is 14.5.






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              2 Answers
              2






              active

              oldest

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              2 Answers
              2






              active

              oldest

              votes









              active

              oldest

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              active

              oldest

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              up vote
              1
              down vote













              Sketch the wheel, the ground and the brick. Draw a right angled triangle with vertices at (a) the centre of the wheel; (b) the point where the wheel contacts the brick, and (c) the point 4 cm above the point where the wheel meets the ground. Point (c) is at the same horizontal level as the point where the wheel contacts the brick, because the brick is 4cm thick.



              If the radius of the wheel is $r$, what are the lengths of the sides of this triangle ? Use Pythagoras's theorem to find an equation involving $r$. Now solve this equation to find the value of $r$.






              share|cite|improve this answer

























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                Sketch the wheel, the ground and the brick. Draw a right angled triangle with vertices at (a) the centre of the wheel; (b) the point where the wheel contacts the brick, and (c) the point 4 cm above the point where the wheel meets the ground. Point (c) is at the same horizontal level as the point where the wheel contacts the brick, because the brick is 4cm thick.



                If the radius of the wheel is $r$, what are the lengths of the sides of this triangle ? Use Pythagoras's theorem to find an equation involving $r$. Now solve this equation to find the value of $r$.






                share|cite|improve this answer























                  up vote
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                  up vote
                  1
                  down vote









                  Sketch the wheel, the ground and the brick. Draw a right angled triangle with vertices at (a) the centre of the wheel; (b) the point where the wheel contacts the brick, and (c) the point 4 cm above the point where the wheel meets the ground. Point (c) is at the same horizontal level as the point where the wheel contacts the brick, because the brick is 4cm thick.



                  If the radius of the wheel is $r$, what are the lengths of the sides of this triangle ? Use Pythagoras's theorem to find an equation involving $r$. Now solve this equation to find the value of $r$.






                  share|cite|improve this answer












                  Sketch the wheel, the ground and the brick. Draw a right angled triangle with vertices at (a) the centre of the wheel; (b) the point where the wheel contacts the brick, and (c) the point 4 cm above the point where the wheel meets the ground. Point (c) is at the same horizontal level as the point where the wheel contacts the brick, because the brick is 4cm thick.



                  If the radius of the wheel is $r$, what are the lengths of the sides of this triangle ? Use Pythagoras's theorem to find an equation involving $r$. Now solve this equation to find the value of $r$.







                  share|cite|improve this answer












                  share|cite|improve this answer



                  share|cite|improve this answer










                  answered yesterday









                  gandalf61

                  7,187523




                  7,187523






















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                      down vote













                      14.5



                      If we draw a right triangle with the radius going from the brick to the center of the wheel being the hypotenuse, one side going from the brick parallel to the ground until it meets with the vertical radius, then we get a triangle with hypotenuse R, one side 10 and the other side R-4. $R^2=(R-4)^2+10^2$ solving for R gives 116/8 which is 14.5.






                      share|cite|improve this answer

























                        up vote
                        0
                        down vote













                        14.5



                        If we draw a right triangle with the radius going from the brick to the center of the wheel being the hypotenuse, one side going from the brick parallel to the ground until it meets with the vertical radius, then we get a triangle with hypotenuse R, one side 10 and the other side R-4. $R^2=(R-4)^2+10^2$ solving for R gives 116/8 which is 14.5.






                        share|cite|improve this answer























                          up vote
                          0
                          down vote










                          up vote
                          0
                          down vote









                          14.5



                          If we draw a right triangle with the radius going from the brick to the center of the wheel being the hypotenuse, one side going from the brick parallel to the ground until it meets with the vertical radius, then we get a triangle with hypotenuse R, one side 10 and the other side R-4. $R^2=(R-4)^2+10^2$ solving for R gives 116/8 which is 14.5.






                          share|cite|improve this answer












                          14.5



                          If we draw a right triangle with the radius going from the brick to the center of the wheel being the hypotenuse, one side going from the brick parallel to the ground until it meets with the vertical radius, then we get a triangle with hypotenuse R, one side 10 and the other side R-4. $R^2=(R-4)^2+10^2$ solving for R gives 116/8 which is 14.5.







                          share|cite|improve this answer












                          share|cite|improve this answer



                          share|cite|improve this answer










                          answered yesterday









                          Mathaddict

                          1484




                          1484















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