Trying to pass variables from JS to PHP file [on hold]

up vote
1
down vote

favorite

I'm trying to pass these variables via AJAX POST method from my JS file to my PHP file, but nothing goes thru. The console log is clean, and the table in the php page loaded, but the fields are empty. The idea is to set the variables in JS & then pass them into the php file to be displayed in the table.

Here's a Screenshot of the Chrome Window

Here's the .JS part:

    $.ajax({

    type: "POST",

    url: "test-php.php",

    dataType: "text",

    data: {

      min: "D201522170",

      invoice: 60,

      sum: 60, // Replace with dynamic radio button values

      descr: "Food Regime",

      exp_date: "31.12.2018"

      },

      success: function(data) {

        console.log(data);

      }

  });

And here's the .PHP part:

<?php

if (session_status() == PHP_SESSION_NONE) {

  session_start();

}

$min        = $_POST['min'];

$invoice    = $_POST['invoice'];

$sum        = $_POST['sum'];

$exp_date   = $_POST['exp_date'];

$descr      = $_POST['descr'];



$data = <<<DATA

MIN={$min}

INVOICE={$invoice}

AMOUNT={$sum}

EXP_TIME={$exp_date}

DESCR={$descr}

DATA;

These variables are displayed on the screen in a table:

      <table class="striped">

        <tbody>

          <tr>

            <td>Merchant Id</td>

            <td> {$min}</td>

          </tr>

          <tr>

            <td>Invoice Number</td>

            <td>{$invoice}</td>

          </tr>

          <tr>

            <td>Product Description</td>

            <td>{$descr}</td>

          </tr>

          <tr>

            <td>Payment</td>

            <td>{$sum}</td>

          </tr>

          <tr>

            <td>Total Amount</td>

            <td>{$sum}</td>

          </tr>

          <tr>

          <td>

          </tbody>

          </table>

?>

javascript php jquery ajax

share|improve this question

edited yesterday

asked yesterday

Pok3r Princ3

63

put on hold as off-topic by ADyson, Masivuye Cokile, Billal Begueradj, Philipp, Blackbam yesterday

This question appears to be off-topic. The users who voted to close gave this specific reason:

• "Questions seeking debugging help ("why isn't this code working?") must include the desired behavior, a specific problem or error and the shortest code necessary to reproduce it in the question itself. Questions without a clear problem statement are not useful to other readers. See: How to create a Minimal, Complete, and Verifiable example." – ADyson, Masivuye Cokile, Billal Begueradj, Philipp, Blackbam

If this question can be reworded to fit the rules in the help center, please edit the question.

• 
  
  
  

  
  4
  

  
  
  
  
  
  

  
  in your .js part you try to call jquery ajax function inside php tags
  – Oleg Nurutdinov
  yesterday
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  "Here's the .JS part:"....and yet it's enclosed in <?php tags....where are your <script> tags?
  – ADyson
  yesterday
  

  
  
  
  


• 
  
  
  

  
  1
  

  
  
  
  
  
  

  
  @Pok3rPrinc3 edit the question and post correct
  – Masivuye Cokile
  yesterday
  

  
  
  
  


• 
  
  
  

  
  2
  

  
  
  
  
  
  

  
  Ok, so then..."nothing goes through" is not an error message or problem statement. Have you used your browser's Developer Tools to try and debug the AJAX call? Is it sent? Is the data in the body correct? What status is returned? Are there any console errors? What about in PHP - how you are verifying that the $_POST data is not what you expected? You haven't given us any clear detail. I note you appear to have included the "success" callback within the data object itself, which I guess is a mistake. It may or may not be the cause of your problem, but without more info it's hard to be certain.
  – ADyson
  yesterday
  
  
  

  
  
  
  


• 
  
  
  

  
  1
  

  
  
  
  
  
  

  
  @MasivuyeCokile no, it isn't.. the only wrong thing is, that success is inside data
  – Philipp
  yesterday
  

  
  
  
  

 | 
show 7 more comments

up vote
1
down vote

favorite

I'm trying to pass these variables via AJAX POST method from my JS file to my PHP file, but nothing goes thru. The console log is clean, and the table in the php page loaded, but the fields are empty. The idea is to set the variables in JS & then pass them into the php file to be displayed in the table.

Here's a Screenshot of the Chrome Window

Here's the .JS part:

    $.ajax({

    type: "POST",

    url: "test-php.php",

    dataType: "text",

    data: {

      min: "D201522170",

      invoice: 60,

      sum: 60, // Replace with dynamic radio button values

      descr: "Food Regime",

      exp_date: "31.12.2018"

      },

      success: function(data) {

        console.log(data);

      }

  });

And here's the .PHP part:

<?php

if (session_status() == PHP_SESSION_NONE) {

  session_start();

}

$min        = $_POST['min'];

$invoice    = $_POST['invoice'];

$sum        = $_POST['sum'];

$exp_date   = $_POST['exp_date'];

$descr      = $_POST['descr'];



$data = <<<DATA

MIN={$min}

INVOICE={$invoice}

AMOUNT={$sum}

EXP_TIME={$exp_date}

DESCR={$descr}

DATA;

These variables are displayed on the screen in a table:

      <table class="striped">

        <tbody>

          <tr>

            <td>Merchant Id</td>

            <td> {$min}</td>

          </tr>

          <tr>

            <td>Invoice Number</td>

            <td>{$invoice}</td>

          </tr>

          <tr>

            <td>Product Description</td>

            <td>{$descr}</td>

          </tr>

          <tr>

            <td>Payment</td>

            <td>{$sum}</td>

          </tr>

          <tr>

            <td>Total Amount</td>

            <td>{$sum}</td>

          </tr>

          <tr>

          <td>

          </tbody>

          </table>

?>

javascript php jquery ajax

share|improve this question

edited yesterday

asked yesterday

Pok3r Princ3

63

put on hold as off-topic by ADyson, Masivuye Cokile, Billal Begueradj, Philipp, Blackbam yesterday

This question appears to be off-topic. The users who voted to close gave this specific reason:

• "Questions seeking debugging help ("why isn't this code working?") must include the desired behavior, a specific problem or error and the shortest code necessary to reproduce it in the question itself. Questions without a clear problem statement are not useful to other readers. See: How to create a Minimal, Complete, and Verifiable example." – ADyson, Masivuye Cokile, Billal Begueradj, Philipp, Blackbam

If this question can be reworded to fit the rules in the help center, please edit the question.

• 
  
  
  

  
  4
  

  
  
  
  
  
  

  
  in your .js part you try to call jquery ajax function inside php tags
  – Oleg Nurutdinov
  yesterday
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  "Here's the .JS part:"....and yet it's enclosed in <?php tags....where are your <script> tags?
  – ADyson
  yesterday
  

  
  
  
  


• 
  
  
  

  
  1
  

  
  
  
  
  
  

  
  @Pok3rPrinc3 edit the question and post correct
  – Masivuye Cokile
  yesterday
  

  
  
  
  


• 
  
  
  

  
  2
  

  
  
  
  
  
  

  
  Ok, so then..."nothing goes through" is not an error message or problem statement. Have you used your browser's Developer Tools to try and debug the AJAX call? Is it sent? Is the data in the body correct? What status is returned? Are there any console errors? What about in PHP - how you are verifying that the $_POST data is not what you expected? You haven't given us any clear detail. I note you appear to have included the "success" callback within the data object itself, which I guess is a mistake. It may or may not be the cause of your problem, but without more info it's hard to be certain.
  – ADyson
  yesterday
  
  
  

  
  
  
  


• 
  
  
  

  
  1
  

  
  
  
  
  
  

  
  @MasivuyeCokile no, it isn't.. the only wrong thing is, that success is inside data
  – Philipp
  yesterday
  

  
  
  
  

 | 
show 7 more comments

up vote
1
down vote

favorite

up vote
1
down vote

favorite

I'm trying to pass these variables via AJAX POST method from my JS file to my PHP file, but nothing goes thru. The console log is clean, and the table in the php page loaded, but the fields are empty. The idea is to set the variables in JS & then pass them into the php file to be displayed in the table.

Here's a Screenshot of the Chrome Window

Here's the .JS part:

    $.ajax({

    type: "POST",

    url: "test-php.php",

    dataType: "text",

    data: {

      min: "D201522170",

      invoice: 60,

      sum: 60, // Replace with dynamic radio button values

      descr: "Food Regime",

      exp_date: "31.12.2018"

      },

      success: function(data) {

        console.log(data);

      }

  });

And here's the .PHP part:

<?php

if (session_status() == PHP_SESSION_NONE) {

  session_start();

}

$min        = $_POST['min'];

$invoice    = $_POST['invoice'];

$sum        = $_POST['sum'];

$exp_date   = $_POST['exp_date'];

$descr      = $_POST['descr'];



$data = <<<DATA

MIN={$min}

INVOICE={$invoice}

AMOUNT={$sum}

EXP_TIME={$exp_date}

DESCR={$descr}

DATA;

These variables are displayed on the screen in a table:

      <table class="striped">

        <tbody>

          <tr>

            <td>Merchant Id</td>

            <td> {$min}</td>

          </tr>

          <tr>

            <td>Invoice Number</td>

            <td>{$invoice}</td>

          </tr>

          <tr>

            <td>Product Description</td>

            <td>{$descr}</td>

          </tr>

          <tr>

            <td>Payment</td>

            <td>{$sum}</td>

          </tr>

          <tr>

            <td>Total Amount</td>

            <td>{$sum}</td>

          </tr>

          <tr>

          <td>

          </tbody>

          </table>

?>

javascript php jquery ajax

share|improve this question

edited yesterday

asked yesterday

Pok3r Princ3

63

I'm trying to pass these variables via AJAX POST method from my JS file to my PHP file, but nothing goes thru. The console log is clean, and the table in the php page loaded, but the fields are empty. The idea is to set the variables in JS & then pass them into the php file to be displayed in the table.

Here's a Screenshot of the Chrome Window

Here's the .JS part:

    $.ajax({

    type: "POST",

    url: "test-php.php",

    dataType: "text",

    data: {

      min: "D201522170",

      invoice: 60,

      sum: 60, // Replace with dynamic radio button values

      descr: "Food Regime",

      exp_date: "31.12.2018"

      },

      success: function(data) {

        console.log(data);

      }

  });

And here's the .PHP part:

<?php

if (session_status() == PHP_SESSION_NONE) {

  session_start();

}

$min        = $_POST['min'];

$invoice    = $_POST['invoice'];

$sum        = $_POST['sum'];

$exp_date   = $_POST['exp_date'];

$descr      = $_POST['descr'];



$data = <<<DATA

MIN={$min}

INVOICE={$invoice}

AMOUNT={$sum}

EXP_TIME={$exp_date}

DESCR={$descr}

DATA;

These variables are displayed on the screen in a table:

      <table class="striped">

        <tbody>

          <tr>

            <td>Merchant Id</td>

            <td> {$min}</td>

          </tr>

          <tr>

            <td>Invoice Number</td>

            <td>{$invoice}</td>

          </tr>

          <tr>

            <td>Product Description</td>

            <td>{$descr}</td>

          </tr>

          <tr>

            <td>Payment</td>

            <td>{$sum}</td>

          </tr>

          <tr>

            <td>Total Amount</td>

            <td>{$sum}</td>

          </tr>

          <tr>

          <td>

          </tbody>

          </table>

?>

javascript php jquery ajax

javascript php jquery ajax

share|improve this question

edited yesterday

asked yesterday

Pok3r Princ3

63

share|improve this question

edited yesterday

asked yesterday

Pok3r Princ3

63

share|improve this question

share|improve this question

edited yesterday

edited yesterday

edited yesterday

asked yesterday

Pok3r Princ3

63

asked yesterday

Pok3r Princ3

63

asked yesterday

Pok3r Princ3

63

63

put on hold as off-topic by ADyson, Masivuye Cokile, Billal Begueradj, Philipp, Blackbam yesterday

This question appears to be off-topic. The users who voted to close gave this specific reason:

• "Questions seeking debugging help ("why isn't this code working?") must include the desired behavior, a specific problem or error and the shortest code necessary to reproduce it in the question itself. Questions without a clear problem statement are not useful to other readers. See: How to create a Minimal, Complete, and Verifiable example." – ADyson, Masivuye Cokile, Billal Begueradj, Philipp, Blackbam

If this question can be reworded to fit the rules in the help center, please edit the question.

put on hold as off-topic by ADyson, Masivuye Cokile, Billal Begueradj, Philipp, Blackbam yesterday

This question appears to be off-topic. The users who voted to close gave this specific reason:

• "Questions seeking debugging help ("why isn't this code working?") must include the desired behavior, a specific problem or error and the shortest code necessary to reproduce it in the question itself. Questions without a clear problem statement are not useful to other readers. See: How to create a Minimal, Complete, and Verifiable example." – ADyson, Masivuye Cokile, Billal Begueradj, Philipp, Blackbam

If this question can be reworded to fit the rules in the help center, please edit the question.

• 
  
  
  

  
  4
  

  
  
  
  
  
  

  
  in your .js part you try to call jquery ajax function inside php tags
  – Oleg Nurutdinov
  yesterday
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  "Here's the .JS part:"....and yet it's enclosed in <?php tags....where are your <script> tags?
  – ADyson
  yesterday
  

  
  
  
  


• 
  
  
  

  
  1
  

  
  
  
  
  
  

  
  @Pok3rPrinc3 edit the question and post correct
  – Masivuye Cokile
  yesterday
  

  
  
  
  


• 
  
  
  

  
  2
  

  
  
  
  
  
  

  
  Ok, so then..."nothing goes through" is not an error message or problem statement. Have you used your browser's Developer Tools to try and debug the AJAX call? Is it sent? Is the data in the body correct? What status is returned? Are there any console errors? What about in PHP - how you are verifying that the $_POST data is not what you expected? You haven't given us any clear detail. I note you appear to have included the "success" callback within the data object itself, which I guess is a mistake. It may or may not be the cause of your problem, but without more info it's hard to be certain.
  – ADyson
  yesterday
  
  
  

  
  
  
  


• 
  
  
  

  
  1
  

  
  
  
  
  
  

  
  @MasivuyeCokile no, it isn't.. the only wrong thing is, that success is inside data
  – Philipp
  yesterday
  

  
  
  
  

 | 
show 7 more comments

• 
  
  
  

  
  4
  

  
  
  
  
  
  

  
  in your .js part you try to call jquery ajax function inside php tags
  – Oleg Nurutdinov
  yesterday
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  "Here's the .JS part:"....and yet it's enclosed in <?php tags....where are your <script> tags?
  – ADyson
  yesterday
  

  
  
  
  


• 
  
  
  

  
  1
  

  
  
  
  
  
  

  
  @Pok3rPrinc3 edit the question and post correct
  – Masivuye Cokile
  yesterday
  

  
  
  
  


• 
  
  
  

  
  2
  

  
  
  
  
  
  

  
  Ok, so then..."nothing goes through" is not an error message or problem statement. Have you used your browser's Developer Tools to try and debug the AJAX call? Is it sent? Is the data in the body correct? What status is returned? Are there any console errors? What about in PHP - how you are verifying that the $_POST data is not what you expected? You haven't given us any clear detail. I note you appear to have included the "success" callback within the data object itself, which I guess is a mistake. It may or may not be the cause of your problem, but without more info it's hard to be certain.
  – ADyson
  yesterday
  
  
  

  
  
  
  


• 
  
  
  

  
  1
  

  
  
  
  
  
  

  
  @MasivuyeCokile no, it isn't.. the only wrong thing is, that success is inside data
  – Philipp
  yesterday
  

  
  
  
  

4

4

in your .js part you try to call jquery ajax function inside php tags
– Oleg Nurutdinov
yesterday

in your .js part you try to call jquery ajax function inside php tags
– Oleg Nurutdinov
yesterday

"Here's the .JS part:"....and yet it's enclosed in <?php tags....where are your <script> tags?
– ADyson
yesterday

"Here's the .JS part:"....and yet it's enclosed in <?php tags....where are your <script> tags?
– ADyson
yesterday

1

1

@Pok3rPrinc3 edit the question and post correct
– Masivuye Cokile
yesterday

@Pok3rPrinc3 edit the question and post correct
– Masivuye Cokile
yesterday

2

2

Ok, so then..."nothing goes through" is not an error message or problem statement. Have you used your browser's Developer Tools to try and debug the AJAX call? Is it sent? Is the data in the body correct? What status is returned? Are there any console errors? What about in PHP - how you are verifying that the $_POST data is not what you expected? You haven't given us any clear detail. I note you appear to have included the "success" callback within the data object itself, which I guess is a mistake. It may or may not be the cause of your problem, but without more info it's hard to be certain.
– ADyson
yesterday

Ok, so then..."nothing goes through" is not an error message or problem statement. Have you used your browser's Developer Tools to try and debug the AJAX call? Is it sent? Is the data in the body correct? What status is returned? Are there any console errors? What about in PHP - how you are verifying that the $_POST data is not what you expected? You haven't given us any clear detail. I note you appear to have included the "success" callback within the data object itself, which I guess is a mistake. It may or may not be the cause of your problem, but without more info it's hard to be certain.
– ADyson
yesterday

1

1

@MasivuyeCokile no, it isn't.. the only wrong thing is, that success is inside data
– Philipp
yesterday

@MasivuyeCokile no, it isn't.. the only wrong thing is, that success is inside data
– Philipp
yesterday

 | 
show 7 more comments

1 Answer
1

active

oldest

votes

up vote
4
down vote

success function should be out side the data

$.ajax({

type: "POST",

url: "test-php.php",

dataType: "text",

data: {

  min: "D201522170",

  invoice: 60,

  sum: 60, // Replace with dynamic radio button values

  descr: "Food Regime",

  exp_date: "31.12.2018"

  },

  success: function(data) {

    console.log(data);

  }

  });

share|improve this answer

edited yesterday

answered yesterday

Fathma siddique

887

add a comment | 

1 Answer
1

active

oldest

votes

1 Answer
1

active

oldest

votes

active

oldest

votes

active

oldest

votes

up vote
4
down vote

success function should be out side the data

$.ajax({

type: "POST",

url: "test-php.php",

dataType: "text",

data: {

  min: "D201522170",

  invoice: 60,

  sum: 60, // Replace with dynamic radio button values

  descr: "Food Regime",

  exp_date: "31.12.2018"

  },

  success: function(data) {

    console.log(data);

  }

  });

share|improve this answer

edited yesterday

answered yesterday

Fathma siddique

887

add a comment | 

up vote
4
down vote

success function should be out side the data

$.ajax({

type: "POST",

url: "test-php.php",

dataType: "text",

data: {

  min: "D201522170",

  invoice: 60,

  sum: 60, // Replace with dynamic radio button values

  descr: "Food Regime",

  exp_date: "31.12.2018"

  },

  success: function(data) {

    console.log(data);

  }

  });

share|improve this answer

edited yesterday

answered yesterday

Fathma siddique

887

add a comment | 

up vote
4
down vote

up vote
4
down vote

success function should be out side the data

$.ajax({

type: "POST",

url: "test-php.php",

dataType: "text",

data: {

  min: "D201522170",

  invoice: 60,

  sum: 60, // Replace with dynamic radio button values

  descr: "Food Regime",

  exp_date: "31.12.2018"

  },

  success: function(data) {

    console.log(data);

  }

  });

share|improve this answer

edited yesterday

answered yesterday

Fathma siddique

887

success function should be out side the data

$.ajax({

type: "POST",

url: "test-php.php",

dataType: "text",

data: {

  min: "D201522170",

  invoice: 60,

  sum: 60, // Replace with dynamic radio button values

  descr: "Food Regime",

  exp_date: "31.12.2018"

  },

  success: function(data) {

    console.log(data);

  }

  });

share|improve this answer

edited yesterday

answered yesterday

Fathma siddique

887

share|improve this answer

share|improve this answer

edited yesterday

edited yesterday

edited yesterday

answered yesterday

Fathma siddique

887

answered yesterday

Fathma siddique

887

answered yesterday

Fathma siddique

887

887

add a comment | 

add a comment | 

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