How to get n first values from an Iterator in Java 8?











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I have sorted a HashMap using Sort a Map<Key, Value> by values (Java) to that I have a LinkedHashMap, i.e. an Iterable which garantees iteration order.



Now, I'd like to retrieve a java.util.List of the first n entries of the map with a one-liner, if possible with a Java 8 Collection Stream API-technique.



I found how can i get two consecutive values from Iterator which explains that there's a possibility to do that with an array, but that's not elegant, differs from my intention to get a List (although that can be transformed, but it's an unnecessary step) and requires an extra method.










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    up vote
    4
    down vote

    favorite
    1












    I have sorted a HashMap using Sort a Map<Key, Value> by values (Java) to that I have a LinkedHashMap, i.e. an Iterable which garantees iteration order.



    Now, I'd like to retrieve a java.util.List of the first n entries of the map with a one-liner, if possible with a Java 8 Collection Stream API-technique.



    I found how can i get two consecutive values from Iterator which explains that there's a possibility to do that with an array, but that's not elegant, differs from my intention to get a List (although that can be transformed, but it's an unnecessary step) and requires an extra method.










    share|improve this question
























      up vote
      4
      down vote

      favorite
      1









      up vote
      4
      down vote

      favorite
      1






      1





      I have sorted a HashMap using Sort a Map<Key, Value> by values (Java) to that I have a LinkedHashMap, i.e. an Iterable which garantees iteration order.



      Now, I'd like to retrieve a java.util.List of the first n entries of the map with a one-liner, if possible with a Java 8 Collection Stream API-technique.



      I found how can i get two consecutive values from Iterator which explains that there's a possibility to do that with an array, but that's not elegant, differs from my intention to get a List (although that can be transformed, but it's an unnecessary step) and requires an extra method.










      share|improve this question













      I have sorted a HashMap using Sort a Map<Key, Value> by values (Java) to that I have a LinkedHashMap, i.e. an Iterable which garantees iteration order.



      Now, I'd like to retrieve a java.util.List of the first n entries of the map with a one-liner, if possible with a Java 8 Collection Stream API-technique.



      I found how can i get two consecutive values from Iterator which explains that there's a possibility to do that with an array, but that's not elegant, differs from my intention to get a List (although that can be transformed, but it's an unnecessary step) and requires an extra method.







      java java-8 java-stream






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      asked May 23 '17 at 13:03









      Karl Richter

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          2 Answers
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          Stream the entrySet and limit the Stream to the first n elements:



          List<Map.Entry<Key,Value>> firstN = 
          map.entrySet().stream().limit(n).collect(Collectors.toList());





          share|improve this answer




























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            1
            down vote













            Writing more concise code with StreamEx:



            List<Map.Entry<Key,Value>> firstN = EntryStream.of(map).limit(n).toList();





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              2 Answers
              2






              active

              oldest

              votes








              2 Answers
              2






              active

              oldest

              votes









              active

              oldest

              votes






              active

              oldest

              votes








              up vote
              11
              down vote



              accepted










              Stream the entrySet and limit the Stream to the first n elements:



              List<Map.Entry<Key,Value>> firstN = 
              map.entrySet().stream().limit(n).collect(Collectors.toList());





              share|improve this answer

























                up vote
                11
                down vote



                accepted










                Stream the entrySet and limit the Stream to the first n elements:



                List<Map.Entry<Key,Value>> firstN = 
                map.entrySet().stream().limit(n).collect(Collectors.toList());





                share|improve this answer























                  up vote
                  11
                  down vote



                  accepted







                  up vote
                  11
                  down vote



                  accepted






                  Stream the entrySet and limit the Stream to the first n elements:



                  List<Map.Entry<Key,Value>> firstN = 
                  map.entrySet().stream().limit(n).collect(Collectors.toList());





                  share|improve this answer












                  Stream the entrySet and limit the Stream to the first n elements:



                  List<Map.Entry<Key,Value>> firstN = 
                  map.entrySet().stream().limit(n).collect(Collectors.toList());






                  share|improve this answer












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                  answered May 23 '17 at 13:05









                  Eran

                  272k35431514




                  272k35431514
























                      up vote
                      1
                      down vote













                      Writing more concise code with StreamEx:



                      List<Map.Entry<Key,Value>> firstN = EntryStream.of(map).limit(n).toList();





                      share|improve this answer

























                        up vote
                        1
                        down vote













                        Writing more concise code with StreamEx:



                        List<Map.Entry<Key,Value>> firstN = EntryStream.of(map).limit(n).toList();





                        share|improve this answer























                          up vote
                          1
                          down vote










                          up vote
                          1
                          down vote









                          Writing more concise code with StreamEx:



                          List<Map.Entry<Key,Value>> firstN = EntryStream.of(map).limit(n).toList();





                          share|improve this answer












                          Writing more concise code with StreamEx:



                          List<Map.Entry<Key,Value>> firstN = EntryStream.of(map).limit(n).toList();






                          share|improve this answer












                          share|improve this answer



                          share|improve this answer










                          answered May 24 '17 at 18:37









                          user_3380739

                          83868




                          83868






























                               

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