Find the remainder from the division of $3^{2017}-1$ into $3^{403}-1$
up vote
0
down vote
favorite
Here is an interesting problem:
Find the remainder from the division of $3^{2017}-1$ into $3^{403}-1$
elementary-number-theory arithmetic divisibility
add a comment |
up vote
0
down vote
favorite
Here is an interesting problem:
Find the remainder from the division of $3^{2017}-1$ into $3^{403}-1$
elementary-number-theory arithmetic divisibility
Since you are a fairly new user, I would first of all like to welcome you to our stack exchange! Secondly, I suggest that you put some effort, thoughts or even any knowledge you have over the subject of your questions. This way, your posts will be way better well taken !
– Rebellos
2 days ago
Hint $bmod n-1!: nequiv 1,Rightarrow, f(n)equiv f(1) $ for any polynomial $f(x)$ with integer coefs
– Bill Dubuque
2 days ago
add a comment |
up vote
0
down vote
favorite
up vote
0
down vote
favorite
Here is an interesting problem:
Find the remainder from the division of $3^{2017}-1$ into $3^{403}-1$
elementary-number-theory arithmetic divisibility
Here is an interesting problem:
Find the remainder from the division of $3^{2017}-1$ into $3^{403}-1$
elementary-number-theory arithmetic divisibility
elementary-number-theory arithmetic divisibility
edited yesterday


Martin Sleziak
44.3k7115266
44.3k7115266
asked 2 days ago
ten1o
1335
1335
Since you are a fairly new user, I would first of all like to welcome you to our stack exchange! Secondly, I suggest that you put some effort, thoughts or even any knowledge you have over the subject of your questions. This way, your posts will be way better well taken !
– Rebellos
2 days ago
Hint $bmod n-1!: nequiv 1,Rightarrow, f(n)equiv f(1) $ for any polynomial $f(x)$ with integer coefs
– Bill Dubuque
2 days ago
add a comment |
Since you are a fairly new user, I would first of all like to welcome you to our stack exchange! Secondly, I suggest that you put some effort, thoughts or even any knowledge you have over the subject of your questions. This way, your posts will be way better well taken !
– Rebellos
2 days ago
Hint $bmod n-1!: nequiv 1,Rightarrow, f(n)equiv f(1) $ for any polynomial $f(x)$ with integer coefs
– Bill Dubuque
2 days ago
Since you are a fairly new user, I would first of all like to welcome you to our stack exchange! Secondly, I suggest that you put some effort, thoughts or even any knowledge you have over the subject of your questions. This way, your posts will be way better well taken !
– Rebellos
2 days ago
Since you are a fairly new user, I would first of all like to welcome you to our stack exchange! Secondly, I suggest that you put some effort, thoughts or even any knowledge you have over the subject of your questions. This way, your posts will be way better well taken !
– Rebellos
2 days ago
Hint $bmod n-1!: nequiv 1,Rightarrow, f(n)equiv f(1) $ for any polynomial $f(x)$ with integer coefs
– Bill Dubuque
2 days ago
Hint $bmod n-1!: nequiv 1,Rightarrow, f(n)equiv f(1) $ for any polynomial $f(x)$ with integer coefs
– Bill Dubuque
2 days ago
add a comment |
3 Answers
3
active
oldest
votes
up vote
4
down vote
Hint :
$$3^{2017} = Big(3^{403}Big)^5 cdot 3^2$$
add a comment |
up vote
3
down vote
$$3^{403}equiv 1pmod{3^{403}-1}$$
Raise to the power 5. You get,
$$3^{2015}equiv 1pmod{3^{403}-1}$$
$$3^{2017}equiv 9pmod{3^{403}-1}$$
$$3^{2017}-1equiv 8pmod{3^{403}-1}$$
So the remainder is 8.
New contributor
Samurai is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
add a comment |
up vote
2
down vote
If $n=3^{403}$, you are dividing $9n^5-1$ by $n-1$.
But $9n^5-1=9(n^5-1)+8$ and the remainder is $8$.
add a comment |
3 Answers
3
active
oldest
votes
3 Answers
3
active
oldest
votes
active
oldest
votes
active
oldest
votes
up vote
4
down vote
Hint :
$$3^{2017} = Big(3^{403}Big)^5 cdot 3^2$$
add a comment |
up vote
4
down vote
Hint :
$$3^{2017} = Big(3^{403}Big)^5 cdot 3^2$$
add a comment |
up vote
4
down vote
up vote
4
down vote
Hint :
$$3^{2017} = Big(3^{403}Big)^5 cdot 3^2$$
Hint :
$$3^{2017} = Big(3^{403}Big)^5 cdot 3^2$$
edited 2 days ago
J.G.
18.4k21932
18.4k21932
answered 2 days ago
Rebellos
11.5k21040
11.5k21040
add a comment |
add a comment |
up vote
3
down vote
$$3^{403}equiv 1pmod{3^{403}-1}$$
Raise to the power 5. You get,
$$3^{2015}equiv 1pmod{3^{403}-1}$$
$$3^{2017}equiv 9pmod{3^{403}-1}$$
$$3^{2017}-1equiv 8pmod{3^{403}-1}$$
So the remainder is 8.
New contributor
Samurai is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
add a comment |
up vote
3
down vote
$$3^{403}equiv 1pmod{3^{403}-1}$$
Raise to the power 5. You get,
$$3^{2015}equiv 1pmod{3^{403}-1}$$
$$3^{2017}equiv 9pmod{3^{403}-1}$$
$$3^{2017}-1equiv 8pmod{3^{403}-1}$$
So the remainder is 8.
New contributor
Samurai is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
add a comment |
up vote
3
down vote
up vote
3
down vote
$$3^{403}equiv 1pmod{3^{403}-1}$$
Raise to the power 5. You get,
$$3^{2015}equiv 1pmod{3^{403}-1}$$
$$3^{2017}equiv 9pmod{3^{403}-1}$$
$$3^{2017}-1equiv 8pmod{3^{403}-1}$$
So the remainder is 8.
New contributor
Samurai is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
$$3^{403}equiv 1pmod{3^{403}-1}$$
Raise to the power 5. You get,
$$3^{2015}equiv 1pmod{3^{403}-1}$$
$$3^{2017}equiv 9pmod{3^{403}-1}$$
$$3^{2017}-1equiv 8pmod{3^{403}-1}$$
So the remainder is 8.
New contributor
Samurai is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
New contributor
Samurai is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
answered 2 days ago


Samurai
987
987
New contributor
Samurai is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
New contributor
Samurai is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
Samurai is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
add a comment |
add a comment |
up vote
2
down vote
If $n=3^{403}$, you are dividing $9n^5-1$ by $n-1$.
But $9n^5-1=9(n^5-1)+8$ and the remainder is $8$.
add a comment |
up vote
2
down vote
If $n=3^{403}$, you are dividing $9n^5-1$ by $n-1$.
But $9n^5-1=9(n^5-1)+8$ and the remainder is $8$.
add a comment |
up vote
2
down vote
up vote
2
down vote
If $n=3^{403}$, you are dividing $9n^5-1$ by $n-1$.
But $9n^5-1=9(n^5-1)+8$ and the remainder is $8$.
If $n=3^{403}$, you are dividing $9n^5-1$ by $n-1$.
But $9n^5-1=9(n^5-1)+8$ and the remainder is $8$.
answered 2 days ago
Yves Daoust
121k668218
121k668218
add a comment |
add a comment |
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
StackExchange.ready(
function () {
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fmath.stackexchange.com%2fquestions%2f3005315%2ffind-the-remainder-from-the-division-of-32017-1-into-3403-1%23new-answer', 'question_page');
}
);
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Since you are a fairly new user, I would first of all like to welcome you to our stack exchange! Secondly, I suggest that you put some effort, thoughts or even any knowledge you have over the subject of your questions. This way, your posts will be way better well taken !
– Rebellos
2 days ago
Hint $bmod n-1!: nequiv 1,Rightarrow, f(n)equiv f(1) $ for any polynomial $f(x)$ with integer coefs
– Bill Dubuque
2 days ago