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Is the photon pair generated from the electron-positron annihilation entangled?
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Is the photon pair generated from the electron-positron annihilation entangled?
And would they work as a source of entangled photons suitable for experiments in quantum optics?
quantum-mechanics particle-physics photons quantum-entanglement
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Peter Mortensen
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E.phy
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Is the photon pair generated from the electron-positron annihilation entangled?
And would they work as a source of entangled photons suitable for experiments in quantum optics?
quantum-mechanics particle-physics photons quantum-entanglement
edited yesterday
Peter Mortensen
1,91211323
asked yesterday
E.phy
1807
add a comment |
up vote
16
down vote
favorite
up vote
16
down vote
favorite
Is the photon pair generated from the electron-positron annihilation entangled?
And would they work as a source of entangled photons suitable for experiments in quantum optics?
quantum-mechanics particle-physics photons quantum-entanglement
edited yesterday
Peter Mortensen
1,91211323
asked yesterday
E.phy
1807
Is the photon pair generated from the electron-positron annihilation entangled?
And would they work as a source of entangled photons suitable for experiments in quantum optics?
quantum-mechanics particle-physics photons quantum-entanglement
quantum-mechanics particle-physics photons quantum-entanglement
edited yesterday
Peter Mortensen
1,91211323
asked yesterday
E.phy
1807
edited yesterday
Peter Mortensen
1,91211323
asked yesterday
E.phy
1807
edited yesterday
Peter Mortensen
1,91211323
edited yesterday
Peter Mortensen
1,91211323
edited yesterday
Peter Mortensen
1,91211323
1,91211323
asked yesterday
E.phy
1807
asked yesterday
E.phy
1807
asked yesterday
E.phy
1807
1807
add a comment |
add a comment |
2 Answers
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Yes, they are definitely entangled. Their combined energy will exactly equal the combined energy of the original electron-positron pair, for example. The same is true for combined momentum and combined spin.
answered yesterday
S. McGrew
5,2452923
"Combined spin" should also include any orbital angular momentum if the electron and positron briefly orbited each other (positronium) before annihilating.
– Andreas Blass
yesterday
That is correct--
– S. McGrew
yesterday
And from what I understand about these things (only a layman as far as physics goes), the angular momentum of the electron-positron pair will almost always be non-zero.
– EvilSnack
23 hours ago
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up vote
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The photon-pair is definitely entangled. It is produced from an $S$-wave state of the electron-positron system and as such has orbital angular momentum $L=0$. But it's not useful for quantum optics, the photons' energy is too high for your usual mirrors to reflect. See fig 33.15 on p. 23 of this http://pdg.lbl.gov/2018/reviews/rpp2018-rev-passage-particles-matter.pdf to get an idea what happens to a 511 keV photon from two-photon annihilation of an electron-positron pair at rest once it hits matter: ionization by Compton scattering dominates the interaction, that's not what you want to happen in a mirror or lense.
It's worth keeping in mind though, that the electron-positron system (Positronium) can decay to any number of photons $>1$, though numbers higher than three are very rare. An even number of photons can be produced for decays of the singlet ground state ${}^1S_0$ (where the electron and positron are in an anti-symmetric spin state
$frac{1}{sqrt{2}}left( left|uparrow downarrow rightrangle - left|downarrow uparrow rightrangleright)$, "Parapositronium"). This defines the spin entanglement in the case you had in mind, and it has actually been measured and found to agree with full entanglement, see e.g. here http://adsabs.harvard.edu/abs/2009APS..HAW.GB108S
An uneven number can be produced from the triplet ${}^3S_0$ ("Orthopositronium"). The triplet is much longer-lived than the singlet state (roughly thousand times), but since it consists of three states and because symmetries ($CP$) prevent the positronium from going from the triplet to the singlet state, an appreciable number of electron-positron pairs decays to three photons.
In fact, also the $S$ states of higher energy levels can decay to photons directly, but usually they will decay to the ground state first, emitting photons of energies $O(10 - 100 emathrm{V})$ before the actual decay to the high-energy pair or to the three continuous spectrum photons.
answered 17 hours ago
tobi_s
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2 Answers
2
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2 Answers
2
active
oldest
votes
active
oldest
votes
active
oldest
votes
up vote
21
down vote
Yes, they are definitely entangled. Their combined energy will exactly equal the combined energy of the original electron-positron pair, for example. The same is true for combined momentum and combined spin.
answered yesterday
S. McGrew
5,2452923
"Combined spin" should also include any orbital angular momentum if the electron and positron briefly orbited each other (positronium) before annihilating.
– Andreas Blass
yesterday
That is correct--
– S. McGrew
yesterday
And from what I understand about these things (only a layman as far as physics goes), the angular momentum of the electron-positron pair will almost always be non-zero.
– EvilSnack
23 hours ago
add a comment |
up vote
21
down vote
Yes, they are definitely entangled. Their combined energy will exactly equal the combined energy of the original electron-positron pair, for example. The same is true for combined momentum and combined spin.
answered yesterday
S. McGrew
5,2452923
"Combined spin" should also include any orbital angular momentum if the electron and positron briefly orbited each other (positronium) before annihilating.
– Andreas Blass
yesterday
That is correct--
– S. McGrew
yesterday
And from what I understand about these things (only a layman as far as physics goes), the angular momentum of the electron-positron pair will almost always be non-zero.
– EvilSnack
23 hours ago
add a comment |
up vote
21
down vote
up vote
21
down vote
Yes, they are definitely entangled. Their combined energy will exactly equal the combined energy of the original electron-positron pair, for example. The same is true for combined momentum and combined spin.
answered yesterday
S. McGrew
5,2452923
Yes, they are definitely entangled. Their combined energy will exactly equal the combined energy of the original electron-positron pair, for example. The same is true for combined momentum and combined spin.
answered yesterday
S. McGrew
5,2452923
answered yesterday
S. McGrew
5,2452923
answered yesterday
S. McGrew
5,2452923
answered yesterday
S. McGrew
5,2452923
5,2452923
"Combined spin" should also include any orbital angular momentum if the electron and positron briefly orbited each other (positronium) before annihilating.
– Andreas Blass
yesterday
That is correct--
– S. McGrew
yesterday
And from what I understand about these things (only a layman as far as physics goes), the angular momentum of the electron-positron pair will almost always be non-zero.
– EvilSnack
23 hours ago
add a comment |
"Combined spin" should also include any orbital angular momentum if the electron and positron briefly orbited each other (positronium) before annihilating.
– Andreas Blass
yesterday
That is correct--
– S. McGrew
yesterday
And from what I understand about these things (only a layman as far as physics goes), the angular momentum of the electron-positron pair will almost always be non-zero.
– EvilSnack
23 hours ago
"Combined spin" should also include any orbital angular momentum if the electron and positron briefly orbited each other (positronium) before annihilating.
– Andreas Blass
yesterday
"Combined spin" should also include any orbital angular momentum if the electron and positron briefly orbited each other (positronium) before annihilating.
– Andreas Blass
yesterday
That is correct--
– S. McGrew
yesterday
That is correct--
– S. McGrew
yesterday
And from what I understand about these things (only a layman as far as physics goes), the angular momentum of the electron-positron pair will almost always be non-zero.
– EvilSnack
23 hours ago
And from what I understand about these things (only a layman as far as physics goes), the angular momentum of the electron-positron pair will almost always be non-zero.
– EvilSnack
23 hours ago
add a comment |
up vote
2
down vote
The photon-pair is definitely entangled. It is produced from an $S$-wave state of the electron-positron system and as such has orbital angular momentum $L=0$. But it's not useful for quantum optics, the photons' energy is too high for your usual mirrors to reflect. See fig 33.15 on p. 23 of this http://pdg.lbl.gov/2018/reviews/rpp2018-rev-passage-particles-matter.pdf to get an idea what happens to a 511 keV photon from two-photon annihilation of an electron-positron pair at rest once it hits matter: ionization by Compton scattering dominates the interaction, that's not what you want to happen in a mirror or lense.
It's worth keeping in mind though, that the electron-positron system (Positronium) can decay to any number of photons $>1$, though numbers higher than three are very rare. An even number of photons can be produced for decays of the singlet ground state ${}^1S_0$ (where the electron and positron are in an anti-symmetric spin state
$frac{1}{sqrt{2}}left( left|uparrow downarrow rightrangle - left|downarrow uparrow rightrangleright)$, "Parapositronium"). This defines the spin entanglement in the case you had in mind, and it has actually been measured and found to agree with full entanglement, see e.g. here http://adsabs.harvard.edu/abs/2009APS..HAW.GB108S
An uneven number can be produced from the triplet ${}^3S_0$ ("Orthopositronium"). The triplet is much longer-lived than the singlet state (roughly thousand times), but since it consists of three states and because symmetries ($CP$) prevent the positronium from going from the triplet to the singlet state, an appreciable number of electron-positron pairs decays to three photons.
In fact, also the $S$ states of higher energy levels can decay to photons directly, but usually they will decay to the ground state first, emitting photons of energies $O(10 - 100 emathrm{V})$ before the actual decay to the high-energy pair or to the three continuous spectrum photons.
answered 17 hours ago
tobi_s
1612
add a comment |
up vote
2
down vote
The photon-pair is definitely entangled. It is produced from an $S$-wave state of the electron-positron system and as such has orbital angular momentum $L=0$. But it's not useful for quantum optics, the photons' energy is too high for your usual mirrors to reflect. See fig 33.15 on p. 23 of this http://pdg.lbl.gov/2018/reviews/rpp2018-rev-passage-particles-matter.pdf to get an idea what happens to a 511 keV photon from two-photon annihilation of an electron-positron pair at rest once it hits matter: ionization by Compton scattering dominates the interaction, that's not what you want to happen in a mirror or lense.
It's worth keeping in mind though, that the electron-positron system (Positronium) can decay to any number of photons $>1$, though numbers higher than three are very rare. An even number of photons can be produced for decays of the singlet ground state ${}^1S_0$ (where the electron and positron are in an anti-symmetric spin state
$frac{1}{sqrt{2}}left( left|uparrow downarrow rightrangle - left|downarrow uparrow rightrangleright)$, "Parapositronium"). This defines the spin entanglement in the case you had in mind, and it has actually been measured and found to agree with full entanglement, see e.g. here http://adsabs.harvard.edu/abs/2009APS..HAW.GB108S
An uneven number can be produced from the triplet ${}^3S_0$ ("Orthopositronium"). The triplet is much longer-lived than the singlet state (roughly thousand times), but since it consists of three states and because symmetries ($CP$) prevent the positronium from going from the triplet to the singlet state, an appreciable number of electron-positron pairs decays to three photons.
In fact, also the $S$ states of higher energy levels can decay to photons directly, but usually they will decay to the ground state first, emitting photons of energies $O(10 - 100 emathrm{V})$ before the actual decay to the high-energy pair or to the three continuous spectrum photons.
answered 17 hours ago
tobi_s
1612
add a comment |
up vote
2
down vote
up vote
2
down vote
The photon-pair is definitely entangled. It is produced from an $S$-wave state of the electron-positron system and as such has orbital angular momentum $L=0$. But it's not useful for quantum optics, the photons' energy is too high for your usual mirrors to reflect. See fig 33.15 on p. 23 of this http://pdg.lbl.gov/2018/reviews/rpp2018-rev-passage-particles-matter.pdf to get an idea what happens to a 511 keV photon from two-photon annihilation of an electron-positron pair at rest once it hits matter: ionization by Compton scattering dominates the interaction, that's not what you want to happen in a mirror or lense.
It's worth keeping in mind though, that the electron-positron system (Positronium) can decay to any number of photons $>1$, though numbers higher than three are very rare. An even number of photons can be produced for decays of the singlet ground state ${}^1S_0$ (where the electron and positron are in an anti-symmetric spin state
$frac{1}{sqrt{2}}left( left|uparrow downarrow rightrangle - left|downarrow uparrow rightrangleright)$, "Parapositronium"). This defines the spin entanglement in the case you had in mind, and it has actually been measured and found to agree with full entanglement, see e.g. here http://adsabs.harvard.edu/abs/2009APS..HAW.GB108S
An uneven number can be produced from the triplet ${}^3S_0$ ("Orthopositronium"). The triplet is much longer-lived than the singlet state (roughly thousand times), but since it consists of three states and because symmetries ($CP$) prevent the positronium from going from the triplet to the singlet state, an appreciable number of electron-positron pairs decays to three photons.
In fact, also the $S$ states of higher energy levels can decay to photons directly, but usually they will decay to the ground state first, emitting photons of energies $O(10 - 100 emathrm{V})$ before the actual decay to the high-energy pair or to the three continuous spectrum photons.
answered 17 hours ago
tobi_s
1612
The photon-pair is definitely entangled. It is produced from an $S$-wave state of the electron-positron system and as such has orbital angular momentum $L=0$. But it's not useful for quantum optics, the photons' energy is too high for your usual mirrors to reflect. See fig 33.15 on p. 23 of this http://pdg.lbl.gov/2018/reviews/rpp2018-rev-passage-particles-matter.pdf to get an idea what happens to a 511 keV photon from two-photon annihilation of an electron-positron pair at rest once it hits matter: ionization by Compton scattering dominates the interaction, that's not what you want to happen in a mirror or lense.
It's worth keeping in mind though, that the electron-positron system (Positronium) can decay to any number of photons $>1$, though numbers higher than three are very rare. An even number of photons can be produced for decays of the singlet ground state ${}^1S_0$ (where the electron and positron are in an anti-symmetric spin state
$frac{1}{sqrt{2}}left( left|uparrow downarrow rightrangle - left|downarrow uparrow rightrangleright)$, "Parapositronium"). This defines the spin entanglement in the case you had in mind, and it has actually been measured and found to agree with full entanglement, see e.g. here http://adsabs.harvard.edu/abs/2009APS..HAW.GB108S
An uneven number can be produced from the triplet ${}^3S_0$ ("Orthopositronium"). The triplet is much longer-lived than the singlet state (roughly thousand times), but since it consists of three states and because symmetries ($CP$) prevent the positronium from going from the triplet to the singlet state, an appreciable number of electron-positron pairs decays to three photons.
In fact, also the $S$ states of higher energy levels can decay to photons directly, but usually they will decay to the ground state first, emitting photons of energies $O(10 - 100 emathrm{V})$ before the actual decay to the high-energy pair or to the three continuous spectrum photons.
answered 17 hours ago
tobi_s
1612
edited 15 hours ago
answered 17 hours ago
tobi_s
1612
answered 17 hours ago
tobi_s
1612
answered 17 hours ago
tobi_s
1612
1612
add a comment |
add a comment |
protected by David Z♦ 14 hours ago
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Because it has attracted low-quality or spam answers that had to be removed, posting an answer now requires 10 reputation on this site (the association bonus does not count).
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