Double integral change of variables to polar coordinates.
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Sketch the region represented in the following double integral:
$I =∬ln(x^2+y^2)dxdy$
In the region:
$x:ycotβ$ to $sqrt(a^2+y^2)$
$y:0$ to $asinβ$
where a > 0 and 0 < β < π/2.
By changing to polar coordinates or otherwise, show that
I = $a^2β(ln a − 1/2)$.
So far I have found that the sketch yields a triangle inscribed in the circle of radius $a$ in the first quadrant. I am having trouble converting to polar coordinates.
calculus integration multivariable-calculus
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add a comment |
$begingroup$
Sketch the region represented in the following double integral:
$I =∬ln(x^2+y^2)dxdy$
In the region:
$x:ycotβ$ to $sqrt(a^2+y^2)$
$y:0$ to $asinβ$
where a > 0 and 0 < β < π/2.
By changing to polar coordinates or otherwise, show that
I = $a^2β(ln a − 1/2)$.
So far I have found that the sketch yields a triangle inscribed in the circle of radius $a$ in the first quadrant. I am having trouble converting to polar coordinates.
calculus integration multivariable-calculus
$endgroup$
add a comment |
$begingroup$
Sketch the region represented in the following double integral:
$I =∬ln(x^2+y^2)dxdy$
In the region:
$x:ycotβ$ to $sqrt(a^2+y^2)$
$y:0$ to $asinβ$
where a > 0 and 0 < β < π/2.
By changing to polar coordinates or otherwise, show that
I = $a^2β(ln a − 1/2)$.
So far I have found that the sketch yields a triangle inscribed in the circle of radius $a$ in the first quadrant. I am having trouble converting to polar coordinates.
calculus integration multivariable-calculus
$endgroup$
Sketch the region represented in the following double integral:
$I =∬ln(x^2+y^2)dxdy$
In the region:
$x:ycotβ$ to $sqrt(a^2+y^2)$
$y:0$ to $asinβ$
where a > 0 and 0 < β < π/2.
By changing to polar coordinates or otherwise, show that
I = $a^2β(ln a − 1/2)$.
So far I have found that the sketch yields a triangle inscribed in the circle of radius $a$ in the first quadrant. I am having trouble converting to polar coordinates.
calculus integration multivariable-calculus
calculus integration multivariable-calculus
asked Feb 3 at 11:29
matmat
12
12
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1 Answer
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Hint: In the polar coordinate system $x^2+y^2 Rightarrow r^2$ and $dxdy Rightarrow rcdot drdtheta$. Also, we have that $y=rcdot sin{theta}$ and $x=rcdot cos{theta}$.
$endgroup$
$begingroup$
My problem is finding the limits for $r$ and theta.
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– mat
Feb 3 at 12:09
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1 Answer
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1 Answer
1
active
oldest
votes
active
oldest
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active
oldest
votes
$begingroup$
Hint: In the polar coordinate system $x^2+y^2 Rightarrow r^2$ and $dxdy Rightarrow rcdot drdtheta$. Also, we have that $y=rcdot sin{theta}$ and $x=rcdot cos{theta}$.
$endgroup$
$begingroup$
My problem is finding the limits for $r$ and theta.
$endgroup$
– mat
Feb 3 at 12:09
add a comment |
$begingroup$
Hint: In the polar coordinate system $x^2+y^2 Rightarrow r^2$ and $dxdy Rightarrow rcdot drdtheta$. Also, we have that $y=rcdot sin{theta}$ and $x=rcdot cos{theta}$.
$endgroup$
$begingroup$
My problem is finding the limits for $r$ and theta.
$endgroup$
– mat
Feb 3 at 12:09
add a comment |
$begingroup$
Hint: In the polar coordinate system $x^2+y^2 Rightarrow r^2$ and $dxdy Rightarrow rcdot drdtheta$. Also, we have that $y=rcdot sin{theta}$ and $x=rcdot cos{theta}$.
$endgroup$
Hint: In the polar coordinate system $x^2+y^2 Rightarrow r^2$ and $dxdy Rightarrow rcdot drdtheta$. Also, we have that $y=rcdot sin{theta}$ and $x=rcdot cos{theta}$.
answered Feb 3 at 11:59
Peter ForemanPeter Foreman
7,5371320
7,5371320
$begingroup$
My problem is finding the limits for $r$ and theta.
$endgroup$
– mat
Feb 3 at 12:09
add a comment |
$begingroup$
My problem is finding the limits for $r$ and theta.
$endgroup$
– mat
Feb 3 at 12:09
$begingroup$
My problem is finding the limits for $r$ and theta.
$endgroup$
– mat
Feb 3 at 12:09
$begingroup$
My problem is finding the limits for $r$ and theta.
$endgroup$
– mat
Feb 3 at 12:09
add a comment |
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