How does isomorphism of schemes induce maps on cohomology groups
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Let $f:X to X$ be an isomorphism of schemes. Let $mathcal{F}$ be sheaf of abelian groups on $X$.
When does $f$ induces a map $H^i(X, mathcal{F}) to H^i(X, mathcal{F})$?
I've seen similar statements at many places at least certain types of $mathcal{F}$ but never seen a proper explanation of how such a map exists?
algebraic-geometry sheaf-theory sheaf-cohomology
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Let $f:X to X$ be an isomorphism of schemes. Let $mathcal{F}$ be sheaf of abelian groups on $X$.
When does $f$ induces a map $H^i(X, mathcal{F}) to H^i(X, mathcal{F})$?
I've seen similar statements at many places at least certain types of $mathcal{F}$ but never seen a proper explanation of how such a map exists?
algebraic-geometry sheaf-theory sheaf-cohomology
add a comment |
up vote
0
down vote
favorite
up vote
0
down vote
favorite
Let $f:X to X$ be an isomorphism of schemes. Let $mathcal{F}$ be sheaf of abelian groups on $X$.
When does $f$ induces a map $H^i(X, mathcal{F}) to H^i(X, mathcal{F})$?
I've seen similar statements at many places at least certain types of $mathcal{F}$ but never seen a proper explanation of how such a map exists?
algebraic-geometry sheaf-theory sheaf-cohomology
Let $f:X to X$ be an isomorphism of schemes. Let $mathcal{F}$ be sheaf of abelian groups on $X$.
When does $f$ induces a map $H^i(X, mathcal{F}) to H^i(X, mathcal{F})$?
I've seen similar statements at many places at least certain types of $mathcal{F}$ but never seen a proper explanation of how such a map exists?
algebraic-geometry sheaf-theory sheaf-cohomology
algebraic-geometry sheaf-theory sheaf-cohomology
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72521017
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