Find global minimum of the following
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The global minimum value of
$$|cot x – 1| + |cot x – 2| + |cot x – 31| + |cot x – 32| + |cot x – 24| + |cot x – 5| + |cot x – 6|
+ |cot x – 17| + |cot x – 8| + |cot x – 9| + |cot x – 10| + |cot x – 11| + |cot x – 12| $$
Then find $x=operatorname{arcsec}(alpha/beta )$ where it is occurring.
calculus
add a comment |
up vote
1
down vote
favorite
The global minimum value of
$$|cot x – 1| + |cot x – 2| + |cot x – 31| + |cot x – 32| + |cot x – 24| + |cot x – 5| + |cot x – 6|
+ |cot x – 17| + |cot x – 8| + |cot x – 9| + |cot x – 10| + |cot x – 11| + |cot x – 12| $$
Then find $x=operatorname{arcsec}(alpha/beta )$ where it is occurring.
calculus
Done now what ?
– D.Manek
20 hours ago
add a comment |
up vote
1
down vote
favorite
up vote
1
down vote
favorite
The global minimum value of
$$|cot x – 1| + |cot x – 2| + |cot x – 31| + |cot x – 32| + |cot x – 24| + |cot x – 5| + |cot x – 6|
+ |cot x – 17| + |cot x – 8| + |cot x – 9| + |cot x – 10| + |cot x – 11| + |cot x – 12| $$
Then find $x=operatorname{arcsec}(alpha/beta )$ where it is occurring.
calculus
The global minimum value of
$$|cot x – 1| + |cot x – 2| + |cot x – 31| + |cot x – 32| + |cot x – 24| + |cot x – 5| + |cot x – 6|
+ |cot x – 17| + |cot x – 8| + |cot x – 9| + |cot x – 10| + |cot x – 11| + |cot x – 12| $$
Then find $x=operatorname{arcsec}(alpha/beta )$ where it is occurring.
calculus
calculus
edited 20 hours ago
amWhy
191k27223437
191k27223437
asked 21 hours ago
D.Manek
173
173
Done now what ?
– D.Manek
20 hours ago
add a comment |
Done now what ?
– D.Manek
20 hours ago
Done now what ?
– D.Manek
20 hours ago
Done now what ?
– D.Manek
20 hours ago
add a comment |
1 Answer
1
active
oldest
votes
up vote
3
down vote
The minimum is achieved when $cot x$ is the median of the constants, i.e. $10$.
If $cot x=10$ then $sec x=dfrac{sqrt{101}}{10}$, which is not a rational number.
why median but not mean?
– idea
20 hours ago
can you kindly please explain me the whole thing I was unable to understand it.
– D.Manek
20 hours ago
@idea The mean would be for the sum of squares.
– Yves Daoust
20 hours ago
Why not try it both ways, @idea, and see what happens?
– Gerry Myerson
20 hours ago
@D.Manek: do you know what the median is ?
– Yves Daoust
20 hours ago
|
show 7 more comments
1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
up vote
3
down vote
The minimum is achieved when $cot x$ is the median of the constants, i.e. $10$.
If $cot x=10$ then $sec x=dfrac{sqrt{101}}{10}$, which is not a rational number.
why median but not mean?
– idea
20 hours ago
can you kindly please explain me the whole thing I was unable to understand it.
– D.Manek
20 hours ago
@idea The mean would be for the sum of squares.
– Yves Daoust
20 hours ago
Why not try it both ways, @idea, and see what happens?
– Gerry Myerson
20 hours ago
@D.Manek: do you know what the median is ?
– Yves Daoust
20 hours ago
|
show 7 more comments
up vote
3
down vote
The minimum is achieved when $cot x$ is the median of the constants, i.e. $10$.
If $cot x=10$ then $sec x=dfrac{sqrt{101}}{10}$, which is not a rational number.
why median but not mean?
– idea
20 hours ago
can you kindly please explain me the whole thing I was unable to understand it.
– D.Manek
20 hours ago
@idea The mean would be for the sum of squares.
– Yves Daoust
20 hours ago
Why not try it both ways, @idea, and see what happens?
– Gerry Myerson
20 hours ago
@D.Manek: do you know what the median is ?
– Yves Daoust
20 hours ago
|
show 7 more comments
up vote
3
down vote
up vote
3
down vote
The minimum is achieved when $cot x$ is the median of the constants, i.e. $10$.
If $cot x=10$ then $sec x=dfrac{sqrt{101}}{10}$, which is not a rational number.
The minimum is achieved when $cot x$ is the median of the constants, i.e. $10$.
If $cot x=10$ then $sec x=dfrac{sqrt{101}}{10}$, which is not a rational number.
edited 20 hours ago
answered 20 hours ago
Yves Daoust
121k668218
121k668218
why median but not mean?
– idea
20 hours ago
can you kindly please explain me the whole thing I was unable to understand it.
– D.Manek
20 hours ago
@idea The mean would be for the sum of squares.
– Yves Daoust
20 hours ago
Why not try it both ways, @idea, and see what happens?
– Gerry Myerson
20 hours ago
@D.Manek: do you know what the median is ?
– Yves Daoust
20 hours ago
|
show 7 more comments
why median but not mean?
– idea
20 hours ago
can you kindly please explain me the whole thing I was unable to understand it.
– D.Manek
20 hours ago
@idea The mean would be for the sum of squares.
– Yves Daoust
20 hours ago
Why not try it both ways, @idea, and see what happens?
– Gerry Myerson
20 hours ago
@D.Manek: do you know what the median is ?
– Yves Daoust
20 hours ago
why median but not mean?
– idea
20 hours ago
why median but not mean?
– idea
20 hours ago
can you kindly please explain me the whole thing I was unable to understand it.
– D.Manek
20 hours ago
can you kindly please explain me the whole thing I was unable to understand it.
– D.Manek
20 hours ago
@idea The mean would be for the sum of squares.
– Yves Daoust
20 hours ago
@idea The mean would be for the sum of squares.
– Yves Daoust
20 hours ago
Why not try it both ways, @idea, and see what happens?
– Gerry Myerson
20 hours ago
Why not try it both ways, @idea, and see what happens?
– Gerry Myerson
20 hours ago
@D.Manek: do you know what the median is ?
– Yves Daoust
20 hours ago
@D.Manek: do you know what the median is ?
– Yves Daoust
20 hours ago
|
show 7 more comments
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Done now what ?
– D.Manek
20 hours ago