Angular conditional class with pipe
Trying to do a conditional class if progress == 100, but my syntax is not correct?
[class.finalDone]="progress[file.name].progress | async == 100"
angular
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Trying to do a conditional class if progress == 100, but my syntax is not correct?
[class.finalDone]="progress[file.name].progress | async == 100"
angular
Are you getting any errors? Also, are you sureprogress[file.name].progress
will return aPromise
or anObservable
?
– SiddAjmera
Nov 20 '18 at 19:40
add a comment |
Trying to do a conditional class if progress == 100, but my syntax is not correct?
[class.finalDone]="progress[file.name].progress | async == 100"
angular
Trying to do a conditional class if progress == 100, but my syntax is not correct?
[class.finalDone]="progress[file.name].progress | async == 100"
angular
angular
asked Nov 20 '18 at 19:33
MarkMark
72531735
72531735
Are you getting any errors? Also, are you sureprogress[file.name].progress
will return aPromise
or anObservable
?
– SiddAjmera
Nov 20 '18 at 19:40
add a comment |
Are you getting any errors? Also, are you sureprogress[file.name].progress
will return aPromise
or anObservable
?
– SiddAjmera
Nov 20 '18 at 19:40
Are you getting any errors? Also, are you sure
progress[file.name].progress
will return a Promise
or an Observable
?– SiddAjmera
Nov 20 '18 at 19:40
Are you getting any errors? Also, are you sure
progress[file.name].progress
will return a Promise
or an Observable
?– SiddAjmera
Nov 20 '18 at 19:40
add a comment |
1 Answer
1
active
oldest
votes
Make sure that progress[file.name].progress
will return a Promise
or an Observable
. And then use it like this(wrap the expression till the async
part in ()
):
[class.finalDone]="(progress[file.name].progress | async) === 100"
Here's a Sample StackBlitz for your ref.
add a comment |
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1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
Make sure that progress[file.name].progress
will return a Promise
or an Observable
. And then use it like this(wrap the expression till the async
part in ()
):
[class.finalDone]="(progress[file.name].progress | async) === 100"
Here's a Sample StackBlitz for your ref.
add a comment |
Make sure that progress[file.name].progress
will return a Promise
or an Observable
. And then use it like this(wrap the expression till the async
part in ()
):
[class.finalDone]="(progress[file.name].progress | async) === 100"
Here's a Sample StackBlitz for your ref.
add a comment |
Make sure that progress[file.name].progress
will return a Promise
or an Observable
. And then use it like this(wrap the expression till the async
part in ()
):
[class.finalDone]="(progress[file.name].progress | async) === 100"
Here's a Sample StackBlitz for your ref.
Make sure that progress[file.name].progress
will return a Promise
or an Observable
. And then use it like this(wrap the expression till the async
part in ()
):
[class.finalDone]="(progress[file.name].progress | async) === 100"
Here's a Sample StackBlitz for your ref.
answered Nov 20 '18 at 19:43
SiddAjmeraSiddAjmera
13.7k31137
13.7k31137
add a comment |
add a comment |
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Are you getting any errors? Also, are you sure
progress[file.name].progress
will return aPromise
or anObservable
?– SiddAjmera
Nov 20 '18 at 19:40