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help in find derivative of intervals function [closed]
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if the function is $f(x) = c + (x-a) (d-c) / (b-a)$
what the derivative is $f(x) ' =$?
I tried lookup for derivatives table, but find nothing meets my question.
Conditions are $a < b$, $c < d$, $a <= x <= b$.
derivatives
asked Jan 1 at 19:24
Vitaly ProtasovVitaly Protasov
33
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closed as off-topic by amWhy, Shailesh, clathratus, KReiser, Andrew Jan 2 at 4:49
This question appears to be off-topic. The users who voted to close gave this specific reason:
- "This question is missing context or other details: Please provide additional context, which ideally explains why the question is relevant to you and our community. Some forms of context include: background and motivation, relevant definitions, source, possible strategies, your current progress, why the question is interesting or important, etc." – amWhy, Shailesh, clathratus, KReiser, Andrew
If this question can be reworded to fit the rules in the help center, please edit the question.
add a comment |
$begingroup$
if the function is $f(x) = c + (x-a) (d-c) / (b-a)$
what the derivative is $f(x) ' =$?
I tried lookup for derivatives table, but find nothing meets my question.
Conditions are $a < b$, $c < d$, $a <= x <= b$.
derivatives
asked Jan 1 at 19:24
Vitaly ProtasovVitaly Protasov
33
$endgroup$
closed as off-topic by amWhy, Shailesh, clathratus, KReiser, Andrew Jan 2 at 4:49
This question appears to be off-topic. The users who voted to close gave this specific reason:
- "This question is missing context or other details: Please provide additional context, which ideally explains why the question is relevant to you and our community. Some forms of context include: background and motivation, relevant definitions, source, possible strategies, your current progress, why the question is interesting or important, etc." – amWhy, Shailesh, clathratus, KReiser, Andrew
If this question can be reworded to fit the rules in the help center, please edit the question.
$begingroup$
Your function is linear- of the form y= C+ Bx where B= (d- c)/(a- c) and C= c- a(d- c)/(a- c). It's derivative is the constant slope of the line, B= (d- c)/(a- c).
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– user247327
Jan 1 at 19:52
add a comment |
$begingroup$
if the function is $f(x) = c + (x-a) (d-c) / (b-a)$
what the derivative is $f(x) ' =$?
I tried lookup for derivatives table, but find nothing meets my question.
Conditions are $a < b$, $c < d$, $a <= x <= b$.
derivatives
asked Jan 1 at 19:24
Vitaly ProtasovVitaly Protasov
33
$endgroup$
if the function is $f(x) = c + (x-a) (d-c) / (b-a)$
what the derivative is $f(x) ' =$?
I tried lookup for derivatives table, but find nothing meets my question.
Conditions are $a < b$, $c < d$, $a <= x <= b$.
derivatives
derivatives
asked Jan 1 at 19:24
Vitaly ProtasovVitaly Protasov
33
asked Jan 1 at 19:24
Vitaly ProtasovVitaly Protasov
33
edited Jan 1 at 19:43
Vitaly Protasov
asked Jan 1 at 19:24
Vitaly ProtasovVitaly Protasov
33
asked Jan 1 at 19:24
Vitaly ProtasovVitaly Protasov
33
asked Jan 1 at 19:24
Vitaly ProtasovVitaly Protasov
33
33
closed as off-topic by amWhy, Shailesh, clathratus, KReiser, Andrew Jan 2 at 4:49
This question appears to be off-topic. The users who voted to close gave this specific reason:
- "This question is missing context or other details: Please provide additional context, which ideally explains why the question is relevant to you and our community. Some forms of context include: background and motivation, relevant definitions, source, possible strategies, your current progress, why the question is interesting or important, etc." – amWhy, Shailesh, clathratus, KReiser, Andrew
If this question can be reworded to fit the rules in the help center, please edit the question.
closed as off-topic by amWhy, Shailesh, clathratus, KReiser, Andrew Jan 2 at 4:49
This question appears to be off-topic. The users who voted to close gave this specific reason:
- "This question is missing context or other details: Please provide additional context, which ideally explains why the question is relevant to you and our community. Some forms of context include: background and motivation, relevant definitions, source, possible strategies, your current progress, why the question is interesting or important, etc." – amWhy, Shailesh, clathratus, KReiser, Andrew
If this question can be reworded to fit the rules in the help center, please edit the question.
$begingroup$
Your function is linear- of the form y= C+ Bx where B= (d- c)/(a- c) and C= c- a(d- c)/(a- c). It's derivative is the constant slope of the line, B= (d- c)/(a- c).
$endgroup$
– user247327
Jan 1 at 19:52
add a comment |
$begingroup$
Your function is linear- of the form y= C+ Bx where B= (d- c)/(a- c) and C= c- a(d- c)/(a- c). It's derivative is the constant slope of the line, B= (d- c)/(a- c).
$endgroup$
– user247327
Jan 1 at 19:52
$begingroup$
Your function is linear- of the form y= C+ Bx where B= (d- c)/(a- c) and C= c- a(d- c)/(a- c). It's derivative is the constant slope of the line, B= (d- c)/(a- c).
$endgroup$
– user247327
Jan 1 at 19:52
$begingroup$
Your function is linear- of the form y= C+ Bx where B= (d- c)/(a- c) and C= c- a(d- c)/(a- c). It's derivative is the constant slope of the line, B= (d- c)/(a- c).
$endgroup$
– user247327
Jan 1 at 19:52
add a comment |
1 Answer
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$$f(x)=c+x.frac{d-c}{b-a}-aleft(frac{d-c}{b-a}right)$$
$$implies f'(x)= frac{d-c}{b-a}$$
answered Jan 1 at 19:29
Rakibul Islam PrinceRakibul Islam Prince
1,018211
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add a comment |
1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
$begingroup$
$$f(x)=c+x.frac{d-c}{b-a}-aleft(frac{d-c}{b-a}right)$$
$$implies f'(x)= frac{d-c}{b-a}$$
answered Jan 1 at 19:29
Rakibul Islam PrinceRakibul Islam Prince
1,018211
$endgroup$
add a comment |
$begingroup$
$$f(x)=c+x.frac{d-c}{b-a}-aleft(frac{d-c}{b-a}right)$$
$$implies f'(x)= frac{d-c}{b-a}$$
answered Jan 1 at 19:29
Rakibul Islam PrinceRakibul Islam Prince
1,018211
$endgroup$
add a comment |
$begingroup$
$$f(x)=c+x.frac{d-c}{b-a}-aleft(frac{d-c}{b-a}right)$$
$$implies f'(x)= frac{d-c}{b-a}$$
answered Jan 1 at 19:29
Rakibul Islam PrinceRakibul Islam Prince
1,018211
$endgroup$
$$f(x)=c+x.frac{d-c}{b-a}-aleft(frac{d-c}{b-a}right)$$
$$implies f'(x)= frac{d-c}{b-a}$$
answered Jan 1 at 19:29
Rakibul Islam PrinceRakibul Islam Prince
1,018211
answered Jan 1 at 19:29
Rakibul Islam PrinceRakibul Islam Prince
1,018211
answered Jan 1 at 19:29
Rakibul Islam PrinceRakibul Islam Prince
1,018211
answered Jan 1 at 19:29
Rakibul Islam PrinceRakibul Islam Prince
1,018211
1,018211
add a comment |
add a comment |
$begingroup$
Your function is linear- of the form y= C+ Bx where B= (d- c)/(a- c) and C= c- a(d- c)/(a- c). It's derivative is the constant slope of the line, B= (d- c)/(a- c).
$endgroup$
– user247327
Jan 1 at 19:52