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Pythagorean Theorem in bash as a function
0
I am trying to display the Pythagorean Theorem in bash for my son - which should be easy. I need it in function. However the theorem a2 + b2 = c2 is just not making sense here. Don't know what I am doing wrong.
#!/bin/bash
read side_a side_b
hypo=$(( (side_a*side_a) + (side_b*side_b) ))
echo "side: $side_a side: $side_b hypotenuse: $hypo"
$ /tmp/hypo
5 5
side: 5 side: 5 hypotenuse: 50
bash
asked Nov 20 '18 at 19:34
capsercapser
87721746
add a comment |
0
I am trying to display the Pythagorean Theorem in bash for my son - which should be easy. I need it in function. However the theorem a2 + b2 = c2 is just not making sense here. Don't know what I am doing wrong.
#!/bin/bash
read side_a side_b
hypo=$(( (side_a*side_a) + (side_b*side_b) ))
echo "side: $side_a side: $side_b hypotenuse: $hypo"
$ /tmp/hypo
5 5
side: 5 side: 5 hypotenuse: 50
bash
asked Nov 20 '18 at 19:34
capsercapser
87721746
what exactly are you confused about in bash? It is performing correctly for the inputs you gave it.
– jeremysprofile
Nov 20 '18 at 19:38
The code gives you square of length of the hypotenuse. You have to calculate square root to get length of hypotenuse.
– pii_ke
Nov 20 '18 at 19:41
... and then you'll bump into stackoverflow.com/questions/12722095/…
– Benjamin W.
Nov 20 '18 at 19:44
add a comment |
0
0
0
I am trying to display the Pythagorean Theorem in bash for my son - which should be easy. I need it in function. However the theorem a2 + b2 = c2 is just not making sense here. Don't know what I am doing wrong.
#!/bin/bash
read side_a side_b
hypo=$(( (side_a*side_a) + (side_b*side_b) ))
echo "side: $side_a side: $side_b hypotenuse: $hypo"
$ /tmp/hypo
5 5
side: 5 side: 5 hypotenuse: 50
bash
asked Nov 20 '18 at 19:34
capsercapser
87721746
I am trying to display the Pythagorean Theorem in bash for my son - which should be easy. I need it in function. However the theorem a2 + b2 = c2 is just not making sense here. Don't know what I am doing wrong.
#!/bin/bash
read side_a side_b
hypo=$(( (side_a*side_a) + (side_b*side_b) ))
echo "side: $side_a side: $side_b hypotenuse: $hypo"
$ /tmp/hypo
5 5
side: 5 side: 5 hypotenuse: 50
bash
bash
asked Nov 20 '18 at 19:34
capsercapser
87721746
asked Nov 20 '18 at 19:34
capsercapser
87721746
asked Nov 20 '18 at 19:34
capsercapser
87721746
asked Nov 20 '18 at 19:34
capsercapser
87721746
asked Nov 20 '18 at 19:34
capsercapser
87721746
87721746
what exactly are you confused about in bash? It is performing correctly for the inputs you gave it.
– jeremysprofile
Nov 20 '18 at 19:38
The code gives you square of length of the hypotenuse. You have to calculate square root to get length of hypotenuse.
– pii_ke
Nov 20 '18 at 19:41
... and then you'll bump into stackoverflow.com/questions/12722095/…
– Benjamin W.
Nov 20 '18 at 19:44
add a comment |
what exactly are you confused about in bash? It is performing correctly for the inputs you gave it.
– jeremysprofile
Nov 20 '18 at 19:38
The code gives you square of length of the hypotenuse. You have to calculate square root to get length of hypotenuse.
– pii_ke
Nov 20 '18 at 19:41
... and then you'll bump into stackoverflow.com/questions/12722095/…
– Benjamin W.
Nov 20 '18 at 19:44
what exactly are you confused about in bash? It is performing correctly for the inputs you gave it.
– jeremysprofile
Nov 20 '18 at 19:38
what exactly are you confused about in bash? It is performing correctly for the inputs you gave it.
– jeremysprofile
Nov 20 '18 at 19:38
The code gives you square of length of the hypotenuse. You have to calculate square root to get length of hypotenuse.
– pii_ke
Nov 20 '18 at 19:41
The code gives you square of length of the hypotenuse. You have to calculate square root to get length of hypotenuse.
– pii_ke
Nov 20 '18 at 19:41
... and then you'll bump into stackoverflow.com/questions/12722095/…
– Benjamin W.
Nov 20 '18 at 19:44
... and then you'll bump into stackoverflow.com/questions/12722095/…
– Benjamin W.
Nov 20 '18 at 19:44
add a comment |
1 Answer
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time to switch to awk
$ awk '{print "side:",$1,"side:",$2,"hypotenuse:",sqrt($1^2+$2^2)}'
3 4
side: 3 side: 4 hypotenuse: 5
$1 and $2 are the input fields, the rest should read trivially.
With little more effort, you can generate the integer solutions as well...
$ awk 'BEGIN{for(i=1;i<=10;i++) for(j=1;j<i;j++) print 2*i*j, i^2-j^2, i^2+j^2}'
4 3 5
6 8 10
12 5 13
8 15 17
16 12 20
24 7 25
10 24 26
20 21 29
30 16 34
40 9 41
12 35 37
...
answered Nov 20 '18 at 19:54
karakfakarakfa
49.1k52738
add a comment |
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1 Answer
1
active
oldest
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1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
0
time to switch to awk
$ awk '{print "side:",$1,"side:",$2,"hypotenuse:",sqrt($1^2+$2^2)}'
3 4
side: 3 side: 4 hypotenuse: 5
$1 and $2 are the input fields, the rest should read trivially.
With little more effort, you can generate the integer solutions as well...
$ awk 'BEGIN{for(i=1;i<=10;i++) for(j=1;j<i;j++) print 2*i*j, i^2-j^2, i^2+j^2}'
4 3 5
6 8 10
12 5 13
8 15 17
16 12 20
24 7 25
10 24 26
20 21 29
30 16 34
40 9 41
12 35 37
...
answered Nov 20 '18 at 19:54
karakfakarakfa
49.1k52738
add a comment |
0
time to switch to awk
$ awk '{print "side:",$1,"side:",$2,"hypotenuse:",sqrt($1^2+$2^2)}'
3 4
side: 3 side: 4 hypotenuse: 5
$1 and $2 are the input fields, the rest should read trivially.
With little more effort, you can generate the integer solutions as well...
$ awk 'BEGIN{for(i=1;i<=10;i++) for(j=1;j<i;j++) print 2*i*j, i^2-j^2, i^2+j^2}'
4 3 5
6 8 10
12 5 13
8 15 17
16 12 20
24 7 25
10 24 26
20 21 29
30 16 34
40 9 41
12 35 37
...
answered Nov 20 '18 at 19:54
karakfakarakfa
49.1k52738
add a comment |
0
0
0
time to switch to awk
$ awk '{print "side:",$1,"side:",$2,"hypotenuse:",sqrt($1^2+$2^2)}'
3 4
side: 3 side: 4 hypotenuse: 5
$1 and $2 are the input fields, the rest should read trivially.
With little more effort, you can generate the integer solutions as well...
$ awk 'BEGIN{for(i=1;i<=10;i++) for(j=1;j<i;j++) print 2*i*j, i^2-j^2, i^2+j^2}'
4 3 5
6 8 10
12 5 13
8 15 17
16 12 20
24 7 25
10 24 26
20 21 29
30 16 34
40 9 41
12 35 37
...
answered Nov 20 '18 at 19:54
karakfakarakfa
49.1k52738
time to switch to awk
$ awk '{print "side:",$1,"side:",$2,"hypotenuse:",sqrt($1^2+$2^2)}'
3 4
side: 3 side: 4 hypotenuse: 5
$1 and $2 are the input fields, the rest should read trivially.
With little more effort, you can generate the integer solutions as well...
$ awk 'BEGIN{for(i=1;i<=10;i++) for(j=1;j<i;j++) print 2*i*j, i^2-j^2, i^2+j^2}'
4 3 5
6 8 10
12 5 13
8 15 17
16 12 20
24 7 25
10 24 26
20 21 29
30 16 34
40 9 41
12 35 37
...
answered Nov 20 '18 at 19:54
karakfakarakfa
49.1k52738
answered Nov 20 '18 at 19:54
karakfakarakfa
49.1k52738
answered Nov 20 '18 at 19:54
karakfakarakfa
49.1k52738
answered Nov 20 '18 at 19:54
karakfakarakfa
49.1k52738
49.1k52738
add a comment |
add a comment |
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what exactly are you confused about in bash? It is performing correctly for the inputs you gave it.
– jeremysprofile
Nov 20 '18 at 19:38
The code gives you square of length of the hypotenuse. You have to calculate square root to get length of hypotenuse.
– pii_ke
Nov 20 '18 at 19:41
... and then you'll bump into stackoverflow.com/questions/12722095/…
– Benjamin W.
Nov 20 '18 at 19:44