How to add sequenced number based on sorted value in query in Access











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0
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Can somebody please give me the solution or explain the right approach for this question. So, I have a query which returns some values (att1). I would like also to have next to it the values which would represent a sorted order of att1. Something like this



att1   att2
19 3
2 2
46 4
78 5
1 1


Thanks in advanced!










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  • 2




    Possible duplicate of How to show row number in Access query like ROW_NUMBER in SQL
    – Darren Bartrup-Cook
    yesterday















up vote
0
down vote

favorite












Can somebody please give me the solution or explain the right approach for this question. So, I have a query which returns some values (att1). I would like also to have next to it the values which would represent a sorted order of att1. Something like this



att1   att2
19 3
2 2
46 4
78 5
1 1


Thanks in advanced!










share|improve this question




















  • 2




    Possible duplicate of How to show row number in Access query like ROW_NUMBER in SQL
    – Darren Bartrup-Cook
    yesterday













up vote
0
down vote

favorite









up vote
0
down vote

favorite











Can somebody please give me the solution or explain the right approach for this question. So, I have a query which returns some values (att1). I would like also to have next to it the values which would represent a sorted order of att1. Something like this



att1   att2
19 3
2 2
46 4
78 5
1 1


Thanks in advanced!










share|improve this question















Can somebody please give me the solution or explain the right approach for this question. So, I have a query which returns some values (att1). I would like also to have next to it the values which would represent a sorted order of att1. Something like this



att1   att2
19 3
2 2
46 4
78 5
1 1


Thanks in advanced!







sql ms-access






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share|improve this question













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share|improve this question








edited yesterday









a_horse_with_no_name

286k45429526




286k45429526










asked yesterday









Mario

185215




185215








  • 2




    Possible duplicate of How to show row number in Access query like ROW_NUMBER in SQL
    – Darren Bartrup-Cook
    yesterday














  • 2




    Possible duplicate of How to show row number in Access query like ROW_NUMBER in SQL
    – Darren Bartrup-Cook
    yesterday








2




2




Possible duplicate of How to show row number in Access query like ROW_NUMBER in SQL
– Darren Bartrup-Cook
yesterday




Possible duplicate of How to show row number in Access query like ROW_NUMBER in SQL
– Darren Bartrup-Cook
yesterday












2 Answers
2






active

oldest

votes

















up vote
2
down vote



accepted










Assuming a table name of table1, The following should yield the desired result:



select a.att1, (select count(*) from table1 b where b.att1 <= a.att1) as att2
from table1 a;


For every record, the query calculates the number of records less than or equal to the current record, which is then output as the sort index.






share|improve this answer



















  • 1




    Thank you. That did the trick!
    – Mario
    22 hours ago


















up vote
2
down vote













I wrote an article on the various methods for this:



Sequential Rows in Microsoft Access



In its simplest form:



SELECT RowNumber(CStr([ID])) AS RowID, *, FROM SomeTable;


using the RowNumber function:



' Builds consecutive row numbers in a select, append, or create query
' with the option of a initial automatic reset.
' Optionally, a grouping key can be passed to reset the row count
' for every group key.
'
' 2018-08-23. Gustav Brock, Cactus Data ApS, CPH.
'
Public Function RowNumber( _
ByVal Key As String, _
Optional ByVal GroupKey As String, _
Optional ByVal Reset As Boolean) _
As Long

' Uncommon character string to assemble GroupKey and Key as a compound key.
Const KeySeparator As String = "¤§¤"
' Expected error codes to accept.
Const CannotAddKey As Long = 457
Const CannotRemoveKey As Long = 5

Static Keys As New Collection
Static GroupKeys As New Collection
Dim Count As Long
Dim CompoundKey As String

On Error GoTo Err_RowNumber

If Reset = True Then
' Erase the collection of keys and group key counts.
Set Keys = Nothing
Set GroupKeys = Nothing
Else
' Create a compound key to uniquely identify GroupKey and its Key.
' Note: If GroupKey is not used, only one element will be added.
CompoundKey = GroupKey & KeySeparator & Key
Count = Keys(CompoundKey)

If Count = 0 Then
' This record has not been enumerated.
'
' Will either fail if the group key is new, leaving Count as zero,
' or retrieve the count of already enumerated records with this group key.
Count = GroupKeys(GroupKey) + 1
If Count > 0 Then
' The group key has been recorded.
' Remove it to allow it to be recreated holding the new count.
GroupKeys.Remove (GroupKey)
Else
' This record is the first having this group key.
' Thus, the count is 1.
Count = 1
End If
' (Re)create the group key item with the value of the count of keys.
GroupKeys.Add Count, GroupKey
End If
' Add the key and its enumeration.
' This will be:
' Using no group key: Relative to the full recordset.
' Using a group key: Relative to the group key.
' Will fail if the key already has been created.
Keys.Add Count, CompoundKey
End If

' Return the key value as this is the row counter.
RowNumber = Count

Exit_RowNumber:
Exit Function

Err_RowNumber:
Select Case Err
Case CannotAddKey
' Key is present, thus cannot be added again.
Resume Next
Case CannotRemoveKey
' GroupKey is not present, thus cannot be removed.
Resume Next
Case Else
' Some other error. Ignore.
Resume Exit_RowNumber
End Select
End Function


All code is also on GitHub: VBA.RowNumbers






share|improve this answer























  • Thank you very much for your help but Lee Mac solution seems simpler and it works.
    – Mario
    22 hours ago










  • Yes, it works for few records, but if you have many, it will be very slow. And the required SQL is as simple as it can get: One line. See edited answer, please.
    – Gustav
    22 hours ago











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2 Answers
2






active

oldest

votes








2 Answers
2






active

oldest

votes









active

oldest

votes






active

oldest

votes








up vote
2
down vote



accepted










Assuming a table name of table1, The following should yield the desired result:



select a.att1, (select count(*) from table1 b where b.att1 <= a.att1) as att2
from table1 a;


For every record, the query calculates the number of records less than or equal to the current record, which is then output as the sort index.






share|improve this answer



















  • 1




    Thank you. That did the trick!
    – Mario
    22 hours ago















up vote
2
down vote



accepted










Assuming a table name of table1, The following should yield the desired result:



select a.att1, (select count(*) from table1 b where b.att1 <= a.att1) as att2
from table1 a;


For every record, the query calculates the number of records less than or equal to the current record, which is then output as the sort index.






share|improve this answer



















  • 1




    Thank you. That did the trick!
    – Mario
    22 hours ago













up vote
2
down vote



accepted







up vote
2
down vote



accepted






Assuming a table name of table1, The following should yield the desired result:



select a.att1, (select count(*) from table1 b where b.att1 <= a.att1) as att2
from table1 a;


For every record, the query calculates the number of records less than or equal to the current record, which is then output as the sort index.






share|improve this answer














Assuming a table name of table1, The following should yield the desired result:



select a.att1, (select count(*) from table1 b where b.att1 <= a.att1) as att2
from table1 a;


For every record, the query calculates the number of records less than or equal to the current record, which is then output as the sort index.







share|improve this answer














share|improve this answer



share|improve this answer








edited 22 hours ago

























answered 23 hours ago









Lee Mac

2,76221036




2,76221036








  • 1




    Thank you. That did the trick!
    – Mario
    22 hours ago














  • 1




    Thank you. That did the trick!
    – Mario
    22 hours ago








1




1




Thank you. That did the trick!
– Mario
22 hours ago




Thank you. That did the trick!
– Mario
22 hours ago












up vote
2
down vote













I wrote an article on the various methods for this:



Sequential Rows in Microsoft Access



In its simplest form:



SELECT RowNumber(CStr([ID])) AS RowID, *, FROM SomeTable;


using the RowNumber function:



' Builds consecutive row numbers in a select, append, or create query
' with the option of a initial automatic reset.
' Optionally, a grouping key can be passed to reset the row count
' for every group key.
'
' 2018-08-23. Gustav Brock, Cactus Data ApS, CPH.
'
Public Function RowNumber( _
ByVal Key As String, _
Optional ByVal GroupKey As String, _
Optional ByVal Reset As Boolean) _
As Long

' Uncommon character string to assemble GroupKey and Key as a compound key.
Const KeySeparator As String = "¤§¤"
' Expected error codes to accept.
Const CannotAddKey As Long = 457
Const CannotRemoveKey As Long = 5

Static Keys As New Collection
Static GroupKeys As New Collection
Dim Count As Long
Dim CompoundKey As String

On Error GoTo Err_RowNumber

If Reset = True Then
' Erase the collection of keys and group key counts.
Set Keys = Nothing
Set GroupKeys = Nothing
Else
' Create a compound key to uniquely identify GroupKey and its Key.
' Note: If GroupKey is not used, only one element will be added.
CompoundKey = GroupKey & KeySeparator & Key
Count = Keys(CompoundKey)

If Count = 0 Then
' This record has not been enumerated.
'
' Will either fail if the group key is new, leaving Count as zero,
' or retrieve the count of already enumerated records with this group key.
Count = GroupKeys(GroupKey) + 1
If Count > 0 Then
' The group key has been recorded.
' Remove it to allow it to be recreated holding the new count.
GroupKeys.Remove (GroupKey)
Else
' This record is the first having this group key.
' Thus, the count is 1.
Count = 1
End If
' (Re)create the group key item with the value of the count of keys.
GroupKeys.Add Count, GroupKey
End If
' Add the key and its enumeration.
' This will be:
' Using no group key: Relative to the full recordset.
' Using a group key: Relative to the group key.
' Will fail if the key already has been created.
Keys.Add Count, CompoundKey
End If

' Return the key value as this is the row counter.
RowNumber = Count

Exit_RowNumber:
Exit Function

Err_RowNumber:
Select Case Err
Case CannotAddKey
' Key is present, thus cannot be added again.
Resume Next
Case CannotRemoveKey
' GroupKey is not present, thus cannot be removed.
Resume Next
Case Else
' Some other error. Ignore.
Resume Exit_RowNumber
End Select
End Function


All code is also on GitHub: VBA.RowNumbers






share|improve this answer























  • Thank you very much for your help but Lee Mac solution seems simpler and it works.
    – Mario
    22 hours ago










  • Yes, it works for few records, but if you have many, it will be very slow. And the required SQL is as simple as it can get: One line. See edited answer, please.
    – Gustav
    22 hours ago















up vote
2
down vote













I wrote an article on the various methods for this:



Sequential Rows in Microsoft Access



In its simplest form:



SELECT RowNumber(CStr([ID])) AS RowID, *, FROM SomeTable;


using the RowNumber function:



' Builds consecutive row numbers in a select, append, or create query
' with the option of a initial automatic reset.
' Optionally, a grouping key can be passed to reset the row count
' for every group key.
'
' 2018-08-23. Gustav Brock, Cactus Data ApS, CPH.
'
Public Function RowNumber( _
ByVal Key As String, _
Optional ByVal GroupKey As String, _
Optional ByVal Reset As Boolean) _
As Long

' Uncommon character string to assemble GroupKey and Key as a compound key.
Const KeySeparator As String = "¤§¤"
' Expected error codes to accept.
Const CannotAddKey As Long = 457
Const CannotRemoveKey As Long = 5

Static Keys As New Collection
Static GroupKeys As New Collection
Dim Count As Long
Dim CompoundKey As String

On Error GoTo Err_RowNumber

If Reset = True Then
' Erase the collection of keys and group key counts.
Set Keys = Nothing
Set GroupKeys = Nothing
Else
' Create a compound key to uniquely identify GroupKey and its Key.
' Note: If GroupKey is not used, only one element will be added.
CompoundKey = GroupKey & KeySeparator & Key
Count = Keys(CompoundKey)

If Count = 0 Then
' This record has not been enumerated.
'
' Will either fail if the group key is new, leaving Count as zero,
' or retrieve the count of already enumerated records with this group key.
Count = GroupKeys(GroupKey) + 1
If Count > 0 Then
' The group key has been recorded.
' Remove it to allow it to be recreated holding the new count.
GroupKeys.Remove (GroupKey)
Else
' This record is the first having this group key.
' Thus, the count is 1.
Count = 1
End If
' (Re)create the group key item with the value of the count of keys.
GroupKeys.Add Count, GroupKey
End If
' Add the key and its enumeration.
' This will be:
' Using no group key: Relative to the full recordset.
' Using a group key: Relative to the group key.
' Will fail if the key already has been created.
Keys.Add Count, CompoundKey
End If

' Return the key value as this is the row counter.
RowNumber = Count

Exit_RowNumber:
Exit Function

Err_RowNumber:
Select Case Err
Case CannotAddKey
' Key is present, thus cannot be added again.
Resume Next
Case CannotRemoveKey
' GroupKey is not present, thus cannot be removed.
Resume Next
Case Else
' Some other error. Ignore.
Resume Exit_RowNumber
End Select
End Function


All code is also on GitHub: VBA.RowNumbers






share|improve this answer























  • Thank you very much for your help but Lee Mac solution seems simpler and it works.
    – Mario
    22 hours ago










  • Yes, it works for few records, but if you have many, it will be very slow. And the required SQL is as simple as it can get: One line. See edited answer, please.
    – Gustav
    22 hours ago













up vote
2
down vote










up vote
2
down vote









I wrote an article on the various methods for this:



Sequential Rows in Microsoft Access



In its simplest form:



SELECT RowNumber(CStr([ID])) AS RowID, *, FROM SomeTable;


using the RowNumber function:



' Builds consecutive row numbers in a select, append, or create query
' with the option of a initial automatic reset.
' Optionally, a grouping key can be passed to reset the row count
' for every group key.
'
' 2018-08-23. Gustav Brock, Cactus Data ApS, CPH.
'
Public Function RowNumber( _
ByVal Key As String, _
Optional ByVal GroupKey As String, _
Optional ByVal Reset As Boolean) _
As Long

' Uncommon character string to assemble GroupKey and Key as a compound key.
Const KeySeparator As String = "¤§¤"
' Expected error codes to accept.
Const CannotAddKey As Long = 457
Const CannotRemoveKey As Long = 5

Static Keys As New Collection
Static GroupKeys As New Collection
Dim Count As Long
Dim CompoundKey As String

On Error GoTo Err_RowNumber

If Reset = True Then
' Erase the collection of keys and group key counts.
Set Keys = Nothing
Set GroupKeys = Nothing
Else
' Create a compound key to uniquely identify GroupKey and its Key.
' Note: If GroupKey is not used, only one element will be added.
CompoundKey = GroupKey & KeySeparator & Key
Count = Keys(CompoundKey)

If Count = 0 Then
' This record has not been enumerated.
'
' Will either fail if the group key is new, leaving Count as zero,
' or retrieve the count of already enumerated records with this group key.
Count = GroupKeys(GroupKey) + 1
If Count > 0 Then
' The group key has been recorded.
' Remove it to allow it to be recreated holding the new count.
GroupKeys.Remove (GroupKey)
Else
' This record is the first having this group key.
' Thus, the count is 1.
Count = 1
End If
' (Re)create the group key item with the value of the count of keys.
GroupKeys.Add Count, GroupKey
End If
' Add the key and its enumeration.
' This will be:
' Using no group key: Relative to the full recordset.
' Using a group key: Relative to the group key.
' Will fail if the key already has been created.
Keys.Add Count, CompoundKey
End If

' Return the key value as this is the row counter.
RowNumber = Count

Exit_RowNumber:
Exit Function

Err_RowNumber:
Select Case Err
Case CannotAddKey
' Key is present, thus cannot be added again.
Resume Next
Case CannotRemoveKey
' GroupKey is not present, thus cannot be removed.
Resume Next
Case Else
' Some other error. Ignore.
Resume Exit_RowNumber
End Select
End Function


All code is also on GitHub: VBA.RowNumbers






share|improve this answer














I wrote an article on the various methods for this:



Sequential Rows in Microsoft Access



In its simplest form:



SELECT RowNumber(CStr([ID])) AS RowID, *, FROM SomeTable;


using the RowNumber function:



' Builds consecutive row numbers in a select, append, or create query
' with the option of a initial automatic reset.
' Optionally, a grouping key can be passed to reset the row count
' for every group key.
'
' 2018-08-23. Gustav Brock, Cactus Data ApS, CPH.
'
Public Function RowNumber( _
ByVal Key As String, _
Optional ByVal GroupKey As String, _
Optional ByVal Reset As Boolean) _
As Long

' Uncommon character string to assemble GroupKey and Key as a compound key.
Const KeySeparator As String = "¤§¤"
' Expected error codes to accept.
Const CannotAddKey As Long = 457
Const CannotRemoveKey As Long = 5

Static Keys As New Collection
Static GroupKeys As New Collection
Dim Count As Long
Dim CompoundKey As String

On Error GoTo Err_RowNumber

If Reset = True Then
' Erase the collection of keys and group key counts.
Set Keys = Nothing
Set GroupKeys = Nothing
Else
' Create a compound key to uniquely identify GroupKey and its Key.
' Note: If GroupKey is not used, only one element will be added.
CompoundKey = GroupKey & KeySeparator & Key
Count = Keys(CompoundKey)

If Count = 0 Then
' This record has not been enumerated.
'
' Will either fail if the group key is new, leaving Count as zero,
' or retrieve the count of already enumerated records with this group key.
Count = GroupKeys(GroupKey) + 1
If Count > 0 Then
' The group key has been recorded.
' Remove it to allow it to be recreated holding the new count.
GroupKeys.Remove (GroupKey)
Else
' This record is the first having this group key.
' Thus, the count is 1.
Count = 1
End If
' (Re)create the group key item with the value of the count of keys.
GroupKeys.Add Count, GroupKey
End If
' Add the key and its enumeration.
' This will be:
' Using no group key: Relative to the full recordset.
' Using a group key: Relative to the group key.
' Will fail if the key already has been created.
Keys.Add Count, CompoundKey
End If

' Return the key value as this is the row counter.
RowNumber = Count

Exit_RowNumber:
Exit Function

Err_RowNumber:
Select Case Err
Case CannotAddKey
' Key is present, thus cannot be added again.
Resume Next
Case CannotRemoveKey
' GroupKey is not present, thus cannot be removed.
Resume Next
Case Else
' Some other error. Ignore.
Resume Exit_RowNumber
End Select
End Function


All code is also on GitHub: VBA.RowNumbers







share|improve this answer














share|improve this answer



share|improve this answer








edited 22 hours ago

























answered yesterday









Gustav

28.7k51734




28.7k51734












  • Thank you very much for your help but Lee Mac solution seems simpler and it works.
    – Mario
    22 hours ago










  • Yes, it works for few records, but if you have many, it will be very slow. And the required SQL is as simple as it can get: One line. See edited answer, please.
    – Gustav
    22 hours ago


















  • Thank you very much for your help but Lee Mac solution seems simpler and it works.
    – Mario
    22 hours ago










  • Yes, it works for few records, but if you have many, it will be very slow. And the required SQL is as simple as it can get: One line. See edited answer, please.
    – Gustav
    22 hours ago
















Thank you very much for your help but Lee Mac solution seems simpler and it works.
– Mario
22 hours ago




Thank you very much for your help but Lee Mac solution seems simpler and it works.
– Mario
22 hours ago












Yes, it works for few records, but if you have many, it will be very slow. And the required SQL is as simple as it can get: One line. See edited answer, please.
– Gustav
22 hours ago




Yes, it works for few records, but if you have many, it will be very slow. And the required SQL is as simple as it can get: One line. See edited answer, please.
– Gustav
22 hours ago


















 

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