Tensor of vector space [closed]












0












$begingroup$



Suppose that $V =text{span}(1,x)$ is a vector space over $frac{mathbb{Z}}{2mathbb{Z}} $ and let
$delta : V rightarrow Votimes V$




Such that $delta (1) = 1otimes x + xotimes 1$ and $delta (x) = x otimes x$.



What is the kernel of $delta$?










share|cite|improve this question











$endgroup$



closed as off-topic by Saad, jgon, zipirovich, Shailesh, mrtaurho Jan 8 at 6:02


This question appears to be off-topic. The users who voted to close gave this specific reason:


  • "This question is missing context or other details: Please provide additional context, which ideally explains why the question is relevant to you and our community. Some forms of context include: background and motivation, relevant definitions, source, possible strategies, your current progress, why the question is interesting or important, etc." – Saad, jgon, zipirovich, Shailesh, mrtaurho

If this question can be reworded to fit the rules in the help center, please edit the question.












  • 1




    $begingroup$
    What are your thoughts on the problem? What have you tried?
    $endgroup$
    – Omnomnomnom
    Jan 8 at 0:33






  • 1




    $begingroup$
    Do you know the dimension of $Votimes V$? Can you set up a basis?
    $endgroup$
    – Berci
    Jan 8 at 0:36










  • $begingroup$
    basis of $V bigotimes V$ are $1otimes 1 , 1otimes x, x otimes 1$, and$ x otimes x$ /then kernel of $delta$ is zero.
    $endgroup$
    – hussein
    Jan 8 at 14:48


















0












$begingroup$



Suppose that $V =text{span}(1,x)$ is a vector space over $frac{mathbb{Z}}{2mathbb{Z}} $ and let
$delta : V rightarrow Votimes V$




Such that $delta (1) = 1otimes x + xotimes 1$ and $delta (x) = x otimes x$.



What is the kernel of $delta$?










share|cite|improve this question











$endgroup$



closed as off-topic by Saad, jgon, zipirovich, Shailesh, mrtaurho Jan 8 at 6:02


This question appears to be off-topic. The users who voted to close gave this specific reason:


  • "This question is missing context or other details: Please provide additional context, which ideally explains why the question is relevant to you and our community. Some forms of context include: background and motivation, relevant definitions, source, possible strategies, your current progress, why the question is interesting or important, etc." – Saad, jgon, zipirovich, Shailesh, mrtaurho

If this question can be reworded to fit the rules in the help center, please edit the question.












  • 1




    $begingroup$
    What are your thoughts on the problem? What have you tried?
    $endgroup$
    – Omnomnomnom
    Jan 8 at 0:33






  • 1




    $begingroup$
    Do you know the dimension of $Votimes V$? Can you set up a basis?
    $endgroup$
    – Berci
    Jan 8 at 0:36










  • $begingroup$
    basis of $V bigotimes V$ are $1otimes 1 , 1otimes x, x otimes 1$, and$ x otimes x$ /then kernel of $delta$ is zero.
    $endgroup$
    – hussein
    Jan 8 at 14:48
















0












0








0


1



$begingroup$



Suppose that $V =text{span}(1,x)$ is a vector space over $frac{mathbb{Z}}{2mathbb{Z}} $ and let
$delta : V rightarrow Votimes V$




Such that $delta (1) = 1otimes x + xotimes 1$ and $delta (x) = x otimes x$.



What is the kernel of $delta$?










share|cite|improve this question











$endgroup$





Suppose that $V =text{span}(1,x)$ is a vector space over $frac{mathbb{Z}}{2mathbb{Z}} $ and let
$delta : V rightarrow Votimes V$




Such that $delta (1) = 1otimes x + xotimes 1$ and $delta (x) = x otimes x$.



What is the kernel of $delta$?







linear-algebra abstract-algebra tensor-products






share|cite|improve this question















share|cite|improve this question













share|cite|improve this question




share|cite|improve this question








edited Jan 8 at 17:15







fateme

















asked Jan 8 at 0:28









fatemefateme

294




294




closed as off-topic by Saad, jgon, zipirovich, Shailesh, mrtaurho Jan 8 at 6:02


This question appears to be off-topic. The users who voted to close gave this specific reason:


  • "This question is missing context or other details: Please provide additional context, which ideally explains why the question is relevant to you and our community. Some forms of context include: background and motivation, relevant definitions, source, possible strategies, your current progress, why the question is interesting or important, etc." – Saad, jgon, zipirovich, Shailesh, mrtaurho

If this question can be reworded to fit the rules in the help center, please edit the question.







closed as off-topic by Saad, jgon, zipirovich, Shailesh, mrtaurho Jan 8 at 6:02


This question appears to be off-topic. The users who voted to close gave this specific reason:


  • "This question is missing context or other details: Please provide additional context, which ideally explains why the question is relevant to you and our community. Some forms of context include: background and motivation, relevant definitions, source, possible strategies, your current progress, why the question is interesting or important, etc." – Saad, jgon, zipirovich, Shailesh, mrtaurho

If this question can be reworded to fit the rules in the help center, please edit the question.








  • 1




    $begingroup$
    What are your thoughts on the problem? What have you tried?
    $endgroup$
    – Omnomnomnom
    Jan 8 at 0:33






  • 1




    $begingroup$
    Do you know the dimension of $Votimes V$? Can you set up a basis?
    $endgroup$
    – Berci
    Jan 8 at 0:36










  • $begingroup$
    basis of $V bigotimes V$ are $1otimes 1 , 1otimes x, x otimes 1$, and$ x otimes x$ /then kernel of $delta$ is zero.
    $endgroup$
    – hussein
    Jan 8 at 14:48
















  • 1




    $begingroup$
    What are your thoughts on the problem? What have you tried?
    $endgroup$
    – Omnomnomnom
    Jan 8 at 0:33






  • 1




    $begingroup$
    Do you know the dimension of $Votimes V$? Can you set up a basis?
    $endgroup$
    – Berci
    Jan 8 at 0:36










  • $begingroup$
    basis of $V bigotimes V$ are $1otimes 1 , 1otimes x, x otimes 1$, and$ x otimes x$ /then kernel of $delta$ is zero.
    $endgroup$
    – hussein
    Jan 8 at 14:48










1




1




$begingroup$
What are your thoughts on the problem? What have you tried?
$endgroup$
– Omnomnomnom
Jan 8 at 0:33




$begingroup$
What are your thoughts on the problem? What have you tried?
$endgroup$
– Omnomnomnom
Jan 8 at 0:33




1




1




$begingroup$
Do you know the dimension of $Votimes V$? Can you set up a basis?
$endgroup$
– Berci
Jan 8 at 0:36




$begingroup$
Do you know the dimension of $Votimes V$? Can you set up a basis?
$endgroup$
– Berci
Jan 8 at 0:36












$begingroup$
basis of $V bigotimes V$ are $1otimes 1 , 1otimes x, x otimes 1$, and$ x otimes x$ /then kernel of $delta$ is zero.
$endgroup$
– hussein
Jan 8 at 14:48






$begingroup$
basis of $V bigotimes V$ are $1otimes 1 , 1otimes x, x otimes 1$, and$ x otimes x$ /then kernel of $delta$ is zero.
$endgroup$
– hussein
Jan 8 at 14:48












1 Answer
1






active

oldest

votes


















1












$begingroup$

Hint: To show that $delta$ has a trivial kernel, it suffices to show that $delta(1)$ and $delta(x)$ are linearly independent.






share|cite|improve this answer









$endgroup$













  • $begingroup$
    Almost. This isn't true when (say) $x=0$.
    $endgroup$
    – darij grinberg
    Jan 8 at 0:59






  • 1




    $begingroup$
    @Darij In this context, I think $x$ is meant to be taken as a function (or formal symbol) rather than as a particular value
    $endgroup$
    – Omnomnomnom
    Jan 8 at 1:42










  • $begingroup$
    @Omnomnomnom exactly right. this question related to khovanov homology and x is a formal symbol.
    $endgroup$
    – hussein
    Jan 8 at 21:39


















1 Answer
1






active

oldest

votes








1 Answer
1






active

oldest

votes









active

oldest

votes






active

oldest

votes









1












$begingroup$

Hint: To show that $delta$ has a trivial kernel, it suffices to show that $delta(1)$ and $delta(x)$ are linearly independent.






share|cite|improve this answer









$endgroup$













  • $begingroup$
    Almost. This isn't true when (say) $x=0$.
    $endgroup$
    – darij grinberg
    Jan 8 at 0:59






  • 1




    $begingroup$
    @Darij In this context, I think $x$ is meant to be taken as a function (or formal symbol) rather than as a particular value
    $endgroup$
    – Omnomnomnom
    Jan 8 at 1:42










  • $begingroup$
    @Omnomnomnom exactly right. this question related to khovanov homology and x is a formal symbol.
    $endgroup$
    – hussein
    Jan 8 at 21:39
















1












$begingroup$

Hint: To show that $delta$ has a trivial kernel, it suffices to show that $delta(1)$ and $delta(x)$ are linearly independent.






share|cite|improve this answer









$endgroup$













  • $begingroup$
    Almost. This isn't true when (say) $x=0$.
    $endgroup$
    – darij grinberg
    Jan 8 at 0:59






  • 1




    $begingroup$
    @Darij In this context, I think $x$ is meant to be taken as a function (or formal symbol) rather than as a particular value
    $endgroup$
    – Omnomnomnom
    Jan 8 at 1:42










  • $begingroup$
    @Omnomnomnom exactly right. this question related to khovanov homology and x is a formal symbol.
    $endgroup$
    – hussein
    Jan 8 at 21:39














1












1








1





$begingroup$

Hint: To show that $delta$ has a trivial kernel, it suffices to show that $delta(1)$ and $delta(x)$ are linearly independent.






share|cite|improve this answer









$endgroup$



Hint: To show that $delta$ has a trivial kernel, it suffices to show that $delta(1)$ and $delta(x)$ are linearly independent.







share|cite|improve this answer












share|cite|improve this answer



share|cite|improve this answer










answered Jan 8 at 0:35









OmnomnomnomOmnomnomnom

128k790179




128k790179












  • $begingroup$
    Almost. This isn't true when (say) $x=0$.
    $endgroup$
    – darij grinberg
    Jan 8 at 0:59






  • 1




    $begingroup$
    @Darij In this context, I think $x$ is meant to be taken as a function (or formal symbol) rather than as a particular value
    $endgroup$
    – Omnomnomnom
    Jan 8 at 1:42










  • $begingroup$
    @Omnomnomnom exactly right. this question related to khovanov homology and x is a formal symbol.
    $endgroup$
    – hussein
    Jan 8 at 21:39


















  • $begingroup$
    Almost. This isn't true when (say) $x=0$.
    $endgroup$
    – darij grinberg
    Jan 8 at 0:59






  • 1




    $begingroup$
    @Darij In this context, I think $x$ is meant to be taken as a function (or formal symbol) rather than as a particular value
    $endgroup$
    – Omnomnomnom
    Jan 8 at 1:42










  • $begingroup$
    @Omnomnomnom exactly right. this question related to khovanov homology and x is a formal symbol.
    $endgroup$
    – hussein
    Jan 8 at 21:39
















$begingroup$
Almost. This isn't true when (say) $x=0$.
$endgroup$
– darij grinberg
Jan 8 at 0:59




$begingroup$
Almost. This isn't true when (say) $x=0$.
$endgroup$
– darij grinberg
Jan 8 at 0:59




1




1




$begingroup$
@Darij In this context, I think $x$ is meant to be taken as a function (or formal symbol) rather than as a particular value
$endgroup$
– Omnomnomnom
Jan 8 at 1:42




$begingroup$
@Darij In this context, I think $x$ is meant to be taken as a function (or formal symbol) rather than as a particular value
$endgroup$
– Omnomnomnom
Jan 8 at 1:42












$begingroup$
@Omnomnomnom exactly right. this question related to khovanov homology and x is a formal symbol.
$endgroup$
– hussein
Jan 8 at 21:39




$begingroup$
@Omnomnomnom exactly right. this question related to khovanov homology and x is a formal symbol.
$endgroup$
– hussein
Jan 8 at 21:39



Popular posts from this blog

MongoDB - Not Authorized To Execute Command

in spring boot 2.1 many test slices are not allowed anymore due to multiple @BootstrapWith

How to fix TextFormField cause rebuild widget in Flutter