Mixing
Are $left{ (x,y) in mathbb{R^2} | |y| > x^2 , |y| x^4 , |y| < 10 right} $ homeomorphic?
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Are spaces $left{ (x,y) in mathbb{R^2} | |y| > x^2 , |y| < 10 right} $ and $left{(x,y) in mathbb{R^2} | |y| > x^4 , |y| < 10 right} $ homeomorphic? I think they might be but can't construct a homeomorphism because one is a subset of the other.
general-topology continuity
asked 19 hours ago
user15269
1438
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up vote
0
down vote
favorite
Are spaces $left{ (x,y) in mathbb{R^2} | |y| > x^2 , |y| < 10 right} $ and $left{(x,y) in mathbb{R^2} | |y| > x^4 , |y| < 10 right} $ homeomorphic? I think they might be but can't construct a homeomorphism because one is a subset of the other.
general-topology continuity
asked 19 hours ago
user15269
1438
Can you construct a homeomorphism between e.g. ${(x,y)mid x^2+y^2leq1}$ and ${(x,y)mid x^2+y^2leq4}$? Also here one is a subset of the other. I don't see why that should be an obstacle.
– drhab
19 hours ago
What is (x,y)(x,y)?
– William Elliot
7 hours ago
sorry I corrected it
– user15269
45 mins ago
add a comment |
up vote
0
down vote
favorite
up vote
0
down vote
favorite
Are spaces $left{ (x,y) in mathbb{R^2} | |y| > x^2 , |y| < 10 right} $ and $left{(x,y) in mathbb{R^2} | |y| > x^4 , |y| < 10 right} $ homeomorphic? I think they might be but can't construct a homeomorphism because one is a subset of the other.
general-topology continuity
asked 19 hours ago
user15269
1438
Are spaces $left{ (x,y) in mathbb{R^2} | |y| > x^2 , |y| < 10 right} $ and $left{(x,y) in mathbb{R^2} | |y| > x^4 , |y| < 10 right} $ homeomorphic? I think they might be but can't construct a homeomorphism because one is a subset of the other.
general-topology continuity
general-topology continuity
asked 19 hours ago
user15269
1438
asked 19 hours ago
user15269
1438
edited 49 mins ago
asked 19 hours ago
user15269
1438
asked 19 hours ago
user15269
1438
asked 19 hours ago
user15269
1438
1438
Can you construct a homeomorphism between e.g. ${(x,y)mid x^2+y^2leq1}$ and ${(x,y)mid x^2+y^2leq4}$? Also here one is a subset of the other. I don't see why that should be an obstacle.
– drhab
19 hours ago
What is (x,y)(x,y)?
– William Elliot
7 hours ago
sorry I corrected it
– user15269
45 mins ago
add a comment |
Can you construct a homeomorphism between e.g. ${(x,y)mid x^2+y^2leq1}$ and ${(x,y)mid x^2+y^2leq4}$? Also here one is a subset of the other. I don't see why that should be an obstacle.
– drhab
19 hours ago
What is (x,y)(x,y)?
– William Elliot
7 hours ago
sorry I corrected it
– user15269
45 mins ago
Can you construct a homeomorphism between e.g. ${(x,y)mid x^2+y^2leq1}$ and ${(x,y)mid x^2+y^2leq4}$? Also here one is a subset of the other. I don't see why that should be an obstacle.
– drhab
19 hours ago
Can you construct a homeomorphism between e.g. ${(x,y)mid x^2+y^2leq1}$ and ${(x,y)mid x^2+y^2leq4}$? Also here one is a subset of the other. I don't see why that should be an obstacle.
– drhab
19 hours ago
What is (x,y)(x,y)?
– William Elliot
7 hours ago
What is (x,y)(x,y)?
– William Elliot
7 hours ago
sorry I corrected it
– user15269
45 mins ago
sorry I corrected it
– user15269
45 mins ago
add a comment |
1 Answer
1
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oldest
votes
up vote
1
down vote
Let's disect those sets. Both of them consist of two connected components: when $y<0$ and when $y>0$. It is enough that we show that those components are pairwise homeomorphic. And since each upper half component is a reflection of the lower half then it is enough to show that $A={(x,y) | y>x^2; y< 10}$ and $B={(x,y) | y>x^4; y< 10}$ are homeomorphic.
To do that you have to realize that both $f(x)=x^2$ and $f(x)=x^4$ are convex functions. A bit of work has to be done to make sure that these conditions together with $y<10$ imply that both $A$ and $B$ are open and convex subsets of $mathbb{R}^2$. And it is well known that every open and convex subset of $mathbb{R}^n$ is homeomorphic to a $n$-ball.
answered 35 mins ago
freakish
10.2k1526
add a comment |
1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
up vote
1
down vote
Let's disect those sets. Both of them consist of two connected components: when $y<0$ and when $y>0$. It is enough that we show that those components are pairwise homeomorphic. And since each upper half component is a reflection of the lower half then it is enough to show that $A={(x,y) | y>x^2; y< 10}$ and $B={(x,y) | y>x^4; y< 10}$ are homeomorphic.
To do that you have to realize that both $f(x)=x^2$ and $f(x)=x^4$ are convex functions. A bit of work has to be done to make sure that these conditions together with $y<10$ imply that both $A$ and $B$ are open and convex subsets of $mathbb{R}^2$. And it is well known that every open and convex subset of $mathbb{R}^n$ is homeomorphic to a $n$-ball.
answered 35 mins ago
freakish
10.2k1526
add a comment |
up vote
1
down vote
Let's disect those sets. Both of them consist of two connected components: when $y<0$ and when $y>0$. It is enough that we show that those components are pairwise homeomorphic. And since each upper half component is a reflection of the lower half then it is enough to show that $A={(x,y) | y>x^2; y< 10}$ and $B={(x,y) | y>x^4; y< 10}$ are homeomorphic.
To do that you have to realize that both $f(x)=x^2$ and $f(x)=x^4$ are convex functions. A bit of work has to be done to make sure that these conditions together with $y<10$ imply that both $A$ and $B$ are open and convex subsets of $mathbb{R}^2$. And it is well known that every open and convex subset of $mathbb{R}^n$ is homeomorphic to a $n$-ball.
answered 35 mins ago
freakish
10.2k1526
add a comment |
up vote
1
down vote
up vote
1
down vote
Let's disect those sets. Both of them consist of two connected components: when $y<0$ and when $y>0$. It is enough that we show that those components are pairwise homeomorphic. And since each upper half component is a reflection of the lower half then it is enough to show that $A={(x,y) | y>x^2; y< 10}$ and $B={(x,y) | y>x^4; y< 10}$ are homeomorphic.
To do that you have to realize that both $f(x)=x^2$ and $f(x)=x^4$ are convex functions. A bit of work has to be done to make sure that these conditions together with $y<10$ imply that both $A$ and $B$ are open and convex subsets of $mathbb{R}^2$. And it is well known that every open and convex subset of $mathbb{R}^n$ is homeomorphic to a $n$-ball.
answered 35 mins ago
freakish
10.2k1526
Let's disect those sets. Both of them consist of two connected components: when $y<0$ and when $y>0$. It is enough that we show that those components are pairwise homeomorphic. And since each upper half component is a reflection of the lower half then it is enough to show that $A={(x,y) | y>x^2; y< 10}$ and $B={(x,y) | y>x^4; y< 10}$ are homeomorphic.
To do that you have to realize that both $f(x)=x^2$ and $f(x)=x^4$ are convex functions. A bit of work has to be done to make sure that these conditions together with $y<10$ imply that both $A$ and $B$ are open and convex subsets of $mathbb{R}^2$. And it is well known that every open and convex subset of $mathbb{R}^n$ is homeomorphic to a $n$-ball.
answered 35 mins ago
freakish
10.2k1526
answered 35 mins ago
freakish
10.2k1526
answered 35 mins ago
freakish
10.2k1526
answered 35 mins ago
freakish
10.2k1526
10.2k1526
add a comment |
add a comment |
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Can you construct a homeomorphism between e.g. ${(x,y)mid x^2+y^2leq1}$ and ${(x,y)mid x^2+y^2leq4}$? Also here one is a subset of the other. I don't see why that should be an obstacle.
– drhab
19 hours ago
What is (x,y)(x,y)?
– William Elliot
7 hours ago
sorry I corrected it
– user15269
45 mins ago