print the same level of xml data with a condition in python











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I have an xml file. I didn't make this file so I don't want to make any changes. I want to print the screen by pulling the information that provides certain conditions from the file. The value I want to get is on the same level as the value I'll do with the comparison. So even if I can check the condition, I can't pull the other data. How can I do this?



asd.xml



<report>

    <name>asd</name>

    <description>example description - 1</description>

</report>

<report>

    <name>dsa</name>

    <description>example description - 2</description>

</report>

<report>

    <name>asd</name>

    <description>example description - 3</description>

</report>


asd.py



import xml.etree.ElementTree as ET

tree = ET.parse('asd.xml')

root = tree.getroot()



for report_1 in root:

    for report_2 in report_1:

        if result.tag == 'name':

            if result.text == 'asd':

                print ?


I find the ones that are equal to asd by retrieving the value from tag name "name". but I cannot access the same level decription value.



I want output



name: asd

description: example description - 1

name: asd

description: example description - 3





python xml







share|improve this question


























    up vote
    0
    down vote

    favorite












    I have an xml file. I didn't make this file so I don't want to make any changes. I want to print the screen by pulling the information that provides certain conditions from the file. The value I want to get is on the same level as the value I'll do with the comparison. So even if I can check the condition, I can't pull the other data. How can I do this?



    asd.xml



    <report>
    
    <name>asd</name>
    
    <description>example description - 1</description>
    
</report>
    
<report>
    
    <name>dsa</name>
    
    <description>example description - 2</description>
    
</report>
    
<report>
    
    <name>asd</name>
    
    <description>example description - 3</description>
    
</report>


    asd.py



    import xml.etree.ElementTree as ET
    
tree = ET.parse('asd.xml')
    
root = tree.getroot()
    

    
for report_1 in root:
    
    for report_2 in report_1:
    
        if result.tag == 'name':
    
            if result.text == 'asd':
    
                print ?


    I find the ones that are equal to asd by retrieving the value from tag name "name". but I cannot access the same level decription value.



    I want output



    name: asd
    
description: example description - 1
    
name: asd
    
description: example description - 3





    python xml







    share|improve this question
























      up vote
      0
      down vote

      favorite









      up vote
      0
      down vote

      favorite











      I have an xml file. I didn't make this file so I don't want to make any changes. I want to print the screen by pulling the information that provides certain conditions from the file. The value I want to get is on the same level as the value I'll do with the comparison. So even if I can check the condition, I can't pull the other data. How can I do this?



      asd.xml



      <report>
      
    <name>asd</name>
      
    <description>example description - 1</description>
      
</report>
      
<report>
      
    <name>dsa</name>
      
    <description>example description - 2</description>
      
</report>
      
<report>
      
    <name>asd</name>
      
    <description>example description - 3</description>
      
</report>


      asd.py



      import xml.etree.ElementTree as ET
      
tree = ET.parse('asd.xml')
      
root = tree.getroot()
      

      
for report_1 in root:
      
    for report_2 in report_1:
      
        if result.tag == 'name':
      
            if result.text == 'asd':
      
                print ?


      I find the ones that are equal to asd by retrieving the value from tag name "name". but I cannot access the same level decription value.



      I want output



      name: asd
      
description: example description - 1
      
name: asd
      
description: example description - 3





      python xml







      share|improve this question













      I have an xml file. I didn't make this file so I don't want to make any changes. I want to print the screen by pulling the information that provides certain conditions from the file. The value I want to get is on the same level as the value I'll do with the comparison. So even if I can check the condition, I can't pull the other data. How can I do this?



      asd.xml



      <report>
      
    <name>asd</name>
      
    <description>example description - 1</description>
      
</report>
      
<report>
      
    <name>dsa</name>
      
    <description>example description - 2</description>
      
</report>
      
<report>
      
    <name>asd</name>
      
    <description>example description - 3</description>
      
</report>


      asd.py



      import xml.etree.ElementTree as ET
      
tree = ET.parse('asd.xml')
      
root = tree.getroot()
      

      
for report_1 in root:
      
    for report_2 in report_1:
      
        if result.tag == 'name':
      
            if result.text == 'asd':
      
                print ?


      I find the ones that are equal to asd by retrieving the value from tag name "name". but I cannot access the same level decription value.



      I want output



      name: asd
      
description: example description - 1
      
name: asd
      
description: example description - 3





      python xml




      python xml






      share|improve this question













      share|improve this question











      share|improve this question




      share|improve this question










      asked yesterday









      Ali.Turkkan

      226




      226
























          2 Answers
          2






          active

          oldest

          votes

















          up vote
          1
          down vote



          accepted










          Your file produces an error:




          ParseError: junk after document element: line 5, column 0




          Should it look like this:



          <data>
          
    <report>
          
        <name>asd</name>
          
        <description>example description - 1</description>
          
    </report>
          
    <report>
          
        <name>dsa</name>
          
        <description>example description - 2</description>
          
    </report>
          
    <report>
          
        <name>asd</name>
          
        <description>example description - 3</description>
          
    </report>
          
</data>


          You could use the following code:



          import xml.etree.ElementTree as ET
          

          
tree = ET.parse('asd.xml')
          

          
root = tree.getroot()
          

          
flag = False
          

          
for report in root:
          
    flag = False
          
    for row in report:
          
        if row.tag == 'name' and row.text == 'asd':
          
            print('name: asd')
          
            flag = True
          
        if flag and row.tag == 'description':
          
            print('description: {}'.format(row.text))


          That would provide you with desired result:



          name: asd
          
description: example description - 1
          
name: asd
          
description: example description - 3





          share|improve this answer





















          • thank you. its's work fine.
            – Ali.Turkkan
            yesterday


















          up vote
          1
          down vote













          What about this?



          asd.xml



          <?xml version="1.0" encoding="UTF-8"?>
          
<root>
          
    <report>
          
        <name>asd</name>
          
        <description>example description - 1</description>
          
    </report>
          
    <report>
          
        <name>dsa</name>
          
        <description>example description - 2</description>
          
    </report>
          
    <report>
          
        <name>asd</name>
          
        <description>example description - 3</description>
          
    </report>
          
</root>


          Python3



          import xml.etree.ElementTree as ET
          
tree = ET.parse(r"asd.xml")
          
root = tree.getroot()
          

          
for report in root:
          
    if report.find('name').text == "asd":
          
        print("name: ", report.find('name').text)
          
        print("description: ", report.find('description').text)





          share|improve this answer





















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            2 Answers
            2






            active

            oldest

            votes








            2 Answers
            2






            active

            oldest

            votes









            active

            oldest

            votes






            active

            oldest

            votes








            up vote
            1
            down vote



            accepted










            Your file produces an error:




            ParseError: junk after document element: line 5, column 0




            Should it look like this:



            <data>
            
    <report>
            
        <name>asd</name>
            
        <description>example description - 1</description>
            
    </report>
            
    <report>
            
        <name>dsa</name>
            
        <description>example description - 2</description>
            
    </report>
            
    <report>
            
        <name>asd</name>
            
        <description>example description - 3</description>
            
    </report>
            
</data>


            You could use the following code:



            import xml.etree.ElementTree as ET
            

            
tree = ET.parse('asd.xml')
            

            
root = tree.getroot()
            

            
flag = False
            

            
for report in root:
            
    flag = False
            
    for row in report:
            
        if row.tag == 'name' and row.text == 'asd':
            
            print('name: asd')
            
            flag = True
            
        if flag and row.tag == 'description':
            
            print('description: {}'.format(row.text))


            That would provide you with desired result:



            name: asd
            
description: example description - 1
            
name: asd
            
description: example description - 3





            share|improve this answer





















            • thank you. its's work fine.
              – Ali.Turkkan
              yesterday















            up vote
            1
            down vote



            accepted










            Your file produces an error:




            ParseError: junk after document element: line 5, column 0




            Should it look like this:



            <data>
            
    <report>
            
        <name>asd</name>
            
        <description>example description - 1</description>
            
    </report>
            
    <report>
            
        <name>dsa</name>
            
        <description>example description - 2</description>
            
    </report>
            
    <report>
            
        <name>asd</name>
            
        <description>example description - 3</description>
            
    </report>
            
</data>


            You could use the following code:



            import xml.etree.ElementTree as ET
            

            
tree = ET.parse('asd.xml')
            

            
root = tree.getroot()
            

            
flag = False
            

            
for report in root:
            
    flag = False
            
    for row in report:
            
        if row.tag == 'name' and row.text == 'asd':
            
            print('name: asd')
            
            flag = True
            
        if flag and row.tag == 'description':
            
            print('description: {}'.format(row.text))


            That would provide you with desired result:



            name: asd
            
description: example description - 1
            
name: asd
            
description: example description - 3





            share|improve this answer





















            • thank you. its's work fine.
              – Ali.Turkkan
              yesterday













            up vote
            1
            down vote



            accepted







            up vote
            1
            down vote



            accepted






            Your file produces an error:




            ParseError: junk after document element: line 5, column 0




            Should it look like this:



            <data>
            
    <report>
            
        <name>asd</name>
            
        <description>example description - 1</description>
            
    </report>
            
    <report>
            
        <name>dsa</name>
            
        <description>example description - 2</description>
            
    </report>
            
    <report>
            
        <name>asd</name>
            
        <description>example description - 3</description>
            
    </report>
            
</data>


            You could use the following code:



            import xml.etree.ElementTree as ET
            

            
tree = ET.parse('asd.xml')
            

            
root = tree.getroot()
            

            
flag = False
            

            
for report in root:
            
    flag = False
            
    for row in report:
            
        if row.tag == 'name' and row.text == 'asd':
            
            print('name: asd')
            
            flag = True
            
        if flag and row.tag == 'description':
            
            print('description: {}'.format(row.text))


            That would provide you with desired result:



            name: asd
            
description: example description - 1
            
name: asd
            
description: example description - 3





            share|improve this answer












            Your file produces an error:




            ParseError: junk after document element: line 5, column 0




            Should it look like this:



            <data>
            
    <report>
            
        <name>asd</name>
            
        <description>example description - 1</description>
            
    </report>
            
    <report>
            
        <name>dsa</name>
            
        <description>example description - 2</description>
            
    </report>
            
    <report>
            
        <name>asd</name>
            
        <description>example description - 3</description>
            
    </report>
            
</data>


            You could use the following code:



            import xml.etree.ElementTree as ET
            

            
tree = ET.parse('asd.xml')
            

            
root = tree.getroot()
            

            
flag = False
            

            
for report in root:
            
    flag = False
            
    for row in report:
            
        if row.tag == 'name' and row.text == 'asd':
            
            print('name: asd')
            
            flag = True
            
        if flag and row.tag == 'description':
            
            print('description: {}'.format(row.text))


            That would provide you with desired result:



            name: asd
            
description: example description - 1
            
name: asd
            
description: example description - 3






            share|improve this answer












            share|improve this answer



            share|improve this answer










            answered yesterday









            zipa

            15.5k21334




            15.5k21334












            • thank you. its's work fine.
              – Ali.Turkkan
              yesterday


















            • thank you. its's work fine.
              – Ali.Turkkan
              yesterday
















            thank you. its's work fine.
            – Ali.Turkkan
            yesterday




            thank you. its's work fine.
            – Ali.Turkkan
            yesterday












            up vote
            1
            down vote













            What about this?



            asd.xml



            <?xml version="1.0" encoding="UTF-8"?>
            
<root>
            
    <report>
            
        <name>asd</name>
            
        <description>example description - 1</description>
            
    </report>
            
    <report>
            
        <name>dsa</name>
            
        <description>example description - 2</description>
            
    </report>
            
    <report>
            
        <name>asd</name>
            
        <description>example description - 3</description>
            
    </report>
            
</root>


            Python3



            import xml.etree.ElementTree as ET
            
tree = ET.parse(r"asd.xml")
            
root = tree.getroot()
            

            
for report in root:
            
    if report.find('name').text == "asd":
            
        print("name: ", report.find('name').text)
            
        print("description: ", report.find('description').text)





            share|improve this answer

























              up vote
              1
              down vote













              What about this?



              asd.xml



              <?xml version="1.0" encoding="UTF-8"?>
              
<root>
              
    <report>
              
        <name>asd</name>
              
        <description>example description - 1</description>
              
    </report>
              
    <report>
              
        <name>dsa</name>
              
        <description>example description - 2</description>
              
    </report>
              
    <report>
              
        <name>asd</name>
              
        <description>example description - 3</description>
              
    </report>
              
</root>


              Python3



              import xml.etree.ElementTree as ET
              
tree = ET.parse(r"asd.xml")
              
root = tree.getroot()
              

              
for report in root:
              
    if report.find('name').text == "asd":
              
        print("name: ", report.find('name').text)
              
        print("description: ", report.find('description').text)





              share|improve this answer























                up vote
                1
                down vote










                up vote
                1
                down vote









                What about this?



                asd.xml



                <?xml version="1.0" encoding="UTF-8"?>
                
<root>
                
    <report>
                
        <name>asd</name>
                
        <description>example description - 1</description>
                
    </report>
                
    <report>
                
        <name>dsa</name>
                
        <description>example description - 2</description>
                
    </report>
                
    <report>
                
        <name>asd</name>
                
        <description>example description - 3</description>
                
    </report>
                
</root>


                Python3



                import xml.etree.ElementTree as ET
                
tree = ET.parse(r"asd.xml")
                
root = tree.getroot()
                

                
for report in root:
                
    if report.find('name').text == "asd":
                
        print("name: ", report.find('name').text)
                
        print("description: ", report.find('description').text)





                share|improve this answer












                What about this?



                asd.xml



                <?xml version="1.0" encoding="UTF-8"?>
                
<root>
                
    <report>
                
        <name>asd</name>
                
        <description>example description - 1</description>
                
    </report>
                
    <report>
                
        <name>dsa</name>
                
        <description>example description - 2</description>
                
    </report>
                
    <report>
                
        <name>asd</name>
                
        <description>example description - 3</description>
                
    </report>
                
</root>


                Python3



                import xml.etree.ElementTree as ET
                
tree = ET.parse(r"asd.xml")
                
root = tree.getroot()
                

                
for report in root:
                
    if report.find('name').text == "asd":
                
        print("name: ", report.find('name').text)
                
        print("description: ", report.find('description').text)






                share|improve this answer












                share|improve this answer



                share|improve this answer










                answered yesterday









                Ettore Rizza

                1,8502617




                1,8502617






























                     

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