Mixing
How to get Client or visitor IP Address:: Despite multiple tries Didn't get solution:
1
How to get Client or visitor IP Address:: Despite multiple tries Didn't get solution: Below what I tried:
public partial class _Default : System.Web.UI.Page
{
protected void Page_Load(object sender, EventArgs e)
{
string ipAddress33 = Request.UserHostAddress.ToString();
string strHostName = System.Net.Dns.GetHostName();
string clientIPAddress22 = System.Net.Dns.GetHostAddresses(strHostName).GetValue(1).ToString();
Response.Write("System.Net.Dns.GetHostAddresses(strHostName).GetValue(1).ToString(); : " + clientIPAddress22 + "<br />");
string ipaddress;
string IP = Request.UserHostAddress;
string clientIPAddress = this.Page.Request.ServerVariables["REMOTE_ADDR"];
string IP2 = Environment.GetEnvironmentVariable("CLIENTNAME");
ipaddress = Request.ServerVariables["HTTP_X_FORWARDED_FOR"];
if (ipaddress == "" || ipaddress == null)
ipaddress = Request.ServerVariables["REMOTE_ADDR"];
Response.Write("Request.ServerVariables['HTTP_X_FORWARDED_FOR'] : " + ipaddress + "<br />");
Response.Write("Request.UserHostAddress.ToString() : " + ipAddress33 + "<br />");
string stringIpAddress;
stringIpAddress = Request.ServerVariables["HTTP_X_FORWARDED_FOR"];
if (stringIpAddress == null) //may be the HTTP_X_FORWARDED_FOR is null
{
stringIpAddress = Request.ServerVariables["REMOTE_ADDR"];//we can use REMOTE_ADDR
}
Response.Write("Request.ServerVariables['REMOTE_ADDR'] : " + stringIpAddress + "<br />");
//Get the Host Name
string stringHostName = Dns.GetHostName();
//Get The Ip Host Entry
IPHostEntry ipHostEntries = Dns.GetHostEntry(stringHostName);
//Get The Ip Address From The Ip Host Entry Address List
IPAddress arrIpAddress = ipHostEntries.AddressList;
Response.Write("Dns.GetHostName(): " + arrIpAddress[arrIpAddress.Length - 1].ToString());
}
}
This is the results I got:
System.Net.Dns.GetHostAddresses(strHostName).GetValue(1).ToString(); : 190.80.90.75
Request.ServerVariables['HTTP_X_FORWARDED_FOR'] : 190.80.90.225
Request.UserHostAddress.ToString() : 190.80.90.225
Request.ServerVariables['REMOTE_ADDR'] : 190.80.90.225
Dns.GetHostName(): 190.80.90.75
Which is not the correct IP address of the visitor.
c# vb.net
asked Nov 20 '18 at 6:23
sunil492307sunil492307
13
add a comment |
1
How to get Client or visitor IP Address:: Despite multiple tries Didn't get solution: Below what I tried:
public partial class _Default : System.Web.UI.Page
{
protected void Page_Load(object sender, EventArgs e)
{
string ipAddress33 = Request.UserHostAddress.ToString();
string strHostName = System.Net.Dns.GetHostName();
string clientIPAddress22 = System.Net.Dns.GetHostAddresses(strHostName).GetValue(1).ToString();
Response.Write("System.Net.Dns.GetHostAddresses(strHostName).GetValue(1).ToString(); : " + clientIPAddress22 + "<br />");
string ipaddress;
string IP = Request.UserHostAddress;
string clientIPAddress = this.Page.Request.ServerVariables["REMOTE_ADDR"];
string IP2 = Environment.GetEnvironmentVariable("CLIENTNAME");
ipaddress = Request.ServerVariables["HTTP_X_FORWARDED_FOR"];
if (ipaddress == "" || ipaddress == null)
ipaddress = Request.ServerVariables["REMOTE_ADDR"];
Response.Write("Request.ServerVariables['HTTP_X_FORWARDED_FOR'] : " + ipaddress + "<br />");
Response.Write("Request.UserHostAddress.ToString() : " + ipAddress33 + "<br />");
string stringIpAddress;
stringIpAddress = Request.ServerVariables["HTTP_X_FORWARDED_FOR"];
if (stringIpAddress == null) //may be the HTTP_X_FORWARDED_FOR is null
{
stringIpAddress = Request.ServerVariables["REMOTE_ADDR"];//we can use REMOTE_ADDR
}
Response.Write("Request.ServerVariables['REMOTE_ADDR'] : " + stringIpAddress + "<br />");
//Get the Host Name
string stringHostName = Dns.GetHostName();
//Get The Ip Host Entry
IPHostEntry ipHostEntries = Dns.GetHostEntry(stringHostName);
//Get The Ip Address From The Ip Host Entry Address List
IPAddress arrIpAddress = ipHostEntries.AddressList;
Response.Write("Dns.GetHostName(): " + arrIpAddress[arrIpAddress.Length - 1].ToString());
}
}
This is the results I got:
System.Net.Dns.GetHostAddresses(strHostName).GetValue(1).ToString(); : 190.80.90.75
Request.ServerVariables['HTTP_X_FORWARDED_FOR'] : 190.80.90.225
Request.UserHostAddress.ToString() : 190.80.90.225
Request.ServerVariables['REMOTE_ADDR'] : 190.80.90.225
Dns.GetHostName(): 190.80.90.75
Which is not the correct IP address of the visitor.
c# vb.net
asked Nov 20 '18 at 6:23
sunil492307sunil492307
13
How do you know that the address is wrong?
– Nico Schertler
Nov 20 '18 at 7:59
I matched with the LAN IP address provided to the system and it didn't matched
– sunil492307
Nov 20 '18 at 10:35
The global IP address that your computer uses to communicate with the internet is most likely not the same as the local one in your LAN.
– Nico Schertler
Nov 20 '18 at 14:03
Thanks Nico schertler, I came to know that when we are using subnets and firewalls, it is not possible to get the clients ip address i.e lan ip address.
– sunil492307
Nov 20 '18 at 17:40
add a comment |
1
1
1
1
How to get Client or visitor IP Address:: Despite multiple tries Didn't get solution: Below what I tried:
public partial class _Default : System.Web.UI.Page
{
protected void Page_Load(object sender, EventArgs e)
{
string ipAddress33 = Request.UserHostAddress.ToString();
string strHostName = System.Net.Dns.GetHostName();
string clientIPAddress22 = System.Net.Dns.GetHostAddresses(strHostName).GetValue(1).ToString();
Response.Write("System.Net.Dns.GetHostAddresses(strHostName).GetValue(1).ToString(); : " + clientIPAddress22 + "<br />");
string ipaddress;
string IP = Request.UserHostAddress;
string clientIPAddress = this.Page.Request.ServerVariables["REMOTE_ADDR"];
string IP2 = Environment.GetEnvironmentVariable("CLIENTNAME");
ipaddress = Request.ServerVariables["HTTP_X_FORWARDED_FOR"];
if (ipaddress == "" || ipaddress == null)
ipaddress = Request.ServerVariables["REMOTE_ADDR"];
Response.Write("Request.ServerVariables['HTTP_X_FORWARDED_FOR'] : " + ipaddress + "<br />");
Response.Write("Request.UserHostAddress.ToString() : " + ipAddress33 + "<br />");
string stringIpAddress;
stringIpAddress = Request.ServerVariables["HTTP_X_FORWARDED_FOR"];
if (stringIpAddress == null) //may be the HTTP_X_FORWARDED_FOR is null
{
stringIpAddress = Request.ServerVariables["REMOTE_ADDR"];//we can use REMOTE_ADDR
}
Response.Write("Request.ServerVariables['REMOTE_ADDR'] : " + stringIpAddress + "<br />");
//Get the Host Name
string stringHostName = Dns.GetHostName();
//Get The Ip Host Entry
IPHostEntry ipHostEntries = Dns.GetHostEntry(stringHostName);
//Get The Ip Address From The Ip Host Entry Address List
IPAddress arrIpAddress = ipHostEntries.AddressList;
Response.Write("Dns.GetHostName(): " + arrIpAddress[arrIpAddress.Length - 1].ToString());
}
}
This is the results I got:
System.Net.Dns.GetHostAddresses(strHostName).GetValue(1).ToString(); : 190.80.90.75
Request.ServerVariables['HTTP_X_FORWARDED_FOR'] : 190.80.90.225
Request.UserHostAddress.ToString() : 190.80.90.225
Request.ServerVariables['REMOTE_ADDR'] : 190.80.90.225
Dns.GetHostName(): 190.80.90.75
Which is not the correct IP address of the visitor.
c# vb.net
asked Nov 20 '18 at 6:23
sunil492307sunil492307
13
How to get Client or visitor IP Address:: Despite multiple tries Didn't get solution: Below what I tried:
public partial class _Default : System.Web.UI.Page
{
protected void Page_Load(object sender, EventArgs e)
{
string ipAddress33 = Request.UserHostAddress.ToString();
string strHostName = System.Net.Dns.GetHostName();
string clientIPAddress22 = System.Net.Dns.GetHostAddresses(strHostName).GetValue(1).ToString();
Response.Write("System.Net.Dns.GetHostAddresses(strHostName).GetValue(1).ToString(); : " + clientIPAddress22 + "<br />");
string ipaddress;
string IP = Request.UserHostAddress;
string clientIPAddress = this.Page.Request.ServerVariables["REMOTE_ADDR"];
string IP2 = Environment.GetEnvironmentVariable("CLIENTNAME");
ipaddress = Request.ServerVariables["HTTP_X_FORWARDED_FOR"];
if (ipaddress == "" || ipaddress == null)
ipaddress = Request.ServerVariables["REMOTE_ADDR"];
Response.Write("Request.ServerVariables['HTTP_X_FORWARDED_FOR'] : " + ipaddress + "<br />");
Response.Write("Request.UserHostAddress.ToString() : " + ipAddress33 + "<br />");
string stringIpAddress;
stringIpAddress = Request.ServerVariables["HTTP_X_FORWARDED_FOR"];
if (stringIpAddress == null) //may be the HTTP_X_FORWARDED_FOR is null
{
stringIpAddress = Request.ServerVariables["REMOTE_ADDR"];//we can use REMOTE_ADDR
}
Response.Write("Request.ServerVariables['REMOTE_ADDR'] : " + stringIpAddress + "<br />");
//Get the Host Name
string stringHostName = Dns.GetHostName();
//Get The Ip Host Entry
IPHostEntry ipHostEntries = Dns.GetHostEntry(stringHostName);
//Get The Ip Address From The Ip Host Entry Address List
IPAddress arrIpAddress = ipHostEntries.AddressList;
Response.Write("Dns.GetHostName(): " + arrIpAddress[arrIpAddress.Length - 1].ToString());
}
}
This is the results I got:
System.Net.Dns.GetHostAddresses(strHostName).GetValue(1).ToString(); : 190.80.90.75
Request.ServerVariables['HTTP_X_FORWARDED_FOR'] : 190.80.90.225
Request.UserHostAddress.ToString() : 190.80.90.225
Request.ServerVariables['REMOTE_ADDR'] : 190.80.90.225
Dns.GetHostName(): 190.80.90.75
Which is not the correct IP address of the visitor.
c# vb.net
c# vb.net
asked Nov 20 '18 at 6:23
sunil492307sunil492307
13
asked Nov 20 '18 at 6:23
sunil492307sunil492307
13
asked Nov 20 '18 at 6:23
sunil492307sunil492307
13
asked Nov 20 '18 at 6:23
sunil492307sunil492307
13
asked Nov 20 '18 at 6:23
sunil492307sunil492307
13
13
How do you know that the address is wrong?
– Nico Schertler
Nov 20 '18 at 7:59
I matched with the LAN IP address provided to the system and it didn't matched
– sunil492307
Nov 20 '18 at 10:35
The global IP address that your computer uses to communicate with the internet is most likely not the same as the local one in your LAN.
– Nico Schertler
Nov 20 '18 at 14:03
Thanks Nico schertler, I came to know that when we are using subnets and firewalls, it is not possible to get the clients ip address i.e lan ip address.
– sunil492307
Nov 20 '18 at 17:40
add a comment |
How do you know that the address is wrong?
– Nico Schertler
Nov 20 '18 at 7:59
I matched with the LAN IP address provided to the system and it didn't matched
– sunil492307
Nov 20 '18 at 10:35
The global IP address that your computer uses to communicate with the internet is most likely not the same as the local one in your LAN.
– Nico Schertler
Nov 20 '18 at 14:03
Thanks Nico schertler, I came to know that when we are using subnets and firewalls, it is not possible to get the clients ip address i.e lan ip address.
– sunil492307
Nov 20 '18 at 17:40
How do you know that the address is wrong?
– Nico Schertler
Nov 20 '18 at 7:59
How do you know that the address is wrong?
– Nico Schertler
Nov 20 '18 at 7:59
I matched with the LAN IP address provided to the system and it didn't matched
– sunil492307
Nov 20 '18 at 10:35
I matched with the LAN IP address provided to the system and it didn't matched
– sunil492307
Nov 20 '18 at 10:35
The global IP address that your computer uses to communicate with the internet is most likely not the same as the local one in your LAN.
– Nico Schertler
Nov 20 '18 at 14:03
The global IP address that your computer uses to communicate with the internet is most likely not the same as the local one in your LAN.
– Nico Schertler
Nov 20 '18 at 14:03
Thanks Nico schertler, I came to know that when we are using subnets and firewalls, it is not possible to get the clients ip address i.e lan ip address.
– sunil492307
Nov 20 '18 at 17:40
Thanks Nico schertler, I came to know that when we are using subnets and firewalls, it is not possible to get the clients ip address i.e lan ip address.
– sunil492307
Nov 20 '18 at 17:40
add a comment |
2 Answers
2
active
oldest
votes
0
according to this answer you can use this :
protected void GetUser_IP()
{
string VisitorsIPAddr = string.Empty;
if (HttpContext.Current.Request.ServerVariables["HTTP_X_FORWARDED_FOR"] != null)
{
VisitorsIPAddr = HttpContext.Current.Request.ServerVariables["HTTP_X_FORWARDED_FOR"].ToString();
}
else if (HttpContext.Current.Request.UserHostAddress.Length != 0)
{
VisitorsIPAddr = HttpContext.Current.Request.UserHostAddress;
}
uip.Text = "Your IP is: " + VisitorsIPAddr;
}
answered Nov 20 '18 at 7:58
FarhadMohseniFarhadMohseni
215
Using the above snippet: I got result as "Your IP is: ::1"
– sunil492307
Nov 20 '18 at 10:09
::1 is the loopback address in IPv6. the IPv6 version of 127.0.0.1 . if you running it on your local host , the result is normal
– FarhadMohseni
Nov 20 '18 at 12:05
Thanks FarhadMoheseni.
– sunil492307
Nov 20 '18 at 17:41
add a comment |
0
VB.Net Version::
-----------------------------------------------
Shared Sub GetUser_IP()
If HttpContext.Current.Request.ServerVariables("HTTP_X_FORWARDED_FOR") IsNot Nothing Then
VisitorsIPAddr = HttpContext.Current.Request.ServerVariables("HTTP_X_FORWARDED_FOR").ToString()
ElseIf HttpContext.Current.Request.UserHostAddress.Length <> 0 Then
VisitorsIPAddr = HttpContext.Current.Request.UserHostAddress
End If
End Sub
answered Nov 21 '18 at 3:58
sunil492307sunil492307
13
add a comment |
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2 Answers
2
active
oldest
votes
2 Answers
2
active
oldest
votes
active
oldest
votes
active
oldest
votes
0
according to this answer you can use this :
protected void GetUser_IP()
{
string VisitorsIPAddr = string.Empty;
if (HttpContext.Current.Request.ServerVariables["HTTP_X_FORWARDED_FOR"] != null)
{
VisitorsIPAddr = HttpContext.Current.Request.ServerVariables["HTTP_X_FORWARDED_FOR"].ToString();
}
else if (HttpContext.Current.Request.UserHostAddress.Length != 0)
{
VisitorsIPAddr = HttpContext.Current.Request.UserHostAddress;
}
uip.Text = "Your IP is: " + VisitorsIPAddr;
}
answered Nov 20 '18 at 7:58
FarhadMohseniFarhadMohseni
215
Using the above snippet: I got result as "Your IP is: ::1"
– sunil492307
Nov 20 '18 at 10:09
::1 is the loopback address in IPv6. the IPv6 version of 127.0.0.1 . if you running it on your local host , the result is normal
– FarhadMohseni
Nov 20 '18 at 12:05
Thanks FarhadMoheseni.
– sunil492307
Nov 20 '18 at 17:41
add a comment |
0
according to this answer you can use this :
protected void GetUser_IP()
{
string VisitorsIPAddr = string.Empty;
if (HttpContext.Current.Request.ServerVariables["HTTP_X_FORWARDED_FOR"] != null)
{
VisitorsIPAddr = HttpContext.Current.Request.ServerVariables["HTTP_X_FORWARDED_FOR"].ToString();
}
else if (HttpContext.Current.Request.UserHostAddress.Length != 0)
{
VisitorsIPAddr = HttpContext.Current.Request.UserHostAddress;
}
uip.Text = "Your IP is: " + VisitorsIPAddr;
}
answered Nov 20 '18 at 7:58
FarhadMohseniFarhadMohseni
215
Using the above snippet: I got result as "Your IP is: ::1"
– sunil492307
Nov 20 '18 at 10:09
::1 is the loopback address in IPv6. the IPv6 version of 127.0.0.1 . if you running it on your local host , the result is normal
– FarhadMohseni
Nov 20 '18 at 12:05
Thanks FarhadMoheseni.
– sunil492307
Nov 20 '18 at 17:41
add a comment |
0
0
0
according to this answer you can use this :
protected void GetUser_IP()
{
string VisitorsIPAddr = string.Empty;
if (HttpContext.Current.Request.ServerVariables["HTTP_X_FORWARDED_FOR"] != null)
{
VisitorsIPAddr = HttpContext.Current.Request.ServerVariables["HTTP_X_FORWARDED_FOR"].ToString();
}
else if (HttpContext.Current.Request.UserHostAddress.Length != 0)
{
VisitorsIPAddr = HttpContext.Current.Request.UserHostAddress;
}
uip.Text = "Your IP is: " + VisitorsIPAddr;
}
answered Nov 20 '18 at 7:58
FarhadMohseniFarhadMohseni
215
according to this answer you can use this :
protected void GetUser_IP()
{
string VisitorsIPAddr = string.Empty;
if (HttpContext.Current.Request.ServerVariables["HTTP_X_FORWARDED_FOR"] != null)
{
VisitorsIPAddr = HttpContext.Current.Request.ServerVariables["HTTP_X_FORWARDED_FOR"].ToString();
}
else if (HttpContext.Current.Request.UserHostAddress.Length != 0)
{
VisitorsIPAddr = HttpContext.Current.Request.UserHostAddress;
}
uip.Text = "Your IP is: " + VisitorsIPAddr;
}
answered Nov 20 '18 at 7:58
FarhadMohseniFarhadMohseni
215
answered Nov 20 '18 at 7:58
FarhadMohseniFarhadMohseni
215
answered Nov 20 '18 at 7:58
FarhadMohseniFarhadMohseni
215
answered Nov 20 '18 at 7:58
FarhadMohseniFarhadMohseni
215
215
Using the above snippet: I got result as "Your IP is: ::1"
– sunil492307
Nov 20 '18 at 10:09
::1 is the loopback address in IPv6. the IPv6 version of 127.0.0.1 . if you running it on your local host , the result is normal
– FarhadMohseni
Nov 20 '18 at 12:05
Thanks FarhadMoheseni.
– sunil492307
Nov 20 '18 at 17:41
add a comment |
Using the above snippet: I got result as "Your IP is: ::1"
– sunil492307
Nov 20 '18 at 10:09
::1 is the loopback address in IPv6. the IPv6 version of 127.0.0.1 . if you running it on your local host , the result is normal
– FarhadMohseni
Nov 20 '18 at 12:05
Thanks FarhadMoheseni.
– sunil492307
Nov 20 '18 at 17:41
Using the above snippet: I got result as "Your IP is: ::1"
– sunil492307
Nov 20 '18 at 10:09
Using the above snippet: I got result as "Your IP is: ::1"
– sunil492307
Nov 20 '18 at 10:09
::1 is the loopback address in IPv6. the IPv6 version of 127.0.0.1 . if you running it on your local host , the result is normal
– FarhadMohseni
Nov 20 '18 at 12:05
::1 is the loopback address in IPv6. the IPv6 version of 127.0.0.1 . if you running it on your local host , the result is normal
– FarhadMohseni
Nov 20 '18 at 12:05
Thanks FarhadMoheseni.
– sunil492307
Nov 20 '18 at 17:41
Thanks FarhadMoheseni.
– sunil492307
Nov 20 '18 at 17:41
add a comment |
0
VB.Net Version::
-----------------------------------------------
Shared Sub GetUser_IP()
If HttpContext.Current.Request.ServerVariables("HTTP_X_FORWARDED_FOR") IsNot Nothing Then
VisitorsIPAddr = HttpContext.Current.Request.ServerVariables("HTTP_X_FORWARDED_FOR").ToString()
ElseIf HttpContext.Current.Request.UserHostAddress.Length <> 0 Then
VisitorsIPAddr = HttpContext.Current.Request.UserHostAddress
End If
End Sub
answered Nov 21 '18 at 3:58
sunil492307sunil492307
13
add a comment |
0
VB.Net Version::
-----------------------------------------------
Shared Sub GetUser_IP()
If HttpContext.Current.Request.ServerVariables("HTTP_X_FORWARDED_FOR") IsNot Nothing Then
VisitorsIPAddr = HttpContext.Current.Request.ServerVariables("HTTP_X_FORWARDED_FOR").ToString()
ElseIf HttpContext.Current.Request.UserHostAddress.Length <> 0 Then
VisitorsIPAddr = HttpContext.Current.Request.UserHostAddress
End If
End Sub
answered Nov 21 '18 at 3:58
sunil492307sunil492307
13
add a comment |
0
0
0
VB.Net Version::
-----------------------------------------------
Shared Sub GetUser_IP()
If HttpContext.Current.Request.ServerVariables("HTTP_X_FORWARDED_FOR") IsNot Nothing Then
VisitorsIPAddr = HttpContext.Current.Request.ServerVariables("HTTP_X_FORWARDED_FOR").ToString()
ElseIf HttpContext.Current.Request.UserHostAddress.Length <> 0 Then
VisitorsIPAddr = HttpContext.Current.Request.UserHostAddress
End If
End Sub
answered Nov 21 '18 at 3:58
sunil492307sunil492307
13
VB.Net Version::
-----------------------------------------------
Shared Sub GetUser_IP()
If HttpContext.Current.Request.ServerVariables("HTTP_X_FORWARDED_FOR") IsNot Nothing Then
VisitorsIPAddr = HttpContext.Current.Request.ServerVariables("HTTP_X_FORWARDED_FOR").ToString()
ElseIf HttpContext.Current.Request.UserHostAddress.Length <> 0 Then
VisitorsIPAddr = HttpContext.Current.Request.UserHostAddress
End If
End Sub
answered Nov 21 '18 at 3:58
sunil492307sunil492307
13
answered Nov 21 '18 at 3:58
sunil492307sunil492307
13
answered Nov 21 '18 at 3:58
sunil492307sunil492307
13
answered Nov 21 '18 at 3:58
sunil492307sunil492307
13
13
add a comment |
add a comment |
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How do you know that the address is wrong?
– Nico Schertler
Nov 20 '18 at 7:59
I matched with the LAN IP address provided to the system and it didn't matched
– sunil492307
Nov 20 '18 at 10:35
The global IP address that your computer uses to communicate with the internet is most likely not the same as the local one in your LAN.
– Nico Schertler
Nov 20 '18 at 14:03
Thanks Nico schertler, I came to know that when we are using subnets and firewalls, it is not possible to get the clients ip address i.e lan ip address.
– sunil492307
Nov 20 '18 at 17:40