Mixing
Sigmas Problem ΣΣ i^2 [closed]
$begingroup$
How can i solve this?
$ΣΣ i^2=?$
both are from 1 to 4
And i is the variable
My Answer is 58.am i correct?
measure-theory
asked Jan 4 at 5:22
Mobina KMobina K
194
$endgroup$
closed as unclear what you're asking by Nosrati, Lord Shark the Unknown, Henrik, José Carlos Santos, Did Jan 4 at 8:18
Please clarify your specific problem or add additional details to highlight exactly what you need. As it's currently written, it’s hard to tell exactly what you're asking. See the How to Ask page for help clarifying this question. If this question can be reworded to fit the rules in the help center, please edit the question.
|
show 3 more comments
$begingroup$
How can i solve this?
$ΣΣ i^2=?$
both are from 1 to 4
And i is the variable
My Answer is 58.am i correct?
measure-theory
asked Jan 4 at 5:22
Mobina KMobina K
194
$endgroup$
closed as unclear what you're asking by Nosrati, Lord Shark the Unknown, Henrik, José Carlos Santos, Did Jan 4 at 8:18
Please clarify your specific problem or add additional details to highlight exactly what you need. As it's currently written, it’s hard to tell exactly what you're asking. See the How to Ask page for help clarifying this question. If this question can be reworded to fit the rules in the help center, please edit the question.
1
$begingroup$
what are the variables of each sum?
$endgroup$
– Zachary Hunter
Jan 4 at 5:25
$begingroup$
i is the variable
$endgroup$
– Mobina K
Jan 4 at 5:26
$begingroup$
i is the variable for both?
$endgroup$
– Zachary Hunter
Jan 4 at 5:27
$begingroup$
also, I believe you can do this short double sum by hand, am I wrong?
$endgroup$
– Zachary Hunter
Jan 4 at 5:28
$begingroup$
Yes.i is the variable for both.i just need to check the answer
$endgroup$
– Mobina K
Jan 4 at 5:32
|
show 3 more comments
$begingroup$
How can i solve this?
$ΣΣ i^2=?$
both are from 1 to 4
And i is the variable
My Answer is 58.am i correct?
measure-theory
asked Jan 4 at 5:22
Mobina KMobina K
194
$endgroup$
How can i solve this?
$ΣΣ i^2=?$
both are from 1 to 4
And i is the variable
My Answer is 58.am i correct?
measure-theory
measure-theory
asked Jan 4 at 5:22
Mobina KMobina K
194
asked Jan 4 at 5:22
Mobina KMobina K
194
edited Jan 4 at 5:36
Mobina K
asked Jan 4 at 5:22
Mobina KMobina K
194
asked Jan 4 at 5:22
Mobina KMobina K
194
asked Jan 4 at 5:22
Mobina KMobina K
194
194
closed as unclear what you're asking by Nosrati, Lord Shark the Unknown, Henrik, José Carlos Santos, Did Jan 4 at 8:18
Please clarify your specific problem or add additional details to highlight exactly what you need. As it's currently written, it’s hard to tell exactly what you're asking. See the How to Ask page for help clarifying this question. If this question can be reworded to fit the rules in the help center, please edit the question.
closed as unclear what you're asking by Nosrati, Lord Shark the Unknown, Henrik, José Carlos Santos, Did Jan 4 at 8:18
Please clarify your specific problem or add additional details to highlight exactly what you need. As it's currently written, it’s hard to tell exactly what you're asking. See the How to Ask page for help clarifying this question. If this question can be reworded to fit the rules in the help center, please edit the question.
1
$begingroup$
what are the variables of each sum?
$endgroup$
– Zachary Hunter
Jan 4 at 5:25
$begingroup$
i is the variable
$endgroup$
– Mobina K
Jan 4 at 5:26
$begingroup$
i is the variable for both?
$endgroup$
– Zachary Hunter
Jan 4 at 5:27
$begingroup$
also, I believe you can do this short double sum by hand, am I wrong?
$endgroup$
– Zachary Hunter
Jan 4 at 5:28
$begingroup$
Yes.i is the variable for both.i just need to check the answer
$endgroup$
– Mobina K
Jan 4 at 5:32
|
show 3 more comments
1
$begingroup$
what are the variables of each sum?
$endgroup$
– Zachary Hunter
Jan 4 at 5:25
$begingroup$
i is the variable
$endgroup$
– Mobina K
Jan 4 at 5:26
$begingroup$
i is the variable for both?
$endgroup$
– Zachary Hunter
Jan 4 at 5:27
$begingroup$
also, I believe you can do this short double sum by hand, am I wrong?
$endgroup$
– Zachary Hunter
Jan 4 at 5:28
$begingroup$
Yes.i is the variable for both.i just need to check the answer
$endgroup$
– Mobina K
Jan 4 at 5:32
1
1
$begingroup$
what are the variables of each sum?
$endgroup$
– Zachary Hunter
Jan 4 at 5:25
$begingroup$
what are the variables of each sum?
$endgroup$
– Zachary Hunter
Jan 4 at 5:25
$begingroup$
i is the variable
$endgroup$
– Mobina K
Jan 4 at 5:26
$begingroup$
i is the variable
$endgroup$
– Mobina K
Jan 4 at 5:26
$begingroup$
i is the variable for both?
$endgroup$
– Zachary Hunter
Jan 4 at 5:27
$begingroup$
i is the variable for both?
$endgroup$
– Zachary Hunter
Jan 4 at 5:27
$begingroup$
also, I believe you can do this short double sum by hand, am I wrong?
$endgroup$
– Zachary Hunter
Jan 4 at 5:28
$begingroup$
also, I believe you can do this short double sum by hand, am I wrong?
$endgroup$
– Zachary Hunter
Jan 4 at 5:28
$begingroup$
Yes.i is the variable for both.i just need to check the answer
$endgroup$
– Mobina K
Jan 4 at 5:32
$begingroup$
Yes.i is the variable for both.i just need to check the answer
$endgroup$
– Mobina K
Jan 4 at 5:32
|
show 3 more comments
1 Answer
1
active
oldest
votes
$begingroup$
Is this the correct expression?
$$sum_{i=1}^{4}sum_{i=1}^{4}i^2$$
If so this is equal to
$$sum_{i=1}^{4}(1^2+2^2+3^2+4^2) = sum_{i=1}^{4}30 = 120$$
answered Jan 4 at 6:05
Erik ParkinsonErik Parkinson
8549
$endgroup$
1
$begingroup$
You should start one of the sums with $j$ or another letter.
$endgroup$
– harshit54
Jan 4 at 6:12
$begingroup$
I agree, I was just trying to stick with the notation Mobina K was using.
$endgroup$
– Erik Parkinson
Jan 4 at 6:13
1
$begingroup$
Ok. I definitely think that the he/she misread the question.
$endgroup$
– harshit54
Jan 4 at 6:14
$begingroup$
Sticking to bad notations is a bad idea. Do not use the same variable twice.
$endgroup$
– Did
Jan 4 at 8:20
add a comment |
1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
$begingroup$
Is this the correct expression?
$$sum_{i=1}^{4}sum_{i=1}^{4}i^2$$
If so this is equal to
$$sum_{i=1}^{4}(1^2+2^2+3^2+4^2) = sum_{i=1}^{4}30 = 120$$
answered Jan 4 at 6:05
Erik ParkinsonErik Parkinson
8549
$endgroup$
1
$begingroup$
You should start one of the sums with $j$ or another letter.
$endgroup$
– harshit54
Jan 4 at 6:12
$begingroup$
I agree, I was just trying to stick with the notation Mobina K was using.
$endgroup$
– Erik Parkinson
Jan 4 at 6:13
1
$begingroup$
Ok. I definitely think that the he/she misread the question.
$endgroup$
– harshit54
Jan 4 at 6:14
$begingroup$
Sticking to bad notations is a bad idea. Do not use the same variable twice.
$endgroup$
– Did
Jan 4 at 8:20
add a comment |
$begingroup$
Is this the correct expression?
$$sum_{i=1}^{4}sum_{i=1}^{4}i^2$$
If so this is equal to
$$sum_{i=1}^{4}(1^2+2^2+3^2+4^2) = sum_{i=1}^{4}30 = 120$$
answered Jan 4 at 6:05
Erik ParkinsonErik Parkinson
8549
$endgroup$
1
$begingroup$
You should start one of the sums with $j$ or another letter.
$endgroup$
– harshit54
Jan 4 at 6:12
$begingroup$
I agree, I was just trying to stick with the notation Mobina K was using.
$endgroup$
– Erik Parkinson
Jan 4 at 6:13
1
$begingroup$
Ok. I definitely think that the he/she misread the question.
$endgroup$
– harshit54
Jan 4 at 6:14
$begingroup$
Sticking to bad notations is a bad idea. Do not use the same variable twice.
$endgroup$
– Did
Jan 4 at 8:20
add a comment |
$begingroup$
Is this the correct expression?
$$sum_{i=1}^{4}sum_{i=1}^{4}i^2$$
If so this is equal to
$$sum_{i=1}^{4}(1^2+2^2+3^2+4^2) = sum_{i=1}^{4}30 = 120$$
answered Jan 4 at 6:05
Erik ParkinsonErik Parkinson
8549
$endgroup$
Is this the correct expression?
$$sum_{i=1}^{4}sum_{i=1}^{4}i^2$$
If so this is equal to
$$sum_{i=1}^{4}(1^2+2^2+3^2+4^2) = sum_{i=1}^{4}30 = 120$$
answered Jan 4 at 6:05
Erik ParkinsonErik Parkinson
8549
answered Jan 4 at 6:05
Erik ParkinsonErik Parkinson
8549
answered Jan 4 at 6:05
Erik ParkinsonErik Parkinson
8549
answered Jan 4 at 6:05
Erik ParkinsonErik Parkinson
8549
8549
1
$begingroup$
You should start one of the sums with $j$ or another letter.
$endgroup$
– harshit54
Jan 4 at 6:12
$begingroup$
I agree, I was just trying to stick with the notation Mobina K was using.
$endgroup$
– Erik Parkinson
Jan 4 at 6:13
1
$begingroup$
Ok. I definitely think that the he/she misread the question.
$endgroup$
– harshit54
Jan 4 at 6:14
$begingroup$
Sticking to bad notations is a bad idea. Do not use the same variable twice.
$endgroup$
– Did
Jan 4 at 8:20
add a comment |
1
$begingroup$
You should start one of the sums with $j$ or another letter.
$endgroup$
– harshit54
Jan 4 at 6:12
$begingroup$
I agree, I was just trying to stick with the notation Mobina K was using.
$endgroup$
– Erik Parkinson
Jan 4 at 6:13
1
$begingroup$
Ok. I definitely think that the he/she misread the question.
$endgroup$
– harshit54
Jan 4 at 6:14
$begingroup$
Sticking to bad notations is a bad idea. Do not use the same variable twice.
$endgroup$
– Did
Jan 4 at 8:20
1
1
$begingroup$
You should start one of the sums with $j$ or another letter.
$endgroup$
– harshit54
Jan 4 at 6:12
$begingroup$
You should start one of the sums with $j$ or another letter.
$endgroup$
– harshit54
Jan 4 at 6:12
$begingroup$
I agree, I was just trying to stick with the notation Mobina K was using.
$endgroup$
– Erik Parkinson
Jan 4 at 6:13
$begingroup$
I agree, I was just trying to stick with the notation Mobina K was using.
$endgroup$
– Erik Parkinson
Jan 4 at 6:13
1
1
$begingroup$
Ok. I definitely think that the he/she misread the question.
$endgroup$
– harshit54
Jan 4 at 6:14
$begingroup$
Ok. I definitely think that the he/she misread the question.
$endgroup$
– harshit54
Jan 4 at 6:14
$begingroup$
Sticking to bad notations is a bad idea. Do not use the same variable twice.
$endgroup$
– Did
Jan 4 at 8:20
$begingroup$
Sticking to bad notations is a bad idea. Do not use the same variable twice.
$endgroup$
– Did
Jan 4 at 8:20
add a comment |
1
$begingroup$
what are the variables of each sum?
$endgroup$
– Zachary Hunter
Jan 4 at 5:25
$begingroup$
i is the variable
$endgroup$
– Mobina K
Jan 4 at 5:26
$begingroup$
i is the variable for both?
$endgroup$
– Zachary Hunter
Jan 4 at 5:27
$begingroup$
also, I believe you can do this short double sum by hand, am I wrong?
$endgroup$
– Zachary Hunter
Jan 4 at 5:28
$begingroup$
Yes.i is the variable for both.i just need to check the answer
$endgroup$
– Mobina K
Jan 4 at 5:32