Similarity and Difference between Separable Space and Separated space?












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Does separability and/or second countability implies $T_2$ or higher axiom sets?



My intuition is "no". Even $T_0$ space can be separability and/or second countability?










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    0














    Does separability and/or second countability implies $T_2$ or higher axiom sets?



    My intuition is "no". Even $T_0$ space can be separability and/or second countability?










    share|cite|improve this question



























      0












      0








      0







      Does separability and/or second countability implies $T_2$ or higher axiom sets?



      My intuition is "no". Even $T_0$ space can be separability and/or second countability?










      share|cite|improve this question















      Does separability and/or second countability implies $T_2$ or higher axiom sets?



      My intuition is "no". Even $T_0$ space can be separability and/or second countability?







      general-topology separation-axioms separable-spaces second-countable






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      edited Nov 20 '18 at 23:43









      Asaf Karagila

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      asked Nov 20 '18 at 22:17









      High GPA

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          No. Consider $X = {a,b}$ just two elements and $mathcal{T} = {emptyset, X}$. This is separable, second countable, and not even $T_0$.






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            1 Answer
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            1 Answer
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            active

            oldest

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            active

            oldest

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            2














            No. Consider $X = {a,b}$ just two elements and $mathcal{T} = {emptyset, X}$. This is separable, second countable, and not even $T_0$.






            share|cite|improve this answer


























              2














              No. Consider $X = {a,b}$ just two elements and $mathcal{T} = {emptyset, X}$. This is separable, second countable, and not even $T_0$.






              share|cite|improve this answer
























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                2








                2






                No. Consider $X = {a,b}$ just two elements and $mathcal{T} = {emptyset, X}$. This is separable, second countable, and not even $T_0$.






                share|cite|improve this answer












                No. Consider $X = {a,b}$ just two elements and $mathcal{T} = {emptyset, X}$. This is separable, second countable, and not even $T_0$.







                share|cite|improve this answer












                share|cite|improve this answer



                share|cite|improve this answer










                answered Nov 20 '18 at 22:25









                mathworker21

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