Mixing
Which Pointer (L or R) to Use for an Empty Binary Tree (Pseudocode)
My issue is not directly related to Python, but the pseudocode that our Python program must follow. The pseudocode creates an empty tree, but insists on using the left pointer (line highlighted in red), rather than the right pointer to connect nodes.
Does it matter if we connect node instances using left or right pointers?
class TreeNode(object):
def __init__(self, l, d, r):
self.LeftPointer = 0
self.Data = ""
self.RightPointer = 0
class Tree(object):
def __init__(self):
self.TreeArray =
for i in range(6):
NewNode = TreeNode(i+1, " ", None)
self.TreeArray.append(NewNode)
Does it really matter if I link the TreeNode instances with the right pointer ...
for i in range(6):
NewNode = TreeNode(None, " ", i+1)
self.TreeArray.append(NewNode)
Or is there a convention/rule that I'm not following?
python tree pseudocode
asked Nov 20 '18 at 8:00
Victor RodriguezVictor Rodriguez
121212
add a comment |
My issue is not directly related to Python, but the pseudocode that our Python program must follow. The pseudocode creates an empty tree, but insists on using the left pointer (line highlighted in red), rather than the right pointer to connect nodes.
Does it matter if we connect node instances using left or right pointers?
class TreeNode(object):
def __init__(self, l, d, r):
self.LeftPointer = 0
self.Data = ""
self.RightPointer = 0
class Tree(object):
def __init__(self):
self.TreeArray =
for i in range(6):
NewNode = TreeNode(i+1, " ", None)
self.TreeArray.append(NewNode)
Does it really matter if I link the TreeNode instances with the right pointer ...
for i in range(6):
NewNode = TreeNode(None, " ", i+1)
self.TreeArray.append(NewNode)
Or is there a convention/rule that I'm not following?
python tree pseudocode
asked Nov 20 '18 at 8:00
Victor RodriguezVictor Rodriguez
121212
It doesn't matter whether the free list is linked through the left or right pointer, so long as it's always the same one. Stick to the pseudocode – you've already deviated quite a bit from it.
– molbdnilo
Nov 20 '18 at 14:48
add a comment |
My issue is not directly related to Python, but the pseudocode that our Python program must follow. The pseudocode creates an empty tree, but insists on using the left pointer (line highlighted in red), rather than the right pointer to connect nodes.
Does it matter if we connect node instances using left or right pointers?
class TreeNode(object):
def __init__(self, l, d, r):
self.LeftPointer = 0
self.Data = ""
self.RightPointer = 0
class Tree(object):
def __init__(self):
self.TreeArray =
for i in range(6):
NewNode = TreeNode(i+1, " ", None)
self.TreeArray.append(NewNode)
Does it really matter if I link the TreeNode instances with the right pointer ...
for i in range(6):
NewNode = TreeNode(None, " ", i+1)
self.TreeArray.append(NewNode)
Or is there a convention/rule that I'm not following?
python tree pseudocode
asked Nov 20 '18 at 8:00
Victor RodriguezVictor Rodriguez
121212
My issue is not directly related to Python, but the pseudocode that our Python program must follow. The pseudocode creates an empty tree, but insists on using the left pointer (line highlighted in red), rather than the right pointer to connect nodes.
Does it matter if we connect node instances using left or right pointers?
class TreeNode(object):
def __init__(self, l, d, r):
self.LeftPointer = 0
self.Data = ""
self.RightPointer = 0
class Tree(object):
def __init__(self):
self.TreeArray =
for i in range(6):
NewNode = TreeNode(i+1, " ", None)
self.TreeArray.append(NewNode)
Does it really matter if I link the TreeNode instances with the right pointer ...
for i in range(6):
NewNode = TreeNode(None, " ", i+1)
self.TreeArray.append(NewNode)
Or is there a convention/rule that I'm not following?
python tree pseudocode
python tree pseudocode
asked Nov 20 '18 at 8:00
Victor RodriguezVictor Rodriguez
121212
asked Nov 20 '18 at 8:00
Victor RodriguezVictor Rodriguez
121212
edited Nov 20 '18 at 14:37
Victor Rodriguez
asked Nov 20 '18 at 8:00
Victor RodriguezVictor Rodriguez
121212
asked Nov 20 '18 at 8:00
Victor RodriguezVictor Rodriguez
121212
asked Nov 20 '18 at 8:00
Victor RodriguezVictor Rodriguez
121212
121212
It doesn't matter whether the free list is linked through the left or right pointer, so long as it's always the same one. Stick to the pseudocode – you've already deviated quite a bit from it.
– molbdnilo
Nov 20 '18 at 14:48
add a comment |
It doesn't matter whether the free list is linked through the left or right pointer, so long as it's always the same one. Stick to the pseudocode – you've already deviated quite a bit from it.
– molbdnilo
Nov 20 '18 at 14:48
It doesn't matter whether the free list is linked through the left or right pointer, so long as it's always the same one. Stick to the pseudocode – you've already deviated quite a bit from it.
– molbdnilo
Nov 20 '18 at 14:48
It doesn't matter whether the free list is linked through the left or right pointer, so long as it's always the same one. Stick to the pseudocode – you've already deviated quite a bit from it.
– molbdnilo
Nov 20 '18 at 14:48
add a comment |
0
active
oldest
votes
Your Answer
StackExchange.ifUsing("editor", function () {
StackExchange.using("externalEditor", function () {
StackExchange.using("snippets", function () {
StackExchange.snippets.init();
});
});
}, "code-snippets");
StackExchange.ready(function() {
var channelOptions = {
tags: "".split(" "),
id: "1"
};
initTagRenderer("".split(" "), "".split(" "), channelOptions);
StackExchange.using("externalEditor", function() {
// Have to fire editor after snippets, if snippets enabled
if (StackExchange.settings.snippets.snippetsEnabled) {
StackExchange.using("snippets", function() {
createEditor();
});
}
else {
createEditor();
}
});
function createEditor() {
StackExchange.prepareEditor({
heartbeatType: 'answer',
autoActivateHeartbeat: false,
convertImagesToLinks: true,
noModals: true,
showLowRepImageUploadWarning: true,
reputationToPostImages: 10,
bindNavPrevention: true,
postfix: "",
imageUploader: {
brandingHtml: "Powered by u003ca class="icon-imgur-white" href="https://imgur.com/"u003eu003c/au003e",
contentPolicyHtml: "User contributions licensed under u003ca href="https://creativecommons.org/licenses/by-sa/3.0/"u003ecc by-sa 3.0 with attribution requiredu003c/au003e u003ca href="https://stackoverflow.com/legal/content-policy"u003e(content policy)u003c/au003e",
allowUrls: true
},
onDemand: true,
discardSelector: ".discard-answer"
,immediatelyShowMarkdownHelp:true
});
}
});
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
StackExchange.ready(
function () {
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fstackoverflow.com%2fquestions%2f53388562%2fwhich-pointer-l-or-r-to-use-for-an-empty-binary-tree-pseudocode%23new-answer', 'question_page');
}
);
Post as a guest
Required, but never shown
0
active
oldest
votes
0
active
oldest
votes
active
oldest
votes
active
oldest
votes
Thanks for contributing an answer to Stack Overflow!
- Please be sure to answer the question. Provide details and share your research!
But avoid …
- Asking for help, clarification, or responding to other answers.
- Making statements based on opinion; back them up with references or personal experience.
To learn more, see our tips on writing great answers.
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
StackExchange.ready(
function () {
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fstackoverflow.com%2fquestions%2f53388562%2fwhich-pointer-l-or-r-to-use-for-an-empty-binary-tree-pseudocode%23new-answer', 'question_page');
}
);
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
It doesn't matter whether the free list is linked through the left or right pointer, so long as it's always the same one. Stick to the pseudocode – you've already deviated quite a bit from it.
– molbdnilo
Nov 20 '18 at 14:48