Let $z_1 = k + 1 + i(k − 1)$ and $z_2 = 2k − ik$ be to complex numbers, whats the value for $k$ if...
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Let $z_1 = k + 1 + i(k − 1)$ and $z_2 = 2k − ik$ be to complex numbers, whats the value for $k$ if $dfrac{z_1}{z_2} $is real number?
Answer is $dfrac13$, but I don't know how to solve it.
calculus analysis
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Let $z_1 = k + 1 + i(k − 1)$ and $z_2 = 2k − ik$ be to complex numbers, whats the value for $k$ if $dfrac{z_1}{z_2} $is real number?
Answer is $dfrac13$, but I don't know how to solve it.
calculus analysis
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Nadja is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
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just set imaginary part to zero
– phdmba7of12
yesterday
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Let $z_1 = k + 1 + i(k − 1)$ and $z_2 = 2k − ik$ be to complex numbers, whats the value for $k$ if $dfrac{z_1}{z_2} $is real number?
Answer is $dfrac13$, but I don't know how to solve it.
calculus analysis
New contributor
Nadja is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
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Let $z_1 = k + 1 + i(k − 1)$ and $z_2 = 2k − ik$ be to complex numbers, whats the value for $k$ if $dfrac{z_1}{z_2} $is real number?
Answer is $dfrac13$, but I don't know how to solve it.
calculus analysis
calculus analysis
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Nadja is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
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edited yesterday
Tianlalu
2,589632
2,589632
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asked yesterday


Nadja
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just set imaginary part to zero
– phdmba7of12
yesterday
add a comment |
just set imaginary part to zero
– phdmba7of12
yesterday
just set imaginary part to zero
– phdmba7of12
yesterday
just set imaginary part to zero
– phdmba7of12
yesterday
add a comment |
1 Answer
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HINT: Note that $frac{z_1}{z_2}=frac{z_1overline{z_2}}{|z_2|^2}$, and in the latter the denominator is a real number (if $k$ is real).
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1 Answer
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1 Answer
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oldest
votes
active
oldest
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active
oldest
votes
up vote
1
down vote
HINT: Note that $frac{z_1}{z_2}=frac{z_1overline{z_2}}{|z_2|^2}$, and in the latter the denominator is a real number (if $k$ is real).
add a comment |
up vote
1
down vote
HINT: Note that $frac{z_1}{z_2}=frac{z_1overline{z_2}}{|z_2|^2}$, and in the latter the denominator is a real number (if $k$ is real).
add a comment |
up vote
1
down vote
up vote
1
down vote
HINT: Note that $frac{z_1}{z_2}=frac{z_1overline{z_2}}{|z_2|^2}$, and in the latter the denominator is a real number (if $k$ is real).
HINT: Note that $frac{z_1}{z_2}=frac{z_1overline{z_2}}{|z_2|^2}$, and in the latter the denominator is a real number (if $k$ is real).
answered yesterday


Servaes
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20.6k33789
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just set imaginary part to zero
– phdmba7of12
yesterday