Let $z_1 = k + 1 + i(k − 1)$ and $z_2 = 2k − ik$ be to complex numbers, whats the value for $k$ if...
up vote
0
down vote
favorite
Let $z_1 = k + 1 + i(k − 1)$ and $z_2 = 2k − ik$ be to complex numbers, whats the value for $k$ if $dfrac{z_1}{z_2} $is real number?
Answer is $dfrac13$, but I don't know how to solve it.
calculus analysis
New contributor
add a comment |
up vote
0
down vote
favorite
Let $z_1 = k + 1 + i(k − 1)$ and $z_2 = 2k − ik$ be to complex numbers, whats the value for $k$ if $dfrac{z_1}{z_2} $is real number?
Answer is $dfrac13$, but I don't know how to solve it.
calculus analysis
New contributor
just set imaginary part to zero
– phdmba7of12
yesterday
add a comment |
up vote
0
down vote
favorite
up vote
0
down vote
favorite
Let $z_1 = k + 1 + i(k − 1)$ and $z_2 = 2k − ik$ be to complex numbers, whats the value for $k$ if $dfrac{z_1}{z_2} $is real number?
Answer is $dfrac13$, but I don't know how to solve it.
calculus analysis
New contributor
Let $z_1 = k + 1 + i(k − 1)$ and $z_2 = 2k − ik$ be to complex numbers, whats the value for $k$ if $dfrac{z_1}{z_2} $is real number?
Answer is $dfrac13$, but I don't know how to solve it.
calculus analysis
calculus analysis
New contributor
New contributor
edited yesterday
Tianlalu
2,589632
2,589632
New contributor
asked yesterday
Nadja
1
1
New contributor
New contributor
just set imaginary part to zero
– phdmba7of12
yesterday
add a comment |
just set imaginary part to zero
– phdmba7of12
yesterday
just set imaginary part to zero
– phdmba7of12
yesterday
just set imaginary part to zero
– phdmba7of12
yesterday
add a comment |
1 Answer
1
active
oldest
votes
up vote
1
down vote
HINT: Note that $frac{z_1}{z_2}=frac{z_1overline{z_2}}{|z_2|^2}$, and in the latter the denominator is a real number (if $k$ is real).
add a comment |
1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
up vote
1
down vote
HINT: Note that $frac{z_1}{z_2}=frac{z_1overline{z_2}}{|z_2|^2}$, and in the latter the denominator is a real number (if $k$ is real).
add a comment |
up vote
1
down vote
HINT: Note that $frac{z_1}{z_2}=frac{z_1overline{z_2}}{|z_2|^2}$, and in the latter the denominator is a real number (if $k$ is real).
add a comment |
up vote
1
down vote
up vote
1
down vote
HINT: Note that $frac{z_1}{z_2}=frac{z_1overline{z_2}}{|z_2|^2}$, and in the latter the denominator is a real number (if $k$ is real).
HINT: Note that $frac{z_1}{z_2}=frac{z_1overline{z_2}}{|z_2|^2}$, and in the latter the denominator is a real number (if $k$ is real).
answered yesterday
Servaes
20.6k33789
20.6k33789
add a comment |
add a comment |
Nadja is a new contributor. Be nice, and check out our Code of Conduct.
Nadja is a new contributor. Be nice, and check out our Code of Conduct.
Nadja is a new contributor. Be nice, and check out our Code of Conduct.
Nadja is a new contributor. Be nice, and check out our Code of Conduct.
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
StackExchange.ready(
function () {
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fmath.stackexchange.com%2fquestions%2f3005076%2flet-z-1-k-1-ik-%25e2%2588%2592-1-and-z-2-2k-%25e2%2588%2592-ik-be-to-complex-numbers-whats-th%23new-answer', 'question_page');
}
);
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
just set imaginary part to zero
– phdmba7of12
yesterday