Proof that geodesic distance is related to Euclidean distance between two vertices in a Tutte embedding?











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Say we have a Tutte embedding of a planar graph (that is, a graph whose positions in a plane are determined by 1. a set of outer vertices and 2. the rule that each interior vertex's position is the average of its geodesic neighbors'). If we choose any vertex $v_0$ in the interior of the embedding and another vertex $v_n$ whose geodesic distance (i.e. shortest path in terms of number of edges or hop count) from $v_0$ is $n$, does there exist some vertex $v_{n-1}$ located on one of the geodesic shortest paths to $v_n$ but at geodesic distance $n-1$ relative to $v_0$ that is also closer to $v_0$ in Euclidean distance?



My intuition suggests that this property is true looking at any Tutte embedding, but I am having difficulty nailing this all down as a proof and have not found any explicit explanation along these lines in the literature.



My progress so far has been realizing that anytime one tries to place a $v_n$ vertex closer to $v_0$ in Euclidean distance than $v_{n-1}$ this seems to create a concave structure, violating a basic property of the Tutte embedding. However I am not certain how to generalize beyond specific scenarios - it seems like some kind of inductive proof would be needed. Another observation is that the contours formed by connecting the points of a fixed geodesic distance around $v_0$ seem to never cross each other, instead forming beautiful concentric polygons.



The context of the problem is that I want to be able to make a mathematically grounded statement regarding what one can say about the Euclidean spatial relations of vertices given only topological/graph connectivity and stipulation that they lie in a Tutte embedding. As my title suggests, other proofs that accomplish this are also of interest to me.



In the attached image, I have identified some example origin points $v_0$ and drawn geodesic distance contours $n=1, 2$ around the two example points. The arrows indicate my attempt to locate points that break the rule, but in fact they never do - always a $v_n$ point is further away from $v_0$ in Euclidean distance than some point $v_{n-1}$ on the path even if not all.



Hope it is all clear, and thanks for your help.



Example Tutte Embedding with Reference Points and Geodesic Distance Denoted










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    Say we have a Tutte embedding of a planar graph (that is, a graph whose positions in a plane are determined by 1. a set of outer vertices and 2. the rule that each interior vertex's position is the average of its geodesic neighbors'). If we choose any vertex $v_0$ in the interior of the embedding and another vertex $v_n$ whose geodesic distance (i.e. shortest path in terms of number of edges or hop count) from $v_0$ is $n$, does there exist some vertex $v_{n-1}$ located on one of the geodesic shortest paths to $v_n$ but at geodesic distance $n-1$ relative to $v_0$ that is also closer to $v_0$ in Euclidean distance?



    My intuition suggests that this property is true looking at any Tutte embedding, but I am having difficulty nailing this all down as a proof and have not found any explicit explanation along these lines in the literature.



    My progress so far has been realizing that anytime one tries to place a $v_n$ vertex closer to $v_0$ in Euclidean distance than $v_{n-1}$ this seems to create a concave structure, violating a basic property of the Tutte embedding. However I am not certain how to generalize beyond specific scenarios - it seems like some kind of inductive proof would be needed. Another observation is that the contours formed by connecting the points of a fixed geodesic distance around $v_0$ seem to never cross each other, instead forming beautiful concentric polygons.



    The context of the problem is that I want to be able to make a mathematically grounded statement regarding what one can say about the Euclidean spatial relations of vertices given only topological/graph connectivity and stipulation that they lie in a Tutte embedding. As my title suggests, other proofs that accomplish this are also of interest to me.



    In the attached image, I have identified some example origin points $v_0$ and drawn geodesic distance contours $n=1, 2$ around the two example points. The arrows indicate my attempt to locate points that break the rule, but in fact they never do - always a $v_n$ point is further away from $v_0$ in Euclidean distance than some point $v_{n-1}$ on the path even if not all.



    Hope it is all clear, and thanks for your help.



    Example Tutte Embedding with Reference Points and Geodesic Distance Denoted










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      Say we have a Tutte embedding of a planar graph (that is, a graph whose positions in a plane are determined by 1. a set of outer vertices and 2. the rule that each interior vertex's position is the average of its geodesic neighbors'). If we choose any vertex $v_0$ in the interior of the embedding and another vertex $v_n$ whose geodesic distance (i.e. shortest path in terms of number of edges or hop count) from $v_0$ is $n$, does there exist some vertex $v_{n-1}$ located on one of the geodesic shortest paths to $v_n$ but at geodesic distance $n-1$ relative to $v_0$ that is also closer to $v_0$ in Euclidean distance?



      My intuition suggests that this property is true looking at any Tutte embedding, but I am having difficulty nailing this all down as a proof and have not found any explicit explanation along these lines in the literature.



      My progress so far has been realizing that anytime one tries to place a $v_n$ vertex closer to $v_0$ in Euclidean distance than $v_{n-1}$ this seems to create a concave structure, violating a basic property of the Tutte embedding. However I am not certain how to generalize beyond specific scenarios - it seems like some kind of inductive proof would be needed. Another observation is that the contours formed by connecting the points of a fixed geodesic distance around $v_0$ seem to never cross each other, instead forming beautiful concentric polygons.



      The context of the problem is that I want to be able to make a mathematically grounded statement regarding what one can say about the Euclidean spatial relations of vertices given only topological/graph connectivity and stipulation that they lie in a Tutte embedding. As my title suggests, other proofs that accomplish this are also of interest to me.



      In the attached image, I have identified some example origin points $v_0$ and drawn geodesic distance contours $n=1, 2$ around the two example points. The arrows indicate my attempt to locate points that break the rule, but in fact they never do - always a $v_n$ point is further away from $v_0$ in Euclidean distance than some point $v_{n-1}$ on the path even if not all.



      Hope it is all clear, and thanks for your help.



      Example Tutte Embedding with Reference Points and Geodesic Distance Denoted










      share|cite|improve this question









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      Entangler is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
      Check out our Code of Conduct.











      Say we have a Tutte embedding of a planar graph (that is, a graph whose positions in a plane are determined by 1. a set of outer vertices and 2. the rule that each interior vertex's position is the average of its geodesic neighbors'). If we choose any vertex $v_0$ in the interior of the embedding and another vertex $v_n$ whose geodesic distance (i.e. shortest path in terms of number of edges or hop count) from $v_0$ is $n$, does there exist some vertex $v_{n-1}$ located on one of the geodesic shortest paths to $v_n$ but at geodesic distance $n-1$ relative to $v_0$ that is also closer to $v_0$ in Euclidean distance?



      My intuition suggests that this property is true looking at any Tutte embedding, but I am having difficulty nailing this all down as a proof and have not found any explicit explanation along these lines in the literature.



      My progress so far has been realizing that anytime one tries to place a $v_n$ vertex closer to $v_0$ in Euclidean distance than $v_{n-1}$ this seems to create a concave structure, violating a basic property of the Tutte embedding. However I am not certain how to generalize beyond specific scenarios - it seems like some kind of inductive proof would be needed. Another observation is that the contours formed by connecting the points of a fixed geodesic distance around $v_0$ seem to never cross each other, instead forming beautiful concentric polygons.



      The context of the problem is that I want to be able to make a mathematically grounded statement regarding what one can say about the Euclidean spatial relations of vertices given only topological/graph connectivity and stipulation that they lie in a Tutte embedding. As my title suggests, other proofs that accomplish this are also of interest to me.



      In the attached image, I have identified some example origin points $v_0$ and drawn geodesic distance contours $n=1, 2$ around the two example points. The arrows indicate my attempt to locate points that break the rule, but in fact they never do - always a $v_n$ point is further away from $v_0$ in Euclidean distance than some point $v_{n-1}$ on the path even if not all.



      Hope it is all clear, and thanks for your help.



      Example Tutte Embedding with Reference Points and Geodesic Distance Denoted







      measure-theory graph-theory euclidean-geometry






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