xgboost in R: is it possibel to cross validation (xgb.cv) get the matrix contain with prediction and...











up vote
1
down vote

favorite












I recently used "xgb.cv" estimate the accuracy of xgboost. I found that the element pred can get the prediction value. I also want to get the corresponding observation value(test data), or a matrix contain with prediction and observation value, however, there was not a useful element or argument to achieve. Did I miss some details? Or is there other ways?



My code:



cv <- xgb.cv(data = x_DMatrix,     

                 max_depth = 3,        

                 nrounds = 10,         

                 nfold = 10,                  

                 prediction = TRUE,           

                 metrics = "rmse",           

                 objective ="reg:linear")    



cv$evaluation_log      # list of evaluation metrics

cv$pred                # get the pretiction value


The argument of "xgb.cv":



feval: custimized evaluation function. Returns list(metric='metric-name', value='metric-value') with given prediction and dtrain.



The help documentation is not specified. What is the mean and usage of feval?



I am searching on net but no match answer. Please help or try to give some ideas how to achieve this. Thanks in advance.






r prediction cross-validation xgboost







share|improve this question







New contributor




Lee is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.




















  • stackoverflow.com/questions/40159415/… can help you.
    – abhiieor
    9 hours ago















up vote
1
down vote

favorite












I recently used "xgb.cv" estimate the accuracy of xgboost. I found that the element pred can get the prediction value. I also want to get the corresponding observation value(test data), or a matrix contain with prediction and observation value, however, there was not a useful element or argument to achieve. Did I miss some details? Or is there other ways?



My code:



cv <- xgb.cv(data = x_DMatrix,     

                 max_depth = 3,        

                 nrounds = 10,         

                 nfold = 10,                  

                 prediction = TRUE,           

                 metrics = "rmse",           

                 objective ="reg:linear")    



cv$evaluation_log      # list of evaluation metrics

cv$pred                # get the pretiction value


The argument of "xgb.cv":



feval: custimized evaluation function. Returns list(metric='metric-name', value='metric-value') with given prediction and dtrain.



The help documentation is not specified. What is the mean and usage of feval?



I am searching on net but no match answer. Please help or try to give some ideas how to achieve this. Thanks in advance.






r prediction cross-validation xgboost







share|improve this question







New contributor




Lee is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.




















  • stackoverflow.com/questions/40159415/… can help you.
    – abhiieor
    9 hours ago













up vote
1
down vote

favorite









up vote
1
down vote

favorite











I recently used "xgb.cv" estimate the accuracy of xgboost. I found that the element pred can get the prediction value. I also want to get the corresponding observation value(test data), or a matrix contain with prediction and observation value, however, there was not a useful element or argument to achieve. Did I miss some details? Or is there other ways?



My code:



cv <- xgb.cv(data = x_DMatrix,     

                 max_depth = 3,        

                 nrounds = 10,         

                 nfold = 10,                  

                 prediction = TRUE,           

                 metrics = "rmse",           

                 objective ="reg:linear")    



cv$evaluation_log      # list of evaluation metrics

cv$pred                # get the pretiction value


The argument of "xgb.cv":



feval: custimized evaluation function. Returns list(metric='metric-name', value='metric-value') with given prediction and dtrain.



The help documentation is not specified. What is the mean and usage of feval?



I am searching on net but no match answer. Please help or try to give some ideas how to achieve this. Thanks in advance.






r prediction cross-validation xgboost







share|improve this question







New contributor




Lee is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.











I recently used "xgb.cv" estimate the accuracy of xgboost. I found that the element pred can get the prediction value. I also want to get the corresponding observation value(test data), or a matrix contain with prediction and observation value, however, there was not a useful element or argument to achieve. Did I miss some details? Or is there other ways?



My code:



cv <- xgb.cv(data = x_DMatrix,     

                 max_depth = 3,        

                 nrounds = 10,         

                 nfold = 10,                  

                 prediction = TRUE,           

                 metrics = "rmse",           

                 objective ="reg:linear")    



cv$evaluation_log      # list of evaluation metrics

cv$pred                # get the pretiction value


The argument of "xgb.cv":



feval: custimized evaluation function. Returns list(metric='metric-name', value='metric-value') with given prediction and dtrain.



The help documentation is not specified. What is the mean and usage of feval?



I am searching on net but no match answer. Please help or try to give some ideas how to achieve this. Thanks in advance.






r prediction cross-validation xgboost




r prediction cross-validation xgboost






share|improve this question







New contributor




Lee is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.











share|improve this question







New contributor




Lee is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.









share|improve this question




share|improve this question






New contributor




Lee is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.









asked 9 hours ago









Lee

61




61




New contributor




Lee is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.





New contributor





Lee is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.






Lee is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.












  • stackoverflow.com/questions/40159415/… can help you.
    – abhiieor
    9 hours ago


















  • stackoverflow.com/questions/40159415/… can help you.
    – abhiieor
    9 hours ago
















stackoverflow.com/questions/40159415/… can help you.
– abhiieor
9 hours ago




stackoverflow.com/questions/40159415/… can help you.
– abhiieor
9 hours ago

















active

oldest

votes











Your Answer






StackExchange.ifUsing("editor", function () {
StackExchange.using("externalEditor", function () {
StackExchange.using("snippets", function () {
StackExchange.snippets.init();
});
});
}, "code-snippets");

StackExchange.ready(function() {
var channelOptions = {
tags: "".split(" "),
id: "1"
};
initTagRenderer("".split(" "), "".split(" "), channelOptions);

StackExchange.using("externalEditor", function() {
// Have to fire editor after snippets, if snippets enabled
if (StackExchange.settings.snippets.snippetsEnabled) {
StackExchange.using("snippets", function() {
createEditor();
});
}
else {
createEditor();
}
});

function createEditor() {
StackExchange.prepareEditor({
heartbeatType: 'answer',
convertImagesToLinks: true,
noModals: true,
showLowRepImageUploadWarning: true,
reputationToPostImages: 10,
bindNavPrevention: true,
postfix: "",
imageUploader: {
brandingHtml: "Powered by u003ca class="icon-imgur-white" href="https://imgur.com/"u003eu003c/au003e",
contentPolicyHtml: "User contributions licensed under u003ca href="https://creativecommons.org/licenses/by-sa/3.0/"u003ecc by-sa 3.0 with attribution requiredu003c/au003e u003ca href="https://stackoverflow.com/legal/content-policy"u003e(content policy)u003c/au003e",
allowUrls: true
},
onDemand: true,
discardSelector: ".discard-answer"
,immediatelyShowMarkdownHelp:true
});


}
});






Lee is a new contributor. Be nice, and check out our Code of Conduct.










 

draft saved


draft discarded


















StackExchange.ready(
function () {
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fstackoverflow.com%2fquestions%2f53371759%2fxgboost-in-r-is-it-possibel-to-cross-validation-xgb-cv-get-the-matrix-contain%23new-answer', 'question_page');
}
);

Post as a guest















Required, but never shown






























active

oldest

votes













active

oldest

votes









active

oldest

votes






active

oldest

votes








Lee is a new contributor. Be nice, and check out our Code of Conduct.










 

draft saved


draft discarded


















Lee is a new contributor. Be nice, and check out our Code of Conduct.













Lee is a new contributor. Be nice, and check out our Code of Conduct.












Lee is a new contributor. Be nice, and check out our Code of Conduct.















 


draft saved


draft discarded














StackExchange.ready(
function () {
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fstackoverflow.com%2fquestions%2f53371759%2fxgboost-in-r-is-it-possibel-to-cross-validation-xgb-cv-get-the-matrix-contain%23new-answer', 'question_page');
}
);

Post as a guest















Required, but never shown





















































Required, but never shown














Required, but never shown












Required, but never shown







Required, but never shown

































Required, but never shown














Required, but never shown












Required, but never shown







Required, but never shown







Popular posts from this blog

Can a sorcerer learn a 5th-level spell early by creating spell slots using the Font of Magic feature?

Image
28 6 $begingroup$ Per the Font of Magic feature, sorcerer can use Flexible Casting to create 5th-level spell slots at level 7, even though they are not typically available until level 9. You can transform unexpended sorcery points into one spell slot as a bonus action on your turn. The Creating Spell Slots table shows the cost of creating a spell slot of [5th level is 7] If such a sorcerer levels up while still having this 5th-level spell slot, can they choose a 5th-level spell as the spell they gain upon levelling up? The Spellcasting feature states: Additionally, when you gain a level in this class, you can choose one of the sorcerer spells you know and replace it with another spell from the sorcerer spell list, which also must be of a level for which you have spell slots.
Read more

Does disintegrating a polymorphed enemy still kill it after the 2018 errata?

Image
up vote 13 down vote favorite 1 After the 2018 errata, the disintegrate spell description now reads: A creature targeted by this spell must make a Dexterity saving throw. On a failed save, the target takes 10d6 + 40 force damage. The target is disintegrated if this damage leaves it with 0 hit points. If you were to polymorph an enemy into a rat and then disintegrate it, would the enemy be disintegrated or would it just return to its original form? I know that for Druids, it’s not an instant kill anymore, but is this the case for polymorph as well? dnd-5e spells polymorph errata share | improve this question edited 18 hours ago
Read more

A Topological Invariant for $pi_3(U(n))$

Image
3 3 $begingroup$ Recently, I saw a construction of topological invariant for $pi_3(U(n))$ with $ngeq 2$ : $$ N=frac{1}{24pi^2}int_{S^3} d^3x epsilon^{ijk} Tr[(U^{-1}partial_{x_i}U)(U^{-1}partial_{x_j}U)(U^{-1}partial_{x_k}U)] , $$ where $Uin U(n)$ depends on $boldsymbol{x}=(x_1,x_2,x_3)in S^3$ , $epsilon^{ijk}$ is the Levi-Civita symbol, $i,j,k=1,2,3$ , and the duplicated indexes are summed over. It is claimed that $N$ is an integer, but why? Update 02/02/2019 I think I got an argument for $n=2$ . In this case, $U=e^{i varphi} q$ with $qin SU(2)$ . Due to the trace and the Levi-Civita symbol in $N$ , $varphi$ does not contribute to $N$ . As $Tr[q^{dagger}partial_i q]=0$ and $(q^{dagger}partial_i q)^{dagger}=-q^{dagger}partial_i q$ , $q^{dagger}partial_i q$ in geneeral has the form $q^{dagger}partia
Read more