Applying Green's formula











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I've been having some trouble proving this, so any help or suggestions would be great. Thanks in advance!





Show using a Green's formula that, for any $u in H^2(Omega)$ satisfying
$$u = frac{partial u}{partial n} = 0$$
we have
$$int_Omega |Delta u|^2 , dx , dy = int_Omega left[(u_{xx})^2 + (u_{yy})^2 - (u_{xy})^2 + (u_{yx})^2 right] , dx , dy$$





My first instinct is to use integration by parts on the left hand side, but I'm a little confused because it says $u in H^2(Omega)$, so doesn't that mean I can't have three derivatives on $u$?



By the way, we can assume that $Omega$ has sufficiently smooth boundary. Also, $frac{partial}{partial n}$ denotes differentiation in the outward normal direction to the boundary $Gamma$.










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    up vote
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    down vote

    favorite












    I've been having some trouble proving this, so any help or suggestions would be great. Thanks in advance!





    Show using a Green's formula that, for any $u in H^2(Omega)$ satisfying
    $$u = frac{partial u}{partial n} = 0$$
    we have
    $$int_Omega |Delta u|^2 , dx , dy = int_Omega left[(u_{xx})^2 + (u_{yy})^2 - (u_{xy})^2 + (u_{yx})^2 right] , dx , dy$$





    My first instinct is to use integration by parts on the left hand side, but I'm a little confused because it says $u in H^2(Omega)$, so doesn't that mean I can't have three derivatives on $u$?



    By the way, we can assume that $Omega$ has sufficiently smooth boundary. Also, $frac{partial}{partial n}$ denotes differentiation in the outward normal direction to the boundary $Gamma$.










    share|cite|improve this question
























      up vote
      1
      down vote

      favorite









      up vote
      1
      down vote

      favorite











      I've been having some trouble proving this, so any help or suggestions would be great. Thanks in advance!





      Show using a Green's formula that, for any $u in H^2(Omega)$ satisfying
      $$u = frac{partial u}{partial n} = 0$$
      we have
      $$int_Omega |Delta u|^2 , dx , dy = int_Omega left[(u_{xx})^2 + (u_{yy})^2 - (u_{xy})^2 + (u_{yx})^2 right] , dx , dy$$





      My first instinct is to use integration by parts on the left hand side, but I'm a little confused because it says $u in H^2(Omega)$, so doesn't that mean I can't have three derivatives on $u$?



      By the way, we can assume that $Omega$ has sufficiently smooth boundary. Also, $frac{partial}{partial n}$ denotes differentiation in the outward normal direction to the boundary $Gamma$.










      share|cite|improve this question













      I've been having some trouble proving this, so any help or suggestions would be great. Thanks in advance!





      Show using a Green's formula that, for any $u in H^2(Omega)$ satisfying
      $$u = frac{partial u}{partial n} = 0$$
      we have
      $$int_Omega |Delta u|^2 , dx , dy = int_Omega left[(u_{xx})^2 + (u_{yy})^2 - (u_{xy})^2 + (u_{yx})^2 right] , dx , dy$$





      My first instinct is to use integration by parts on the left hand side, but I'm a little confused because it says $u in H^2(Omega)$, so doesn't that mean I can't have three derivatives on $u$?



      By the way, we can assume that $Omega$ has sufficiently smooth boundary. Also, $frac{partial}{partial n}$ denotes differentiation in the outward normal direction to the boundary $Gamma$.







      multivariable-calculus






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      asked Aug 16 '14 at 21:21









      EpicMochi

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