Predicate logic, substitution when using resolutionmethod











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Formulae F = p(x) ∧ (q(y) ∨ r(z))
substitution = {x := a, y := f(z), z := g(b)}



This example is from a course am having right now. I dont know what I am missing
but can someone explain why y and z are substituted by a function (f(z), g(b)) while x is substituted with a constant (a)?
I cant find the reason in the book, on the recorded lecture or on the classforums, so I guess its really obvious.



Really greatfull for input
/Jonatan






substitution







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    up vote
    0
    down vote

    favorite












    Formulae F = p(x) ∧ (q(y) ∨ r(z))
    substitution = {x := a, y := f(z), z := g(b)}



    This example is from a course am having right now. I dont know what I am missing
    but can someone explain why y and z are substituted by a function (f(z), g(b)) while x is substituted with a constant (a)?
    I cant find the reason in the book, on the recorded lecture or on the classforums, so I guess its really obvious.



    Really greatfull for input
    /Jonatan






    substitution







    share|cite|improve this question







    New contributor




    Jonatan Helenason is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
    Check out our Code of Conduct.






















      up vote
      0
      down vote

      favorite









      up vote
      0
      down vote

      favorite











      Formulae F = p(x) ∧ (q(y) ∨ r(z))
      substitution = {x := a, y := f(z), z := g(b)}



      This example is from a course am having right now. I dont know what I am missing
      but can someone explain why y and z are substituted by a function (f(z), g(b)) while x is substituted with a constant (a)?
      I cant find the reason in the book, on the recorded lecture or on the classforums, so I guess its really obvious.



      Really greatfull for input
      /Jonatan






      substitution







      share|cite|improve this question







      New contributor




      Jonatan Helenason is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
      Check out our Code of Conduct.











      Formulae F = p(x) ∧ (q(y) ∨ r(z))
      substitution = {x := a, y := f(z), z := g(b)}



      This example is from a course am having right now. I dont know what I am missing
      but can someone explain why y and z are substituted by a function (f(z), g(b)) while x is substituted with a constant (a)?
      I cant find the reason in the book, on the recorded lecture or on the classforums, so I guess its really obvious.



      Really greatfull for input
      /Jonatan






      substitution




      substitution






      share|cite|improve this question







      New contributor




      Jonatan Helenason is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
      Check out our Code of Conduct.











      share|cite|improve this question







      New contributor




      Jonatan Helenason is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
      Check out our Code of Conduct.









      share|cite|improve this question




      share|cite|improve this question






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