Generate hash from chunked file











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I'm programming a web service for uploading long files. The client sends the chunks whenever it wants. I need to calculate the hash of this file while theese chunks are received.



I've seen that you can do somenthing like this:



byte buf = new byte[8192];
MessageDigest sha = MessageDigest.getInstance("SHA1");

FileInputStream inp = new FileInputStream(new File("D:\season4_mlp.rar"));

int n;
while((n = inp.read(buf)) > 0)
sha.update(buf, 0, n);

byte hash = sha.digest();


The problem is that I need to do this with different chunks of the same file and I don't know when they are going to come. I would need to keep the state of this hash calculation.










share|improve this question
























  • The code you posted doesn't require BouncyCastle, and unless you've jiggered your provider list doesn't use it at all. But if you mean you want to hash the data chunks out of order, you can't do that, not with JCE nor with BC LWAPI, because that's altering the data which is exactly what any decent crypto-hash and even SHA1 is designed to prevent.
    – dave_thompson_085
    yesterday










  • I will work the hash out using the chunks in order. The question it's been edited for better undestanding... In the example I have MessageDigest sha that it's used to generate the final hash. The point is that there is a gap between one chunk and the next one and so I have to keep the state of MessageDigest sha until I have all the data and then I can do byte hash = sha.digest();
    – Enrique de Miguel
    yesterday








  • 1




    The MessageDigest objects retains all the necessary state. That's why there's an update() method.
    – James K Polk
    yesterday















up vote
0
down vote

favorite












I'm programming a web service for uploading long files. The client sends the chunks whenever it wants. I need to calculate the hash of this file while theese chunks are received.



I've seen that you can do somenthing like this:



byte buf = new byte[8192];
MessageDigest sha = MessageDigest.getInstance("SHA1");

FileInputStream inp = new FileInputStream(new File("D:\season4_mlp.rar"));

int n;
while((n = inp.read(buf)) > 0)
sha.update(buf, 0, n);

byte hash = sha.digest();


The problem is that I need to do this with different chunks of the same file and I don't know when they are going to come. I would need to keep the state of this hash calculation.










share|improve this question
























  • The code you posted doesn't require BouncyCastle, and unless you've jiggered your provider list doesn't use it at all. But if you mean you want to hash the data chunks out of order, you can't do that, not with JCE nor with BC LWAPI, because that's altering the data which is exactly what any decent crypto-hash and even SHA1 is designed to prevent.
    – dave_thompson_085
    yesterday










  • I will work the hash out using the chunks in order. The question it's been edited for better undestanding... In the example I have MessageDigest sha that it's used to generate the final hash. The point is that there is a gap between one chunk and the next one and so I have to keep the state of MessageDigest sha until I have all the data and then I can do byte hash = sha.digest();
    – Enrique de Miguel
    yesterday








  • 1




    The MessageDigest objects retains all the necessary state. That's why there's an update() method.
    – James K Polk
    yesterday













up vote
0
down vote

favorite









up vote
0
down vote

favorite











I'm programming a web service for uploading long files. The client sends the chunks whenever it wants. I need to calculate the hash of this file while theese chunks are received.



I've seen that you can do somenthing like this:



byte buf = new byte[8192];
MessageDigest sha = MessageDigest.getInstance("SHA1");

FileInputStream inp = new FileInputStream(new File("D:\season4_mlp.rar"));

int n;
while((n = inp.read(buf)) > 0)
sha.update(buf, 0, n);

byte hash = sha.digest();


The problem is that I need to do this with different chunks of the same file and I don't know when they are going to come. I would need to keep the state of this hash calculation.










share|improve this question















I'm programming a web service for uploading long files. The client sends the chunks whenever it wants. I need to calculate the hash of this file while theese chunks are received.



I've seen that you can do somenthing like this:



byte buf = new byte[8192];
MessageDigest sha = MessageDigest.getInstance("SHA1");

FileInputStream inp = new FileInputStream(new File("D:\season4_mlp.rar"));

int n;
while((n = inp.read(buf)) > 0)
sha.update(buf, 0, n);

byte hash = sha.digest();


The problem is that I need to do this with different chunks of the same file and I don't know when they are going to come. I would need to keep the state of this hash calculation.







java hash cryptography bouncycastle message-digest






share|improve this question















share|improve this question













share|improve this question




share|improve this question








edited yesterday

























asked yesterday









Enrique de Miguel

11819




11819












  • The code you posted doesn't require BouncyCastle, and unless you've jiggered your provider list doesn't use it at all. But if you mean you want to hash the data chunks out of order, you can't do that, not with JCE nor with BC LWAPI, because that's altering the data which is exactly what any decent crypto-hash and even SHA1 is designed to prevent.
    – dave_thompson_085
    yesterday










  • I will work the hash out using the chunks in order. The question it's been edited for better undestanding... In the example I have MessageDigest sha that it's used to generate the final hash. The point is that there is a gap between one chunk and the next one and so I have to keep the state of MessageDigest sha until I have all the data and then I can do byte hash = sha.digest();
    – Enrique de Miguel
    yesterday








  • 1




    The MessageDigest objects retains all the necessary state. That's why there's an update() method.
    – James K Polk
    yesterday


















  • The code you posted doesn't require BouncyCastle, and unless you've jiggered your provider list doesn't use it at all. But if you mean you want to hash the data chunks out of order, you can't do that, not with JCE nor with BC LWAPI, because that's altering the data which is exactly what any decent crypto-hash and even SHA1 is designed to prevent.
    – dave_thompson_085
    yesterday










  • I will work the hash out using the chunks in order. The question it's been edited for better undestanding... In the example I have MessageDigest sha that it's used to generate the final hash. The point is that there is a gap between one chunk and the next one and so I have to keep the state of MessageDigest sha until I have all the data and then I can do byte hash = sha.digest();
    – Enrique de Miguel
    yesterday








  • 1




    The MessageDigest objects retains all the necessary state. That's why there's an update() method.
    – James K Polk
    yesterday
















The code you posted doesn't require BouncyCastle, and unless you've jiggered your provider list doesn't use it at all. But if you mean you want to hash the data chunks out of order, you can't do that, not with JCE nor with BC LWAPI, because that's altering the data which is exactly what any decent crypto-hash and even SHA1 is designed to prevent.
– dave_thompson_085
yesterday




The code you posted doesn't require BouncyCastle, and unless you've jiggered your provider list doesn't use it at all. But if you mean you want to hash the data chunks out of order, you can't do that, not with JCE nor with BC LWAPI, because that's altering the data which is exactly what any decent crypto-hash and even SHA1 is designed to prevent.
– dave_thompson_085
yesterday












I will work the hash out using the chunks in order. The question it's been edited for better undestanding... In the example I have MessageDigest sha that it's used to generate the final hash. The point is that there is a gap between one chunk and the next one and so I have to keep the state of MessageDigest sha until I have all the data and then I can do byte hash = sha.digest();
– Enrique de Miguel
yesterday






I will work the hash out using the chunks in order. The question it's been edited for better undestanding... In the example I have MessageDigest sha that it's used to generate the final hash. The point is that there is a gap between one chunk and the next one and so I have to keep the state of MessageDigest sha until I have all the data and then I can do byte hash = sha.digest();
– Enrique de Miguel
yesterday






1




1




The MessageDigest objects retains all the necessary state. That's why there's an update() method.
– James K Polk
yesterday




The MessageDigest objects retains all the necessary state. That's why there's an update() method.
– James K Polk
yesterday

















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