how can i find the position of maximum value in this code [on hold]











up vote
0
down vote

favorite












I wrote this code but i do not know how can i wrote the code gets the position of maximum value. Actually i am beginner and i do not know arrays and methods completely.



package findposition;

import java.util.Scanner;

public class findposition {

public static void main(String args) {
Scanner input=new Scanner(System.in);

int counter, max = 0, num = 0;
counter = 1;

while (counter<=10) {

System.out.println("Enter the " + counter + ". number:");
num=input.nextInt();
counter++;
}

max = Math.max(num, max);
System.out.printf("Maximum value is %d", max);

}
}









share|improve this question









New contributor




Sena is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.











put on hold as too broad by Seelenvirtuose, Owen Pauling, greg-449, Umair, GhostCat yesterday


Please edit the question to limit it to a specific problem with enough detail to identify an adequate answer. Avoid asking multiple distinct questions at once. See the How to Ask page for help clarifying this question. If this question can be reworded to fit the rules in the help center, please edit the question.











  • 2




    Java !== Javascript!
    – Nina Scholz
    yesterday










  • Maximum position where exactly? You don't save all entered numbers so there isn't really any position to find. Also note that because you don't save all numbers entered and only ever save the last entered number your Maximum value will always be the last entered number (or 0 if it is negative)
    – OH GOD SPIDERS
    yesterday








  • 1




    It might be helpful to go through each line of your program and add a comment detailing EXACTLY what you think that line does. Your code isn't unsalvageable, but it's rather clear that (as you admitted yourself) you don't quite understand a few key concepts to make this work
    – Jeroen Steenbeeke
    yesterday










  • @NinaScholz i know but thank you
    – Sena
    yesterday










  • @OHGODSPIDERS thank you
    – Sena
    yesterday















up vote
0
down vote

favorite












I wrote this code but i do not know how can i wrote the code gets the position of maximum value. Actually i am beginner and i do not know arrays and methods completely.



package findposition;

import java.util.Scanner;

public class findposition {

public static void main(String args) {
Scanner input=new Scanner(System.in);

int counter, max = 0, num = 0;
counter = 1;

while (counter<=10) {

System.out.println("Enter the " + counter + ". number:");
num=input.nextInt();
counter++;
}

max = Math.max(num, max);
System.out.printf("Maximum value is %d", max);

}
}









share|improve this question









New contributor




Sena is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.











put on hold as too broad by Seelenvirtuose, Owen Pauling, greg-449, Umair, GhostCat yesterday


Please edit the question to limit it to a specific problem with enough detail to identify an adequate answer. Avoid asking multiple distinct questions at once. See the How to Ask page for help clarifying this question. If this question can be reworded to fit the rules in the help center, please edit the question.











  • 2




    Java !== Javascript!
    – Nina Scholz
    yesterday










  • Maximum position where exactly? You don't save all entered numbers so there isn't really any position to find. Also note that because you don't save all numbers entered and only ever save the last entered number your Maximum value will always be the last entered number (or 0 if it is negative)
    – OH GOD SPIDERS
    yesterday








  • 1




    It might be helpful to go through each line of your program and add a comment detailing EXACTLY what you think that line does. Your code isn't unsalvageable, but it's rather clear that (as you admitted yourself) you don't quite understand a few key concepts to make this work
    – Jeroen Steenbeeke
    yesterday










  • @NinaScholz i know but thank you
    – Sena
    yesterday










  • @OHGODSPIDERS thank you
    – Sena
    yesterday













up vote
0
down vote

favorite









up vote
0
down vote

favorite











I wrote this code but i do not know how can i wrote the code gets the position of maximum value. Actually i am beginner and i do not know arrays and methods completely.



package findposition;

import java.util.Scanner;

public class findposition {

public static void main(String args) {
Scanner input=new Scanner(System.in);

int counter, max = 0, num = 0;
counter = 1;

while (counter<=10) {

System.out.println("Enter the " + counter + ". number:");
num=input.nextInt();
counter++;
}

max = Math.max(num, max);
System.out.printf("Maximum value is %d", max);

}
}









share|improve this question









New contributor




Sena is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.











I wrote this code but i do not know how can i wrote the code gets the position of maximum value. Actually i am beginner and i do not know arrays and methods completely.



package findposition;

import java.util.Scanner;

public class findposition {

public static void main(String args) {
Scanner input=new Scanner(System.in);

int counter, max = 0, num = 0;
counter = 1;

while (counter<=10) {

System.out.println("Enter the " + counter + ". number:");
num=input.nextInt();
counter++;
}

max = Math.max(num, max);
System.out.printf("Maximum value is %d", max);

}
}






java arrays indexing position






share|improve this question









New contributor




Sena is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.











share|improve this question









New contributor




Sena is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.









share|improve this question




share|improve this question








edited yesterday









Jérôme Teisseire

9721819




9721819






New contributor




Sena is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.









asked yesterday









Sena

61




61




New contributor




Sena is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.





New contributor





Sena is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.






Sena is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.




put on hold as too broad by Seelenvirtuose, Owen Pauling, greg-449, Umair, GhostCat yesterday


Please edit the question to limit it to a specific problem with enough detail to identify an adequate answer. Avoid asking multiple distinct questions at once. See the How to Ask page for help clarifying this question. If this question can be reworded to fit the rules in the help center, please edit the question.






put on hold as too broad by Seelenvirtuose, Owen Pauling, greg-449, Umair, GhostCat yesterday


Please edit the question to limit it to a specific problem with enough detail to identify an adequate answer. Avoid asking multiple distinct questions at once. See the How to Ask page for help clarifying this question. If this question can be reworded to fit the rules in the help center, please edit the question.










  • 2




    Java !== Javascript!
    – Nina Scholz
    yesterday










  • Maximum position where exactly? You don't save all entered numbers so there isn't really any position to find. Also note that because you don't save all numbers entered and only ever save the last entered number your Maximum value will always be the last entered number (or 0 if it is negative)
    – OH GOD SPIDERS
    yesterday








  • 1




    It might be helpful to go through each line of your program and add a comment detailing EXACTLY what you think that line does. Your code isn't unsalvageable, but it's rather clear that (as you admitted yourself) you don't quite understand a few key concepts to make this work
    – Jeroen Steenbeeke
    yesterday










  • @NinaScholz i know but thank you
    – Sena
    yesterday










  • @OHGODSPIDERS thank you
    – Sena
    yesterday














  • 2




    Java !== Javascript!
    – Nina Scholz
    yesterday










  • Maximum position where exactly? You don't save all entered numbers so there isn't really any position to find. Also note that because you don't save all numbers entered and only ever save the last entered number your Maximum value will always be the last entered number (or 0 if it is negative)
    – OH GOD SPIDERS
    yesterday








  • 1




    It might be helpful to go through each line of your program and add a comment detailing EXACTLY what you think that line does. Your code isn't unsalvageable, but it's rather clear that (as you admitted yourself) you don't quite understand a few key concepts to make this work
    – Jeroen Steenbeeke
    yesterday










  • @NinaScholz i know but thank you
    – Sena
    yesterday










  • @OHGODSPIDERS thank you
    – Sena
    yesterday








2




2




Java !== Javascript!
– Nina Scholz
yesterday




Java !== Javascript!
– Nina Scholz
yesterday












Maximum position where exactly? You don't save all entered numbers so there isn't really any position to find. Also note that because you don't save all numbers entered and only ever save the last entered number your Maximum value will always be the last entered number (or 0 if it is negative)
– OH GOD SPIDERS
yesterday






Maximum position where exactly? You don't save all entered numbers so there isn't really any position to find. Also note that because you don't save all numbers entered and only ever save the last entered number your Maximum value will always be the last entered number (or 0 if it is negative)
– OH GOD SPIDERS
yesterday






1




1




It might be helpful to go through each line of your program and add a comment detailing EXACTLY what you think that line does. Your code isn't unsalvageable, but it's rather clear that (as you admitted yourself) you don't quite understand a few key concepts to make this work
– Jeroen Steenbeeke
yesterday




It might be helpful to go through each line of your program and add a comment detailing EXACTLY what you think that line does. Your code isn't unsalvageable, but it's rather clear that (as you admitted yourself) you don't quite understand a few key concepts to make this work
– Jeroen Steenbeeke
yesterday












@NinaScholz i know but thank you
– Sena
yesterday




@NinaScholz i know but thank you
– Sena
yesterday












@OHGODSPIDERS thank you
– Sena
yesterday




@OHGODSPIDERS thank you
– Sena
yesterday












2 Answers
2






active

oldest

votes

















up vote
0
down vote













You would need something like this:



public int getIndexOfMaxValue( int array )
{
int maxIndex = 0;
for ( int i = 1; i < array.length; i++ )
{
if ( array[i] > array[maxIndex] ) maxIndex = i;
}
return maxIndex;
}


In order to use the code from above you could try the following:



public static void main(String args) 
{

int a = new int { 12, 44, 23, 56, 23, 78, 13 };
int maxIndex = getIndexOfMaxValue(a);

System.out.println("Index position of Maximum value in an array is : " + maxIndex );
}





share|improve this answer










New contributor




Andrea Calin is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.














  • 2




    Considering that the poster stated a lack of understanding of arrays, you might want to include a bit about how to glue it together.
    – Jeroen Steenbeeke
    yesterday










  • Thanks for the idea. I have updated my answer.
    – Andrea Calin
    yesterday










  • thank you Andrea @AndreaCalin
    – Sena
    yesterday


















up vote
0
down vote













Though its a simple code, You have to learn that from your logic. you can follow this



import java.util.Scanner;

public class App {
public static void main(String args) {
Scanner input=new Scanner(System.in);
//dont need to instantiate that if you declare void findMax(int arrayOfnum) static
App app = new App();
int counter;
counter=1;

System.out.println("Enter how many number you want to take :");
int total=input.nextInt();
int arrayOfnum = new int[total];
//taking input on a array
while (counter<=total) {

System.out.println("Enter the "+counter+". number:");
arrayOfnum[counter]=input.nextInt();
counter++;
}
//method call
app.findMax(arrayOfnum);
}

private void findMax(int arrayOfnum) {
int num=0,max=0,pos=0;
for(int i=0;i<arrayOfnum.length;i++)
{
if(arrayOfnum[i]>max)
{
max = arrayOfnum[i];
pos = i;
}
}
System.out.printf("Maximum value is %d and position is %d",max,pos+1);
}
}


Here arrayOfnum is a one dimensional array whereyou can keep numbers that you take as input and then using private void findMax(int arrayOfnum) method you can find maximum value and position. I didnot return nothing from this method but if you want to return something from this method like you want to return position then you have to declare return type like private int findMax(int arrayOfnum) . and then implementation will be like this.



private  int findMax(int arrayOfnum) {
int num=0,max=0,pos=0;
for(int i=0;i<arrayOfnum.length;i++)
{
if(arrayOfnum[i]>max)
{
max = arrayOfnum[i];
pos = i;
}
}
System.out.printf("Maximum value is %d and position is %d",max,pos+1);
return (pos+1);
}


You can make this method like public, protected etc. which is called access modifier.



If you declare this method as static then you do not need to create App app = new App(); instance in main method. You can directly access static method from main method like this findMax(arrayOfnum); instead of app.findMax(arrayOfnum); . Because main method is static. you can not access non-static variables from a static context. JVM keep main method is static by default.



NB: Try to learn highlighted terms from internet.






share|improve this answer























  • thank you for your answer @flopcoder
    – Sena
    yesterday


















2 Answers
2






active

oldest

votes








2 Answers
2






active

oldest

votes









active

oldest

votes






active

oldest

votes








up vote
0
down vote













You would need something like this:



public int getIndexOfMaxValue( int array )
{
int maxIndex = 0;
for ( int i = 1; i < array.length; i++ )
{
if ( array[i] > array[maxIndex] ) maxIndex = i;
}
return maxIndex;
}


In order to use the code from above you could try the following:



public static void main(String args) 
{

int a = new int { 12, 44, 23, 56, 23, 78, 13 };
int maxIndex = getIndexOfMaxValue(a);

System.out.println("Index position of Maximum value in an array is : " + maxIndex );
}





share|improve this answer










New contributor




Andrea Calin is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.














  • 2




    Considering that the poster stated a lack of understanding of arrays, you might want to include a bit about how to glue it together.
    – Jeroen Steenbeeke
    yesterday










  • Thanks for the idea. I have updated my answer.
    – Andrea Calin
    yesterday










  • thank you Andrea @AndreaCalin
    – Sena
    yesterday















up vote
0
down vote













You would need something like this:



public int getIndexOfMaxValue( int array )
{
int maxIndex = 0;
for ( int i = 1; i < array.length; i++ )
{
if ( array[i] > array[maxIndex] ) maxIndex = i;
}
return maxIndex;
}


In order to use the code from above you could try the following:



public static void main(String args) 
{

int a = new int { 12, 44, 23, 56, 23, 78, 13 };
int maxIndex = getIndexOfMaxValue(a);

System.out.println("Index position of Maximum value in an array is : " + maxIndex );
}





share|improve this answer










New contributor




Andrea Calin is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.














  • 2




    Considering that the poster stated a lack of understanding of arrays, you might want to include a bit about how to glue it together.
    – Jeroen Steenbeeke
    yesterday










  • Thanks for the idea. I have updated my answer.
    – Andrea Calin
    yesterday










  • thank you Andrea @AndreaCalin
    – Sena
    yesterday













up vote
0
down vote










up vote
0
down vote









You would need something like this:



public int getIndexOfMaxValue( int array )
{
int maxIndex = 0;
for ( int i = 1; i < array.length; i++ )
{
if ( array[i] > array[maxIndex] ) maxIndex = i;
}
return maxIndex;
}


In order to use the code from above you could try the following:



public static void main(String args) 
{

int a = new int { 12, 44, 23, 56, 23, 78, 13 };
int maxIndex = getIndexOfMaxValue(a);

System.out.println("Index position of Maximum value in an array is : " + maxIndex );
}





share|improve this answer










New contributor




Andrea Calin is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.









You would need something like this:



public int getIndexOfMaxValue( int array )
{
int maxIndex = 0;
for ( int i = 1; i < array.length; i++ )
{
if ( array[i] > array[maxIndex] ) maxIndex = i;
}
return maxIndex;
}


In order to use the code from above you could try the following:



public static void main(String args) 
{

int a = new int { 12, 44, 23, 56, 23, 78, 13 };
int maxIndex = getIndexOfMaxValue(a);

System.out.println("Index position of Maximum value in an array is : " + maxIndex );
}






share|improve this answer










New contributor




Andrea Calin is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.









share|improve this answer



share|improve this answer








edited yesterday





















New contributor




Andrea Calin is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.









answered yesterday









Andrea Calin

895




895




New contributor




Andrea Calin is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.





New contributor





Andrea Calin is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.






Andrea Calin is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.








  • 2




    Considering that the poster stated a lack of understanding of arrays, you might want to include a bit about how to glue it together.
    – Jeroen Steenbeeke
    yesterday










  • Thanks for the idea. I have updated my answer.
    – Andrea Calin
    yesterday










  • thank you Andrea @AndreaCalin
    – Sena
    yesterday














  • 2




    Considering that the poster stated a lack of understanding of arrays, you might want to include a bit about how to glue it together.
    – Jeroen Steenbeeke
    yesterday










  • Thanks for the idea. I have updated my answer.
    – Andrea Calin
    yesterday










  • thank you Andrea @AndreaCalin
    – Sena
    yesterday








2




2




Considering that the poster stated a lack of understanding of arrays, you might want to include a bit about how to glue it together.
– Jeroen Steenbeeke
yesterday




Considering that the poster stated a lack of understanding of arrays, you might want to include a bit about how to glue it together.
– Jeroen Steenbeeke
yesterday












Thanks for the idea. I have updated my answer.
– Andrea Calin
yesterday




Thanks for the idea. I have updated my answer.
– Andrea Calin
yesterday












thank you Andrea @AndreaCalin
– Sena
yesterday




thank you Andrea @AndreaCalin
– Sena
yesterday












up vote
0
down vote













Though its a simple code, You have to learn that from your logic. you can follow this



import java.util.Scanner;

public class App {
public static void main(String args) {
Scanner input=new Scanner(System.in);
//dont need to instantiate that if you declare void findMax(int arrayOfnum) static
App app = new App();
int counter;
counter=1;

System.out.println("Enter how many number you want to take :");
int total=input.nextInt();
int arrayOfnum = new int[total];
//taking input on a array
while (counter<=total) {

System.out.println("Enter the "+counter+". number:");
arrayOfnum[counter]=input.nextInt();
counter++;
}
//method call
app.findMax(arrayOfnum);
}

private void findMax(int arrayOfnum) {
int num=0,max=0,pos=0;
for(int i=0;i<arrayOfnum.length;i++)
{
if(arrayOfnum[i]>max)
{
max = arrayOfnum[i];
pos = i;
}
}
System.out.printf("Maximum value is %d and position is %d",max,pos+1);
}
}


Here arrayOfnum is a one dimensional array whereyou can keep numbers that you take as input and then using private void findMax(int arrayOfnum) method you can find maximum value and position. I didnot return nothing from this method but if you want to return something from this method like you want to return position then you have to declare return type like private int findMax(int arrayOfnum) . and then implementation will be like this.



private  int findMax(int arrayOfnum) {
int num=0,max=0,pos=0;
for(int i=0;i<arrayOfnum.length;i++)
{
if(arrayOfnum[i]>max)
{
max = arrayOfnum[i];
pos = i;
}
}
System.out.printf("Maximum value is %d and position is %d",max,pos+1);
return (pos+1);
}


You can make this method like public, protected etc. which is called access modifier.



If you declare this method as static then you do not need to create App app = new App(); instance in main method. You can directly access static method from main method like this findMax(arrayOfnum); instead of app.findMax(arrayOfnum); . Because main method is static. you can not access non-static variables from a static context. JVM keep main method is static by default.



NB: Try to learn highlighted terms from internet.






share|improve this answer























  • thank you for your answer @flopcoder
    – Sena
    yesterday















up vote
0
down vote













Though its a simple code, You have to learn that from your logic. you can follow this



import java.util.Scanner;

public class App {
public static void main(String args) {
Scanner input=new Scanner(System.in);
//dont need to instantiate that if you declare void findMax(int arrayOfnum) static
App app = new App();
int counter;
counter=1;

System.out.println("Enter how many number you want to take :");
int total=input.nextInt();
int arrayOfnum = new int[total];
//taking input on a array
while (counter<=total) {

System.out.println("Enter the "+counter+". number:");
arrayOfnum[counter]=input.nextInt();
counter++;
}
//method call
app.findMax(arrayOfnum);
}

private void findMax(int arrayOfnum) {
int num=0,max=0,pos=0;
for(int i=0;i<arrayOfnum.length;i++)
{
if(arrayOfnum[i]>max)
{
max = arrayOfnum[i];
pos = i;
}
}
System.out.printf("Maximum value is %d and position is %d",max,pos+1);
}
}


Here arrayOfnum is a one dimensional array whereyou can keep numbers that you take as input and then using private void findMax(int arrayOfnum) method you can find maximum value and position. I didnot return nothing from this method but if you want to return something from this method like you want to return position then you have to declare return type like private int findMax(int arrayOfnum) . and then implementation will be like this.



private  int findMax(int arrayOfnum) {
int num=0,max=0,pos=0;
for(int i=0;i<arrayOfnum.length;i++)
{
if(arrayOfnum[i]>max)
{
max = arrayOfnum[i];
pos = i;
}
}
System.out.printf("Maximum value is %d and position is %d",max,pos+1);
return (pos+1);
}


You can make this method like public, protected etc. which is called access modifier.



If you declare this method as static then you do not need to create App app = new App(); instance in main method. You can directly access static method from main method like this findMax(arrayOfnum); instead of app.findMax(arrayOfnum); . Because main method is static. you can not access non-static variables from a static context. JVM keep main method is static by default.



NB: Try to learn highlighted terms from internet.






share|improve this answer























  • thank you for your answer @flopcoder
    – Sena
    yesterday













up vote
0
down vote










up vote
0
down vote









Though its a simple code, You have to learn that from your logic. you can follow this



import java.util.Scanner;

public class App {
public static void main(String args) {
Scanner input=new Scanner(System.in);
//dont need to instantiate that if you declare void findMax(int arrayOfnum) static
App app = new App();
int counter;
counter=1;

System.out.println("Enter how many number you want to take :");
int total=input.nextInt();
int arrayOfnum = new int[total];
//taking input on a array
while (counter<=total) {

System.out.println("Enter the "+counter+". number:");
arrayOfnum[counter]=input.nextInt();
counter++;
}
//method call
app.findMax(arrayOfnum);
}

private void findMax(int arrayOfnum) {
int num=0,max=0,pos=0;
for(int i=0;i<arrayOfnum.length;i++)
{
if(arrayOfnum[i]>max)
{
max = arrayOfnum[i];
pos = i;
}
}
System.out.printf("Maximum value is %d and position is %d",max,pos+1);
}
}


Here arrayOfnum is a one dimensional array whereyou can keep numbers that you take as input and then using private void findMax(int arrayOfnum) method you can find maximum value and position. I didnot return nothing from this method but if you want to return something from this method like you want to return position then you have to declare return type like private int findMax(int arrayOfnum) . and then implementation will be like this.



private  int findMax(int arrayOfnum) {
int num=0,max=0,pos=0;
for(int i=0;i<arrayOfnum.length;i++)
{
if(arrayOfnum[i]>max)
{
max = arrayOfnum[i];
pos = i;
}
}
System.out.printf("Maximum value is %d and position is %d",max,pos+1);
return (pos+1);
}


You can make this method like public, protected etc. which is called access modifier.



If you declare this method as static then you do not need to create App app = new App(); instance in main method. You can directly access static method from main method like this findMax(arrayOfnum); instead of app.findMax(arrayOfnum); . Because main method is static. you can not access non-static variables from a static context. JVM keep main method is static by default.



NB: Try to learn highlighted terms from internet.






share|improve this answer














Though its a simple code, You have to learn that from your logic. you can follow this



import java.util.Scanner;

public class App {
public static void main(String args) {
Scanner input=new Scanner(System.in);
//dont need to instantiate that if you declare void findMax(int arrayOfnum) static
App app = new App();
int counter;
counter=1;

System.out.println("Enter how many number you want to take :");
int total=input.nextInt();
int arrayOfnum = new int[total];
//taking input on a array
while (counter<=total) {

System.out.println("Enter the "+counter+". number:");
arrayOfnum[counter]=input.nextInt();
counter++;
}
//method call
app.findMax(arrayOfnum);
}

private void findMax(int arrayOfnum) {
int num=0,max=0,pos=0;
for(int i=0;i<arrayOfnum.length;i++)
{
if(arrayOfnum[i]>max)
{
max = arrayOfnum[i];
pos = i;
}
}
System.out.printf("Maximum value is %d and position is %d",max,pos+1);
}
}


Here arrayOfnum is a one dimensional array whereyou can keep numbers that you take as input and then using private void findMax(int arrayOfnum) method you can find maximum value and position. I didnot return nothing from this method but if you want to return something from this method like you want to return position then you have to declare return type like private int findMax(int arrayOfnum) . and then implementation will be like this.



private  int findMax(int arrayOfnum) {
int num=0,max=0,pos=0;
for(int i=0;i<arrayOfnum.length;i++)
{
if(arrayOfnum[i]>max)
{
max = arrayOfnum[i];
pos = i;
}
}
System.out.printf("Maximum value is %d and position is %d",max,pos+1);
return (pos+1);
}


You can make this method like public, protected etc. which is called access modifier.



If you declare this method as static then you do not need to create App app = new App(); instance in main method. You can directly access static method from main method like this findMax(arrayOfnum); instead of app.findMax(arrayOfnum); . Because main method is static. you can not access non-static variables from a static context. JVM keep main method is static by default.



NB: Try to learn highlighted terms from internet.







share|improve this answer














share|improve this answer



share|improve this answer








edited yesterday

























answered yesterday









flopcoder

383111




383111












  • thank you for your answer @flopcoder
    – Sena
    yesterday


















  • thank you for your answer @flopcoder
    – Sena
    yesterday
















thank you for your answer @flopcoder
– Sena
yesterday




thank you for your answer @flopcoder
– Sena
yesterday



Popular posts from this blog

'app-layout' is not a known element: how to share Component with different Modules

android studio warns about leanback feature tag usage required on manifest while using Unity exported app?

WPF add header to Image with URL pettitions [duplicate]