Successfully registered COM DLL is not being listed in “Insert ActiveX control” dialog of visual studio











up vote
0
down vote

favorite












I have created a COM DLL using the ATL project (Composite object) which basically has one tree control (which is a part of VS toolbox) within a dialog.



After registering it, I'm trying to insert it in a dialog based MFC/ATL application by using the standard approach of using "Insert ActiveX control" dialog of Visual Studio.



But the problem here is, even after its successful registration it is not getting listed in the "Insert ActiveX control" dialog. So I'm not able to insert it in the container dialog.



Alternatives that I've tried and that worked:



In a tool provided by Microsoft to test such controls i.e., "ActiveX control test container"(TSTCON32.exe), my COM DLL is getting listed properly and I'm able to use it.



Alternatives that I've tried and that not worked:




  1. Un-registering the DLL and re-registering it back.

  2. Rebooting the PC.


So, any help on this regard is warmly appreciated.



Couple more details:




  1. Both ".idl" and ".rgs" file looks proper.

  2. I will share my project if it is needed.






visual-c++ mfc com atl







share|improve this question









New contributor




Prajyoth Raveendra is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
















  • 1




    Did you register an ActiveX control with the same bitness as that of the designated consumer project?
    – IInspectable
    yesterday










  • Yes. I have registered the ActiveX control with the same bitness as that of the designated consumer project.
    – Prajyoth Raveendra
    14 hours ago















up vote
0
down vote

favorite












I have created a COM DLL using the ATL project (Composite object) which basically has one tree control (which is a part of VS toolbox) within a dialog.



After registering it, I'm trying to insert it in a dialog based MFC/ATL application by using the standard approach of using "Insert ActiveX control" dialog of Visual Studio.



But the problem here is, even after its successful registration it is not getting listed in the "Insert ActiveX control" dialog. So I'm not able to insert it in the container dialog.



Alternatives that I've tried and that worked:



In a tool provided by Microsoft to test such controls i.e., "ActiveX control test container"(TSTCON32.exe), my COM DLL is getting listed properly and I'm able to use it.



Alternatives that I've tried and that not worked:




  1. Un-registering the DLL and re-registering it back.

  2. Rebooting the PC.


So, any help on this regard is warmly appreciated.



Couple more details:




  1. Both ".idl" and ".rgs" file looks proper.

  2. I will share my project if it is needed.






visual-c++ mfc com atl







share|improve this question









New contributor




Prajyoth Raveendra is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
















  • 1




    Did you register an ActiveX control with the same bitness as that of the designated consumer project?
    – IInspectable
    yesterday










  • Yes. I have registered the ActiveX control with the same bitness as that of the designated consumer project.
    – Prajyoth Raveendra
    14 hours ago













up vote
0
down vote

favorite









up vote
0
down vote

favorite











I have created a COM DLL using the ATL project (Composite object) which basically has one tree control (which is a part of VS toolbox) within a dialog.



After registering it, I'm trying to insert it in a dialog based MFC/ATL application by using the standard approach of using "Insert ActiveX control" dialog of Visual Studio.



But the problem here is, even after its successful registration it is not getting listed in the "Insert ActiveX control" dialog. So I'm not able to insert it in the container dialog.



Alternatives that I've tried and that worked:



In a tool provided by Microsoft to test such controls i.e., "ActiveX control test container"(TSTCON32.exe), my COM DLL is getting listed properly and I'm able to use it.



Alternatives that I've tried and that not worked:




  1. Un-registering the DLL and re-registering it back.

  2. Rebooting the PC.


So, any help on this regard is warmly appreciated.



Couple more details:




  1. Both ".idl" and ".rgs" file looks proper.

  2. I will share my project if it is needed.






visual-c++ mfc com atl







share|improve this question









New contributor




Prajyoth Raveendra is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.











I have created a COM DLL using the ATL project (Composite object) which basically has one tree control (which is a part of VS toolbox) within a dialog.



After registering it, I'm trying to insert it in a dialog based MFC/ATL application by using the standard approach of using "Insert ActiveX control" dialog of Visual Studio.



But the problem here is, even after its successful registration it is not getting listed in the "Insert ActiveX control" dialog. So I'm not able to insert it in the container dialog.



Alternatives that I've tried and that worked:



In a tool provided by Microsoft to test such controls i.e., "ActiveX control test container"(TSTCON32.exe), my COM DLL is getting listed properly and I'm able to use it.



Alternatives that I've tried and that not worked:




  1. Un-registering the DLL and re-registering it back.

  2. Rebooting the PC.


So, any help on this regard is warmly appreciated.



Couple more details:




  1. Both ".idl" and ".rgs" file looks proper.

  2. I will share my project if it is needed.






visual-c++ mfc com atl




visual-c++ mfc com atl






share|improve this question









New contributor




Prajyoth Raveendra is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.











share|improve this question









New contributor




Prajyoth Raveendra is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.









share|improve this question




share|improve this question








edited yesterday









Karol Dowbecki

13.2k62745




13.2k62745






New contributor




Prajyoth Raveendra is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.









asked yesterday









Prajyoth Raveendra

11




11




New contributor




Prajyoth Raveendra is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.





New contributor





Prajyoth Raveendra is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.






Prajyoth Raveendra is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.








  • 1




    Did you register an ActiveX control with the same bitness as that of the designated consumer project?
    – IInspectable
    yesterday










  • Yes. I have registered the ActiveX control with the same bitness as that of the designated consumer project.
    – Prajyoth Raveendra
    14 hours ago














  • 1




    Did you register an ActiveX control with the same bitness as that of the designated consumer project?
    – IInspectable
    yesterday










  • Yes. I have registered the ActiveX control with the same bitness as that of the designated consumer project.
    – Prajyoth Raveendra
    14 hours ago








1




1




Did you register an ActiveX control with the same bitness as that of the designated consumer project?
– IInspectable
yesterday




Did you register an ActiveX control with the same bitness as that of the designated consumer project?
– IInspectable
yesterday












Yes. I have registered the ActiveX control with the same bitness as that of the designated consumer project.
– Prajyoth Raveendra
14 hours ago




Yes. I have registered the ActiveX control with the same bitness as that of the designated consumer project.
– Prajyoth Raveendra
14 hours ago

















active

oldest

votes











Your Answer






StackExchange.ifUsing("editor", function () {
StackExchange.using("externalEditor", function () {
StackExchange.using("snippets", function () {
StackExchange.snippets.init();
});
});
}, "code-snippets");

StackExchange.ready(function() {
var channelOptions = {
tags: "".split(" "),
id: "1"
};
initTagRenderer("".split(" "), "".split(" "), channelOptions);

StackExchange.using("externalEditor", function() {
// Have to fire editor after snippets, if snippets enabled
if (StackExchange.settings.snippets.snippetsEnabled) {
StackExchange.using("snippets", function() {
createEditor();
});
}
else {
createEditor();
}
});

function createEditor() {
StackExchange.prepareEditor({
heartbeatType: 'answer',
convertImagesToLinks: true,
noModals: true,
showLowRepImageUploadWarning: true,
reputationToPostImages: 10,
bindNavPrevention: true,
postfix: "",
imageUploader: {
brandingHtml: "Powered by u003ca class="icon-imgur-white" href="https://imgur.com/"u003eu003c/au003e",
contentPolicyHtml: "User contributions licensed under u003ca href="https://creativecommons.org/licenses/by-sa/3.0/"u003ecc by-sa 3.0 with attribution requiredu003c/au003e u003ca href="https://stackoverflow.com/legal/content-policy"u003e(content policy)u003c/au003e",
allowUrls: true
},
onDemand: true,
discardSelector: ".discard-answer"
,immediatelyShowMarkdownHelp:true
});


}
});






Prajyoth Raveendra is a new contributor. Be nice, and check out our Code of Conduct.










 

draft saved


draft discarded


















StackExchange.ready(
function () {
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fstackoverflow.com%2fquestions%2f53372353%2fsuccessfully-registered-com-dll-is-not-being-listed-in-insert-activex-control%23new-answer', 'question_page');
}
);

Post as a guest















Required, but never shown






























active

oldest

votes













active

oldest

votes









active

oldest

votes






active

oldest

votes








Prajyoth Raveendra is a new contributor. Be nice, and check out our Code of Conduct.










 

draft saved


draft discarded


















Prajyoth Raveendra is a new contributor. Be nice, and check out our Code of Conduct.













Prajyoth Raveendra is a new contributor. Be nice, and check out our Code of Conduct.












Prajyoth Raveendra is a new contributor. Be nice, and check out our Code of Conduct.















 


draft saved


draft discarded














StackExchange.ready(
function () {
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fstackoverflow.com%2fquestions%2f53372353%2fsuccessfully-registered-com-dll-is-not-being-listed-in-insert-activex-control%23new-answer', 'question_page');
}
);

Post as a guest















Required, but never shown





















































Required, but never shown














Required, but never shown












Required, but never shown







Required, but never shown

































Required, but never shown














Required, but never shown












Required, but never shown







Required, but never shown







Popular posts from this blog

Can a sorcerer learn a 5th-level spell early by creating spell slots using the Font of Magic feature?

Image
28 6 $begingroup$ Per the Font of Magic feature, sorcerer can use Flexible Casting to create 5th-level spell slots at level 7, even though they are not typically available until level 9. You can transform unexpended sorcery points into one spell slot as a bonus action on your turn. The Creating Spell Slots table shows the cost of creating a spell slot of [5th level is 7] If such a sorcerer levels up while still having this 5th-level spell slot, can they choose a 5th-level spell as the spell they gain upon levelling up? The Spellcasting feature states: Additionally, when you gain a level in this class, you can choose one of the sorcerer spells you know and replace it with another spell from the sorcerer spell list, which also must be of a level for which you have spell slots.
Read more

Does disintegrating a polymorphed enemy still kill it after the 2018 errata?

Image
up vote 13 down vote favorite 1 After the 2018 errata, the disintegrate spell description now reads: A creature targeted by this spell must make a Dexterity saving throw. On a failed save, the target takes 10d6 + 40 force damage. The target is disintegrated if this damage leaves it with 0 hit points. If you were to polymorph an enemy into a rat and then disintegrate it, would the enemy be disintegrated or would it just return to its original form? I know that for Druids, it’s not an instant kill anymore, but is this the case for polymorph as well? dnd-5e spells polymorph errata share | improve this question edited 18 hours ago
Read more

A Topological Invariant for $pi_3(U(n))$

Image
3 3 $begingroup$ Recently, I saw a construction of topological invariant for $pi_3(U(n))$ with $ngeq 2$ : $$ N=frac{1}{24pi^2}int_{S^3} d^3x epsilon^{ijk} Tr[(U^{-1}partial_{x_i}U)(U^{-1}partial_{x_j}U)(U^{-1}partial_{x_k}U)] , $$ where $Uin U(n)$ depends on $boldsymbol{x}=(x_1,x_2,x_3)in S^3$ , $epsilon^{ijk}$ is the Levi-Civita symbol, $i,j,k=1,2,3$ , and the duplicated indexes are summed over. It is claimed that $N$ is an integer, but why? Update 02/02/2019 I think I got an argument for $n=2$ . In this case, $U=e^{i varphi} q$ with $qin SU(2)$ . Due to the trace and the Levi-Civita symbol in $N$ , $varphi$ does not contribute to $N$ . As $Tr[q^{dagger}partial_i q]=0$ and $(q^{dagger}partial_i q)^{dagger}=-q^{dagger}partial_i q$ , $q^{dagger}partial_i q$ in geneeral has the form $q^{dagger}partia
Read more