Capture dot notation property values ignoring random characters at the start and end











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1
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Hi I have the following string:



'TD#{test1.test.test3234.rsatars.23432i.rstrsti.arstarst}'


Is there a way with regex to strip out the stings so I get the following:



'test1.test.test3234.rsatars.23432i.rstrsti.arstarst'


What I have so far is just capturing the '.' character, can't figure out how to get the whole property path string.



[w].[w+]





regex







share|improve this question




























    up vote
    1
    down vote

    favorite












    Hi I have the following string:



    'TD#{test1.test.test3234.rsatars.23432i.rstrsti.arstarst}'


    Is there a way with regex to strip out the stings so I get the following:



    'test1.test.test3234.rsatars.23432i.rstrsti.arstarst'


    What I have so far is just capturing the '.' character, can't figure out how to get the whole property path string.



    [w].[w+]





    regex







    share|improve this question


























      up vote
      1
      down vote

      favorite









      up vote
      1
      down vote

      favorite











      Hi I have the following string:



      'TD#{test1.test.test3234.rsatars.23432i.rstrsti.arstarst}'


      Is there a way with regex to strip out the stings so I get the following:



      'test1.test.test3234.rsatars.23432i.rstrsti.arstarst'


      What I have so far is just capturing the '.' character, can't figure out how to get the whole property path string.



      [w].[w+]





      regex







      share|improve this question















      Hi I have the following string:



      'TD#{test1.test.test3234.rsatars.23432i.rstrsti.arstarst}'


      Is there a way with regex to strip out the stings so I get the following:



      'test1.test.test3234.rsatars.23432i.rstrsti.arstarst'


      What I have so far is just capturing the '.' character, can't figure out how to get the whole property path string.



      [w].[w+]





      regex




      regex






      share|improve this question















      share|improve this question













      share|improve this question




      share|improve this question








      edited Nov 19 at 11:46









      Wiktor Stribiżew

      301k16122197




      301k16122197










      asked Nov 19 at 11:42









      run yards

      1,56341635




      1,56341635
























          1 Answer
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          down vote



          accepted










          You may use



          w+.[w.]*


          See the regex demo



          The w+.[w.]* pattern will match 1 or more word chars, then a dot and then 0 or more word or dot chars.



          Or, alternatively



          w+(?:.w+)+


          See another demo.



          The w+(?:.w+)+ pattern matches 1+ word chars, and then 1 or more repetitions of a dot followed with 1+ word chars.






          share|improve this answer





















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            active

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            1 Answer
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            active

            oldest

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            active

            oldest

            votes






            active

            oldest

            votes








            up vote
            1
            down vote



            accepted










            You may use



            w+.[w.]*


            See the regex demo



            The w+.[w.]* pattern will match 1 or more word chars, then a dot and then 0 or more word or dot chars.



            Or, alternatively



            w+(?:.w+)+


            See another demo.



            The w+(?:.w+)+ pattern matches 1+ word chars, and then 1 or more repetitions of a dot followed with 1+ word chars.






            share|improve this answer

























              up vote
              1
              down vote



              accepted










              You may use



              w+.[w.]*


              See the regex demo



              The w+.[w.]* pattern will match 1 or more word chars, then a dot and then 0 or more word or dot chars.



              Or, alternatively



              w+(?:.w+)+


              See another demo.



              The w+(?:.w+)+ pattern matches 1+ word chars, and then 1 or more repetitions of a dot followed with 1+ word chars.






              share|improve this answer























                up vote
                1
                down vote



                accepted







                up vote
                1
                down vote



                accepted






                You may use



                w+.[w.]*


                See the regex demo



                The w+.[w.]* pattern will match 1 or more word chars, then a dot and then 0 or more word or dot chars.



                Or, alternatively



                w+(?:.w+)+


                See another demo.



                The w+(?:.w+)+ pattern matches 1+ word chars, and then 1 or more repetitions of a dot followed with 1+ word chars.






                share|improve this answer












                You may use



                w+.[w.]*


                See the regex demo



                The w+.[w.]* pattern will match 1 or more word chars, then a dot and then 0 or more word or dot chars.



                Or, alternatively



                w+(?:.w+)+


                See another demo.



                The w+(?:.w+)+ pattern matches 1+ word chars, and then 1 or more repetitions of a dot followed with 1+ word chars.







                share|improve this answer












                share|improve this answer



                share|improve this answer










                answered Nov 19 at 11:44









                Wiktor Stribiżew

                301k16122197




                301k16122197






























                     

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