Find constants $b_i$ such that $sum_{n=1}^{N} a_n (sum_{n=1}^{t} b_i[r_n-(r_n)^2]+s(i))=0$












-2












$begingroup$


I am trying to find the real constants $b_i$ such the $displaystyle sum_{n=1}^{N} a_n left(displaystyle sum_{n=1}^{t} b_i[r_n-(r_n)^2]+s(i))right)=0$ where I am given that $displaystyle sum_{n=1}^{N} a_n r_n=0$ for every natural $N$ and $s(i)$ is certain function of $i$ (I have the explicit form for $s(i)$ as well in terms of a series).



Note that $t$ is at our disposal. I tried to manipulate my expression for $t=3$ to find such constants $b_1,b_2,b_3$ unsuccessfully. I also want to mention that there is no guarantee for the existence of such constants except $b_i=0$ for all $i$.



EDIT: I reviewed my work and I found my original question was wrong. I took the index $N$ in a wrong direction. Now in above question $N$ (say $N=2$) is fixed so that $displaystyle sum_{n=1}^{2} a_n r_n=0$ with $a_1,a_2inmathbb{R}$ and $r_1,r_2in (0,1]$.



Now for fixed but arbitrary $N$ (and corresponding $a_i,r_i$), I am supposed to choose $t$ number of constants $b_i$ (not all zero) making that expression zero.










share|cite|improve this question











$endgroup$








  • 3




    $begingroup$
    Again, if you are "given that $ sumlimits_{n=1}^{N} a_n r_n=0$ for every natural $N$" then you know that $a_nr_n=0$ for every $n$. Thus, which parts of your question, if any, do not fall?
    $endgroup$
    – Did
    Jan 2 at 22:36










  • $begingroup$
    I think there is something missing in my work. I will be back after reviewing my note books.
    $endgroup$
    – ersh
    Jan 2 at 22:38












  • $begingroup$
    @Did I reviewed my work and I find this question is wrong. I took the index $N$ in a wrong direction in my work. Apparently my whole day wasted.
    $endgroup$
    – ersh
    Jan 2 at 23:03










  • $begingroup$
    I have edited my question. Does it make sense now? Now for fixed but arbitrary $N$ (and corresponding $a_i,r_i$), I am supposed to choose $t$ number of constants $b_i$ making that expression zero.
    $endgroup$
    – ersh
    Jan 2 at 23:13


















-2












$begingroup$


I am trying to find the real constants $b_i$ such the $displaystyle sum_{n=1}^{N} a_n left(displaystyle sum_{n=1}^{t} b_i[r_n-(r_n)^2]+s(i))right)=0$ where I am given that $displaystyle sum_{n=1}^{N} a_n r_n=0$ for every natural $N$ and $s(i)$ is certain function of $i$ (I have the explicit form for $s(i)$ as well in terms of a series).



Note that $t$ is at our disposal. I tried to manipulate my expression for $t=3$ to find such constants $b_1,b_2,b_3$ unsuccessfully. I also want to mention that there is no guarantee for the existence of such constants except $b_i=0$ for all $i$.



EDIT: I reviewed my work and I found my original question was wrong. I took the index $N$ in a wrong direction. Now in above question $N$ (say $N=2$) is fixed so that $displaystyle sum_{n=1}^{2} a_n r_n=0$ with $a_1,a_2inmathbb{R}$ and $r_1,r_2in (0,1]$.



Now for fixed but arbitrary $N$ (and corresponding $a_i,r_i$), I am supposed to choose $t$ number of constants $b_i$ (not all zero) making that expression zero.










share|cite|improve this question











$endgroup$








  • 3




    $begingroup$
    Again, if you are "given that $ sumlimits_{n=1}^{N} a_n r_n=0$ for every natural $N$" then you know that $a_nr_n=0$ for every $n$. Thus, which parts of your question, if any, do not fall?
    $endgroup$
    – Did
    Jan 2 at 22:36










  • $begingroup$
    I think there is something missing in my work. I will be back after reviewing my note books.
    $endgroup$
    – ersh
    Jan 2 at 22:38












  • $begingroup$
    @Did I reviewed my work and I find this question is wrong. I took the index $N$ in a wrong direction in my work. Apparently my whole day wasted.
    $endgroup$
    – ersh
    Jan 2 at 23:03










  • $begingroup$
    I have edited my question. Does it make sense now? Now for fixed but arbitrary $N$ (and corresponding $a_i,r_i$), I am supposed to choose $t$ number of constants $b_i$ making that expression zero.
    $endgroup$
    – ersh
    Jan 2 at 23:13
















-2












-2








-2





$begingroup$


I am trying to find the real constants $b_i$ such the $displaystyle sum_{n=1}^{N} a_n left(displaystyle sum_{n=1}^{t} b_i[r_n-(r_n)^2]+s(i))right)=0$ where I am given that $displaystyle sum_{n=1}^{N} a_n r_n=0$ for every natural $N$ and $s(i)$ is certain function of $i$ (I have the explicit form for $s(i)$ as well in terms of a series).



Note that $t$ is at our disposal. I tried to manipulate my expression for $t=3$ to find such constants $b_1,b_2,b_3$ unsuccessfully. I also want to mention that there is no guarantee for the existence of such constants except $b_i=0$ for all $i$.



EDIT: I reviewed my work and I found my original question was wrong. I took the index $N$ in a wrong direction. Now in above question $N$ (say $N=2$) is fixed so that $displaystyle sum_{n=1}^{2} a_n r_n=0$ with $a_1,a_2inmathbb{R}$ and $r_1,r_2in (0,1]$.



Now for fixed but arbitrary $N$ (and corresponding $a_i,r_i$), I am supposed to choose $t$ number of constants $b_i$ (not all zero) making that expression zero.










share|cite|improve this question











$endgroup$




I am trying to find the real constants $b_i$ such the $displaystyle sum_{n=1}^{N} a_n left(displaystyle sum_{n=1}^{t} b_i[r_n-(r_n)^2]+s(i))right)=0$ where I am given that $displaystyle sum_{n=1}^{N} a_n r_n=0$ for every natural $N$ and $s(i)$ is certain function of $i$ (I have the explicit form for $s(i)$ as well in terms of a series).



Note that $t$ is at our disposal. I tried to manipulate my expression for $t=3$ to find such constants $b_1,b_2,b_3$ unsuccessfully. I also want to mention that there is no guarantee for the existence of such constants except $b_i=0$ for all $i$.



EDIT: I reviewed my work and I found my original question was wrong. I took the index $N$ in a wrong direction. Now in above question $N$ (say $N=2$) is fixed so that $displaystyle sum_{n=1}^{2} a_n r_n=0$ with $a_1,a_2inmathbb{R}$ and $r_1,r_2in (0,1]$.



Now for fixed but arbitrary $N$ (and corresponding $a_i,r_i$), I am supposed to choose $t$ number of constants $b_i$ (not all zero) making that expression zero.







real-analysis sequences-and-series summation






share|cite|improve this question















share|cite|improve this question













share|cite|improve this question




share|cite|improve this question








edited Jan 2 at 23:18







ersh

















asked Jan 2 at 22:32









ershersh

294112




294112








  • 3




    $begingroup$
    Again, if you are "given that $ sumlimits_{n=1}^{N} a_n r_n=0$ for every natural $N$" then you know that $a_nr_n=0$ for every $n$. Thus, which parts of your question, if any, do not fall?
    $endgroup$
    – Did
    Jan 2 at 22:36










  • $begingroup$
    I think there is something missing in my work. I will be back after reviewing my note books.
    $endgroup$
    – ersh
    Jan 2 at 22:38












  • $begingroup$
    @Did I reviewed my work and I find this question is wrong. I took the index $N$ in a wrong direction in my work. Apparently my whole day wasted.
    $endgroup$
    – ersh
    Jan 2 at 23:03










  • $begingroup$
    I have edited my question. Does it make sense now? Now for fixed but arbitrary $N$ (and corresponding $a_i,r_i$), I am supposed to choose $t$ number of constants $b_i$ making that expression zero.
    $endgroup$
    – ersh
    Jan 2 at 23:13
















  • 3




    $begingroup$
    Again, if you are "given that $ sumlimits_{n=1}^{N} a_n r_n=0$ for every natural $N$" then you know that $a_nr_n=0$ for every $n$. Thus, which parts of your question, if any, do not fall?
    $endgroup$
    – Did
    Jan 2 at 22:36










  • $begingroup$
    I think there is something missing in my work. I will be back after reviewing my note books.
    $endgroup$
    – ersh
    Jan 2 at 22:38












  • $begingroup$
    @Did I reviewed my work and I find this question is wrong. I took the index $N$ in a wrong direction in my work. Apparently my whole day wasted.
    $endgroup$
    – ersh
    Jan 2 at 23:03










  • $begingroup$
    I have edited my question. Does it make sense now? Now for fixed but arbitrary $N$ (and corresponding $a_i,r_i$), I am supposed to choose $t$ number of constants $b_i$ making that expression zero.
    $endgroup$
    – ersh
    Jan 2 at 23:13










3




3




$begingroup$
Again, if you are "given that $ sumlimits_{n=1}^{N} a_n r_n=0$ for every natural $N$" then you know that $a_nr_n=0$ for every $n$. Thus, which parts of your question, if any, do not fall?
$endgroup$
– Did
Jan 2 at 22:36




$begingroup$
Again, if you are "given that $ sumlimits_{n=1}^{N} a_n r_n=0$ for every natural $N$" then you know that $a_nr_n=0$ for every $n$. Thus, which parts of your question, if any, do not fall?
$endgroup$
– Did
Jan 2 at 22:36












$begingroup$
I think there is something missing in my work. I will be back after reviewing my note books.
$endgroup$
– ersh
Jan 2 at 22:38






$begingroup$
I think there is something missing in my work. I will be back after reviewing my note books.
$endgroup$
– ersh
Jan 2 at 22:38














$begingroup$
@Did I reviewed my work and I find this question is wrong. I took the index $N$ in a wrong direction in my work. Apparently my whole day wasted.
$endgroup$
– ersh
Jan 2 at 23:03




$begingroup$
@Did I reviewed my work and I find this question is wrong. I took the index $N$ in a wrong direction in my work. Apparently my whole day wasted.
$endgroup$
– ersh
Jan 2 at 23:03












$begingroup$
I have edited my question. Does it make sense now? Now for fixed but arbitrary $N$ (and corresponding $a_i,r_i$), I am supposed to choose $t$ number of constants $b_i$ making that expression zero.
$endgroup$
– ersh
Jan 2 at 23:13






$begingroup$
I have edited my question. Does it make sense now? Now for fixed but arbitrary $N$ (and corresponding $a_i,r_i$), I am supposed to choose $t$ number of constants $b_i$ making that expression zero.
$endgroup$
– ersh
Jan 2 at 23:13












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