SQL Server : Mapping table design
I have 2 tables, Table A and Table B which have the following structure:
and
There is a 1-1 relationship between tables identified by Product_group
in Table A
and <campaign_month,campaign>
in Table B
.
For example, ‘ 1808 Product - Group 3a’ = <’201808’,‘group_3a’>.
I am trying to create a mapping table using Tables A and B which should contain 3 columns, namely, <Product_group, campaign_month, campaign>.
Since I am not able to join the two tables, I am looking for other ways of creating the mapping table.
Can someone point me in the right direction?
sql sql-server database-design mapping
add a comment |
I have 2 tables, Table A and Table B which have the following structure:
and
There is a 1-1 relationship between tables identified by Product_group
in Table A
and <campaign_month,campaign>
in Table B
.
For example, ‘ 1808 Product - Group 3a’ = <’201808’,‘group_3a’>.
I am trying to create a mapping table using Tables A and B which should contain 3 columns, namely, <Product_group, campaign_month, campaign>.
Since I am not able to join the two tables, I am looking for other ways of creating the mapping table.
Can someone point me in the right direction?
sql sql-server database-design mapping
Is the format of Product_group consistent? If so then you can create a CTE that reformats the columns of Table A to match the formats of Table B. Then you can join the CTE to Table B and obtain the result.
– John Tamburo
Nov 20 '18 at 4:33
In your example there are two <201808’,‘group_3a> in table_b. Is there a preference to use the first record<111,201808,'group_3a'> and not the second one<115,'201808','group_3a'> for mapping with '1808 Product - Group 3a'
– George Joseph
Nov 20 '18 at 5:03
@GeorgeJoseph Every Product_group will have one entry in the mapping table, so both record<111,201808,'group_3a'> and <115,'201808','group_3a'> should be mapped to the same product_group from table A which is '1808 Product - Group 3a'.
– Sumedha Nagpal
Nov 20 '18 at 5:43
@JohnTamburo Yes, as far as I know product group is consistent. However, I do see some entries in Table A like‘ 1809 Product - Group 1c - Test1’
for which I do not have a correspondinggroup_1c-Test1
as campaign in Table B.
– Sumedha Nagpal
Nov 20 '18 at 5:46
add a comment |
I have 2 tables, Table A and Table B which have the following structure:
and
There is a 1-1 relationship between tables identified by Product_group
in Table A
and <campaign_month,campaign>
in Table B
.
For example, ‘ 1808 Product - Group 3a’ = <’201808’,‘group_3a’>.
I am trying to create a mapping table using Tables A and B which should contain 3 columns, namely, <Product_group, campaign_month, campaign>.
Since I am not able to join the two tables, I am looking for other ways of creating the mapping table.
Can someone point me in the right direction?
sql sql-server database-design mapping
I have 2 tables, Table A and Table B which have the following structure:
and
There is a 1-1 relationship between tables identified by Product_group
in Table A
and <campaign_month,campaign>
in Table B
.
For example, ‘ 1808 Product - Group 3a’ = <’201808’,‘group_3a’>.
I am trying to create a mapping table using Tables A and B which should contain 3 columns, namely, <Product_group, campaign_month, campaign>.
Since I am not able to join the two tables, I am looking for other ways of creating the mapping table.
Can someone point me in the right direction?
sql sql-server database-design mapping
sql sql-server database-design mapping
edited Nov 20 '18 at 5:37
marc_s
573k12811071254
573k12811071254
asked Nov 20 '18 at 3:56
Sumedha NagpalSumedha Nagpal
226
226
Is the format of Product_group consistent? If so then you can create a CTE that reformats the columns of Table A to match the formats of Table B. Then you can join the CTE to Table B and obtain the result.
– John Tamburo
Nov 20 '18 at 4:33
In your example there are two <201808’,‘group_3a> in table_b. Is there a preference to use the first record<111,201808,'group_3a'> and not the second one<115,'201808','group_3a'> for mapping with '1808 Product - Group 3a'
– George Joseph
Nov 20 '18 at 5:03
@GeorgeJoseph Every Product_group will have one entry in the mapping table, so both record<111,201808,'group_3a'> and <115,'201808','group_3a'> should be mapped to the same product_group from table A which is '1808 Product - Group 3a'.
– Sumedha Nagpal
Nov 20 '18 at 5:43
@JohnTamburo Yes, as far as I know product group is consistent. However, I do see some entries in Table A like‘ 1809 Product - Group 1c - Test1’
for which I do not have a correspondinggroup_1c-Test1
as campaign in Table B.
– Sumedha Nagpal
Nov 20 '18 at 5:46
add a comment |
Is the format of Product_group consistent? If so then you can create a CTE that reformats the columns of Table A to match the formats of Table B. Then you can join the CTE to Table B and obtain the result.
– John Tamburo
Nov 20 '18 at 4:33
In your example there are two <201808’,‘group_3a> in table_b. Is there a preference to use the first record<111,201808,'group_3a'> and not the second one<115,'201808','group_3a'> for mapping with '1808 Product - Group 3a'
– George Joseph
Nov 20 '18 at 5:03
@GeorgeJoseph Every Product_group will have one entry in the mapping table, so both record<111,201808,'group_3a'> and <115,'201808','group_3a'> should be mapped to the same product_group from table A which is '1808 Product - Group 3a'.
– Sumedha Nagpal
Nov 20 '18 at 5:43
@JohnTamburo Yes, as far as I know product group is consistent. However, I do see some entries in Table A like‘ 1809 Product - Group 1c - Test1’
for which I do not have a correspondinggroup_1c-Test1
as campaign in Table B.
– Sumedha Nagpal
Nov 20 '18 at 5:46
Is the format of Product_group consistent? If so then you can create a CTE that reformats the columns of Table A to match the formats of Table B. Then you can join the CTE to Table B and obtain the result.
– John Tamburo
Nov 20 '18 at 4:33
Is the format of Product_group consistent? If so then you can create a CTE that reformats the columns of Table A to match the formats of Table B. Then you can join the CTE to Table B and obtain the result.
– John Tamburo
Nov 20 '18 at 4:33
In your example there are two <201808’,‘group_3a> in table_b. Is there a preference to use the first record<111,201808,'group_3a'> and not the second one<115,'201808','group_3a'> for mapping with '1808 Product - Group 3a'
– George Joseph
Nov 20 '18 at 5:03
In your example there are two <201808’,‘group_3a> in table_b. Is there a preference to use the first record<111,201808,'group_3a'> and not the second one<115,'201808','group_3a'> for mapping with '1808 Product - Group 3a'
– George Joseph
Nov 20 '18 at 5:03
@GeorgeJoseph Every Product_group will have one entry in the mapping table, so both record<111,201808,'group_3a'> and <115,'201808','group_3a'> should be mapped to the same product_group from table A which is '1808 Product - Group 3a'.
– Sumedha Nagpal
Nov 20 '18 at 5:43
@GeorgeJoseph Every Product_group will have one entry in the mapping table, so both record<111,201808,'group_3a'> and <115,'201808','group_3a'> should be mapped to the same product_group from table A which is '1808 Product - Group 3a'.
– Sumedha Nagpal
Nov 20 '18 at 5:43
@JohnTamburo Yes, as far as I know product group is consistent. However, I do see some entries in Table A like
‘ 1809 Product - Group 1c - Test1’
for which I do not have a corresponding group_1c-Test1
as campaign in Table B.– Sumedha Nagpal
Nov 20 '18 at 5:46
@JohnTamburo Yes, as far as I know product group is consistent. However, I do see some entries in Table A like
‘ 1809 Product - Group 1c - Test1’
for which I do not have a corresponding group_1c-Test1
as campaign in Table B.– Sumedha Nagpal
Nov 20 '18 at 5:46
add a comment |
1 Answer
1
active
oldest
votes
Consider the following, I am joining the two tables on the basis of whether the string in campaign column(without the _ ) is contained in product_group.
create table tablea(product_group varchar(50));
create table tableb(id_c int,campaign_month int, campaign varchar(50));
insert into tablea values('1808 Product - Group 3a')
insert into tablea values('1808 Product - Group 3b')
insert into tablea values('1808 Product - Group 1c - Test1')
insert into tablea values('1808 Product - Group 3s -1')
insert into tablea values('1808 Product - Group 4d')
insert into tablea values('1808 Product - Group 3a')
insert into tablea values('1808 Product - Group 3b')
insert into tablea values('1808 Product - Group 1c - Test1')
insert into tablea values('1808 Product - Group 3s -1')
insert into tablea values('1808 Product - Group 4d')
select a.product_group, b.id_c,b.campaign_month,b.campaign
from tablea a
left join tableb b
on replace(a.product_group,' -',' ') like '%'+replace(b.campaign,'_',' ')+'%'
Demo link
https://dbfiddle.uk/?rdbms=sqlserver_2017&fiddle=b1c19bc020e3a8a313ce78dd387f7c43
1
Hey @george this is actually helpful. Though, the issue is, that the date is not being used to match the correct product_group. Also, I tried matching a campaign namedgroup_3s_1
toproduct_group
which would be1809 Product - Group 3s -1
. Do you have any suggestions on this?
– Sumedha Nagpal
Nov 20 '18 at 6:36
The idea would be to compare by replace <space><hyphen> with a <space> in the column "product_group" and perform the comparison. I have updated the dbfiddle link and answer.I didnt follow the comment on "date not being used to match"?.
– George Joseph
Nov 20 '18 at 7:09
add a comment |
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oldest
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oldest
votes
Consider the following, I am joining the two tables on the basis of whether the string in campaign column(without the _ ) is contained in product_group.
create table tablea(product_group varchar(50));
create table tableb(id_c int,campaign_month int, campaign varchar(50));
insert into tablea values('1808 Product - Group 3a')
insert into tablea values('1808 Product - Group 3b')
insert into tablea values('1808 Product - Group 1c - Test1')
insert into tablea values('1808 Product - Group 3s -1')
insert into tablea values('1808 Product - Group 4d')
insert into tablea values('1808 Product - Group 3a')
insert into tablea values('1808 Product - Group 3b')
insert into tablea values('1808 Product - Group 1c - Test1')
insert into tablea values('1808 Product - Group 3s -1')
insert into tablea values('1808 Product - Group 4d')
select a.product_group, b.id_c,b.campaign_month,b.campaign
from tablea a
left join tableb b
on replace(a.product_group,' -',' ') like '%'+replace(b.campaign,'_',' ')+'%'
Demo link
https://dbfiddle.uk/?rdbms=sqlserver_2017&fiddle=b1c19bc020e3a8a313ce78dd387f7c43
1
Hey @george this is actually helpful. Though, the issue is, that the date is not being used to match the correct product_group. Also, I tried matching a campaign namedgroup_3s_1
toproduct_group
which would be1809 Product - Group 3s -1
. Do you have any suggestions on this?
– Sumedha Nagpal
Nov 20 '18 at 6:36
The idea would be to compare by replace <space><hyphen> with a <space> in the column "product_group" and perform the comparison. I have updated the dbfiddle link and answer.I didnt follow the comment on "date not being used to match"?.
– George Joseph
Nov 20 '18 at 7:09
add a comment |
Consider the following, I am joining the two tables on the basis of whether the string in campaign column(without the _ ) is contained in product_group.
create table tablea(product_group varchar(50));
create table tableb(id_c int,campaign_month int, campaign varchar(50));
insert into tablea values('1808 Product - Group 3a')
insert into tablea values('1808 Product - Group 3b')
insert into tablea values('1808 Product - Group 1c - Test1')
insert into tablea values('1808 Product - Group 3s -1')
insert into tablea values('1808 Product - Group 4d')
insert into tablea values('1808 Product - Group 3a')
insert into tablea values('1808 Product - Group 3b')
insert into tablea values('1808 Product - Group 1c - Test1')
insert into tablea values('1808 Product - Group 3s -1')
insert into tablea values('1808 Product - Group 4d')
select a.product_group, b.id_c,b.campaign_month,b.campaign
from tablea a
left join tableb b
on replace(a.product_group,' -',' ') like '%'+replace(b.campaign,'_',' ')+'%'
Demo link
https://dbfiddle.uk/?rdbms=sqlserver_2017&fiddle=b1c19bc020e3a8a313ce78dd387f7c43
1
Hey @george this is actually helpful. Though, the issue is, that the date is not being used to match the correct product_group. Also, I tried matching a campaign namedgroup_3s_1
toproduct_group
which would be1809 Product - Group 3s -1
. Do you have any suggestions on this?
– Sumedha Nagpal
Nov 20 '18 at 6:36
The idea would be to compare by replace <space><hyphen> with a <space> in the column "product_group" and perform the comparison. I have updated the dbfiddle link and answer.I didnt follow the comment on "date not being used to match"?.
– George Joseph
Nov 20 '18 at 7:09
add a comment |
Consider the following, I am joining the two tables on the basis of whether the string in campaign column(without the _ ) is contained in product_group.
create table tablea(product_group varchar(50));
create table tableb(id_c int,campaign_month int, campaign varchar(50));
insert into tablea values('1808 Product - Group 3a')
insert into tablea values('1808 Product - Group 3b')
insert into tablea values('1808 Product - Group 1c - Test1')
insert into tablea values('1808 Product - Group 3s -1')
insert into tablea values('1808 Product - Group 4d')
insert into tablea values('1808 Product - Group 3a')
insert into tablea values('1808 Product - Group 3b')
insert into tablea values('1808 Product - Group 1c - Test1')
insert into tablea values('1808 Product - Group 3s -1')
insert into tablea values('1808 Product - Group 4d')
select a.product_group, b.id_c,b.campaign_month,b.campaign
from tablea a
left join tableb b
on replace(a.product_group,' -',' ') like '%'+replace(b.campaign,'_',' ')+'%'
Demo link
https://dbfiddle.uk/?rdbms=sqlserver_2017&fiddle=b1c19bc020e3a8a313ce78dd387f7c43
Consider the following, I am joining the two tables on the basis of whether the string in campaign column(without the _ ) is contained in product_group.
create table tablea(product_group varchar(50));
create table tableb(id_c int,campaign_month int, campaign varchar(50));
insert into tablea values('1808 Product - Group 3a')
insert into tablea values('1808 Product - Group 3b')
insert into tablea values('1808 Product - Group 1c - Test1')
insert into tablea values('1808 Product - Group 3s -1')
insert into tablea values('1808 Product - Group 4d')
insert into tablea values('1808 Product - Group 3a')
insert into tablea values('1808 Product - Group 3b')
insert into tablea values('1808 Product - Group 1c - Test1')
insert into tablea values('1808 Product - Group 3s -1')
insert into tablea values('1808 Product - Group 4d')
select a.product_group, b.id_c,b.campaign_month,b.campaign
from tablea a
left join tableb b
on replace(a.product_group,' -',' ') like '%'+replace(b.campaign,'_',' ')+'%'
Demo link
https://dbfiddle.uk/?rdbms=sqlserver_2017&fiddle=b1c19bc020e3a8a313ce78dd387f7c43
edited Nov 20 '18 at 7:08
answered Nov 20 '18 at 5:59
George JosephGeorge Joseph
1,41749
1,41749
1
Hey @george this is actually helpful. Though, the issue is, that the date is not being used to match the correct product_group. Also, I tried matching a campaign namedgroup_3s_1
toproduct_group
which would be1809 Product - Group 3s -1
. Do you have any suggestions on this?
– Sumedha Nagpal
Nov 20 '18 at 6:36
The idea would be to compare by replace <space><hyphen> with a <space> in the column "product_group" and perform the comparison. I have updated the dbfiddle link and answer.I didnt follow the comment on "date not being used to match"?.
– George Joseph
Nov 20 '18 at 7:09
add a comment |
1
Hey @george this is actually helpful. Though, the issue is, that the date is not being used to match the correct product_group. Also, I tried matching a campaign namedgroup_3s_1
toproduct_group
which would be1809 Product - Group 3s -1
. Do you have any suggestions on this?
– Sumedha Nagpal
Nov 20 '18 at 6:36
The idea would be to compare by replace <space><hyphen> with a <space> in the column "product_group" and perform the comparison. I have updated the dbfiddle link and answer.I didnt follow the comment on "date not being used to match"?.
– George Joseph
Nov 20 '18 at 7:09
1
1
Hey @george this is actually helpful. Though, the issue is, that the date is not being used to match the correct product_group. Also, I tried matching a campaign named
group_3s_1
to product_group
which would be 1809 Product - Group 3s -1
. Do you have any suggestions on this?– Sumedha Nagpal
Nov 20 '18 at 6:36
Hey @george this is actually helpful. Though, the issue is, that the date is not being used to match the correct product_group. Also, I tried matching a campaign named
group_3s_1
to product_group
which would be 1809 Product - Group 3s -1
. Do you have any suggestions on this?– Sumedha Nagpal
Nov 20 '18 at 6:36
The idea would be to compare by replace <space><hyphen> with a <space> in the column "product_group" and perform the comparison. I have updated the dbfiddle link and answer.I didnt follow the comment on "date not being used to match"?.
– George Joseph
Nov 20 '18 at 7:09
The idea would be to compare by replace <space><hyphen> with a <space> in the column "product_group" and perform the comparison. I have updated the dbfiddle link and answer.I didnt follow the comment on "date not being used to match"?.
– George Joseph
Nov 20 '18 at 7:09
add a comment |
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Is the format of Product_group consistent? If so then you can create a CTE that reformats the columns of Table A to match the formats of Table B. Then you can join the CTE to Table B and obtain the result.
– John Tamburo
Nov 20 '18 at 4:33
In your example there are two <201808’,‘group_3a> in table_b. Is there a preference to use the first record<111,201808,'group_3a'> and not the second one<115,'201808','group_3a'> for mapping with '1808 Product - Group 3a'
– George Joseph
Nov 20 '18 at 5:03
@GeorgeJoseph Every Product_group will have one entry in the mapping table, so both record<111,201808,'group_3a'> and <115,'201808','group_3a'> should be mapped to the same product_group from table A which is '1808 Product - Group 3a'.
– Sumedha Nagpal
Nov 20 '18 at 5:43
@JohnTamburo Yes, as far as I know product group is consistent. However, I do see some entries in Table A like
‘ 1809 Product - Group 1c - Test1’
for which I do not have a correspondinggroup_1c-Test1
as campaign in Table B.– Sumedha Nagpal
Nov 20 '18 at 5:46