locate column location from variable and pass to .range“” code
I am using the partial code below to locate a borrower's name in a horizontal list. Once I find the name I need to pass the column and be able to reference that column in range("").value
. So for example it finds the name in column G I can then use the range.value code and some how pair it up with different rows to do copy or do other things with.
Sub Copy_From_Borrower_DBase()
Dim myVal As String
Dim sourceRng As Range
myVal = Sheets("Main").Range("F2").Value ' dropdown list
Set sourceRng = Worksheets("Borrower Database").Range("5:5").Find( _
What:=myVal, LookAt:=xlWhole) 'locate column where to copy from
Sheets("Main").Range("F5").Value = Worksheets("Borrower Database"). _
Range("??????????").Value 'Borrower Name
End Sub
excel vba excel-vba
add a comment |
I am using the partial code below to locate a borrower's name in a horizontal list. Once I find the name I need to pass the column and be able to reference that column in range("").value
. So for example it finds the name in column G I can then use the range.value code and some how pair it up with different rows to do copy or do other things with.
Sub Copy_From_Borrower_DBase()
Dim myVal As String
Dim sourceRng As Range
myVal = Sheets("Main").Range("F2").Value ' dropdown list
Set sourceRng = Worksheets("Borrower Database").Range("5:5").Find( _
What:=myVal, LookAt:=xlWhole) 'locate column where to copy from
Sheets("Main").Range("F5").Value = Worksheets("Borrower Database"). _
Range("??????????").Value 'Borrower Name
End Sub
excel vba excel-vba
add a comment |
I am using the partial code below to locate a borrower's name in a horizontal list. Once I find the name I need to pass the column and be able to reference that column in range("").value
. So for example it finds the name in column G I can then use the range.value code and some how pair it up with different rows to do copy or do other things with.
Sub Copy_From_Borrower_DBase()
Dim myVal As String
Dim sourceRng As Range
myVal = Sheets("Main").Range("F2").Value ' dropdown list
Set sourceRng = Worksheets("Borrower Database").Range("5:5").Find( _
What:=myVal, LookAt:=xlWhole) 'locate column where to copy from
Sheets("Main").Range("F5").Value = Worksheets("Borrower Database"). _
Range("??????????").Value 'Borrower Name
End Sub
excel vba excel-vba
I am using the partial code below to locate a borrower's name in a horizontal list. Once I find the name I need to pass the column and be able to reference that column in range("").value
. So for example it finds the name in column G I can then use the range.value code and some how pair it up with different rows to do copy or do other things with.
Sub Copy_From_Borrower_DBase()
Dim myVal As String
Dim sourceRng As Range
myVal = Sheets("Main").Range("F2").Value ' dropdown list
Set sourceRng = Worksheets("Borrower Database").Range("5:5").Find( _
What:=myVal, LookAt:=xlWhole) 'locate column where to copy from
Sheets("Main").Range("F5").Value = Worksheets("Borrower Database"). _
Range("??????????").Value 'Borrower Name
End Sub
excel vba excel-vba
excel vba excel-vba
edited Nov 20 '18 at 7:11
Pᴇʜ
20.6k42650
20.6k42650
asked Nov 20 '18 at 3:52
MECMEC
697
697
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add a comment |
1 Answer
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oldest
votes
To grab the column from your sourceRng
, you can simply use the .Column
property. I personally would use Cells()
instead of Range()
since you're dealing with column numbers.
So, in your use case:
Worksheets("Main").Range("F5").Value = Worksheets("Borrower Database"). _
Cells(Row, sourceRng.Column).Value 'Borrower Name
Where you would replace Row
with your corresponding row number.
Glad to assist!
– K.Dᴀᴠɪs
Nov 20 '18 at 4:46
add a comment |
Your Answer
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1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
To grab the column from your sourceRng
, you can simply use the .Column
property. I personally would use Cells()
instead of Range()
since you're dealing with column numbers.
So, in your use case:
Worksheets("Main").Range("F5").Value = Worksheets("Borrower Database"). _
Cells(Row, sourceRng.Column).Value 'Borrower Name
Where you would replace Row
with your corresponding row number.
Glad to assist!
– K.Dᴀᴠɪs
Nov 20 '18 at 4:46
add a comment |
To grab the column from your sourceRng
, you can simply use the .Column
property. I personally would use Cells()
instead of Range()
since you're dealing with column numbers.
So, in your use case:
Worksheets("Main").Range("F5").Value = Worksheets("Borrower Database"). _
Cells(Row, sourceRng.Column).Value 'Borrower Name
Where you would replace Row
with your corresponding row number.
Glad to assist!
– K.Dᴀᴠɪs
Nov 20 '18 at 4:46
add a comment |
To grab the column from your sourceRng
, you can simply use the .Column
property. I personally would use Cells()
instead of Range()
since you're dealing with column numbers.
So, in your use case:
Worksheets("Main").Range("F5").Value = Worksheets("Borrower Database"). _
Cells(Row, sourceRng.Column).Value 'Borrower Name
Where you would replace Row
with your corresponding row number.
To grab the column from your sourceRng
, you can simply use the .Column
property. I personally would use Cells()
instead of Range()
since you're dealing with column numbers.
So, in your use case:
Worksheets("Main").Range("F5").Value = Worksheets("Borrower Database"). _
Cells(Row, sourceRng.Column).Value 'Borrower Name
Where you would replace Row
with your corresponding row number.
answered Nov 20 '18 at 4:14
K.DᴀᴠɪsK.Dᴀᴠɪs
7,071112339
7,071112339
Glad to assist!
– K.Dᴀᴠɪs
Nov 20 '18 at 4:46
add a comment |
Glad to assist!
– K.Dᴀᴠɪs
Nov 20 '18 at 4:46
Glad to assist!
– K.Dᴀᴠɪs
Nov 20 '18 at 4:46
Glad to assist!
– K.Dᴀᴠɪs
Nov 20 '18 at 4:46
add a comment |
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