locate column location from variable and pass to .range“” code












1















I am using the partial code below to locate a borrower's name in a horizontal list. Once I find the name I need to pass the column and be able to reference that column in range("").value. So for example it finds the name in column G I can then use the range.value code and some how pair it up with different rows to do copy or do other things with.



Sub Copy_From_Borrower_DBase()
Dim myVal As String
Dim sourceRng As Range
myVal = Sheets("Main").Range("F2").Value ' dropdown list
Set sourceRng = Worksheets("Borrower Database").Range("5:5").Find( _
What:=myVal, LookAt:=xlWhole) 'locate column where to copy from
Sheets("Main").Range("F5").Value = Worksheets("Borrower Database"). _
Range("??????????").Value 'Borrower Name
End Sub









share|improve this question





























    1















    I am using the partial code below to locate a borrower's name in a horizontal list. Once I find the name I need to pass the column and be able to reference that column in range("").value. So for example it finds the name in column G I can then use the range.value code and some how pair it up with different rows to do copy or do other things with.



    Sub Copy_From_Borrower_DBase()
    Dim myVal As String
    Dim sourceRng As Range
    myVal = Sheets("Main").Range("F2").Value ' dropdown list
    Set sourceRng = Worksheets("Borrower Database").Range("5:5").Find( _
    What:=myVal, LookAt:=xlWhole) 'locate column where to copy from
    Sheets("Main").Range("F5").Value = Worksheets("Borrower Database"). _
    Range("??????????").Value 'Borrower Name
    End Sub









    share|improve this question



























      1












      1








      1








      I am using the partial code below to locate a borrower's name in a horizontal list. Once I find the name I need to pass the column and be able to reference that column in range("").value. So for example it finds the name in column G I can then use the range.value code and some how pair it up with different rows to do copy or do other things with.



      Sub Copy_From_Borrower_DBase()
      Dim myVal As String
      Dim sourceRng As Range
      myVal = Sheets("Main").Range("F2").Value ' dropdown list
      Set sourceRng = Worksheets("Borrower Database").Range("5:5").Find( _
      What:=myVal, LookAt:=xlWhole) 'locate column where to copy from
      Sheets("Main").Range("F5").Value = Worksheets("Borrower Database"). _
      Range("??????????").Value 'Borrower Name
      End Sub









      share|improve this question
















      I am using the partial code below to locate a borrower's name in a horizontal list. Once I find the name I need to pass the column and be able to reference that column in range("").value. So for example it finds the name in column G I can then use the range.value code and some how pair it up with different rows to do copy or do other things with.



      Sub Copy_From_Borrower_DBase()
      Dim myVal As String
      Dim sourceRng As Range
      myVal = Sheets("Main").Range("F2").Value ' dropdown list
      Set sourceRng = Worksheets("Borrower Database").Range("5:5").Find( _
      What:=myVal, LookAt:=xlWhole) 'locate column where to copy from
      Sheets("Main").Range("F5").Value = Worksheets("Borrower Database"). _
      Range("??????????").Value 'Borrower Name
      End Sub






      excel vba excel-vba






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      edited Nov 20 '18 at 7:11









      Pᴇʜ

      20.6k42650




      20.6k42650










      asked Nov 20 '18 at 3:52









      MECMEC

      697




      697
























          1 Answer
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          To grab the column from your sourceRng, you can simply use the .Column property. I personally would use Cells() instead of Range() since you're dealing with column numbers.



          So, in your use case:



          Worksheets("Main").Range("F5").Value = Worksheets("Borrower Database"). _
          Cells(Row, sourceRng.Column).Value 'Borrower Name


          Where you would replace Row with your corresponding row number.






          share|improve this answer
























          • Glad to assist!

            – K.Dᴀᴠɪs
            Nov 20 '18 at 4:46











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          1 Answer
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          active

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          0














          To grab the column from your sourceRng, you can simply use the .Column property. I personally would use Cells() instead of Range() since you're dealing with column numbers.



          So, in your use case:



          Worksheets("Main").Range("F5").Value = Worksheets("Borrower Database"). _
          Cells(Row, sourceRng.Column).Value 'Borrower Name


          Where you would replace Row with your corresponding row number.






          share|improve this answer
























          • Glad to assist!

            – K.Dᴀᴠɪs
            Nov 20 '18 at 4:46
















          0














          To grab the column from your sourceRng, you can simply use the .Column property. I personally would use Cells() instead of Range() since you're dealing with column numbers.



          So, in your use case:



          Worksheets("Main").Range("F5").Value = Worksheets("Borrower Database"). _
          Cells(Row, sourceRng.Column).Value 'Borrower Name


          Where you would replace Row with your corresponding row number.






          share|improve this answer
























          • Glad to assist!

            – K.Dᴀᴠɪs
            Nov 20 '18 at 4:46














          0












          0








          0







          To grab the column from your sourceRng, you can simply use the .Column property. I personally would use Cells() instead of Range() since you're dealing with column numbers.



          So, in your use case:



          Worksheets("Main").Range("F5").Value = Worksheets("Borrower Database"). _
          Cells(Row, sourceRng.Column).Value 'Borrower Name


          Where you would replace Row with your corresponding row number.






          share|improve this answer













          To grab the column from your sourceRng, you can simply use the .Column property. I personally would use Cells() instead of Range() since you're dealing with column numbers.



          So, in your use case:



          Worksheets("Main").Range("F5").Value = Worksheets("Borrower Database"). _
          Cells(Row, sourceRng.Column).Value 'Borrower Name


          Where you would replace Row with your corresponding row number.







          share|improve this answer












          share|improve this answer



          share|improve this answer










          answered Nov 20 '18 at 4:14









          K.DᴀᴠɪsK.Dᴀᴠɪs

          7,071112339




          7,071112339













          • Glad to assist!

            – K.Dᴀᴠɪs
            Nov 20 '18 at 4:46



















          • Glad to assist!

            – K.Dᴀᴠɪs
            Nov 20 '18 at 4:46

















          Glad to assist!

          – K.Dᴀᴠɪs
          Nov 20 '18 at 4:46





          Glad to assist!

          – K.Dᴀᴠɪs
          Nov 20 '18 at 4:46


















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