How to add a Friend's name (element) into a stack from my Driver Class? [duplicate]












-1
















This question already has an answer here:




  • How do I print my Java object without getting “SomeType@2f92e0f4”?

    10 answers




The user has to input name (ex: "jeff") and add it to the stack of friends. After that, the compiler prints the name of the friend added



(ex: print("Friend added: " + //friend's name)



Ive already tried this myself, but the compiler gives me some weird output (I enter the name "jeff", compiler prints back this:



("Friend added: Friend@3d4eac69").
Where did I go wrong? Here's my code:



Friend Class:



public class Friend{
private Stack friends;

public Friend(){
friends = new Stack(2);
}
public void addFriend(String name){
friends.push(name);
}
}


Profile class:



public class Profile{
private Friend f;

public Profile(String first, String last, int age){
f = new Friend();
}
}


Driver:



public class FBL{
private Scanner sc;
private Profile profiles;
private idx numPro;//number of profiles
public void FBL{
sc = new Scanner(System.in);
idx = -1;
nop = 0;
profiles = new Profile[3];
}
public void lolFriend(){
Friend newFriend = new Friend();
newFriend.addFriend(sc.nextLine());
System.out.println("Friend added: "+newFriend);
//main
//call lolFriend() method
}


I already have a class dedicated to Stacks, so here it is: https://pastebin.com/3y2sv4ia










share|improve this question













marked as duplicate by Scary Wombat java
Users with the  java badge can single-handedly close java questions as duplicates and reopen them as needed.

StackExchange.ready(function() {
if (StackExchange.options.isMobile) return;

$('.dupe-hammer-message-hover:not(.hover-bound)').each(function() {
var $hover = $(this).addClass('hover-bound'),
$msg = $hover.siblings('.dupe-hammer-message');

$hover.hover(
function() {
$hover.showInfoMessage('', {
messageElement: $msg.clone().show(),
transient: false,
position: { my: 'bottom left', at: 'top center', offsetTop: -7 },
dismissable: false,
relativeToBody: true
});
},
function() {
StackExchange.helpers.removeMessages();
}
);
});
});
Nov 20 '18 at 4:08


This question has been asked before and already has an answer. If those answers do not fully address your question, please ask a new question.
















  • System.out.println("Friend added: "+newFriend); => you attempt to print out the name of the class, an @ symbol and the hashcode of the object in hexadecimal. Because that how it works my friend. should get the stack inside the Friend then print out first element

    – Dang Nguyen
    Nov 20 '18 at 3:53











  • How do i print the first element of my stack thats from another class?

    – lol k
    Nov 20 '18 at 4:03
















-1
















This question already has an answer here:




  • How do I print my Java object without getting “SomeType@2f92e0f4”?

    10 answers




The user has to input name (ex: "jeff") and add it to the stack of friends. After that, the compiler prints the name of the friend added



(ex: print("Friend added: " + //friend's name)



Ive already tried this myself, but the compiler gives me some weird output (I enter the name "jeff", compiler prints back this:



("Friend added: Friend@3d4eac69").
Where did I go wrong? Here's my code:



Friend Class:



public class Friend{
private Stack friends;

public Friend(){
friends = new Stack(2);
}
public void addFriend(String name){
friends.push(name);
}
}


Profile class:



public class Profile{
private Friend f;

public Profile(String first, String last, int age){
f = new Friend();
}
}


Driver:



public class FBL{
private Scanner sc;
private Profile profiles;
private idx numPro;//number of profiles
public void FBL{
sc = new Scanner(System.in);
idx = -1;
nop = 0;
profiles = new Profile[3];
}
public void lolFriend(){
Friend newFriend = new Friend();
newFriend.addFriend(sc.nextLine());
System.out.println("Friend added: "+newFriend);
//main
//call lolFriend() method
}


I already have a class dedicated to Stacks, so here it is: https://pastebin.com/3y2sv4ia










share|improve this question













marked as duplicate by Scary Wombat java
Users with the  java badge can single-handedly close java questions as duplicates and reopen them as needed.

StackExchange.ready(function() {
if (StackExchange.options.isMobile) return;

$('.dupe-hammer-message-hover:not(.hover-bound)').each(function() {
var $hover = $(this).addClass('hover-bound'),
$msg = $hover.siblings('.dupe-hammer-message');

$hover.hover(
function() {
$hover.showInfoMessage('', {
messageElement: $msg.clone().show(),
transient: false,
position: { my: 'bottom left', at: 'top center', offsetTop: -7 },
dismissable: false,
relativeToBody: true
});
},
function() {
StackExchange.helpers.removeMessages();
}
);
});
});
Nov 20 '18 at 4:08


This question has been asked before and already has an answer. If those answers do not fully address your question, please ask a new question.
















  • System.out.println("Friend added: "+newFriend); => you attempt to print out the name of the class, an @ symbol and the hashcode of the object in hexadecimal. Because that how it works my friend. should get the stack inside the Friend then print out first element

    – Dang Nguyen
    Nov 20 '18 at 3:53











  • How do i print the first element of my stack thats from another class?

    – lol k
    Nov 20 '18 at 4:03














-1












-1








-1









This question already has an answer here:




  • How do I print my Java object without getting “SomeType@2f92e0f4”?

    10 answers




The user has to input name (ex: "jeff") and add it to the stack of friends. After that, the compiler prints the name of the friend added



(ex: print("Friend added: " + //friend's name)



Ive already tried this myself, but the compiler gives me some weird output (I enter the name "jeff", compiler prints back this:



("Friend added: Friend@3d4eac69").
Where did I go wrong? Here's my code:



Friend Class:



public class Friend{
private Stack friends;

public Friend(){
friends = new Stack(2);
}
public void addFriend(String name){
friends.push(name);
}
}


Profile class:



public class Profile{
private Friend f;

public Profile(String first, String last, int age){
f = new Friend();
}
}


Driver:



public class FBL{
private Scanner sc;
private Profile profiles;
private idx numPro;//number of profiles
public void FBL{
sc = new Scanner(System.in);
idx = -1;
nop = 0;
profiles = new Profile[3];
}
public void lolFriend(){
Friend newFriend = new Friend();
newFriend.addFriend(sc.nextLine());
System.out.println("Friend added: "+newFriend);
//main
//call lolFriend() method
}


I already have a class dedicated to Stacks, so here it is: https://pastebin.com/3y2sv4ia










share|improve this question















This question already has an answer here:




  • How do I print my Java object without getting “SomeType@2f92e0f4”?

    10 answers




The user has to input name (ex: "jeff") and add it to the stack of friends. After that, the compiler prints the name of the friend added



(ex: print("Friend added: " + //friend's name)



Ive already tried this myself, but the compiler gives me some weird output (I enter the name "jeff", compiler prints back this:



("Friend added: Friend@3d4eac69").
Where did I go wrong? Here's my code:



Friend Class:



public class Friend{
private Stack friends;

public Friend(){
friends = new Stack(2);
}
public void addFriend(String name){
friends.push(name);
}
}


Profile class:



public class Profile{
private Friend f;

public Profile(String first, String last, int age){
f = new Friend();
}
}


Driver:



public class FBL{
private Scanner sc;
private Profile profiles;
private idx numPro;//number of profiles
public void FBL{
sc = new Scanner(System.in);
idx = -1;
nop = 0;
profiles = new Profile[3];
}
public void lolFriend(){
Friend newFriend = new Friend();
newFriend.addFriend(sc.nextLine());
System.out.println("Friend added: "+newFriend);
//main
//call lolFriend() method
}


I already have a class dedicated to Stacks, so here it is: https://pastebin.com/3y2sv4ia





This question already has an answer here:




  • How do I print my Java object without getting “SomeType@2f92e0f4”?

    10 answers








java stack






share|improve this question













share|improve this question











share|improve this question




share|improve this question










asked Nov 20 '18 at 3:44









lol klol k

113




113




marked as duplicate by Scary Wombat java
Users with the  java badge can single-handedly close java questions as duplicates and reopen them as needed.

StackExchange.ready(function() {
if (StackExchange.options.isMobile) return;

$('.dupe-hammer-message-hover:not(.hover-bound)').each(function() {
var $hover = $(this).addClass('hover-bound'),
$msg = $hover.siblings('.dupe-hammer-message');

$hover.hover(
function() {
$hover.showInfoMessage('', {
messageElement: $msg.clone().show(),
transient: false,
position: { my: 'bottom left', at: 'top center', offsetTop: -7 },
dismissable: false,
relativeToBody: true
});
},
function() {
StackExchange.helpers.removeMessages();
}
);
});
});
Nov 20 '18 at 4:08


This question has been asked before and already has an answer. If those answers do not fully address your question, please ask a new question.






marked as duplicate by Scary Wombat java
Users with the  java badge can single-handedly close java questions as duplicates and reopen them as needed.

StackExchange.ready(function() {
if (StackExchange.options.isMobile) return;

$('.dupe-hammer-message-hover:not(.hover-bound)').each(function() {
var $hover = $(this).addClass('hover-bound'),
$msg = $hover.siblings('.dupe-hammer-message');

$hover.hover(
function() {
$hover.showInfoMessage('', {
messageElement: $msg.clone().show(),
transient: false,
position: { my: 'bottom left', at: 'top center', offsetTop: -7 },
dismissable: false,
relativeToBody: true
});
},
function() {
StackExchange.helpers.removeMessages();
}
);
});
});
Nov 20 '18 at 4:08


This question has been asked before and already has an answer. If those answers do not fully address your question, please ask a new question.















  • System.out.println("Friend added: "+newFriend); => you attempt to print out the name of the class, an @ symbol and the hashcode of the object in hexadecimal. Because that how it works my friend. should get the stack inside the Friend then print out first element

    – Dang Nguyen
    Nov 20 '18 at 3:53











  • How do i print the first element of my stack thats from another class?

    – lol k
    Nov 20 '18 at 4:03



















  • System.out.println("Friend added: "+newFriend); => you attempt to print out the name of the class, an @ symbol and the hashcode of the object in hexadecimal. Because that how it works my friend. should get the stack inside the Friend then print out first element

    – Dang Nguyen
    Nov 20 '18 at 3:53











  • How do i print the first element of my stack thats from another class?

    – lol k
    Nov 20 '18 at 4:03

















System.out.println("Friend added: "+newFriend); => you attempt to print out the name of the class, an @ symbol and the hashcode of the object in hexadecimal. Because that how it works my friend. should get the stack inside the Friend then print out first element

– Dang Nguyen
Nov 20 '18 at 3:53





System.out.println("Friend added: "+newFriend); => you attempt to print out the name of the class, an @ symbol and the hashcode of the object in hexadecimal. Because that how it works my friend. should get the stack inside the Friend then print out first element

– Dang Nguyen
Nov 20 '18 at 3:53













How do i print the first element of my stack thats from another class?

– lol k
Nov 20 '18 at 4:03





How do i print the first element of my stack thats from another class?

– lol k
Nov 20 '18 at 4:03












1 Answer
1






active

oldest

votes


















0














You need to override the toString() method of the Friend class as follows :



@Override
public String toString() {
return "Friend [friends=" + friends + "]";
}


What are seeing now is the address of the object represented in the format




NameOfObjectType@MemoryLocationOfObject




Also, your code is not compiling change this friends = new Stack(2); to friends = new Stack();. There is no parameterized constructor for the class Stack






share|improve this answer
































    1 Answer
    1






    active

    oldest

    votes








    1 Answer
    1






    active

    oldest

    votes









    active

    oldest

    votes






    active

    oldest

    votes









    0














    You need to override the toString() method of the Friend class as follows :



    @Override
    public String toString() {
    return "Friend [friends=" + friends + "]";
    }


    What are seeing now is the address of the object represented in the format




    NameOfObjectType@MemoryLocationOfObject




    Also, your code is not compiling change this friends = new Stack(2); to friends = new Stack();. There is no parameterized constructor for the class Stack






    share|improve this answer






























      0














      You need to override the toString() method of the Friend class as follows :



      @Override
      public String toString() {
      return "Friend [friends=" + friends + "]";
      }


      What are seeing now is the address of the object represented in the format




      NameOfObjectType@MemoryLocationOfObject




      Also, your code is not compiling change this friends = new Stack(2); to friends = new Stack();. There is no parameterized constructor for the class Stack






      share|improve this answer




























        0












        0








        0







        You need to override the toString() method of the Friend class as follows :



        @Override
        public String toString() {
        return "Friend [friends=" + friends + "]";
        }


        What are seeing now is the address of the object represented in the format




        NameOfObjectType@MemoryLocationOfObject




        Also, your code is not compiling change this friends = new Stack(2); to friends = new Stack();. There is no parameterized constructor for the class Stack






        share|improve this answer















        You need to override the toString() method of the Friend class as follows :



        @Override
        public String toString() {
        return "Friend [friends=" + friends + "]";
        }


        What are seeing now is the address of the object represented in the format




        NameOfObjectType@MemoryLocationOfObject




        Also, your code is not compiling change this friends = new Stack(2); to friends = new Stack();. There is no parameterized constructor for the class Stack







        share|improve this answer














        share|improve this answer



        share|improve this answer








        edited Nov 20 '18 at 4:08

























        answered Nov 20 '18 at 3:58









        Nicholas KNicholas K

        6,16751031




        6,16751031















            Popular posts from this blog

            android studio warns about leanback feature tag usage required on manifest while using Unity exported app?

            SQL update select statement

            WPF add header to Image with URL pettitions [duplicate]