fade out container, change content, fade in container
I'm trying to fade out a container div, then replace another div inside it, then after all content is loaded, fade in the container div again. My code fades out and loads the content but opacity stays at 0. Can someone point me how to make this work? Why does the opacity stay at 0?
Here's the jQuery:
$("#button").click(function(){
$('#content').fadeOut(600, function(){
$("#container").css("opacity", "0");
$.get("frontpage.html", function(data) {
$("#content").replaceWith(data), function(){
$("#container").css("opacity", "1");
};
});
});
});
and html is simply:
<div id="container">
<div id="content"></div>
</div>
CSS:
#container {
transition: opacity 0.6s ease-in-out;
}
jquery
add a comment |
I'm trying to fade out a container div, then replace another div inside it, then after all content is loaded, fade in the container div again. My code fades out and loads the content but opacity stays at 0. Can someone point me how to make this work? Why does the opacity stay at 0?
Here's the jQuery:
$("#button").click(function(){
$('#content').fadeOut(600, function(){
$("#container").css("opacity", "0");
$.get("frontpage.html", function(data) {
$("#content").replaceWith(data), function(){
$("#container").css("opacity", "1");
};
});
});
});
and html is simply:
<div id="container">
<div id="content"></div>
</div>
CSS:
#container {
transition: opacity 0.6s ease-in-out;
}
jquery
try to use.done()
$.get(Replace_Part_Here).done(return_opacity)
and keep eyes on console for errors this.replaceWith(data), function(){
should gives you an error
– Mohamed-Yousef
Nov 19 '18 at 17:54
add a comment |
I'm trying to fade out a container div, then replace another div inside it, then after all content is loaded, fade in the container div again. My code fades out and loads the content but opacity stays at 0. Can someone point me how to make this work? Why does the opacity stay at 0?
Here's the jQuery:
$("#button").click(function(){
$('#content').fadeOut(600, function(){
$("#container").css("opacity", "0");
$.get("frontpage.html", function(data) {
$("#content").replaceWith(data), function(){
$("#container").css("opacity", "1");
};
});
});
});
and html is simply:
<div id="container">
<div id="content"></div>
</div>
CSS:
#container {
transition: opacity 0.6s ease-in-out;
}
jquery
I'm trying to fade out a container div, then replace another div inside it, then after all content is loaded, fade in the container div again. My code fades out and loads the content but opacity stays at 0. Can someone point me how to make this work? Why does the opacity stay at 0?
Here's the jQuery:
$("#button").click(function(){
$('#content').fadeOut(600, function(){
$("#container").css("opacity", "0");
$.get("frontpage.html", function(data) {
$("#content").replaceWith(data), function(){
$("#container").css("opacity", "1");
};
});
});
});
and html is simply:
<div id="container">
<div id="content"></div>
</div>
CSS:
#container {
transition: opacity 0.6s ease-in-out;
}
jquery
jquery
asked Nov 19 '18 at 17:48
Ilkka Gustafsson
163
163
try to use.done()
$.get(Replace_Part_Here).done(return_opacity)
and keep eyes on console for errors this.replaceWith(data), function(){
should gives you an error
– Mohamed-Yousef
Nov 19 '18 at 17:54
add a comment |
try to use.done()
$.get(Replace_Part_Here).done(return_opacity)
and keep eyes on console for errors this.replaceWith(data), function(){
should gives you an error
– Mohamed-Yousef
Nov 19 '18 at 17:54
try to use
.done()
$.get(Replace_Part_Here).done(return_opacity)
and keep eyes on console for errors this .replaceWith(data), function(){
should gives you an error– Mohamed-Yousef
Nov 19 '18 at 17:54
try to use
.done()
$.get(Replace_Part_Here).done(return_opacity)
and keep eyes on console for errors this .replaceWith(data), function(){
should gives you an error– Mohamed-Yousef
Nov 19 '18 at 17:54
add a comment |
1 Answer
1
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oldest
votes
I don't think it's picking up that last call to function()
. Try running your code in the same callback.
$.get("frontpage.html", function(data) {
$("#content").replaceWith(data);
$("#container").css("opacity", "1");
});
add a comment |
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1 Answer
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active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
I don't think it's picking up that last call to function()
. Try running your code in the same callback.
$.get("frontpage.html", function(data) {
$("#content").replaceWith(data);
$("#container").css("opacity", "1");
});
add a comment |
I don't think it's picking up that last call to function()
. Try running your code in the same callback.
$.get("frontpage.html", function(data) {
$("#content").replaceWith(data);
$("#container").css("opacity", "1");
});
add a comment |
I don't think it's picking up that last call to function()
. Try running your code in the same callback.
$.get("frontpage.html", function(data) {
$("#content").replaceWith(data);
$("#container").css("opacity", "1");
});
I don't think it's picking up that last call to function()
. Try running your code in the same callback.
$.get("frontpage.html", function(data) {
$("#content").replaceWith(data);
$("#container").css("opacity", "1");
});
answered Nov 19 '18 at 17:56


jmargolisvt
2,96341526
2,96341526
add a comment |
add a comment |
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try to use
.done()
$.get(Replace_Part_Here).done(return_opacity)
and keep eyes on console for errors this.replaceWith(data), function(){
should gives you an error– Mohamed-Yousef
Nov 19 '18 at 17:54