Mixing
How do I include multiple conditions for MySql query?
I am trying to count the number of clinics in each zipcode for my table. Using the query below, this counts the number of clinics but also includes repetitions. E.g Clinic A is shown to appear in 5 rows because there is a column that shows the days for each clinic. To make this easy to understand, please look at a snapshot of my table: 
So you see there are some addresses that appear only on one day and some appear more than once. How do I write my query to account for that? I tried addresses but it gave me a syntax error. Here is what I tried but I know its still adding repeated clinics:
SELECT SUBSTRING_INDEX(Date, "/", -1) As `Year`, `ZIP Code`, COUNT(`ZIP Code`) AS `Facilities` FROM `past_chicago_clinics` GROUP BY `ZIP Code`, `Year`
The result of the query is shown below:
mysql
asked Nov 20 '18 at 2:51
cheenacheena
2410
add a comment |
I am trying to count the number of clinics in each zipcode for my table. Using the query below, this counts the number of clinics but also includes repetitions. E.g Clinic A is shown to appear in 5 rows because there is a column that shows the days for each clinic. To make this easy to understand, please look at a snapshot of my table: So you see there are some addresses that appear only on one day and some appear more than once. How do I write my query to account for that? I tried addresses but it gave me a syntax error. Here is what I tried but I know its still adding repeated clinics:
SELECT SUBSTRING_INDEX(Date, "/", -1) As `Year`, `ZIP Code`, COUNT(`ZIP Code`) AS `Facilities` FROM `past_chicago_clinics` GROUP BY `ZIP Code`, `Year`
The result of the query is shown below:
mysql
asked Nov 20 '18 at 2:51
cheenacheena
2410
add a comment |
I am trying to count the number of clinics in each zipcode for my table. Using the query below, this counts the number of clinics but also includes repetitions. E.g Clinic A is shown to appear in 5 rows because there is a column that shows the days for each clinic. To make this easy to understand, please look at a snapshot of my table: So you see there are some addresses that appear only on one day and some appear more than once. How do I write my query to account for that? I tried addresses but it gave me a syntax error. Here is what I tried but I know its still adding repeated clinics:
SELECT SUBSTRING_INDEX(Date, "/", -1) As `Year`, `ZIP Code`, COUNT(`ZIP Code`) AS `Facilities` FROM `past_chicago_clinics` GROUP BY `ZIP Code`, `Year`
The result of the query is shown below:
mysql
asked Nov 20 '18 at 2:51
cheenacheena
2410
I am trying to count the number of clinics in each zipcode for my table. Using the query below, this counts the number of clinics but also includes repetitions. E.g Clinic A is shown to appear in 5 rows because there is a column that shows the days for each clinic. To make this easy to understand, please look at a snapshot of my table: So you see there are some addresses that appear only on one day and some appear more than once. How do I write my query to account for that? I tried addresses but it gave me a syntax error. Here is what I tried but I know its still adding repeated clinics:
SELECT SUBSTRING_INDEX(Date, "/", -1) As `Year`, `ZIP Code`, COUNT(`ZIP Code`) AS `Facilities` FROM `past_chicago_clinics` GROUP BY `ZIP Code`, `Year`
The result of the query is shown below:
mysql
mysql
asked Nov 20 '18 at 2:51
cheenacheena
2410
asked Nov 20 '18 at 2:51
cheenacheena
2410
asked Nov 20 '18 at 2:51
cheenacheena
2410
asked Nov 20 '18 at 2:51
cheenacheena
2410
asked Nov 20 '18 at 2:51
cheenacheena
2410
2410
add a comment |
add a comment |
1 Answer
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The word 'distinct' just came to me. I simply edited my code to:
SELECT SUBSTRING_INDEX(Date, "/", -1) As `Year`, `ZIP Code`, COUNT(DISTINCT `Address`) AS `Facilities` FROM `past_chicago_clinics` GROUP BY `ZIP Code`, `Year`
This shows the number of unique addresses and thus, the number of clinics based on the address.
answered Nov 20 '18 at 3:00
cheenacheena
2410
add a comment |
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1 Answer
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1 Answer
1
active
oldest
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active
oldest
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active
oldest
votes
The word 'distinct' just came to me. I simply edited my code to:
SELECT SUBSTRING_INDEX(Date, "/", -1) As `Year`, `ZIP Code`, COUNT(DISTINCT `Address`) AS `Facilities` FROM `past_chicago_clinics` GROUP BY `ZIP Code`, `Year`
This shows the number of unique addresses and thus, the number of clinics based on the address.
answered Nov 20 '18 at 3:00
cheenacheena
2410
add a comment |
The word 'distinct' just came to me. I simply edited my code to:
SELECT SUBSTRING_INDEX(Date, "/", -1) As `Year`, `ZIP Code`, COUNT(DISTINCT `Address`) AS `Facilities` FROM `past_chicago_clinics` GROUP BY `ZIP Code`, `Year`
This shows the number of unique addresses and thus, the number of clinics based on the address.
answered Nov 20 '18 at 3:00
cheenacheena
2410
add a comment |
The word 'distinct' just came to me. I simply edited my code to:
SELECT SUBSTRING_INDEX(Date, "/", -1) As `Year`, `ZIP Code`, COUNT(DISTINCT `Address`) AS `Facilities` FROM `past_chicago_clinics` GROUP BY `ZIP Code`, `Year`
This shows the number of unique addresses and thus, the number of clinics based on the address.
answered Nov 20 '18 at 3:00
cheenacheena
2410
The word 'distinct' just came to me. I simply edited my code to:
SELECT SUBSTRING_INDEX(Date, "/", -1) As `Year`, `ZIP Code`, COUNT(DISTINCT `Address`) AS `Facilities` FROM `past_chicago_clinics` GROUP BY `ZIP Code`, `Year`
This shows the number of unique addresses and thus, the number of clinics based on the address.
answered Nov 20 '18 at 3:00
cheenacheena
2410
answered Nov 20 '18 at 3:00
cheenacheena
2410
answered Nov 20 '18 at 3:00
cheenacheena
2410
answered Nov 20 '18 at 3:00
cheenacheena
2410
2410
add a comment |
add a comment |
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