Prove that the rank of $(1-I)$ is $n$
1
1
$begingroup$
The rank of $(1-I_n)$, where $1$ is the $n times n$ all-1 matrix and $I_n$ the $n times n$ identity matrix, seems to be $n$. How to prove this concisely?
linear-algebra matrices
share | cite | improve this question
edited Jun 20 '13 at 18:57
Davide Giraudo
128k 17 156 268
asked Jun 20 '13 at 18:02
ranky ranky
6 1
$endgroup$
...
