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Prove that the rank of $(1-I)$ is $n$

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1 1 $begingroup$ The rank of $(1-I_n)$, where $1$ is the $n times n$ all-1 matrix and $I_n$ the $n times n$ identity matrix, seems to be $n$. How to prove this concisely? linear-algebra matrices share | cite | improve this question edited Jun 20 '13 at 18:57 Davide Giraudo 128k 17 156 268 asked Jun 20 '13 at 18:02 ranky ranky 6 1 $endgroup$ ...