If $vtimes w = 4i + 7j + 5k$ then what is $vtimes w + wtimes v$?
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If $vtimes w = 4i + 7j + 5k$ then what is $vtimes w + wtimes v$?
$v$ and $w$ are vectors, they aren't given. I have no idea how to do this and apparently it's asked on a quiz as a "surprise" question.
multivariable-calculus vectors 3d
New contributor
add a comment |
up vote
-3
down vote
favorite
If $vtimes w = 4i + 7j + 5k$ then what is $vtimes w + wtimes v$?
$v$ and $w$ are vectors, they aren't given. I have no idea how to do this and apparently it's asked on a quiz as a "surprise" question.
multivariable-calculus vectors 3d
New contributor
The edited title and question were significantly more readable. When rendered, the command times is displayed as the appropriate cross product symbol. The title is now not very unreadable.
– Joey Kilpatrick
22 hours ago
add a comment |
up vote
-3
down vote
favorite
up vote
-3
down vote
favorite
If $vtimes w = 4i + 7j + 5k$ then what is $vtimes w + wtimes v$?
$v$ and $w$ are vectors, they aren't given. I have no idea how to do this and apparently it's asked on a quiz as a "surprise" question.
multivariable-calculus vectors 3d
New contributor
If $vtimes w = 4i + 7j + 5k$ then what is $vtimes w + wtimes v$?
$v$ and $w$ are vectors, they aren't given. I have no idea how to do this and apparently it's asked on a quiz as a "surprise" question.
multivariable-calculus vectors 3d
multivariable-calculus vectors 3d
New contributor
New contributor
edited 21 hours ago
Brahadeesh
5,52941956
5,52941956
New contributor
asked 22 hours ago
ufotink
43
43
New contributor
New contributor
The edited title and question were significantly more readable. When rendered, the command times is displayed as the appropriate cross product symbol. The title is now not very unreadable.
– Joey Kilpatrick
22 hours ago
add a comment |
The edited title and question were significantly more readable. When rendered, the command times is displayed as the appropriate cross product symbol. The title is now not very unreadable.
– Joey Kilpatrick
22 hours ago
The edited title and question were significantly more readable. When rendered, the command times is displayed as the appropriate cross product symbol. The title is now not very unreadable.
– Joey Kilpatrick
22 hours ago
The edited title and question were significantly more readable. When rendered, the command times is displayed as the appropriate cross product symbol. The title is now not very unreadable.
– Joey Kilpatrick
22 hours ago
add a comment |
1 Answer
1
active
oldest
votes
up vote
2
down vote
Note that the cross product is what we call anti-commutative, i.e.
$$(vec{v} times vec{w}) = - (vec{w} times vec{v})$$
I feel like this fact will simplify your work greatly.
thanks! I figured it out if I'm correct, the answer would be 0?
– ufotink
22 hours ago
Well, the zero vector, $vec{0} = 0hat{i} + 0hat{j} + 0hat{k}$, more appropriately, but yeah you get the idea.
– Eevee Trainer
22 hours ago
add a comment |
1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
up vote
2
down vote
Note that the cross product is what we call anti-commutative, i.e.
$$(vec{v} times vec{w}) = - (vec{w} times vec{v})$$
I feel like this fact will simplify your work greatly.
thanks! I figured it out if I'm correct, the answer would be 0?
– ufotink
22 hours ago
Well, the zero vector, $vec{0} = 0hat{i} + 0hat{j} + 0hat{k}$, more appropriately, but yeah you get the idea.
– Eevee Trainer
22 hours ago
add a comment |
up vote
2
down vote
Note that the cross product is what we call anti-commutative, i.e.
$$(vec{v} times vec{w}) = - (vec{w} times vec{v})$$
I feel like this fact will simplify your work greatly.
thanks! I figured it out if I'm correct, the answer would be 0?
– ufotink
22 hours ago
Well, the zero vector, $vec{0} = 0hat{i} + 0hat{j} + 0hat{k}$, more appropriately, but yeah you get the idea.
– Eevee Trainer
22 hours ago
add a comment |
up vote
2
down vote
up vote
2
down vote
Note that the cross product is what we call anti-commutative, i.e.
$$(vec{v} times vec{w}) = - (vec{w} times vec{v})$$
I feel like this fact will simplify your work greatly.
Note that the cross product is what we call anti-commutative, i.e.
$$(vec{v} times vec{w}) = - (vec{w} times vec{v})$$
I feel like this fact will simplify your work greatly.
answered 22 hours ago
Eevee Trainer
8278
8278
thanks! I figured it out if I'm correct, the answer would be 0?
– ufotink
22 hours ago
Well, the zero vector, $vec{0} = 0hat{i} + 0hat{j} + 0hat{k}$, more appropriately, but yeah you get the idea.
– Eevee Trainer
22 hours ago
add a comment |
thanks! I figured it out if I'm correct, the answer would be 0?
– ufotink
22 hours ago
Well, the zero vector, $vec{0} = 0hat{i} + 0hat{j} + 0hat{k}$, more appropriately, but yeah you get the idea.
– Eevee Trainer
22 hours ago
thanks! I figured it out if I'm correct, the answer would be 0?
– ufotink
22 hours ago
thanks! I figured it out if I'm correct, the answer would be 0?
– ufotink
22 hours ago
Well, the zero vector, $vec{0} = 0hat{i} + 0hat{j} + 0hat{k}$, more appropriately, but yeah you get the idea.
– Eevee Trainer
22 hours ago
Well, the zero vector, $vec{0} = 0hat{i} + 0hat{j} + 0hat{k}$, more appropriately, but yeah you get the idea.
– Eevee Trainer
22 hours ago
add a comment |
ufotink is a new contributor. Be nice, and check out our Code of Conduct.
ufotink is a new contributor. Be nice, and check out our Code of Conduct.
ufotink is a new contributor. Be nice, and check out our Code of Conduct.
ufotink is a new contributor. Be nice, and check out our Code of Conduct.
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The edited title and question were significantly more readable. When rendered, the command times is displayed as the appropriate cross product symbol. The title is now not very unreadable.
– Joey Kilpatrick
22 hours ago