Approximating left continuous process $(L_t)_{0 leq t leq T}$ uniformly on $[0,T]$ by step functions on the...












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The question is closely related to optional quadratic variation. If I have a left-continuous adapted stochastic process $(L_t)_{0 leq t leq T}$ with $L_0 = 0$ on the probability space $(Omega, mathcal{F},P)$, is it possible to approximate it uniformly on $[0,T]$ on the dyadics by step functions, i.e. if $D_n=2^{-n} T mathbb{N} cap [0,T]$ is the set of all $n$-th dyadic points, do I have the following convergence
$$
sup_{t in [0,T]}left|L_t(omega) - sum_{t_i in D_n}L_{t_i}(omega) 1_{((t_i,t_i+1]]}(t, omega)right| rightarrow 0, text{ for } n rightarrow infty
$$

for almost every $omega in Omega$ ? The function $1_{((t_i,t_{i+1}]]}$ denotes the left half open stochastic interval.



Thanks a lot in advance!










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    $begingroup$


    The question is closely related to optional quadratic variation. If I have a left-continuous adapted stochastic process $(L_t)_{0 leq t leq T}$ with $L_0 = 0$ on the probability space $(Omega, mathcal{F},P)$, is it possible to approximate it uniformly on $[0,T]$ on the dyadics by step functions, i.e. if $D_n=2^{-n} T mathbb{N} cap [0,T]$ is the set of all $n$-th dyadic points, do I have the following convergence
    $$
    sup_{t in [0,T]}left|L_t(omega) - sum_{t_i in D_n}L_{t_i}(omega) 1_{((t_i,t_i+1]]}(t, omega)right| rightarrow 0, text{ for } n rightarrow infty
    $$

    for almost every $omega in Omega$ ? The function $1_{((t_i,t_{i+1}]]}$ denotes the left half open stochastic interval.



    Thanks a lot in advance!










    share|cite|improve this question











    $endgroup$















      3












      3








      3


      1



      $begingroup$


      The question is closely related to optional quadratic variation. If I have a left-continuous adapted stochastic process $(L_t)_{0 leq t leq T}$ with $L_0 = 0$ on the probability space $(Omega, mathcal{F},P)$, is it possible to approximate it uniformly on $[0,T]$ on the dyadics by step functions, i.e. if $D_n=2^{-n} T mathbb{N} cap [0,T]$ is the set of all $n$-th dyadic points, do I have the following convergence
      $$
      sup_{t in [0,T]}left|L_t(omega) - sum_{t_i in D_n}L_{t_i}(omega) 1_{((t_i,t_i+1]]}(t, omega)right| rightarrow 0, text{ for } n rightarrow infty
      $$

      for almost every $omega in Omega$ ? The function $1_{((t_i,t_{i+1}]]}$ denotes the left half open stochastic interval.



      Thanks a lot in advance!










      share|cite|improve this question











      $endgroup$




      The question is closely related to optional quadratic variation. If I have a left-continuous adapted stochastic process $(L_t)_{0 leq t leq T}$ with $L_0 = 0$ on the probability space $(Omega, mathcal{F},P)$, is it possible to approximate it uniformly on $[0,T]$ on the dyadics by step functions, i.e. if $D_n=2^{-n} T mathbb{N} cap [0,T]$ is the set of all $n$-th dyadic points, do I have the following convergence
      $$
      sup_{t in [0,T]}left|L_t(omega) - sum_{t_i in D_n}L_{t_i}(omega) 1_{((t_i,t_i+1]]}(t, omega)right| rightarrow 0, text{ for } n rightarrow infty
      $$

      for almost every $omega in Omega$ ? The function $1_{((t_i,t_{i+1}]]}$ denotes the left half open stochastic interval.



      Thanks a lot in advance!







      probability probability-theory stochastic-processes stochastic-calculus stochastic-analysis






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      share|cite|improve this question













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      edited Jan 2 at 14:43









      Davide Giraudo

      125k16150261




      125k16150261










      asked Jan 2 at 12:01









      vaoyvaoy

      537210




      537210






















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