Compare one String with multiple values in one expression

I have one String variable, str with possible values, val1, val2 and val3.

I want to compare (with equal case) str to all of these values using an if statement, for example:

if("val1".equalsIgnoreCase(str)||"val2".equalsIgnoreCase(str)||"val3.equalsIgnoreCase(str))

{

      //remaining code

}

Is there a way to avoid using multiple OR (||) operators and compare values in one expression? For example, like this:

 if(("val1" OR "val2" OR "val3").equalsIgnoreCase(str)   //this is only an idea.

edited Apr 2 '15 at 4:45

asked Apr 18 '12 at 8:13

kundan bora

2,72811527

1

possible duplicate of A Cleaner IF Statement

– WoodenKitty
Jan 17 '15 at 3:07

add a comment |

I have one String variable, str with possible values, val1, val2 and val3.

I want to compare (with equal case) str to all of these values using an if statement, for example:

if("val1".equalsIgnoreCase(str)||"val2".equalsIgnoreCase(str)||"val3.equalsIgnoreCase(str))

{

      //remaining code

}

Is there a way to avoid using multiple OR (||) operators and compare values in one expression? For example, like this:

 if(("val1" OR "val2" OR "val3").equalsIgnoreCase(str)   //this is only an idea.

edited Apr 2 '15 at 4:45

asked Apr 18 '12 at 8:13

kundan bora

2,72811527

1

possible duplicate of A Cleaner IF Statement

– WoodenKitty
Jan 17 '15 at 3:07

add a comment |

I have one String variable, str with possible values, val1, val2 and val3.

I want to compare (with equal case) str to all of these values using an if statement, for example:

if("val1".equalsIgnoreCase(str)||"val2".equalsIgnoreCase(str)||"val3.equalsIgnoreCase(str))

{

      //remaining code

}

Is there a way to avoid using multiple OR (||) operators and compare values in one expression? For example, like this:

 if(("val1" OR "val2" OR "val3").equalsIgnoreCase(str)   //this is only an idea.

edited Apr 2 '15 at 4:45

asked Apr 18 '12 at 8:13

kundan bora

2,72811527

I have one String variable, str with possible values, val1, val2 and val3.

I want to compare (with equal case) str to all of these values using an if statement, for example:

if("val1".equalsIgnoreCase(str)||"val2".equalsIgnoreCase(str)||"val3.equalsIgnoreCase(str))

{

      //remaining code

}

Is there a way to avoid using multiple OR (||) operators and compare values in one expression? For example, like this:

 if(("val1" OR "val2" OR "val3").equalsIgnoreCase(str)   //this is only an idea.

java regex string

edited Apr 2 '15 at 4:45

asked Apr 18 '12 at 8:13

kundan bora

2,72811527

edited Apr 2 '15 at 4:45

asked Apr 18 '12 at 8:13

kundan bora

2,72811527

edited Apr 2 '15 at 4:45

asked Apr 18 '12 at 8:13

kundan bora

2,72811527

asked Apr 18 '12 at 8:13

kundan bora

2,72811527

asked Apr 18 '12 at 8:13

kundan bora

2,72811527

1

possible duplicate of A Cleaner IF Statement

– WoodenKitty
Jan 17 '15 at 3:07

add a comment |

1

possible duplicate of A Cleaner IF Statement

– WoodenKitty
Jan 17 '15 at 3:07

possible duplicate of A Cleaner IF Statement

– WoodenKitty
Jan 17 '15 at 3:07

add a comment |

12 Answers
12

active

oldest

votes

I found the better solution. This can be achieved through RegEx:

if (str.matches("val1|val2|val3")) {

     // remaining code

}

For case insensitive matching:

if (str.matches("(?i)val1|val2|val3")) {

     // remaining code

}

edited Aug 3 '18 at 7:07

answered Apr 18 '12 at 15:59

kundan bora

2,72811527

The matches function does not work well for all cases. The answer of @hmjd did it for my case. See Regex doesn't work in String.matches() for more info.

– Primoz990
May 11 '17 at 10:20

add a comment |

In Java 8+, you might use a Stream<T> and anyMatch(Predicate<? super T>) with something like

if (Stream.of("val1", "val2", "val3").anyMatch(str::equalsIgnoreCase)) {

    // ...

}

edited Dec 6 '17 at 17:17

ZhekaKozlov

14.8k866111

answered Dec 3 '16 at 21:08

Elliott Frisch

153k1389178

4

This should be the accepted answer!

– higuaro
Aug 11 '17 at 6:33

add a comment |

You could store all the strings that you want to compare str with into a collection and check if the collection contains str. Store all strings in the collection as lowercase and convert str to lowercase before querying the collection. For example:

Set<String> strings = new HashSet<String>();

strings.add("val1");

strings.add("val2");



String str = "Val1";



if (strings.contains(str.toLowerCase()))

{

}

answered Apr 18 '12 at 8:16

hmjd

102k13161217

What if str contain value like "val" only ???

– kundan bora
Apr 18 '12 at 8:23

You can populate the collection with whatever values you require. In case if str was "val" then in the code in my answer strings.contains() would return false.

– hmjd
Apr 18 '12 at 8:25

No no i am saying that if someone pass str value as "Val" which is not as equal as "Val1","Val2,"Val3". That mean passing str value as "Val" must be failed.. but in your case this will be pass.Not satisfy my condition.

– kundan bora
Apr 18 '12 at 8:28

From the question case is irrelevant due to presence of equalsIgnoreCase(). If "Val" is passed and strings contains "val1", "val2", and "val3" then contains() will return false. See ideone.com/LiYKP .

– hmjd
Apr 18 '12 at 8:35

Oh you used HashSet to store Strings . OK I got this.

– kundan bora
Apr 18 '12 at 9:24

|
show 1 more comment

ArrayUtils may be helpful.

ArrayUtils.contains(new String{"1", "2"}, "1")

answered Aug 27 '15 at 5:53

Jeffrey4l

685

add a comment |

Small enhancement to perfectly valid @hmjd's answer: you can use following syntax:

class A {



  final Set<String> strings = new HashSet<>() {{

    add("val1");

    add("val2");

  }};



  // ...



  if (strings.contains(str.toLowerCase())) {

  }



  // ...

}

It allows you to initialize you Set in-place.

edited May 23 '17 at 12:10

Community♦

answered Sep 14 '15 at 10:51

Andrey Starodubtsev

3,87522037

add a comment |

Just use var-args and write your own static method:

public static boolean compareWithMany(String first, String next, String ... rest)

{

    if(first.equalsIgnoreCase(next))

        return true;

    for(int i = 0; i < rest.length; i++)

    {

        if(first.equalsIgnoreCase(rest[i]))

            return true;

    }

    return false;

}



public static void main(String args)

{

    final String str = "val1";

    System.out.println(compareWithMany(str, "val1", "val2", "val3"));

}

answered Apr 18 '12 at 8:19

Neet

3,3771016

I like this one! I'm probably overlooking something, but why do you include next as a parameter? That can just as well be part of the var-args rest, right?

– Martijn
May 10 '15 at 9:44

By having 'next' I enforce passing at least one parameter. So you can not do compareWithMany("foo"). It's a compile-time sanity check, instead of having to deal with an empty set to compare against during runtime.

– Neet
May 11 '15 at 18:00

add a comment |

Yet another alternative (kinda similar to https://stackoverflow.com/a/32241628/6095216 above) using StringUtils from the apache commons library: https://commons.apache.org/proper/commons-lang/apidocs/org/apache/commons/lang3/StringUtils.html#equalsAnyIgnoreCase-java.lang.CharSequence-java.lang.CharSequence...-

if (StringUtils.equalsAnyIgnoreCase(str, "val1", "val2", "val3")) {

  // remaining code

}

answered Nov 19 '18 at 23:06

Yury

13218

add a comment |

You can achieve this with Collections framework. Put all your options in a Collection say something like Collection<String> options ;

Then loop throgh this to compare your string with the list elements and if it is you can return a boolean value true and otherwise false.

answered Apr 18 '12 at 8:21

Tijo K Varghese

1,33293253

add a comment |

Remember in Java a quoted String is still a String object. Therefore you can use the String function contains() to test for a range of Strings or integers using this method:

if ("A C Viking G M Ocelot".contains(mAnswer)) {...}

for numbers it's a tad more involved but still works:

if ("1 4 5 9 10 17 23 96457".contains(String.valueOf(mNumAnswer))) {...}

edited Jan 19 '17 at 8:52

answered Jan 19 '17 at 8:46

Stuart Walsh

2112

add a comment |

Apache Commons Collection class.

StringUtils.equalsAny(CharSequence string, CharSequence... searchStrings)

So in your case, it would be

StringUtils.equalsAny(str, "val1", "val2", "val3");

answered Dec 26 '18 at 18:40

user3583333

112

add a comment |

-2

No, there is no such possibility.
Allthough, one could imagine:

public static boolean contains(String s, Collection<String>c) {

    for (String ss : c) {

       if (s.equalsIgnoreCase(ss)) return true;

    }

    return false;

}

answered Apr 18 '12 at 8:17

slipset

2,26721616

For the collections worth to consider, like HashSet, contains() has much more efficient implementation.

– Alexei Kaigorodov
Apr 18 '12 at 8:24

True, but (which may be a moot point), equals and equalsIgnoreCase do not yield the same result. This could of course be overcome by storing the strings as lower case and lowercasing the key you're looking for, but, YMMV

– slipset
Apr 18 '12 at 8:27

add a comment |

-3

!string.matches("a|b|c|d")

works fine for me.

edited Nov 14 '16 at 10:50

answered Nov 10 '16 at 10:09

Bru

6

Please give explanation / reason for better answer, It is too short

– sangram parmar
Nov 10 '16 at 10:14

1

How is this different from the accepted answer?

– Jiri Tousek
Nov 14 '16 at 12:24

add a comment |

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12 Answers
12

active

oldest

votes

12 Answers
12

active

oldest

votes

I found the better solution. This can be achieved through RegEx:

if (str.matches("val1|val2|val3")) {

     // remaining code

}

For case insensitive matching:

if (str.matches("(?i)val1|val2|val3")) {

     // remaining code

}

edited Aug 3 '18 at 7:07

answered Apr 18 '12 at 15:59

kundan bora

2,72811527

The matches function does not work well for all cases. The answer of @hmjd did it for my case. See Regex doesn't work in String.matches() for more info.

– Primoz990
May 11 '17 at 10:20

add a comment |

I found the better solution. This can be achieved through RegEx:

if (str.matches("val1|val2|val3")) {

     // remaining code

}

For case insensitive matching:

if (str.matches("(?i)val1|val2|val3")) {

     // remaining code

}

edited Aug 3 '18 at 7:07

answered Apr 18 '12 at 15:59

kundan bora

2,72811527

The matches function does not work well for all cases. The answer of @hmjd did it for my case. See Regex doesn't work in String.matches() for more info.

– Primoz990
May 11 '17 at 10:20

add a comment |

I found the better solution. This can be achieved through RegEx:

if (str.matches("val1|val2|val3")) {

     // remaining code

}

For case insensitive matching:

if (str.matches("(?i)val1|val2|val3")) {

     // remaining code

}

edited Aug 3 '18 at 7:07

answered Apr 18 '12 at 15:59

kundan bora

2,72811527

I found the better solution. This can be achieved through RegEx:

if (str.matches("val1|val2|val3")) {

     // remaining code

}

For case insensitive matching:

if (str.matches("(?i)val1|val2|val3")) {

     // remaining code

}

edited Aug 3 '18 at 7:07

answered Apr 18 '12 at 15:59

kundan bora

2,72811527

edited Aug 3 '18 at 7:07

answered Apr 18 '12 at 15:59

kundan bora

2,72811527

answered Apr 18 '12 at 15:59

kundan bora

2,72811527

answered Apr 18 '12 at 15:59

kundan bora

2,72811527

The matches function does not work well for all cases. The answer of @hmjd did it for my case. See Regex doesn't work in String.matches() for more info.

– Primoz990
May 11 '17 at 10:20

add a comment |

The matches function does not work well for all cases. The answer of @hmjd did it for my case. See Regex doesn't work in String.matches() for more info.

– Primoz990
May 11 '17 at 10:20

The matches function does not work well for all cases. The answer of @hmjd did it for my case. See Regex doesn't work in String.matches() for more info.

– Primoz990
May 11 '17 at 10:20

add a comment |

In Java 8+, you might use a Stream<T> and anyMatch(Predicate<? super T>) with something like

if (Stream.of("val1", "val2", "val3").anyMatch(str::equalsIgnoreCase)) {

    // ...

}

edited Dec 6 '17 at 17:17

ZhekaKozlov

14.8k866111

answered Dec 3 '16 at 21:08

Elliott Frisch

153k1389178

4

This should be the accepted answer!

– higuaro
Aug 11 '17 at 6:33

add a comment |

In Java 8+, you might use a Stream<T> and anyMatch(Predicate<? super T>) with something like

if (Stream.of("val1", "val2", "val3").anyMatch(str::equalsIgnoreCase)) {

    // ...

}

edited Dec 6 '17 at 17:17

ZhekaKozlov

14.8k866111

answered Dec 3 '16 at 21:08

Elliott Frisch

153k1389178

4

This should be the accepted answer!

– higuaro
Aug 11 '17 at 6:33

add a comment |

In Java 8+, you might use a Stream<T> and anyMatch(Predicate<? super T>) with something like

if (Stream.of("val1", "val2", "val3").anyMatch(str::equalsIgnoreCase)) {

    // ...

}

edited Dec 6 '17 at 17:17

ZhekaKozlov

14.8k866111

answered Dec 3 '16 at 21:08

Elliott Frisch

153k1389178

In Java 8+, you might use a Stream<T> and anyMatch(Predicate<? super T>) with something like

if (Stream.of("val1", "val2", "val3").anyMatch(str::equalsIgnoreCase)) {

    // ...

}

edited Dec 6 '17 at 17:17

ZhekaKozlov

14.8k866111

answered Dec 3 '16 at 21:08

Elliott Frisch

153k1389178

edited Dec 6 '17 at 17:17

ZhekaKozlov

14.8k866111

edited Dec 6 '17 at 17:17

ZhekaKozlov

14.8k866111

edited Dec 6 '17 at 17:17

ZhekaKozlov

14.8k866111

answered Dec 3 '16 at 21:08

Elliott Frisch

153k1389178

answered Dec 3 '16 at 21:08

Elliott Frisch

153k1389178

answered Dec 3 '16 at 21:08

Elliott Frisch

153k1389178

4

This should be the accepted answer!

– higuaro
Aug 11 '17 at 6:33

add a comment |

4

This should be the accepted answer!

– higuaro
Aug 11 '17 at 6:33

This should be the accepted answer!

– higuaro
Aug 11 '17 at 6:33

add a comment |

Set<String> strings = new HashSet<String>();

strings.add("val1");

strings.add("val2");



String str = "Val1";



if (strings.contains(str.toLowerCase()))

{

}

answered Apr 18 '12 at 8:16

hmjd

102k13161217

What if str contain value like "val" only ???

– kundan bora
Apr 18 '12 at 8:23

You can populate the collection with whatever values you require. In case if str was "val" then in the code in my answer strings.contains() would return false.

– hmjd
Apr 18 '12 at 8:25

No no i am saying that if someone pass str value as "Val" which is not as equal as "Val1","Val2,"Val3". That mean passing str value as "Val" must be failed.. but in your case this will be pass.Not satisfy my condition.

– kundan bora
Apr 18 '12 at 8:28

From the question case is irrelevant due to presence of equalsIgnoreCase(). If "Val" is passed and strings contains "val1", "val2", and "val3" then contains() will return false. See ideone.com/LiYKP .

– hmjd
Apr 18 '12 at 8:35

Oh you used HashSet to store Strings . OK I got this.

– kundan bora
Apr 18 '12 at 9:24

|
show 1 more comment

Set<String> strings = new HashSet<String>();

strings.add("val1");

strings.add("val2");



String str = "Val1";



if (strings.contains(str.toLowerCase()))

{

}

answered Apr 18 '12 at 8:16

hmjd

102k13161217

What if str contain value like "val" only ???

– kundan bora
Apr 18 '12 at 8:23

You can populate the collection with whatever values you require. In case if str was "val" then in the code in my answer strings.contains() would return false.

– hmjd
Apr 18 '12 at 8:25

No no i am saying that if someone pass str value as "Val" which is not as equal as "Val1","Val2,"Val3". That mean passing str value as "Val" must be failed.. but in your case this will be pass.Not satisfy my condition.

– kundan bora
Apr 18 '12 at 8:28

From the question case is irrelevant due to presence of equalsIgnoreCase(). If "Val" is passed and strings contains "val1", "val2", and "val3" then contains() will return false. See ideone.com/LiYKP .

– hmjd
Apr 18 '12 at 8:35

Oh you used HashSet to store Strings . OK I got this.

– kundan bora
Apr 18 '12 at 9:24

|
show 1 more comment

Set<String> strings = new HashSet<String>();

strings.add("val1");

strings.add("val2");



String str = "Val1";



if (strings.contains(str.toLowerCase()))

{

}

answered Apr 18 '12 at 8:16

hmjd

102k13161217

Set<String> strings = new HashSet<String>();

strings.add("val1");

strings.add("val2");



String str = "Val1";



if (strings.contains(str.toLowerCase()))

{

}

answered Apr 18 '12 at 8:16

hmjd

102k13161217

answered Apr 18 '12 at 8:16

hmjd

102k13161217

answered Apr 18 '12 at 8:16

hmjd

102k13161217

answered Apr 18 '12 at 8:16

hmjd

102k13161217

What if str contain value like "val" only ???

– kundan bora
Apr 18 '12 at 8:23

You can populate the collection with whatever values you require. In case if str was "val" then in the code in my answer strings.contains() would return false.

– hmjd
Apr 18 '12 at 8:25

No no i am saying that if someone pass str value as "Val" which is not as equal as "Val1","Val2,"Val3". That mean passing str value as "Val" must be failed.. but in your case this will be pass.Not satisfy my condition.

– kundan bora
Apr 18 '12 at 8:28

From the question case is irrelevant due to presence of equalsIgnoreCase(). If "Val" is passed and strings contains "val1", "val2", and "val3" then contains() will return false. See ideone.com/LiYKP .

– hmjd
Apr 18 '12 at 8:35

Oh you used HashSet to store Strings . OK I got this.

– kundan bora
Apr 18 '12 at 9:24

|
show 1 more comment

What if str contain value like "val" only ???

– kundan bora
Apr 18 '12 at 8:23

You can populate the collection with whatever values you require. In case if str was "val" then in the code in my answer strings.contains() would return false.

– hmjd
Apr 18 '12 at 8:25

No no i am saying that if someone pass str value as "Val" which is not as equal as "Val1","Val2,"Val3". That mean passing str value as "Val" must be failed.. but in your case this will be pass.Not satisfy my condition.

– kundan bora
Apr 18 '12 at 8:28

From the question case is irrelevant due to presence of equalsIgnoreCase(). If "Val" is passed and strings contains "val1", "val2", and "val3" then contains() will return false. See ideone.com/LiYKP .

– hmjd
Apr 18 '12 at 8:35

Oh you used HashSet to store Strings . OK I got this.

– kundan bora
Apr 18 '12 at 9:24

What if str contain value like "val" only ???

– kundan bora
Apr 18 '12 at 8:23

You can populate the collection with whatever values you require. In case if str was "val" then in the code in my answer strings.contains() would return false.

– hmjd
Apr 18 '12 at 8:25

No no i am saying that if someone pass str value as "Val" which is not as equal as "Val1","Val2,"Val3". That mean passing str value as "Val" must be failed.. but in your case this will be pass.Not satisfy my condition.

– kundan bora
Apr 18 '12 at 8:28

From the question case is irrelevant due to presence of equalsIgnoreCase(). If "Val" is passed and strings contains "val1", "val2", and "val3" then contains() will return false. See ideone.com/LiYKP .

– hmjd
Apr 18 '12 at 8:35

Oh you used HashSet to store Strings . OK I got this.

– kundan bora
Apr 18 '12 at 9:24

|
show 1 more comment

ArrayUtils may be helpful.

ArrayUtils.contains(new String{"1", "2"}, "1")

answered Aug 27 '15 at 5:53

Jeffrey4l

685

add a comment |

ArrayUtils may be helpful.

ArrayUtils.contains(new String{"1", "2"}, "1")

answered Aug 27 '15 at 5:53

Jeffrey4l

685

add a comment |

ArrayUtils may be helpful.

ArrayUtils.contains(new String{"1", "2"}, "1")

answered Aug 27 '15 at 5:53

Jeffrey4l

685

ArrayUtils may be helpful.

ArrayUtils.contains(new String{"1", "2"}, "1")

answered Aug 27 '15 at 5:53

Jeffrey4l

685

answered Aug 27 '15 at 5:53

Jeffrey4l

685

answered Aug 27 '15 at 5:53

Jeffrey4l

685

answered Aug 27 '15 at 5:53

Jeffrey4l

685

add a comment |

Small enhancement to perfectly valid @hmjd's answer: you can use following syntax:

class A {



  final Set<String> strings = new HashSet<>() {{

    add("val1");

    add("val2");

  }};



  // ...



  if (strings.contains(str.toLowerCase())) {

  }



  // ...

}

It allows you to initialize you Set in-place.

edited May 23 '17 at 12:10

Community♦

answered Sep 14 '15 at 10:51

Andrey Starodubtsev

3,87522037

add a comment |

Small enhancement to perfectly valid @hmjd's answer: you can use following syntax:

class A {



  final Set<String> strings = new HashSet<>() {{

    add("val1");

    add("val2");

  }};



  // ...



  if (strings.contains(str.toLowerCase())) {

  }



  // ...

}

It allows you to initialize you Set in-place.

edited May 23 '17 at 12:10

Community♦

answered Sep 14 '15 at 10:51

Andrey Starodubtsev

3,87522037

add a comment |

Small enhancement to perfectly valid @hmjd's answer: you can use following syntax:

class A {



  final Set<String> strings = new HashSet<>() {{

    add("val1");

    add("val2");

  }};



  // ...



  if (strings.contains(str.toLowerCase())) {

  }



  // ...

}

It allows you to initialize you Set in-place.

edited May 23 '17 at 12:10

Community♦

answered Sep 14 '15 at 10:51

Andrey Starodubtsev

3,87522037

Small enhancement to perfectly valid @hmjd's answer: you can use following syntax:

class A {



  final Set<String> strings = new HashSet<>() {{

    add("val1");

    add("val2");

  }};



  // ...



  if (strings.contains(str.toLowerCase())) {

  }



  // ...

}

It allows you to initialize you Set in-place.

edited May 23 '17 at 12:10

Community♦

answered Sep 14 '15 at 10:51

Andrey Starodubtsev

3,87522037

edited May 23 '17 at 12:10

Community♦

edited May 23 '17 at 12:10

Community♦

edited May 23 '17 at 12:10

Community♦

answered Sep 14 '15 at 10:51

Andrey Starodubtsev

3,87522037

answered Sep 14 '15 at 10:51

Andrey Starodubtsev

3,87522037

answered Sep 14 '15 at 10:51

Andrey Starodubtsev

3,87522037

add a comment |

Just use var-args and write your own static method:

public static boolean compareWithMany(String first, String next, String ... rest)

{

    if(first.equalsIgnoreCase(next))

        return true;

    for(int i = 0; i < rest.length; i++)

    {

        if(first.equalsIgnoreCase(rest[i]))

            return true;

    }

    return false;

}



public static void main(String args)

{

    final String str = "val1";

    System.out.println(compareWithMany(str, "val1", "val2", "val3"));

}

answered Apr 18 '12 at 8:19

Neet

3,3771016

I like this one! I'm probably overlooking something, but why do you include next as a parameter? That can just as well be part of the var-args rest, right?

– Martijn
May 10 '15 at 9:44

By having 'next' I enforce passing at least one parameter. So you can not do compareWithMany("foo"). It's a compile-time sanity check, instead of having to deal with an empty set to compare against during runtime.

– Neet
May 11 '15 at 18:00

add a comment |

Just use var-args and write your own static method:

public static boolean compareWithMany(String first, String next, String ... rest)

{

    if(first.equalsIgnoreCase(next))

        return true;

    for(int i = 0; i < rest.length; i++)

    {

        if(first.equalsIgnoreCase(rest[i]))

            return true;

    }

    return false;

}



public static void main(String args)

{

    final String str = "val1";

    System.out.println(compareWithMany(str, "val1", "val2", "val3"));

}

answered Apr 18 '12 at 8:19

Neet

3,3771016

I like this one! I'm probably overlooking something, but why do you include next as a parameter? That can just as well be part of the var-args rest, right?

– Martijn
May 10 '15 at 9:44

By having 'next' I enforce passing at least one parameter. So you can not do compareWithMany("foo"). It's a compile-time sanity check, instead of having to deal with an empty set to compare against during runtime.

– Neet
May 11 '15 at 18:00

add a comment |

Just use var-args and write your own static method:

public static boolean compareWithMany(String first, String next, String ... rest)

{

    if(first.equalsIgnoreCase(next))

        return true;

    for(int i = 0; i < rest.length; i++)

    {

        if(first.equalsIgnoreCase(rest[i]))

            return true;

    }

    return false;

}



public static void main(String args)

{

    final String str = "val1";

    System.out.println(compareWithMany(str, "val1", "val2", "val3"));

}

answered Apr 18 '12 at 8:19

Neet

3,3771016

Just use var-args and write your own static method:

public static boolean compareWithMany(String first, String next, String ... rest)

{

    if(first.equalsIgnoreCase(next))

        return true;

    for(int i = 0; i < rest.length; i++)

    {

        if(first.equalsIgnoreCase(rest[i]))

            return true;

    }

    return false;

}



public static void main(String args)

{

    final String str = "val1";

    System.out.println(compareWithMany(str, "val1", "val2", "val3"));

}

answered Apr 18 '12 at 8:19

Neet

3,3771016

answered Apr 18 '12 at 8:19

Neet

3,3771016

answered Apr 18 '12 at 8:19

Neet

3,3771016

answered Apr 18 '12 at 8:19

Neet

3,3771016

I like this one! I'm probably overlooking something, but why do you include next as a parameter? That can just as well be part of the var-args rest, right?

– Martijn
May 10 '15 at 9:44

By having 'next' I enforce passing at least one parameter. So you can not do compareWithMany("foo"). It's a compile-time sanity check, instead of having to deal with an empty set to compare against during runtime.

– Neet
May 11 '15 at 18:00

add a comment |

I like this one! I'm probably overlooking something, but why do you include next as a parameter? That can just as well be part of the var-args rest, right?

– Martijn
May 10 '15 at 9:44

By having 'next' I enforce passing at least one parameter. So you can not do compareWithMany("foo"). It's a compile-time sanity check, instead of having to deal with an empty set to compare against during runtime.

– Neet
May 11 '15 at 18:00

I like this one! I'm probably overlooking something, but why do you include next as a parameter? That can just as well be part of the var-args rest, right?

– Martijn
May 10 '15 at 9:44

By having 'next' I enforce passing at least one parameter. So you can not do compareWithMany("foo"). It's a compile-time sanity check, instead of having to deal with an empty set to compare against during runtime.

– Neet
May 11 '15 at 18:00

add a comment |

if (StringUtils.equalsAnyIgnoreCase(str, "val1", "val2", "val3")) {

  // remaining code

}

answered Nov 19 '18 at 23:06

Yury

13218

add a comment |

if (StringUtils.equalsAnyIgnoreCase(str, "val1", "val2", "val3")) {

  // remaining code

}

answered Nov 19 '18 at 23:06

Yury

13218

add a comment |

if (StringUtils.equalsAnyIgnoreCase(str, "val1", "val2", "val3")) {

  // remaining code

}

answered Nov 19 '18 at 23:06

Yury

13218

if (StringUtils.equalsAnyIgnoreCase(str, "val1", "val2", "val3")) {

  // remaining code

}

answered Nov 19 '18 at 23:06

Yury

13218

answered Nov 19 '18 at 23:06

Yury

13218

answered Nov 19 '18 at 23:06

Yury

13218

answered Nov 19 '18 at 23:06

Yury

13218

add a comment |

You can achieve this with Collections framework. Put all your options in a Collection say something like Collection<String> options ;

Then loop throgh this to compare your string with the list elements and if it is you can return a boolean value true and otherwise false.

answered Apr 18 '12 at 8:21

Tijo K Varghese

1,33293253

add a comment |

You can achieve this with Collections framework. Put all your options in a Collection say something like Collection<String> options ;

Then loop throgh this to compare your string with the list elements and if it is you can return a boolean value true and otherwise false.

answered Apr 18 '12 at 8:21

Tijo K Varghese

1,33293253

add a comment |

You can achieve this with Collections framework. Put all your options in a Collection say something like Collection<String> options ;

Then loop throgh this to compare your string with the list elements and if it is you can return a boolean value true and otherwise false.

answered Apr 18 '12 at 8:21

Tijo K Varghese

1,33293253

You can achieve this with Collections framework. Put all your options in a Collection say something like Collection<String> options ;

Then loop throgh this to compare your string with the list elements and if it is you can return a boolean value true and otherwise false.

answered Apr 18 '12 at 8:21

Tijo K Varghese

1,33293253

answered Apr 18 '12 at 8:21

Tijo K Varghese

1,33293253

answered Apr 18 '12 at 8:21

Tijo K Varghese

1,33293253

answered Apr 18 '12 at 8:21

Tijo K Varghese

1,33293253

add a comment |

Remember in Java a quoted String is still a String object. Therefore you can use the String function contains() to test for a range of Strings or integers using this method:

if ("A C Viking G M Ocelot".contains(mAnswer)) {...}

for numbers it's a tad more involved but still works:

if ("1 4 5 9 10 17 23 96457".contains(String.valueOf(mNumAnswer))) {...}

edited Jan 19 '17 at 8:52

answered Jan 19 '17 at 8:46

Stuart Walsh

2112

add a comment |

Remember in Java a quoted String is still a String object. Therefore you can use the String function contains() to test for a range of Strings or integers using this method:

if ("A C Viking G M Ocelot".contains(mAnswer)) {...}

for numbers it's a tad more involved but still works:

if ("1 4 5 9 10 17 23 96457".contains(String.valueOf(mNumAnswer))) {...}

edited Jan 19 '17 at 8:52

answered Jan 19 '17 at 8:46

Stuart Walsh

2112

add a comment |

Remember in Java a quoted String is still a String object. Therefore you can use the String function contains() to test for a range of Strings or integers using this method:

if ("A C Viking G M Ocelot".contains(mAnswer)) {...}

for numbers it's a tad more involved but still works:

if ("1 4 5 9 10 17 23 96457".contains(String.valueOf(mNumAnswer))) {...}

edited Jan 19 '17 at 8:52

answered Jan 19 '17 at 8:46

Stuart Walsh

2112

Remember in Java a quoted String is still a String object. Therefore you can use the String function contains() to test for a range of Strings or integers using this method:

if ("A C Viking G M Ocelot".contains(mAnswer)) {...}

for numbers it's a tad more involved but still works:

if ("1 4 5 9 10 17 23 96457".contains(String.valueOf(mNumAnswer))) {...}

edited Jan 19 '17 at 8:52

answered Jan 19 '17 at 8:46

Stuart Walsh

2112

edited Jan 19 '17 at 8:52

answered Jan 19 '17 at 8:46

Stuart Walsh

2112

answered Jan 19 '17 at 8:46

Stuart Walsh

2112

answered Jan 19 '17 at 8:46

Stuart Walsh

2112

add a comment |

Apache Commons Collection class.

StringUtils.equalsAny(CharSequence string, CharSequence... searchStrings)

So in your case, it would be

StringUtils.equalsAny(str, "val1", "val2", "val3");

answered Dec 26 '18 at 18:40

user3583333

112

add a comment |

Apache Commons Collection class.

StringUtils.equalsAny(CharSequence string, CharSequence... searchStrings)

So in your case, it would be

StringUtils.equalsAny(str, "val1", "val2", "val3");

answered Dec 26 '18 at 18:40

user3583333

112

add a comment |

Apache Commons Collection class.

StringUtils.equalsAny(CharSequence string, CharSequence... searchStrings)

So in your case, it would be

StringUtils.equalsAny(str, "val1", "val2", "val3");

answered Dec 26 '18 at 18:40

user3583333

112

Apache Commons Collection class.

StringUtils.equalsAny(CharSequence string, CharSequence... searchStrings)

So in your case, it would be

StringUtils.equalsAny(str, "val1", "val2", "val3");

answered Dec 26 '18 at 18:40

user3583333

112

answered Dec 26 '18 at 18:40

user3583333

112

answered Dec 26 '18 at 18:40

user3583333

112

answered Dec 26 '18 at 18:40

user3583333

112

add a comment |

-2

No, there is no such possibility.
Allthough, one could imagine:

public static boolean contains(String s, Collection<String>c) {

    for (String ss : c) {

       if (s.equalsIgnoreCase(ss)) return true;

    }

    return false;

}

answered Apr 18 '12 at 8:17

slipset

2,26721616

For the collections worth to consider, like HashSet, contains() has much more efficient implementation.

– Alexei Kaigorodov
Apr 18 '12 at 8:24

True, but (which may be a moot point), equals and equalsIgnoreCase do not yield the same result. This could of course be overcome by storing the strings as lower case and lowercasing the key you're looking for, but, YMMV

– slipset
Apr 18 '12 at 8:27

add a comment |

-2

No, there is no such possibility.
Allthough, one could imagine:

public static boolean contains(String s, Collection<String>c) {

    for (String ss : c) {

       if (s.equalsIgnoreCase(ss)) return true;

    }

    return false;

}

answered Apr 18 '12 at 8:17

slipset

2,26721616

For the collections worth to consider, like HashSet, contains() has much more efficient implementation.

– Alexei Kaigorodov
Apr 18 '12 at 8:24

True, but (which may be a moot point), equals and equalsIgnoreCase do not yield the same result. This could of course be overcome by storing the strings as lower case and lowercasing the key you're looking for, but, YMMV

– slipset
Apr 18 '12 at 8:27

add a comment |

-2

No, there is no such possibility.
Allthough, one could imagine:

public static boolean contains(String s, Collection<String>c) {

    for (String ss : c) {

       if (s.equalsIgnoreCase(ss)) return true;

    }

    return false;

}

answered Apr 18 '12 at 8:17

slipset

2,26721616

No, there is no such possibility.
Allthough, one could imagine:

public static boolean contains(String s, Collection<String>c) {

    for (String ss : c) {

       if (s.equalsIgnoreCase(ss)) return true;

    }

    return false;

}

answered Apr 18 '12 at 8:17

slipset

2,26721616

answered Apr 18 '12 at 8:17

slipset

2,26721616

answered Apr 18 '12 at 8:17

slipset

2,26721616

answered Apr 18 '12 at 8:17

slipset

2,26721616

For the collections worth to consider, like HashSet, contains() has much more efficient implementation.

– Alexei Kaigorodov
Apr 18 '12 at 8:24

True, but (which may be a moot point), equals and equalsIgnoreCase do not yield the same result. This could of course be overcome by storing the strings as lower case and lowercasing the key you're looking for, but, YMMV

– slipset
Apr 18 '12 at 8:27

add a comment |

For the collections worth to consider, like HashSet, contains() has much more efficient implementation.

– Alexei Kaigorodov
Apr 18 '12 at 8:24

True, but (which may be a moot point), equals and equalsIgnoreCase do not yield the same result. This could of course be overcome by storing the strings as lower case and lowercasing the key you're looking for, but, YMMV

– slipset
Apr 18 '12 at 8:27

For the collections worth to consider, like HashSet, contains() has much more efficient implementation.

– Alexei Kaigorodov
Apr 18 '12 at 8:24

True, but (which may be a moot point), equals and equalsIgnoreCase do not yield the same result. This could of course be overcome by storing the strings as lower case and lowercasing the key you're looking for, but, YMMV

– slipset
Apr 18 '12 at 8:27

add a comment |

-3

!string.matches("a|b|c|d")

works fine for me.

edited Nov 14 '16 at 10:50

answered Nov 10 '16 at 10:09

Bru

6

Please give explanation / reason for better answer, It is too short

– sangram parmar
Nov 10 '16 at 10:14

1

How is this different from the accepted answer?

– Jiri Tousek
Nov 14 '16 at 12:24

add a comment |

-3

!string.matches("a|b|c|d")

works fine for me.

edited Nov 14 '16 at 10:50

answered Nov 10 '16 at 10:09

Bru

6

Please give explanation / reason for better answer, It is too short

– sangram parmar
Nov 10 '16 at 10:14

1

How is this different from the accepted answer?

– Jiri Tousek
Nov 14 '16 at 12:24

add a comment |

-3

!string.matches("a|b|c|d")

works fine for me.

edited Nov 14 '16 at 10:50

answered Nov 10 '16 at 10:09

Bru

!string.matches("a|b|c|d")

works fine for me.

edited Nov 14 '16 at 10:50

answered Nov 10 '16 at 10:09

Bru

edited Nov 14 '16 at 10:50

answered Nov 10 '16 at 10:09

Bru

answered Nov 10 '16 at 10:09

Bru

answered Nov 10 '16 at 10:09

Bru

6

Please give explanation / reason for better answer, It is too short

– sangram parmar
Nov 10 '16 at 10:14

1

How is this different from the accepted answer?

– Jiri Tousek
Nov 14 '16 at 12:24

add a comment |

6

Please give explanation / reason for better answer, It is too short

– sangram parmar
Nov 10 '16 at 10:14

1

How is this different from the accepted answer?

– Jiri Tousek
Nov 14 '16 at 12:24

Please give explanation / reason for better answer, It is too short

– sangram parmar
Nov 10 '16 at 10:14

How is this different from the accepted answer?

– Jiri Tousek
Nov 14 '16 at 12:24

add a comment |

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