Subquery in FROM clause using CriteriaQuery












0















I need to implement select from a nested query, for the sake of simplicity let it be:



select * from (select * from city) c


How can this be done using CriteriaQuery and Subquery?










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0















I need to implement select from a nested query, for the sake of simplicity let it be:



select * from (select * from city) c


How can this be done using CriteriaQuery and Subquery?










share|improve this question

























  • Welcome to stackoverflow. Please read stackoverflow.com/help/how-to-ask and improve your question.

    – M. Deinum
    Nov 20 '18 at 11:22














0












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0


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I need to implement select from a nested query, for the sake of simplicity let it be:



select * from (select * from city) c


How can this be done using CriteriaQuery and Subquery?










share|improve this question
















I need to implement select from a nested query, for the sake of simplicity let it be:



select * from (select * from city) c


How can this be done using CriteriaQuery and Subquery?







jpa spring-data-jpa criteria-api






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edited Nov 20 '18 at 11:13









JustLearning

99521635




99521635










asked Nov 20 '18 at 10:50









chekhovanachekhovana

161




161













  • Welcome to stackoverflow. Please read stackoverflow.com/help/how-to-ask and improve your question.

    – M. Deinum
    Nov 20 '18 at 11:22



















  • Welcome to stackoverflow. Please read stackoverflow.com/help/how-to-ask and improve your question.

    – M. Deinum
    Nov 20 '18 at 11:22

















Welcome to stackoverflow. Please read stackoverflow.com/help/how-to-ask and improve your question.

– M. Deinum
Nov 20 '18 at 11:22





Welcome to stackoverflow. Please read stackoverflow.com/help/how-to-ask and improve your question.

– M. Deinum
Nov 20 '18 at 11:22












2 Answers
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You can't because (select * from city) is not an entity and CritieriaAPI queries on entities not on tables.



The only way would be to create a view for (select * from city) and map that view to an entity.






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    0














    First, your syntax is not JPA compliant as mentioned previously, secondly, you must know that subqueries in JPQL are allowed only in WHERE and HAVING clauses. The same applies to Criteria queries. If you need the more powerful SQL subquery features then with JPA you have to use JPA provisions for native queries, or otherwise, use another type of JDBC library.






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      2 Answers
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      2 Answers
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      0














      You can't because (select * from city) is not an entity and CritieriaAPI queries on entities not on tables.



      The only way would be to create a view for (select * from city) and map that view to an entity.






      share|improve this answer




























        0














        You can't because (select * from city) is not an entity and CritieriaAPI queries on entities not on tables.



        The only way would be to create a view for (select * from city) and map that view to an entity.






        share|improve this answer


























          0












          0








          0







          You can't because (select * from city) is not an entity and CritieriaAPI queries on entities not on tables.



          The only way would be to create a view for (select * from city) and map that view to an entity.






          share|improve this answer













          You can't because (select * from city) is not an entity and CritieriaAPI queries on entities not on tables.



          The only way would be to create a view for (select * from city) and map that view to an entity.







          share|improve this answer












          share|improve this answer



          share|improve this answer










          answered Nov 20 '18 at 11:19









          Simon MartinelliSimon Martinelli

          5,85111230




          5,85111230

























              0














              First, your syntax is not JPA compliant as mentioned previously, secondly, you must know that subqueries in JPQL are allowed only in WHERE and HAVING clauses. The same applies to Criteria queries. If you need the more powerful SQL subquery features then with JPA you have to use JPA provisions for native queries, or otherwise, use another type of JDBC library.






              share|improve this answer






























                0














                First, your syntax is not JPA compliant as mentioned previously, secondly, you must know that subqueries in JPQL are allowed only in WHERE and HAVING clauses. The same applies to Criteria queries. If you need the more powerful SQL subquery features then with JPA you have to use JPA provisions for native queries, or otherwise, use another type of JDBC library.






                share|improve this answer




























                  0












                  0








                  0







                  First, your syntax is not JPA compliant as mentioned previously, secondly, you must know that subqueries in JPQL are allowed only in WHERE and HAVING clauses. The same applies to Criteria queries. If you need the more powerful SQL subquery features then with JPA you have to use JPA provisions for native queries, or otherwise, use another type of JDBC library.






                  share|improve this answer















                  First, your syntax is not JPA compliant as mentioned previously, secondly, you must know that subqueries in JPQL are allowed only in WHERE and HAVING clauses. The same applies to Criteria queries. If you need the more powerful SQL subquery features then with JPA you have to use JPA provisions for native queries, or otherwise, use another type of JDBC library.







                  share|improve this answer














                  share|improve this answer



                  share|improve this answer








                  edited Nov 20 '18 at 14:12

























                  answered Nov 20 '18 at 13:57









                  garfieldgarfield

                  452612




                  452612






























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