Limit point and interior point












6












$begingroup$


Is any interior point also a limit point?



Judging from the definition, I believe every interior point is a limit point, but I'm not sure about it. If this is wrong, could you give me a counterexample?



(Since an interior point $p$ of a set $E$ has a neighborhood $N$ with radius $r$ such that $N$ is a subset of $E$. Obviously any neighborhood of $p$ with radius less than $r$ is a subset of $E$. Also, any neighborhood with radius greater than $r$ contains $N$ as a subset, so (I think) it is a limit point.)










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$endgroup$












  • $begingroup$
    By the way, you tagged this "general-topology", but speak of radii of nhoods. Are you working in metric spaces?
    $endgroup$
    – David Mitra
    Aug 1 '12 at 22:06










  • $begingroup$
    Yes. I just started analysis (Walter Rudin The principle of mathematical analysis) and I came up with this question when reading the chapter named the basic topology
    $endgroup$
    – Tengu
    Aug 1 '12 at 22:09
















6












$begingroup$


Is any interior point also a limit point?



Judging from the definition, I believe every interior point is a limit point, but I'm not sure about it. If this is wrong, could you give me a counterexample?



(Since an interior point $p$ of a set $E$ has a neighborhood $N$ with radius $r$ such that $N$ is a subset of $E$. Obviously any neighborhood of $p$ with radius less than $r$ is a subset of $E$. Also, any neighborhood with radius greater than $r$ contains $N$ as a subset, so (I think) it is a limit point.)










share|cite|improve this question











$endgroup$












  • $begingroup$
    By the way, you tagged this "general-topology", but speak of radii of nhoods. Are you working in metric spaces?
    $endgroup$
    – David Mitra
    Aug 1 '12 at 22:06










  • $begingroup$
    Yes. I just started analysis (Walter Rudin The principle of mathematical analysis) and I came up with this question when reading the chapter named the basic topology
    $endgroup$
    – Tengu
    Aug 1 '12 at 22:09














6












6








6


2



$begingroup$


Is any interior point also a limit point?



Judging from the definition, I believe every interior point is a limit point, but I'm not sure about it. If this is wrong, could you give me a counterexample?



(Since an interior point $p$ of a set $E$ has a neighborhood $N$ with radius $r$ such that $N$ is a subset of $E$. Obviously any neighborhood of $p$ with radius less than $r$ is a subset of $E$. Also, any neighborhood with radius greater than $r$ contains $N$ as a subset, so (I think) it is a limit point.)










share|cite|improve this question











$endgroup$




Is any interior point also a limit point?



Judging from the definition, I believe every interior point is a limit point, but I'm not sure about it. If this is wrong, could you give me a counterexample?



(Since an interior point $p$ of a set $E$ has a neighborhood $N$ with radius $r$ such that $N$ is a subset of $E$. Obviously any neighborhood of $p$ with radius less than $r$ is a subset of $E$. Also, any neighborhood with radius greater than $r$ contains $N$ as a subset, so (I think) it is a limit point.)







general-topology






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share|cite|improve this question













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edited Aug 2 '12 at 4:31









enzotib

5,85321531




5,85321531










asked Aug 1 '12 at 21:59









TenguTengu

5331617




5331617












  • $begingroup$
    By the way, you tagged this "general-topology", but speak of radii of nhoods. Are you working in metric spaces?
    $endgroup$
    – David Mitra
    Aug 1 '12 at 22:06










  • $begingroup$
    Yes. I just started analysis (Walter Rudin The principle of mathematical analysis) and I came up with this question when reading the chapter named the basic topology
    $endgroup$
    – Tengu
    Aug 1 '12 at 22:09


















  • $begingroup$
    By the way, you tagged this "general-topology", but speak of radii of nhoods. Are you working in metric spaces?
    $endgroup$
    – David Mitra
    Aug 1 '12 at 22:06










  • $begingroup$
    Yes. I just started analysis (Walter Rudin The principle of mathematical analysis) and I came up with this question when reading the chapter named the basic topology
    $endgroup$
    – Tengu
    Aug 1 '12 at 22:09
















$begingroup$
By the way, you tagged this "general-topology", but speak of radii of nhoods. Are you working in metric spaces?
$endgroup$
– David Mitra
Aug 1 '12 at 22:06




$begingroup$
By the way, you tagged this "general-topology", but speak of radii of nhoods. Are you working in metric spaces?
$endgroup$
– David Mitra
Aug 1 '12 at 22:06












$begingroup$
Yes. I just started analysis (Walter Rudin The principle of mathematical analysis) and I came up with this question when reading the chapter named the basic topology
$endgroup$
– Tengu
Aug 1 '12 at 22:09




$begingroup$
Yes. I just started analysis (Walter Rudin The principle of mathematical analysis) and I came up with this question when reading the chapter named the basic topology
$endgroup$
– Tengu
Aug 1 '12 at 22:09










2 Answers
2






active

oldest

votes


















12












$begingroup$

A discrete space has no limit points, but every point is an interior point.






share|cite|improve this answer









$endgroup$













  • $begingroup$
    Brilliant answer, Ink!
    $endgroup$
    – WishingFish
    Jul 28 '13 at 3:13



















6












$begingroup$

No an interior point is not a limit point in general. Suppose you have $mathbb{N}$ with the discrete metric. The point $1$ is a interior point since ${1}$ is an open set. However, $1$ is not a limit point of $mathbb{N}$ because ${1}$ is an open neighborhood of $1$ which does not intersect $mathbb{N}$ in any point beside $1$.






share|cite|improve this answer









$endgroup$













  • $begingroup$
    Is a discrete space a space all of whose points are isolated points? (I could not find it in my textbook) Anyway I don't quite understand why 1 is a interior point of N...
    $endgroup$
    – Tengu
    Aug 1 '12 at 22:16










  • $begingroup$
    A discrete topology is a space where every subset is open. Topologically equivalent, it is a space endowed with the discrete metric. Since every subset is open, the set ${1}$ is open.
    $endgroup$
    – William
    Aug 1 '12 at 22:18












  • $begingroup$
    Thank you very much. I think I should study more in topology.
    $endgroup$
    – Tengu
    Aug 1 '12 at 22:23










  • $begingroup$
    @Tengu in the language of Rudin, the set of points in $mathbb{N}$ whose distance from 1 is less than, say, $frac{1}{2}$, is exactly ${1}$, thus this single-element set is an open ball (and thus open).
    $endgroup$
    – MartianInvader
    Aug 1 '12 at 22:23












  • $begingroup$
    Thank you for your reply. Since the neighborhood of 1 with radius 1/2 does not include any point except 1 on N, 1 is an open subset of N?
    $endgroup$
    – Tengu
    Aug 2 '12 at 23:09











Your Answer





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2 Answers
2






active

oldest

votes








2 Answers
2






active

oldest

votes









active

oldest

votes






active

oldest

votes









12












$begingroup$

A discrete space has no limit points, but every point is an interior point.






share|cite|improve this answer









$endgroup$













  • $begingroup$
    Brilliant answer, Ink!
    $endgroup$
    – WishingFish
    Jul 28 '13 at 3:13
















12












$begingroup$

A discrete space has no limit points, but every point is an interior point.






share|cite|improve this answer









$endgroup$













  • $begingroup$
    Brilliant answer, Ink!
    $endgroup$
    – WishingFish
    Jul 28 '13 at 3:13














12












12








12





$begingroup$

A discrete space has no limit points, but every point is an interior point.






share|cite|improve this answer









$endgroup$



A discrete space has no limit points, but every point is an interior point.







share|cite|improve this answer












share|cite|improve this answer



share|cite|improve this answer










answered Aug 1 '12 at 22:17









InkInk

4,46611017




4,46611017












  • $begingroup$
    Brilliant answer, Ink!
    $endgroup$
    – WishingFish
    Jul 28 '13 at 3:13


















  • $begingroup$
    Brilliant answer, Ink!
    $endgroup$
    – WishingFish
    Jul 28 '13 at 3:13
















$begingroup$
Brilliant answer, Ink!
$endgroup$
– WishingFish
Jul 28 '13 at 3:13




$begingroup$
Brilliant answer, Ink!
$endgroup$
– WishingFish
Jul 28 '13 at 3:13











6












$begingroup$

No an interior point is not a limit point in general. Suppose you have $mathbb{N}$ with the discrete metric. The point $1$ is a interior point since ${1}$ is an open set. However, $1$ is not a limit point of $mathbb{N}$ because ${1}$ is an open neighborhood of $1$ which does not intersect $mathbb{N}$ in any point beside $1$.






share|cite|improve this answer









$endgroup$













  • $begingroup$
    Is a discrete space a space all of whose points are isolated points? (I could not find it in my textbook) Anyway I don't quite understand why 1 is a interior point of N...
    $endgroup$
    – Tengu
    Aug 1 '12 at 22:16










  • $begingroup$
    A discrete topology is a space where every subset is open. Topologically equivalent, it is a space endowed with the discrete metric. Since every subset is open, the set ${1}$ is open.
    $endgroup$
    – William
    Aug 1 '12 at 22:18












  • $begingroup$
    Thank you very much. I think I should study more in topology.
    $endgroup$
    – Tengu
    Aug 1 '12 at 22:23










  • $begingroup$
    @Tengu in the language of Rudin, the set of points in $mathbb{N}$ whose distance from 1 is less than, say, $frac{1}{2}$, is exactly ${1}$, thus this single-element set is an open ball (and thus open).
    $endgroup$
    – MartianInvader
    Aug 1 '12 at 22:23












  • $begingroup$
    Thank you for your reply. Since the neighborhood of 1 with radius 1/2 does not include any point except 1 on N, 1 is an open subset of N?
    $endgroup$
    – Tengu
    Aug 2 '12 at 23:09
















6












$begingroup$

No an interior point is not a limit point in general. Suppose you have $mathbb{N}$ with the discrete metric. The point $1$ is a interior point since ${1}$ is an open set. However, $1$ is not a limit point of $mathbb{N}$ because ${1}$ is an open neighborhood of $1$ which does not intersect $mathbb{N}$ in any point beside $1$.






share|cite|improve this answer









$endgroup$













  • $begingroup$
    Is a discrete space a space all of whose points are isolated points? (I could not find it in my textbook) Anyway I don't quite understand why 1 is a interior point of N...
    $endgroup$
    – Tengu
    Aug 1 '12 at 22:16










  • $begingroup$
    A discrete topology is a space where every subset is open. Topologically equivalent, it is a space endowed with the discrete metric. Since every subset is open, the set ${1}$ is open.
    $endgroup$
    – William
    Aug 1 '12 at 22:18












  • $begingroup$
    Thank you very much. I think I should study more in topology.
    $endgroup$
    – Tengu
    Aug 1 '12 at 22:23










  • $begingroup$
    @Tengu in the language of Rudin, the set of points in $mathbb{N}$ whose distance from 1 is less than, say, $frac{1}{2}$, is exactly ${1}$, thus this single-element set is an open ball (and thus open).
    $endgroup$
    – MartianInvader
    Aug 1 '12 at 22:23












  • $begingroup$
    Thank you for your reply. Since the neighborhood of 1 with radius 1/2 does not include any point except 1 on N, 1 is an open subset of N?
    $endgroup$
    – Tengu
    Aug 2 '12 at 23:09














6












6








6





$begingroup$

No an interior point is not a limit point in general. Suppose you have $mathbb{N}$ with the discrete metric. The point $1$ is a interior point since ${1}$ is an open set. However, $1$ is not a limit point of $mathbb{N}$ because ${1}$ is an open neighborhood of $1$ which does not intersect $mathbb{N}$ in any point beside $1$.






share|cite|improve this answer









$endgroup$



No an interior point is not a limit point in general. Suppose you have $mathbb{N}$ with the discrete metric. The point $1$ is a interior point since ${1}$ is an open set. However, $1$ is not a limit point of $mathbb{N}$ because ${1}$ is an open neighborhood of $1$ which does not intersect $mathbb{N}$ in any point beside $1$.







share|cite|improve this answer












share|cite|improve this answer



share|cite|improve this answer










answered Aug 1 '12 at 22:03









WilliamWilliam

17.3k22256




17.3k22256












  • $begingroup$
    Is a discrete space a space all of whose points are isolated points? (I could not find it in my textbook) Anyway I don't quite understand why 1 is a interior point of N...
    $endgroup$
    – Tengu
    Aug 1 '12 at 22:16










  • $begingroup$
    A discrete topology is a space where every subset is open. Topologically equivalent, it is a space endowed with the discrete metric. Since every subset is open, the set ${1}$ is open.
    $endgroup$
    – William
    Aug 1 '12 at 22:18












  • $begingroup$
    Thank you very much. I think I should study more in topology.
    $endgroup$
    – Tengu
    Aug 1 '12 at 22:23










  • $begingroup$
    @Tengu in the language of Rudin, the set of points in $mathbb{N}$ whose distance from 1 is less than, say, $frac{1}{2}$, is exactly ${1}$, thus this single-element set is an open ball (and thus open).
    $endgroup$
    – MartianInvader
    Aug 1 '12 at 22:23












  • $begingroup$
    Thank you for your reply. Since the neighborhood of 1 with radius 1/2 does not include any point except 1 on N, 1 is an open subset of N?
    $endgroup$
    – Tengu
    Aug 2 '12 at 23:09


















  • $begingroup$
    Is a discrete space a space all of whose points are isolated points? (I could not find it in my textbook) Anyway I don't quite understand why 1 is a interior point of N...
    $endgroup$
    – Tengu
    Aug 1 '12 at 22:16










  • $begingroup$
    A discrete topology is a space where every subset is open. Topologically equivalent, it is a space endowed with the discrete metric. Since every subset is open, the set ${1}$ is open.
    $endgroup$
    – William
    Aug 1 '12 at 22:18












  • $begingroup$
    Thank you very much. I think I should study more in topology.
    $endgroup$
    – Tengu
    Aug 1 '12 at 22:23










  • $begingroup$
    @Tengu in the language of Rudin, the set of points in $mathbb{N}$ whose distance from 1 is less than, say, $frac{1}{2}$, is exactly ${1}$, thus this single-element set is an open ball (and thus open).
    $endgroup$
    – MartianInvader
    Aug 1 '12 at 22:23












  • $begingroup$
    Thank you for your reply. Since the neighborhood of 1 with radius 1/2 does not include any point except 1 on N, 1 is an open subset of N?
    $endgroup$
    – Tengu
    Aug 2 '12 at 23:09
















$begingroup$
Is a discrete space a space all of whose points are isolated points? (I could not find it in my textbook) Anyway I don't quite understand why 1 is a interior point of N...
$endgroup$
– Tengu
Aug 1 '12 at 22:16




$begingroup$
Is a discrete space a space all of whose points are isolated points? (I could not find it in my textbook) Anyway I don't quite understand why 1 is a interior point of N...
$endgroup$
– Tengu
Aug 1 '12 at 22:16












$begingroup$
A discrete topology is a space where every subset is open. Topologically equivalent, it is a space endowed with the discrete metric. Since every subset is open, the set ${1}$ is open.
$endgroup$
– William
Aug 1 '12 at 22:18






$begingroup$
A discrete topology is a space where every subset is open. Topologically equivalent, it is a space endowed with the discrete metric. Since every subset is open, the set ${1}$ is open.
$endgroup$
– William
Aug 1 '12 at 22:18














$begingroup$
Thank you very much. I think I should study more in topology.
$endgroup$
– Tengu
Aug 1 '12 at 22:23




$begingroup$
Thank you very much. I think I should study more in topology.
$endgroup$
– Tengu
Aug 1 '12 at 22:23












$begingroup$
@Tengu in the language of Rudin, the set of points in $mathbb{N}$ whose distance from 1 is less than, say, $frac{1}{2}$, is exactly ${1}$, thus this single-element set is an open ball (and thus open).
$endgroup$
– MartianInvader
Aug 1 '12 at 22:23






$begingroup$
@Tengu in the language of Rudin, the set of points in $mathbb{N}$ whose distance from 1 is less than, say, $frac{1}{2}$, is exactly ${1}$, thus this single-element set is an open ball (and thus open).
$endgroup$
– MartianInvader
Aug 1 '12 at 22:23














$begingroup$
Thank you for your reply. Since the neighborhood of 1 with radius 1/2 does not include any point except 1 on N, 1 is an open subset of N?
$endgroup$
– Tengu
Aug 2 '12 at 23:09




$begingroup$
Thank you for your reply. Since the neighborhood of 1 with radius 1/2 does not include any point except 1 on N, 1 is an open subset of N?
$endgroup$
– Tengu
Aug 2 '12 at 23:09


















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