Mixing
Netsed dictionary in Python
-1
Trying to type a nested dictionary, but the results show the nested value with last entry. I guess this is because I'm trying to add the nested key with is the same for all:
for i in range(15, 19, 1):
left_index = counters[i].find(']')
right_index = counters[i].rfind(': ')
key = counters[i][left_index + 1:right_index]
value = counters[i][right_index + 1:].replace('[(','').replace(')]','').replace(') - (',' ').strip().split(' ')
d1['value'] = value[0]
d1['minimum'] = value[1]
d1['maximum'] = value[-1]
print 'key: ',key, 'value: ', d1
d[key] = d1
encoder.FLOAT_REPR = lambda x: format(x, '.5f')
print json.dumps(d, indent=5, sort_keys=True)
And the result is:
key: Socket/Modem 1/Bytes sent value: {'minimum': '0', 'maximum': '2482262614', 'value': '2482262614'}
key: Socket/Modem 1/recv value: {'minimum': '0', 'maximum': '19646', 'value': '19646'}
key: Socket/Modem 1/send value: {'minimum': '0', 'maximum': '2078818', 'value': '2078818'}
key: StreamerEngine/Bonding/Priority queue/Packets of '' priority dequeued value: {'minimum': '0', 'maximum': '0', 'value': '0'}
{
" Socket/Modem 1/Bytes sent": {
"maximum": "0",
"minimum": "0",
"value": "0"
},
" Socket/Modem 1/recv": {
"maximum": "0",
"minimum": "0",
"value": "0"
},
" Socket/Modem 1/send": {
"maximum": "0",
"minimum": "0",
"value": "0"
},
" StreamerEngine/Bonding/Priority queue/Packets of '' priority dequeued": {
"maximum": "0",
"minimum": "0",
"value": "0"
}
}
So you can see that the d1 dictionary is typed well but the accumulated dictionary d is not.
python dictionary
edited Nov 21 '18 at 15:00
John Kugelman
243k54405457
asked Nov 21 '18 at 13:40
ItaybzItaybz
134
add a comment |
-1
Trying to type a nested dictionary, but the results show the nested value with last entry. I guess this is because I'm trying to add the nested key with is the same for all:
for i in range(15, 19, 1):
left_index = counters[i].find(']')
right_index = counters[i].rfind(': ')
key = counters[i][left_index + 1:right_index]
value = counters[i][right_index + 1:].replace('[(','').replace(')]','').replace(') - (',' ').strip().split(' ')
d1['value'] = value[0]
d1['minimum'] = value[1]
d1['maximum'] = value[-1]
print 'key: ',key, 'value: ', d1
d[key] = d1
encoder.FLOAT_REPR = lambda x: format(x, '.5f')
print json.dumps(d, indent=5, sort_keys=True)
And the result is:
key: Socket/Modem 1/Bytes sent value: {'minimum': '0', 'maximum': '2482262614', 'value': '2482262614'}
key: Socket/Modem 1/recv value: {'minimum': '0', 'maximum': '19646', 'value': '19646'}
key: Socket/Modem 1/send value: {'minimum': '0', 'maximum': '2078818', 'value': '2078818'}
key: StreamerEngine/Bonding/Priority queue/Packets of '' priority dequeued value: {'minimum': '0', 'maximum': '0', 'value': '0'}
{
" Socket/Modem 1/Bytes sent": {
"maximum": "0",
"minimum": "0",
"value": "0"
},
" Socket/Modem 1/recv": {
"maximum": "0",
"minimum": "0",
"value": "0"
},
" Socket/Modem 1/send": {
"maximum": "0",
"minimum": "0",
"value": "0"
},
" StreamerEngine/Bonding/Priority queue/Packets of '' priority dequeued": {
"maximum": "0",
"minimum": "0",
"value": "0"
}
}
So you can see that the d1 dictionary is typed well but the accumulated dictionary d is not.
python dictionary
edited Nov 21 '18 at 15:00
John Kugelman
243k54405457
asked Nov 21 '18 at 13:40
ItaybzItaybz
134
Possible duplicate of Defining a nested dictionary in python
– Isma
Nov 21 '18 at 13:43
add a comment |
-1
-1
-1
Trying to type a nested dictionary, but the results show the nested value with last entry. I guess this is because I'm trying to add the nested key with is the same for all:
for i in range(15, 19, 1):
left_index = counters[i].find(']')
right_index = counters[i].rfind(': ')
key = counters[i][left_index + 1:right_index]
value = counters[i][right_index + 1:].replace('[(','').replace(')]','').replace(') - (',' ').strip().split(' ')
d1['value'] = value[0]
d1['minimum'] = value[1]
d1['maximum'] = value[-1]
print 'key: ',key, 'value: ', d1
d[key] = d1
encoder.FLOAT_REPR = lambda x: format(x, '.5f')
print json.dumps(d, indent=5, sort_keys=True)
And the result is:
key: Socket/Modem 1/Bytes sent value: {'minimum': '0', 'maximum': '2482262614', 'value': '2482262614'}
key: Socket/Modem 1/recv value: {'minimum': '0', 'maximum': '19646', 'value': '19646'}
key: Socket/Modem 1/send value: {'minimum': '0', 'maximum': '2078818', 'value': '2078818'}
key: StreamerEngine/Bonding/Priority queue/Packets of '' priority dequeued value: {'minimum': '0', 'maximum': '0', 'value': '0'}
{
" Socket/Modem 1/Bytes sent": {
"maximum": "0",
"minimum": "0",
"value": "0"
},
" Socket/Modem 1/recv": {
"maximum": "0",
"minimum": "0",
"value": "0"
},
" Socket/Modem 1/send": {
"maximum": "0",
"minimum": "0",
"value": "0"
},
" StreamerEngine/Bonding/Priority queue/Packets of '' priority dequeued": {
"maximum": "0",
"minimum": "0",
"value": "0"
}
}
So you can see that the d1 dictionary is typed well but the accumulated dictionary d is not.
python dictionary
edited Nov 21 '18 at 15:00
John Kugelman
243k54405457
asked Nov 21 '18 at 13:40
ItaybzItaybz
134
Trying to type a nested dictionary, but the results show the nested value with last entry. I guess this is because I'm trying to add the nested key with is the same for all:
for i in range(15, 19, 1):
left_index = counters[i].find(']')
right_index = counters[i].rfind(': ')
key = counters[i][left_index + 1:right_index]
value = counters[i][right_index + 1:].replace('[(','').replace(')]','').replace(') - (',' ').strip().split(' ')
d1['value'] = value[0]
d1['minimum'] = value[1]
d1['maximum'] = value[-1]
print 'key: ',key, 'value: ', d1
d[key] = d1
encoder.FLOAT_REPR = lambda x: format(x, '.5f')
print json.dumps(d, indent=5, sort_keys=True)
And the result is:
key: Socket/Modem 1/Bytes sent value: {'minimum': '0', 'maximum': '2482262614', 'value': '2482262614'}
key: Socket/Modem 1/recv value: {'minimum': '0', 'maximum': '19646', 'value': '19646'}
key: Socket/Modem 1/send value: {'minimum': '0', 'maximum': '2078818', 'value': '2078818'}
key: StreamerEngine/Bonding/Priority queue/Packets of '' priority dequeued value: {'minimum': '0', 'maximum': '0', 'value': '0'}
{
" Socket/Modem 1/Bytes sent": {
"maximum": "0",
"minimum": "0",
"value": "0"
},
" Socket/Modem 1/recv": {
"maximum": "0",
"minimum": "0",
"value": "0"
},
" Socket/Modem 1/send": {
"maximum": "0",
"minimum": "0",
"value": "0"
},
" StreamerEngine/Bonding/Priority queue/Packets of '' priority dequeued": {
"maximum": "0",
"minimum": "0",
"value": "0"
}
}
So you can see that the d1 dictionary is typed well but the accumulated dictionary d is not.
python dictionary
python dictionary
edited Nov 21 '18 at 15:00
John Kugelman
243k54405457
asked Nov 21 '18 at 13:40
ItaybzItaybz
134
edited Nov 21 '18 at 15:00
John Kugelman
243k54405457
asked Nov 21 '18 at 13:40
ItaybzItaybz
134
edited Nov 21 '18 at 15:00
John Kugelman
243k54405457
edited Nov 21 '18 at 15:00
John Kugelman
243k54405457
edited Nov 21 '18 at 15:00
John Kugelman
243k54405457
243k54405457
asked Nov 21 '18 at 13:40
ItaybzItaybz
134
asked Nov 21 '18 at 13:40
ItaybzItaybz
134
asked Nov 21 '18 at 13:40
ItaybzItaybz
134
134
Possible duplicate of Defining a nested dictionary in python
– Isma
Nov 21 '18 at 13:43
add a comment |
Possible duplicate of Defining a nested dictionary in python
– Isma
Nov 21 '18 at 13:43
Possible duplicate of Defining a nested dictionary in python
– Isma
Nov 21 '18 at 13:43
Possible duplicate of Defining a nested dictionary in python
– Isma
Nov 21 '18 at 13:43
add a comment |
1 Answer
1
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0
d1 is (probably) declared outside of your loop, so you are using the same object again and again, that's why the last assigned values are used in all other dicts.
Instead define d1 inside your loop:
for i in range(15, 19, 1):
left_index = counters[i].find(']')
right_index = counters[i].rfind(': ')
key = counters[i][left_index + 1:right_index]
value = counters[i][right_index + 1:].replace('[(','').replace(')]','').replace(') - (',' ').strip().split(' ')
d1 = {} # <- new dict!
d1['value'] = value[0]
d1['minimum'] = value[1]
d1['maximum'] = value[-1]
print 'key: ',key, 'value: ', d1
d[key] = d1
answered Nov 21 '18 at 13:45
Mike ScottyMike Scotty
5,81052033
add a comment |
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1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
0
d1 is (probably) declared outside of your loop, so you are using the same object again and again, that's why the last assigned values are used in all other dicts.
Instead define d1 inside your loop:
for i in range(15, 19, 1):
left_index = counters[i].find(']')
right_index = counters[i].rfind(': ')
key = counters[i][left_index + 1:right_index]
value = counters[i][right_index + 1:].replace('[(','').replace(')]','').replace(') - (',' ').strip().split(' ')
d1 = {} # <- new dict!
d1['value'] = value[0]
d1['minimum'] = value[1]
d1['maximum'] = value[-1]
print 'key: ',key, 'value: ', d1
d[key] = d1
answered Nov 21 '18 at 13:45
Mike ScottyMike Scotty
5,81052033
add a comment |
0
d1 is (probably) declared outside of your loop, so you are using the same object again and again, that's why the last assigned values are used in all other dicts.
Instead define d1 inside your loop:
for i in range(15, 19, 1):
left_index = counters[i].find(']')
right_index = counters[i].rfind(': ')
key = counters[i][left_index + 1:right_index]
value = counters[i][right_index + 1:].replace('[(','').replace(')]','').replace(') - (',' ').strip().split(' ')
d1 = {} # <- new dict!
d1['value'] = value[0]
d1['minimum'] = value[1]
d1['maximum'] = value[-1]
print 'key: ',key, 'value: ', d1
d[key] = d1
answered Nov 21 '18 at 13:45
Mike ScottyMike Scotty
5,81052033
add a comment |
0
0
0
d1 is (probably) declared outside of your loop, so you are using the same object again and again, that's why the last assigned values are used in all other dicts.
Instead define d1 inside your loop:
for i in range(15, 19, 1):
left_index = counters[i].find(']')
right_index = counters[i].rfind(': ')
key = counters[i][left_index + 1:right_index]
value = counters[i][right_index + 1:].replace('[(','').replace(')]','').replace(') - (',' ').strip().split(' ')
d1 = {} # <- new dict!
d1['value'] = value[0]
d1['minimum'] = value[1]
d1['maximum'] = value[-1]
print 'key: ',key, 'value: ', d1
d[key] = d1
answered Nov 21 '18 at 13:45
Mike ScottyMike Scotty
5,81052033
d1 is (probably) declared outside of your loop, so you are using the same object again and again, that's why the last assigned values are used in all other dicts.
Instead define d1 inside your loop:
for i in range(15, 19, 1):
left_index = counters[i].find(']')
right_index = counters[i].rfind(': ')
key = counters[i][left_index + 1:right_index]
value = counters[i][right_index + 1:].replace('[(','').replace(')]','').replace(') - (',' ').strip().split(' ')
d1 = {} # <- new dict!
d1['value'] = value[0]
d1['minimum'] = value[1]
d1['maximum'] = value[-1]
print 'key: ',key, 'value: ', d1
d[key] = d1
answered Nov 21 '18 at 13:45
Mike ScottyMike Scotty
5,81052033
answered Nov 21 '18 at 13:45
Mike ScottyMike Scotty
5,81052033
answered Nov 21 '18 at 13:45
Mike ScottyMike Scotty
5,81052033
answered Nov 21 '18 at 13:45
Mike ScottyMike Scotty
5,81052033
5,81052033
add a comment |
add a comment |
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Possible duplicate of Defining a nested dictionary in python
– Isma
Nov 21 '18 at 13:43