approximating a decreasing function with hyperbolic functions












1












$begingroup$


Let $y = f(x)$, where $x, y in mathbb{R}_1$ and $f in mathcal{C}^1$ with $f'(x) le 0$.



Partition the range using $t$ points ${y_1, ldots, y_t}$ and - on each interval $[y_m, y_{m+1})$ - approximate the function $f$ by $g(x) = frac{b_m}{y}$ for some constant $b_m$, chosen so that $f(x_m) = g(x_m)$ for $x_m = f^{-1}(y_m)$.



This approach is ad hoc. If I wish to minimise the approximation error, $||g(x) - f(x)||$, is there a better way to proceed (e.g. how to choose the ${y_1, ldots, y_t}$)?



(n.b. if $b_{m+1} < b_m$, then $g$ is not a function over the full domain. I am actually interested in the inverse functions, $x = f^{-1}(y)$ and $x = g^{-1}(y)$, where this is not a problem.)










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$endgroup$

















    1












    $begingroup$


    Let $y = f(x)$, where $x, y in mathbb{R}_1$ and $f in mathcal{C}^1$ with $f'(x) le 0$.



    Partition the range using $t$ points ${y_1, ldots, y_t}$ and - on each interval $[y_m, y_{m+1})$ - approximate the function $f$ by $g(x) = frac{b_m}{y}$ for some constant $b_m$, chosen so that $f(x_m) = g(x_m)$ for $x_m = f^{-1}(y_m)$.



    This approach is ad hoc. If I wish to minimise the approximation error, $||g(x) - f(x)||$, is there a better way to proceed (e.g. how to choose the ${y_1, ldots, y_t}$)?



    (n.b. if $b_{m+1} < b_m$, then $g$ is not a function over the full domain. I am actually interested in the inverse functions, $x = f^{-1}(y)$ and $x = g^{-1}(y)$, where this is not a problem.)










    share|cite|improve this question











    $endgroup$















      1












      1








      1





      $begingroup$


      Let $y = f(x)$, where $x, y in mathbb{R}_1$ and $f in mathcal{C}^1$ with $f'(x) le 0$.



      Partition the range using $t$ points ${y_1, ldots, y_t}$ and - on each interval $[y_m, y_{m+1})$ - approximate the function $f$ by $g(x) = frac{b_m}{y}$ for some constant $b_m$, chosen so that $f(x_m) = g(x_m)$ for $x_m = f^{-1}(y_m)$.



      This approach is ad hoc. If I wish to minimise the approximation error, $||g(x) - f(x)||$, is there a better way to proceed (e.g. how to choose the ${y_1, ldots, y_t}$)?



      (n.b. if $b_{m+1} < b_m$, then $g$ is not a function over the full domain. I am actually interested in the inverse functions, $x = f^{-1}(y)$ and $x = g^{-1}(y)$, where this is not a problem.)










      share|cite|improve this question











      $endgroup$




      Let $y = f(x)$, where $x, y in mathbb{R}_1$ and $f in mathcal{C}^1$ with $f'(x) le 0$.



      Partition the range using $t$ points ${y_1, ldots, y_t}$ and - on each interval $[y_m, y_{m+1})$ - approximate the function $f$ by $g(x) = frac{b_m}{y}$ for some constant $b_m$, chosen so that $f(x_m) = g(x_m)$ for $x_m = f^{-1}(y_m)$.



      This approach is ad hoc. If I wish to minimise the approximation error, $||g(x) - f(x)||$, is there a better way to proceed (e.g. how to choose the ${y_1, ldots, y_t}$)?



      (n.b. if $b_{m+1} < b_m$, then $g$ is not a function over the full domain. I am actually interested in the inverse functions, $x = f^{-1}(y)$ and $x = g^{-1}(y)$, where this is not a problem.)







      real-analysis functional-analysis approximation-theory






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      share|cite|improve this question













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      edited Jan 23 at 13:51







      Colin Rowat

















      asked Jan 23 at 9:59









      Colin RowatColin Rowat

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