Mixing
Find coordinates of intersection of vector and a square's edges
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Not big problem, but I can't find a formula for the following stuff.
I have this kind of things:
(I was not able to draw vector in my application so I represented the source by point and the end of the arrow by nothing, and the vector is the segment) ; also don't pay attention the red ones on this image)
So I'll have a lot of vectors composed of a source point (inside the square) and a destination point (inside or outside the square).
The square is delimited by the four black points in the corners.
I need a formula to get the coordinates of the intersection with the edge (if there is one).
For example I'd need the coordinates of the "points" on the following image:
Anybody has an idea on how to achieve that?
geometry
asked 14 hours ago
Axel Carré
112
add a comment |
up vote
0
down vote
favorite
Not big problem, but I can't find a formula for the following stuff.
I have this kind of things:
(I was not able to draw vector in my application so I represented the source by point and the end of the arrow by nothing, and the vector is the segment) ; also don't pay attention the red ones on this image)
So I'll have a lot of vectors composed of a source point (inside the square) and a destination point (inside or outside the square).
The square is delimited by the four black points in the corners.
I need a formula to get the coordinates of the intersection with the edge (if there is one).
For example I'd need the coordinates of the "points" on the following image:
Anybody has an idea on how to achieve that?
geometry
asked 14 hours ago
Axel Carré
112
It is not clear how you define the red vectors and how they relate to the black vectors in the other drawing. You have 5 red vectors(?) in the square...
– Moti
13 hours ago
Just edited my post.
– Axel Carré
6 hours ago
In your case, the direction seems to be irrelevant. Is there no reason you don't work with segments? (Also, note that vectors typically have magnitude and direction, but not a starting point - they can be "moved around" and still be the same vector).
– Todor Markov
5 hours ago
Yes I just don't know how to call a vector with a starting point, maybe a translation? I figured out a formula by myself anyways, I was a bit tired, that was not that hard finally sorry to annoye ans thanks.
– Axel Carré
4 hours ago
And yes direction was irrelevant you were right.
– Axel Carré
4 hours ago
add a comment |
up vote
0
down vote
favorite
up vote
0
down vote
favorite
Not big problem, but I can't find a formula for the following stuff.
I have this kind of things:
(I was not able to draw vector in my application so I represented the source by point and the end of the arrow by nothing, and the vector is the segment) ; also don't pay attention the red ones on this image)
So I'll have a lot of vectors composed of a source point (inside the square) and a destination point (inside or outside the square).
The square is delimited by the four black points in the corners.
I need a formula to get the coordinates of the intersection with the edge (if there is one).
For example I'd need the coordinates of the "points" on the following image:
Anybody has an idea on how to achieve that?
geometry
asked 14 hours ago
Axel Carré
112
Not big problem, but I can't find a formula for the following stuff.
I have this kind of things:
(I was not able to draw vector in my application so I represented the source by point and the end of the arrow by nothing, and the vector is the segment) ; also don't pay attention the red ones on this image)
So I'll have a lot of vectors composed of a source point (inside the square) and a destination point (inside or outside the square).
The square is delimited by the four black points in the corners.
I need a formula to get the coordinates of the intersection with the edge (if there is one).
For example I'd need the coordinates of the "points" on the following image:
Anybody has an idea on how to achieve that?
geometry
geometry
asked 14 hours ago
Axel Carré
112
asked 14 hours ago
Axel Carré
112
edited 6 hours ago
asked 14 hours ago
Axel Carré
112
asked 14 hours ago
Axel Carré
112
asked 14 hours ago
Axel Carré
112
112
It is not clear how you define the red vectors and how they relate to the black vectors in the other drawing. You have 5 red vectors(?) in the square...
– Moti
13 hours ago
Just edited my post.
– Axel Carré
6 hours ago
In your case, the direction seems to be irrelevant. Is there no reason you don't work with segments? (Also, note that vectors typically have magnitude and direction, but not a starting point - they can be "moved around" and still be the same vector).
– Todor Markov
5 hours ago
Yes I just don't know how to call a vector with a starting point, maybe a translation? I figured out a formula by myself anyways, I was a bit tired, that was not that hard finally sorry to annoye ans thanks.
– Axel Carré
4 hours ago
And yes direction was irrelevant you were right.
– Axel Carré
4 hours ago
add a comment |
It is not clear how you define the red vectors and how they relate to the black vectors in the other drawing. You have 5 red vectors(?) in the square...
– Moti
13 hours ago
Just edited my post.
– Axel Carré
6 hours ago
In your case, the direction seems to be irrelevant. Is there no reason you don't work with segments? (Also, note that vectors typically have magnitude and direction, but not a starting point - they can be "moved around" and still be the same vector).
– Todor Markov
5 hours ago
Yes I just don't know how to call a vector with a starting point, maybe a translation? I figured out a formula by myself anyways, I was a bit tired, that was not that hard finally sorry to annoye ans thanks.
– Axel Carré
4 hours ago
And yes direction was irrelevant you were right.
– Axel Carré
4 hours ago
It is not clear how you define the red vectors and how they relate to the black vectors in the other drawing. You have 5 red vectors(?) in the square...
– Moti
13 hours ago
It is not clear how you define the red vectors and how they relate to the black vectors in the other drawing. You have 5 red vectors(?) in the square...
– Moti
13 hours ago
Just edited my post.
– Axel Carré
6 hours ago
Just edited my post.
– Axel Carré
6 hours ago
In your case, the direction seems to be irrelevant. Is there no reason you don't work with segments? (Also, note that vectors typically have magnitude and direction, but not a starting point - they can be "moved around" and still be the same vector).
– Todor Markov
5 hours ago
In your case, the direction seems to be irrelevant. Is there no reason you don't work with segments? (Also, note that vectors typically have magnitude and direction, but not a starting point - they can be "moved around" and still be the same vector).
– Todor Markov
5 hours ago
Yes I just don't know how to call a vector with a starting point, maybe a translation? I figured out a formula by myself anyways, I was a bit tired, that was not that hard finally sorry to annoye ans thanks.
– Axel Carré
4 hours ago
Yes I just don't know how to call a vector with a starting point, maybe a translation? I figured out a formula by myself anyways, I was a bit tired, that was not that hard finally sorry to annoye ans thanks.
– Axel Carré
4 hours ago
And yes direction was irrelevant you were right.
– Axel Carré
4 hours ago
And yes direction was irrelevant you were right.
– Axel Carré
4 hours ago
add a comment |
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It is not clear how you define the red vectors and how they relate to the black vectors in the other drawing. You have 5 red vectors(?) in the square...
– Moti
13 hours ago
Just edited my post.
– Axel Carré
6 hours ago
In your case, the direction seems to be irrelevant. Is there no reason you don't work with segments? (Also, note that vectors typically have magnitude and direction, but not a starting point - they can be "moved around" and still be the same vector).
– Todor Markov
5 hours ago
Yes I just don't know how to call a vector with a starting point, maybe a translation? I figured out a formula by myself anyways, I was a bit tired, that was not that hard finally sorry to annoye ans thanks.
– Axel Carré
4 hours ago
And yes direction was irrelevant you were right.
– Axel Carré
4 hours ago