How can I calculate a Bernoulli random variable that features retries?











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I have a situation modeled by a Bernoulli random variable with $p=0.4$, but with the added complication that five failures can be "rerolled" for the same probability. I can't use a binomial distribution on that, so how can I determine how many successes I'll get in a number of trials, say 20?






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    I have a situation modeled by a Bernoulli random variable with $p=0.4$, but with the added complication that five failures can be "rerolled" for the same probability. I can't use a binomial distribution on that, so how can I determine how many successes I'll get in a number of trials, say 20?






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      I have a situation modeled by a Bernoulli random variable with $p=0.4$, but with the added complication that five failures can be "rerolled" for the same probability. I can't use a binomial distribution on that, so how can I determine how many successes I'll get in a number of trials, say 20?






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      I have a situation modeled by a Bernoulli random variable with $p=0.4$, but with the added complication that five failures can be "rerolled" for the same probability. I can't use a binomial distribution on that, so how can I determine how many successes I'll get in a number of trials, say 20?






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      asked 2 days ago









      Raiden Worley

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          Found an answer! I used a binomial distribution to figure out how many successes and failures I would have. Then I chose 5 of the failures and figured that 0.4(5) of them would succeed after retry, and added that to the number of successes.






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            Found an answer! I used a binomial distribution to figure out how many successes and failures I would have. Then I chose 5 of the failures and figured that 0.4(5) of them would succeed after retry, and added that to the number of successes.






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              Found an answer! I used a binomial distribution to figure out how many successes and failures I would have. Then I chose 5 of the failures and figured that 0.4(5) of them would succeed after retry, and added that to the number of successes.






              share|cite|improve this answer























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                up vote
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                Found an answer! I used a binomial distribution to figure out how many successes and failures I would have. Then I chose 5 of the failures and figured that 0.4(5) of them would succeed after retry, and added that to the number of successes.






                share|cite|improve this answer












                Found an answer! I used a binomial distribution to figure out how many successes and failures I would have. Then I chose 5 of the failures and figured that 0.4(5) of them would succeed after retry, and added that to the number of successes.







                share|cite|improve this answer












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                share|cite|improve this answer










                answered 2 days ago









                Raiden Worley

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