Mixing
Poker Statistics & Probability
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Probability of being dealt pairs
$4P2 * 13over 52P2$ = 5.88%, 4 different ways to choose from and arrange 4 cards from a suit times thirteen suits.
Given Board State {10D, 10C, JD, ?, ?} and 2 dead hands and one active hand, and your hand {JC, JS}:
Probability of other player holding two tens:
$2 over 43*42 $ = 0.11%, all the dead cards mean that 43 are remaining and there are 43P2 ways of choosing hands for that and only 2 in which the opposite player would have 2 10s.
River is Jack:
$frac{1}{41} + frac{1}{40}$ = 4.9%, either the first one is a Jack or the second one is a Jack
Dealt QD, probability of Royal Flush:
$frac{3P2*39}{41P3}$ = 14.6%, 3P2 ways to arrange the 2 cards you need and the other card you don't need over the possible ways you could be dealt the cards.
$frac{3P2}{39P2}$ = 0.6%, 3P2 ways to choose the jacks that you can have from 39P2 choices.
I apologize profusely because I am not very good at statistics and this has been troubling me greatly. I want to know the flaws in how I am thinking.
probability statistics poker
asked 2 days ago
Ryan Schaefer
991
add a comment |
up vote
-1
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Probability of being dealt pairs
$4P2 * 13over 52P2$ = 5.88%, 4 different ways to choose from and arrange 4 cards from a suit times thirteen suits.
Given Board State {10D, 10C, JD, ?, ?} and 2 dead hands and one active hand, and your hand {JC, JS}:
Probability of other player holding two tens:
$2 over 43*42 $ = 0.11%, all the dead cards mean that 43 are remaining and there are 43P2 ways of choosing hands for that and only 2 in which the opposite player would have 2 10s.
River is Jack:
$frac{1}{41} + frac{1}{40}$ = 4.9%, either the first one is a Jack or the second one is a Jack
Dealt QD, probability of Royal Flush:
$frac{3P2*39}{41P3}$ = 14.6%, 3P2 ways to arrange the 2 cards you need and the other card you don't need over the possible ways you could be dealt the cards.
$frac{3P2}{39P2}$ = 0.6%, 3P2 ways to choose the jacks that you can have from 39P2 choices.
I apologize profusely because I am not very good at statistics and this has been troubling me greatly. I want to know the flaws in how I am thinking.
probability statistics poker
asked 2 days ago
Ryan Schaefer
991
add a comment |
up vote
-1
down vote
favorite
up vote
-1
down vote
favorite
Probability of being dealt pairs
$4P2 * 13over 52P2$ = 5.88%, 4 different ways to choose from and arrange 4 cards from a suit times thirteen suits.
Given Board State {10D, 10C, JD, ?, ?} and 2 dead hands and one active hand, and your hand {JC, JS}:
Probability of other player holding two tens:
$2 over 43*42 $ = 0.11%, all the dead cards mean that 43 are remaining and there are 43P2 ways of choosing hands for that and only 2 in which the opposite player would have 2 10s.
River is Jack:
$frac{1}{41} + frac{1}{40}$ = 4.9%, either the first one is a Jack or the second one is a Jack
Dealt QD, probability of Royal Flush:
$frac{3P2*39}{41P3}$ = 14.6%, 3P2 ways to arrange the 2 cards you need and the other card you don't need over the possible ways you could be dealt the cards.
$frac{3P2}{39P2}$ = 0.6%, 3P2 ways to choose the jacks that you can have from 39P2 choices.
I apologize profusely because I am not very good at statistics and this has been troubling me greatly. I want to know the flaws in how I am thinking.
probability statistics poker
asked 2 days ago
Ryan Schaefer
991
Probability of being dealt pairs
$4P2 * 13over 52P2$ = 5.88%, 4 different ways to choose from and arrange 4 cards from a suit times thirteen suits.
Given Board State {10D, 10C, JD, ?, ?} and 2 dead hands and one active hand, and your hand {JC, JS}:
Probability of other player holding two tens:
$2 over 43*42 $ = 0.11%, all the dead cards mean that 43 are remaining and there are 43P2 ways of choosing hands for that and only 2 in which the opposite player would have 2 10s.
River is Jack:
$frac{1}{41} + frac{1}{40}$ = 4.9%, either the first one is a Jack or the second one is a Jack
Dealt QD, probability of Royal Flush:
$frac{3P2*39}{41P3}$ = 14.6%, 3P2 ways to arrange the 2 cards you need and the other card you don't need over the possible ways you could be dealt the cards.
$frac{3P2}{39P2}$ = 0.6%, 3P2 ways to choose the jacks that you can have from 39P2 choices.
I apologize profusely because I am not very good at statistics and this has been troubling me greatly. I want to know the flaws in how I am thinking.
probability statistics poker
probability statistics poker
asked 2 days ago
Ryan Schaefer
991
asked 2 days ago
Ryan Schaefer
991
asked 2 days ago
Ryan Schaefer
991
asked 2 days ago
Ryan Schaefer
991
asked 2 days ago
Ryan Schaefer
991
991
add a comment |
add a comment |
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