Ec primes dividing ec numbers











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A conjecture about numbers of the form $10^{m}(2^{k}−1)+2^{k-1}−1$, where $m$ is the number of decimal digits of $ 2^{k-1}$.



In this question ec numbers are introduced, formed by the concatenation of two consecutive Mersenne numbers ($157$ for example is denoted by $ec(4)$).

The ec prime $ec(7)=12763$ divides ec numbers $ec(7717)$, $ec(14259)$, $ec(15906)$,...



Does $ec(7)$ divide an infinite number of ec-numbers?



Is $255127$ the largest ec prime dividing at least one ec number besides itself?










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    A conjecture about numbers of the form $10^{m}(2^{k}−1)+2^{k-1}−1$, where $m$ is the number of decimal digits of $ 2^{k-1}$.



    In this question ec numbers are introduced, formed by the concatenation of two consecutive Mersenne numbers ($157$ for example is denoted by $ec(4)$).

    The ec prime $ec(7)=12763$ divides ec numbers $ec(7717)$, $ec(14259)$, $ec(15906)$,...



    Does $ec(7)$ divide an infinite number of ec-numbers?



    Is $255127$ the largest ec prime dividing at least one ec number besides itself?










    share|cite|improve this question









    New contributor




    paolo galli is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
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      A conjecture about numbers of the form $10^{m}(2^{k}−1)+2^{k-1}−1$, where $m$ is the number of decimal digits of $ 2^{k-1}$.



      In this question ec numbers are introduced, formed by the concatenation of two consecutive Mersenne numbers ($157$ for example is denoted by $ec(4)$).

      The ec prime $ec(7)=12763$ divides ec numbers $ec(7717)$, $ec(14259)$, $ec(15906)$,...



      Does $ec(7)$ divide an infinite number of ec-numbers?



      Is $255127$ the largest ec prime dividing at least one ec number besides itself?










      share|cite|improve this question









      New contributor




      paolo galli is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
      Check out our Code of Conduct.











      A conjecture about numbers of the form $10^{m}(2^{k}−1)+2^{k-1}−1$, where $m$ is the number of decimal digits of $ 2^{k-1}$.



      In this question ec numbers are introduced, formed by the concatenation of two consecutive Mersenne numbers ($157$ for example is denoted by $ec(4)$).

      The ec prime $ec(7)=12763$ divides ec numbers $ec(7717)$, $ec(14259)$, $ec(15906)$,...



      Does $ec(7)$ divide an infinite number of ec-numbers?



      Is $255127$ the largest ec prime dividing at least one ec number besides itself?







      number-theory






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      paolo galli is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
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          The ec-prime $ec(8)$ divides $ec(k)$ for the following exponents upto $10^7$



          284274 1129738 1189846 1214317 1301821 1362842 1445186 1795733 1853089 2203032 2
          237654 2267753 3055770 3080516 3532082 3624320 3842054 4653541 4839828 5220495 5
          436726 5444103 5828733 5956001 6144125 6432347 6821804 7135640 7173850 7458223 7
          513523 7690720 7979828 8006289 8010227 8162195 8195920 8255472 8412247 8449267 8
          590602 8936597 9571824 9625677 9853929


          I do not know hot to prove it, but both $ec(7)$ and $ec(8)$ should divide infinite many ec-numbers. For example $(2^{n+1}-1)cdot 10^m+2^n-1$ is divisble by $ec(7)$ , if $n$ is of the form $12762k+81$ and $m$ of the form $709l+1$ (but not only then!) . And $(2^{n+1}-1)cdot 10^m+2^n-1$ is divisible by $ec(8)$ , if $n$ is of the form $42521k+1$ and $m$ of the form $85042l+31514$ (but not only then!). I do not know whether even larger ec-primes divide some ec-numbers.






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            The ec-prime $ec(8)$ divides $ec(k)$ for the following exponents upto $10^7$



            284274 1129738 1189846 1214317 1301821 1362842 1445186 1795733 1853089 2203032 2
            237654 2267753 3055770 3080516 3532082 3624320 3842054 4653541 4839828 5220495 5
            436726 5444103 5828733 5956001 6144125 6432347 6821804 7135640 7173850 7458223 7
            513523 7690720 7979828 8006289 8010227 8162195 8195920 8255472 8412247 8449267 8
            590602 8936597 9571824 9625677 9853929


            I do not know hot to prove it, but both $ec(7)$ and $ec(8)$ should divide infinite many ec-numbers. For example $(2^{n+1}-1)cdot 10^m+2^n-1$ is divisble by $ec(7)$ , if $n$ is of the form $12762k+81$ and $m$ of the form $709l+1$ (but not only then!) . And $(2^{n+1}-1)cdot 10^m+2^n-1$ is divisible by $ec(8)$ , if $n$ is of the form $42521k+1$ and $m$ of the form $85042l+31514$ (but not only then!). I do not know whether even larger ec-primes divide some ec-numbers.






            share|cite|improve this answer

























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              The ec-prime $ec(8)$ divides $ec(k)$ for the following exponents upto $10^7$



              284274 1129738 1189846 1214317 1301821 1362842 1445186 1795733 1853089 2203032 2
              237654 2267753 3055770 3080516 3532082 3624320 3842054 4653541 4839828 5220495 5
              436726 5444103 5828733 5956001 6144125 6432347 6821804 7135640 7173850 7458223 7
              513523 7690720 7979828 8006289 8010227 8162195 8195920 8255472 8412247 8449267 8
              590602 8936597 9571824 9625677 9853929


              I do not know hot to prove it, but both $ec(7)$ and $ec(8)$ should divide infinite many ec-numbers. For example $(2^{n+1}-1)cdot 10^m+2^n-1$ is divisble by $ec(7)$ , if $n$ is of the form $12762k+81$ and $m$ of the form $709l+1$ (but not only then!) . And $(2^{n+1}-1)cdot 10^m+2^n-1$ is divisible by $ec(8)$ , if $n$ is of the form $42521k+1$ and $m$ of the form $85042l+31514$ (but not only then!). I do not know whether even larger ec-primes divide some ec-numbers.






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                The ec-prime $ec(8)$ divides $ec(k)$ for the following exponents upto $10^7$



                284274 1129738 1189846 1214317 1301821 1362842 1445186 1795733 1853089 2203032 2
                237654 2267753 3055770 3080516 3532082 3624320 3842054 4653541 4839828 5220495 5
                436726 5444103 5828733 5956001 6144125 6432347 6821804 7135640 7173850 7458223 7
                513523 7690720 7979828 8006289 8010227 8162195 8195920 8255472 8412247 8449267 8
                590602 8936597 9571824 9625677 9853929


                I do not know hot to prove it, but both $ec(7)$ and $ec(8)$ should divide infinite many ec-numbers. For example $(2^{n+1}-1)cdot 10^m+2^n-1$ is divisble by $ec(7)$ , if $n$ is of the form $12762k+81$ and $m$ of the form $709l+1$ (but not only then!) . And $(2^{n+1}-1)cdot 10^m+2^n-1$ is divisible by $ec(8)$ , if $n$ is of the form $42521k+1$ and $m$ of the form $85042l+31514$ (but not only then!). I do not know whether even larger ec-primes divide some ec-numbers.






                share|cite|improve this answer












                The ec-prime $ec(8)$ divides $ec(k)$ for the following exponents upto $10^7$



                284274 1129738 1189846 1214317 1301821 1362842 1445186 1795733 1853089 2203032 2
                237654 2267753 3055770 3080516 3532082 3624320 3842054 4653541 4839828 5220495 5
                436726 5444103 5828733 5956001 6144125 6432347 6821804 7135640 7173850 7458223 7
                513523 7690720 7979828 8006289 8010227 8162195 8195920 8255472 8412247 8449267 8
                590602 8936597 9571824 9625677 9853929


                I do not know hot to prove it, but both $ec(7)$ and $ec(8)$ should divide infinite many ec-numbers. For example $(2^{n+1}-1)cdot 10^m+2^n-1$ is divisble by $ec(7)$ , if $n$ is of the form $12762k+81$ and $m$ of the form $709l+1$ (but not only then!) . And $(2^{n+1}-1)cdot 10^m+2^n-1$ is divisible by $ec(8)$ , if $n$ is of the form $42521k+1$ and $m$ of the form $85042l+31514$ (but not only then!). I do not know whether even larger ec-primes divide some ec-numbers.







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                answered 2 days ago









                Peter

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