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If $3n^3-5n^2-4n-2$ can be divided by $n-2$ . Find all possible integer values for $n$. [on hold]
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If $3n^3-5n^2-4n-2$ can be divided by $n-2$ , Find all possible integer values for $n$.
algebra-precalculus
edited yesterday
Bill Dubuque
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asked yesterday
ten1o
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put on hold as off-topic by Clayton, greedoid, amWhy, Rebellos, jgon yesterday
This question appears to be off-topic. The users who voted to close gave this specific reason:
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up vote
-1
down vote
favorite
If $3n^3-5n^2-4n-2$ can be divided by $n-2$ , Find all possible integer values for $n$.
algebra-precalculus
edited yesterday
Bill Dubuque
206k29189621
asked yesterday
ten1o
1335
put on hold as off-topic by Clayton, greedoid, amWhy, Rebellos, jgon yesterday
This question appears to be off-topic. The users who voted to close gave this specific reason:
- "This question is missing context or other details: Please improve the question by providing additional context, which ideally includes your thoughts on the problem and any attempts you have made to solve it. This information helps others identify where you have difficulties and helps them write answers appropriate to your experience level." – Clayton, greedoid, amWhy, Rebellos, jgon
If this question can be reworded to fit the rules in the help center, please edit the question.
add a comment |
up vote
-1
down vote
favorite
up vote
-1
down vote
favorite
If $3n^3-5n^2-4n-2$ can be divided by $n-2$ , Find all possible integer values for $n$.
algebra-precalculus
edited yesterday
Bill Dubuque
206k29189621
asked yesterday
ten1o
1335
If $3n^3-5n^2-4n-2$ can be divided by $n-2$ , Find all possible integer values for $n$.
algebra-precalculus
algebra-precalculus
edited yesterday
Bill Dubuque
206k29189621
asked yesterday
ten1o
1335
edited yesterday
Bill Dubuque
206k29189621
asked yesterday
ten1o
1335
edited yesterday
Bill Dubuque
206k29189621
edited yesterday
Bill Dubuque
206k29189621
edited yesterday
Bill Dubuque
206k29189621
206k29189621
asked yesterday
ten1o
1335
asked yesterday
ten1o
1335
asked yesterday
ten1o
1335
1335
put on hold as off-topic by Clayton, greedoid, amWhy, Rebellos, jgon yesterday
This question appears to be off-topic. The users who voted to close gave this specific reason:
- "This question is missing context or other details: Please improve the question by providing additional context, which ideally includes your thoughts on the problem and any attempts you have made to solve it. This information helps others identify where you have difficulties and helps them write answers appropriate to your experience level." – Clayton, greedoid, amWhy, Rebellos, jgon
If this question can be reworded to fit the rules in the help center, please edit the question.
put on hold as off-topic by Clayton, greedoid, amWhy, Rebellos, jgon yesterday
This question appears to be off-topic. The users who voted to close gave this specific reason:
- "This question is missing context or other details: Please improve the question by providing additional context, which ideally includes your thoughts on the problem and any attempts you have made to solve it. This information helps others identify where you have difficulties and helps them write answers appropriate to your experience level." – Clayton, greedoid, amWhy, Rebellos, jgon
If this question can be reworded to fit the rules in the help center, please edit the question.
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3 Answers
3
active
oldest
votes
up vote
0
down vote
accepted
Remainder theorem:
$P(n)=3n^3-5n^2-4n-2$ is divided by $(n-2)$,
the remainder is $P(2).$
$P(2)=$
$2(2^3)-5(2^2) -4(2) -2=-6.$
$P(n)$ is divisible by $(n-2)$ if $(n-2)|(-6).$
https://en.m.wikipedia.org/wiki/Polynomial_remainder_theorem
answered yesterday
Peter Szilas
9,9192720
add a comment |
up vote
1
down vote
hint
$$3n^3-5n^2-4n-2=$$
$$3n^3-6n^2+n^2-2n-2n+4-6=$$
$$(n-2)(3n^2+n-2)-6$$
it is divisible if $n-2$ divise $6$.
answered yesterday
hamam_Abdallah
36.5k21533
add a comment |
up vote
0
down vote
$$frac{3n^3-5n^2-4n-22}{n-2}=3n^2+n-2-frac6{n-2}$$
This is an integer iff $n-2mid 6$.
answered yesterday
ajotatxe
52.1k23688
Take of two from twotwo in numerator.
– hamam_Abdallah
yesterday
add a comment |
3 Answers
3
active
oldest
votes
3 Answers
3
active
oldest
votes
active
oldest
votes
active
oldest
votes
up vote
0
down vote
accepted
Remainder theorem:
$P(n)=3n^3-5n^2-4n-2$ is divided by $(n-2)$,
the remainder is $P(2).$
$P(2)=$
$2(2^3)-5(2^2) -4(2) -2=-6.$
$P(n)$ is divisible by $(n-2)$ if $(n-2)|(-6).$
https://en.m.wikipedia.org/wiki/Polynomial_remainder_theorem
answered yesterday
Peter Szilas
9,9192720
add a comment |
up vote
0
down vote
accepted
Remainder theorem:
$P(n)=3n^3-5n^2-4n-2$ is divided by $(n-2)$,
the remainder is $P(2).$
$P(2)=$
$2(2^3)-5(2^2) -4(2) -2=-6.$
$P(n)$ is divisible by $(n-2)$ if $(n-2)|(-6).$
https://en.m.wikipedia.org/wiki/Polynomial_remainder_theorem
answered yesterday
Peter Szilas
9,9192720
add a comment |
up vote
0
down vote
accepted
up vote
0
down vote
accepted
Remainder theorem:
$P(n)=3n^3-5n^2-4n-2$ is divided by $(n-2)$,
the remainder is $P(2).$
$P(2)=$
$2(2^3)-5(2^2) -4(2) -2=-6.$
$P(n)$ is divisible by $(n-2)$ if $(n-2)|(-6).$
https://en.m.wikipedia.org/wiki/Polynomial_remainder_theorem
answered yesterday
Peter Szilas
9,9192720
Remainder theorem:
$P(n)=3n^3-5n^2-4n-2$ is divided by $(n-2)$,
the remainder is $P(2).$
$P(2)=$
$2(2^3)-5(2^2) -4(2) -2=-6.$
$P(n)$ is divisible by $(n-2)$ if $(n-2)|(-6).$
https://en.m.wikipedia.org/wiki/Polynomial_remainder_theorem
answered yesterday
Peter Szilas
9,9192720
answered yesterday
Peter Szilas
9,9192720
answered yesterday
Peter Szilas
9,9192720
answered yesterday
Peter Szilas
9,9192720
9,9192720
add a comment |
add a comment |
up vote
1
down vote
hint
$$3n^3-5n^2-4n-2=$$
$$3n^3-6n^2+n^2-2n-2n+4-6=$$
$$(n-2)(3n^2+n-2)-6$$
it is divisible if $n-2$ divise $6$.
answered yesterday
hamam_Abdallah
36.5k21533
add a comment |
up vote
1
down vote
hint
$$3n^3-5n^2-4n-2=$$
$$3n^3-6n^2+n^2-2n-2n+4-6=$$
$$(n-2)(3n^2+n-2)-6$$
it is divisible if $n-2$ divise $6$.
answered yesterday
hamam_Abdallah
36.5k21533
add a comment |
up vote
1
down vote
up vote
1
down vote
hint
$$3n^3-5n^2-4n-2=$$
$$3n^3-6n^2+n^2-2n-2n+4-6=$$
$$(n-2)(3n^2+n-2)-6$$
it is divisible if $n-2$ divise $6$.
answered yesterday
hamam_Abdallah
36.5k21533
hint
$$3n^3-5n^2-4n-2=$$
$$3n^3-6n^2+n^2-2n-2n+4-6=$$
$$(n-2)(3n^2+n-2)-6$$
it is divisible if $n-2$ divise $6$.
answered yesterday
hamam_Abdallah
36.5k21533
answered yesterday
hamam_Abdallah
36.5k21533
answered yesterday
hamam_Abdallah
36.5k21533
answered yesterday
hamam_Abdallah
36.5k21533
36.5k21533
add a comment |
add a comment |
up vote
0
down vote
$$frac{3n^3-5n^2-4n-22}{n-2}=3n^2+n-2-frac6{n-2}$$
This is an integer iff $n-2mid 6$.
answered yesterday
ajotatxe
52.1k23688
Take of two from twotwo in numerator.
– hamam_Abdallah
yesterday
add a comment |
up vote
0
down vote
$$frac{3n^3-5n^2-4n-22}{n-2}=3n^2+n-2-frac6{n-2}$$
This is an integer iff $n-2mid 6$.
answered yesterday
ajotatxe
52.1k23688
Take of two from twotwo in numerator.
– hamam_Abdallah
yesterday
add a comment |
up vote
0
down vote
up vote
0
down vote
$$frac{3n^3-5n^2-4n-22}{n-2}=3n^2+n-2-frac6{n-2}$$
This is an integer iff $n-2mid 6$.
answered yesterday
ajotatxe
52.1k23688
$$frac{3n^3-5n^2-4n-22}{n-2}=3n^2+n-2-frac6{n-2}$$
This is an integer iff $n-2mid 6$.
answered yesterday
ajotatxe
52.1k23688
edited yesterday
answered yesterday
ajotatxe
52.1k23688
answered yesterday
ajotatxe
52.1k23688
answered yesterday
ajotatxe
52.1k23688
52.1k23688
Take of two from twotwo in numerator.
– hamam_Abdallah
yesterday
add a comment |
Take of two from twotwo in numerator.
– hamam_Abdallah
yesterday
Take of two from twotwo in numerator.
– hamam_Abdallah
yesterday
Take of two from twotwo in numerator.
– hamam_Abdallah
yesterday
add a comment |
